20
Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 , 2021 @ KERN Lukas Kiihne Max Planck Institute for Mathematics in the Sciences Leipzig Joint work with Mohamed Barakat , Reimer Behrends , Christopher Jefferson , and Martin Lerner

Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

  • Upload
    others

  • View
    11

  • Download
    0

Embed Size (px)

Citation preview

Page 1: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Verifying Tercio 's freeness conjecture for small

arrangements in arbitrary characteristic

February 17 , 2021 @ KERN

Lukas Kiihne

Max Planck Institute for

Mathematics in the SciencesLeipzig

Joint work with Mohamed Barakat,Reimer Behrends

,

Christopher Jefferson , and Martin Lerner

Page 2: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

DEFINITIONS EXAMPLE

a. A arrangement of hyperplanes in V The Braid

over ff with equations on. for HEA . arrangement As° The module of logarithmic X

, y , Z ,X-y

derivations D H) is defined as X- Z, y- z

DIA)= ( D- C-Devs 10 c- cops the A. 3.

Where S-FCK .... ,xd (dim V-- l) As is free :

A is called free if DCA) Q -

- XE -1yd, -1 Zoeis a free S- module

o-z-efcf-iysytz.dz• The intersection lattice LCA) is

( ( A) =L Heh, HI BEA 3.

05-55+59,t Ecf

Page 3: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

CONJECTURE (Tera o ) THEOREM ( B 133 KL'

19 , Barakat, K.

'21+7

If A,B are arrangements over Tera o 's conjecture holds for arrangements

IF with LCA ) - LCB) then of size up to 14 and rank 3

A is free ⇐ B is free in arbitrary characteristic.

Matroid. mathematik

. Uni- Siegen .de User : matroid Password : matroid

Page 4: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Sage experimentation with stable Grothendieckpolynomials

arXiv: 1911.08732The Electronic Journal of Combinatorics 27(2) (2020), #P2.29

Joint with Jennifer Morse, Wencin Poh and Anne Schilling

Sage/Oscar Days for Combinatorial Algebraic Geometry, ICERMFeburary 17, 2021

Pan, Jianping (UC Davis) Crystal for stable Grothendieck polynomials 1 / 3

Page 5: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

[Xw ]

G(β)w

poly rep, K -theory

G (β)w

stable limit

FwSw

β = 0β = 0

stable limit

{ decreasingfactorization of H0(n)

}

{ reduced decreasingfactorization of Sn

}gen. fun.

gen. fun.

crystalscombinat. model for rep.

directed graphs

today!

Pan, Jianping (UC Davis) Crystal for stable Grothendieck polynomials 2 / 3

Page 6: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

(31)(32)( )(31)(1)(2)(31)(2)(2)(31)(3)(2)(1)(31)(2)(1)(32)(2)(3)(31)(2)(31)( )(32)(1)(1)(32)(1)(3)(32)(3)(1)(32)( )(31)(32)

G132(x, β) = s21+β(2s211 + s22)+β2(3s2111+2s221)+· · ·

(31) (32) ( )

(31) (1) (2)

(1) (3) (3, 2)

(1) (32) (2)

(31) (2) (2)

(31) (3) (2)

(31) ( ) (32)

( ) (31) (32)

(3) (1) (32) (1) (31) (2)

(1) (1) (32)

(3) (31) (2)

1

1

1

2

2

1

2

2

2 1

2 31 3

, 3 32 2

Pan, Jianping (UC Davis) Crystal for stable Grothendieck polynomials 3 / 3

Page 7: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Deformation classes of bitangentsto tropical quartic curves

Marta Pani zzut ( TU Berlin )

jww Acheydis Geiger

sage Oscar Days - February 17, 2021

Page 8: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Tropical smooth plane.

quartic curve ~,dual to the r

regular Unimodulartriangulation T of 412-

w Ehas infinitely many bi tangent tropical

lines grouped into seven bitangent classes .

These classes are encoded by subcomplexes of Tdescribed by Cueto and Markwig

'

20.

Page 9: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Our starting points :

f. regularunimodular triangulations offs,

Brodsky . Joswig. Morrison and Sturm fees 'isRs . bi tangent classes and real lifting conditions

Current work :Cueto and Markwig

'

20.

•Enumeration of ( deformationsbi tangent classes B

• Hyperplane arrangements Goal :induced by bitangent classes . computational proof of

u. . Pliicker 's Theorem :

•Real lifting conditions Real smooth quartic curve has

[polymakeeither 48.16028 reaebitangents .

Page 10: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Variational GIT for Complete Intersections and a Hyperplane Section via Sage

Variational GIT for Complete Intersections and aHyperplane Section via Sage

Papazachariou Theodoros Stylianos

15 February 2021

Page 11: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Variational GIT for Complete Intersections and a Hyperplane Section via Sage

Some Background on (Variational) GIT

Main goal: describe quotients of (projective) varieties X with (reductive)group actions, with respect to some G -linearization L.

If Pic(X )G = Z2, the (categorical quotient)X �L G : = Proj

⊕m≥0H

0(X ,L⊗m)G depends on L = O(a, b). Ifx ∈ X �L G we say x is a semi-stable point. We also have a finitewall-chamber decomposition [ti , ti+1], where stability conditions are thesame for each wall/chamber, ti = bi

ai.

We also have a moduli space MGITwhere the points are stable. We find

stable/semi-stable points via the Hilbert-Mumford numerical criterion.

The action of G on X induces an action of Gm on X via one-parametersubgroups, λ : Gm → G , via x → λ(t) · x , t ∈ Gm.

For all λ, H-M function µt(X , λ) ≥ 0 (> 0 resp.) for (semi)-stable points.If X is a Hilbert scheme parametrising hypersurfaces, µt depends onmonomials of a specific degree.

Page 12: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Variational GIT for Complete Intersections and a Hyperplane Section via Sage

Complete Intersections and Hyperplane Section

We study pairs X = {f1 = · · · = fk = 0} ⊂ Pn, H a hyperplane,parametrized by their Hilbert scheme R where Pic(R)G = Z2,G = SL(n + 1).

Can find an explicit finite set Pn,k,d of 1-PS that is maximal with respectto unstable and non-stable points. This is achieved by solving a number oflinear systems dependent on the n, k , d on Sage. Using this, we can findall walls and chambers [ti , ti+1] by solving a number of equationsdependant on the monomials of degree d and 1.

We also compute finite sets Nt (λ) for λ ∈ Pn,k,d , N−t (λ), thatparametrise non-stable/unstable pairs. This is achieved by testing theH-M function for each t for all λ with some constraints on the monomials.

Constraints: as n, k , d increase the program becomes computationallyoverloaded and slows down.

Page 13: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Matrix Schubert varieties and CM regularity

Colleen RobichauxUniversity of Illinois at Urbana-Champaign

joint work with Jenna Rajchgot and Anna WeigandtIntroductory Workshop: Combinatorial Algebraic Geometry Lightning Talks

February 17, 2021

Colleen Robichaux University of Illinois at Urbana-Champaign

Matrix Schubert varieties and CM regularity

Page 14: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Matrix Schubert varieties and CM regularity

Matrix Schubert varieties Xw , where w ∈ Sn, are generalizeddeterminantal varieties. To study Xw we can consider the algebraicinvariant of CM regularity reg(C[Xw ]).

Theorem

reg(C[Xw ]) = deg Gw (x1, . . . , xn) − `(w).

Problem

Give an easily computable formula for deg Gw (x1, . . . , xn).

Colleen Robichaux University of Illinois at Urbana-Champaign

Matrix Schubert varieties and CM regularity

Page 15: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Finding the degree of Gv vexillary

Theorem [Rajchgot-R.-Weigandt ’21+]

Suppose v ∈ Sn vexillary. Then

deg(Gv ) = `(v) +n∑

i=1

∑µ∈comp(λ(v)|≥i)

sv(µ).

Example: v = 5713624

0 0 0 00 0 0 0 1

11 2

0 0 0 0 10 0 0 01 21

gives deg(Gv ) = `(v) + ((2+ 1) + (1)) = 12+ 4 = 16.

Colleen Robichaux University of Illinois at Urbana-Champaign

Matrix Schubert varieties and CM regularity

Page 16: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Bound Quivers of Exceptional Collections

Mahrud Sayrafi, University of Minnesota, Twin Cities Exceptional Collections and the Quiver of Sections

Page 17: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

Resolution of the Diagonal, the Hochschild way

S6

{5,−5}{4,−4}{3,−3}{2,−2}{1,−1}{0, 0}

a b c 0 0 0 0 0 0 0 0 0−x 0 0 a b c 0 0 0 0 0 00 −y 0 −x 0 0 a b c 0 0 00 0 −z 0 −y 0 −x 0 0 a b 00 0 0 0 0 −z 0 −y 0 −x 0 a0 0 0 0 0 0 0 0 −z 0 −y −x

←−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−− S12

S12

{5,−4}{5,−3}{5,−2}{4,−3}{4,−2}{4,−1}{3,−2}{3,−1}{3, 0}{2,−1}{2, 0}{1, 0}

−b −c 0 0 0 0a 0 −c 0 0 00 a b 0 0 00 0 0 −b −c 0−x 0 0 a 0 00 −x 0 0 a 0y 0 0 0 0 −b0 0 0 −x 0 a0 0 −y 0 −x 00 z 0 y 0 00 0 z 0 0 −x0 0 0 0 z y

←−−−−−−−−−−−−−−−−−−−−− S6

Mahrud Sayrafi, University of Minnesota, Twin Cities Exceptional Collections and the Quiver of Sections

Page 18: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

a ‘quantum equals classical’ theoremfor n-pointed gromov-witten

invariants of degree one

Weihong Xu(Joint with Linda Chen, Angela Gibney, Lauren Heller,

Elana Kalashnikov, and Hannah Larson)

February, 20211 / 3

Page 19: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

A Good Old Example

Fl(1, 2; 4)p−−−−→ P3

q

yGr(2, 4)

=

M0,1(P3, 1)ev−−−−→ P3y

M0,0(P3, 1)

Line Γ ⊂ P3

q(p−1(Γ)) Schubert divisor4

= 2 · = 2 · [point]

4 · codim(Γ) = dim(M0,4(P3, 1))The Gromov-Witten invariant∫M0,4(P3,1)

ev∗1 [Γ] · · · ev∗

4 [Γ] = 2

2 / 3

Page 20: Verifying Tercio 's freeness for small - ICERM - Home · 2021. 2. 17. · Verifying Tercio 's freeness conjecture for small arrangements in arbitrary characteristic February 17 2021

More Generally

X = G/P flag varietyP maximal parabolic corresponding to a long simple rootevi : M0,n(X , 1)→ XSchubert varieties Γ1, · · · , Γn ⊂ X ,

∑ni=1 codim(Γi ) = dim(M0,n(X , 1))

Theorem The (n-pointed, genus 0, degree 1) Gromov-Witten Invariant∫M0,n(X ,1)

ev∗1 [Γ1] · · · ev∗

n [Γn]

= #{line in X meeting g1Γ1, · · · , gnΓn} for g1, · · · , gn ∈ G general=

∫G/Q

[q(p−1(Γ1))] · · · [q(p−1(Γn))]

G/(P ∩ Q)p−−−−→ G/P

q

yG/Q

=

M0,1(X , 1)ev−−−−→ Xy

M0,0(X , 1)

Remarks: 1) n = 3 case is known; 2) proof is independent of Lie type

3 / 3