vectors.pptx

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    Ch 3 Working with Vectors

    To describe motion correctly, we have toknow relative to what does the objectmove.

    Consider a passenger walking on a movingbus. The bus moves 80 m in 10 s. Duringthat time the passenger walks m !rom theback o! the bus to the !ront.

    The velocity o! the bus relative to the road is" #.......#..The velocity o! the passenger relative to the bus is"

    ####...The velocity o! the passenger relative to the road is"

    ####...

    8,0 m$s0, m$s

    8, m$s

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    Vb= 8m/s

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    Vb= 8m/s

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    Vb= 8m/s

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    Vb= 8m/s

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    Vp= 0,5 m/s

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    vp= 0,5 m/svb= 8 m/s

    vres= vb+ vp ?

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    vp= 0,5 m/s

    vb= 8 m/s

    (vres)2= (vb)

    2+ (vp)2

    = 64 + 0,25

    = 64,25

    vres= 8,02 m/s

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    %calar

    &ector

    ' scalar is a (uantity speci)ed

    only by its magnitude, like

    mass, energy.

    ' vector is a (uantity which isspeci)ed by both magnitude

    and direction, like !orce.

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    Displacement, 2 km, 45 Velocity, 60 km/h, N

    Force, 12 N, down

    2km

    some more e!amples o" #ectors$

    V = 1000 km/h, S

    W = 50 N, down

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    %!ample 1

    A

    B

    A B

    R A B

    %!ample 2

    A B

    A

    BR A B

    %!ample &

    A B

    A

    B

    R A B

    'ddin( and s)*tractin( o" #ectors$

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    A

    B

    Determine$

    R A BR A B

    AB

    R A B A

    B

    B

    ( )A B= +

    R

    'ddin( as opposed to s)*tractin(

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    A

    B

    R A B

    +he arallelo(ram method$

    R

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    R

    y x

    Rx

    yR

    R R Rx y

    R Rx cos

    sinyR R =

    -plittin( a #ector into components$

    1tan

    y

    x

    R

    R

    =

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    Rx

    yR

    -plittin( a #ector into components$

    The two components Rxand Rywill have

    the same e*ect as the original vector R.

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    %plit the !ollowing !orce into twoperpendicular components such that#

    cosmg

    sinmg

    one component is perpendicular tothe incline plane, and

    the other component is parallel to

    the incline plane.

    mg

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    cosmg

    sinmg

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    ! "#er$ge #e%ocit&

    distance coveredAve speed =time taken

    peed is a sca!ar "#antit$, b#t ve!ocit$ isa vector % &avin' sie and direction

    disp!acementAve ve!ocit$ =time taken

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    !3 'nst$nt$neo(s #e%ocit&

    0

    instantaneo#s ve!ocit$ = !imt

    xv

    t

    =

    r

    x

    tt1

    t2

    x1

    x2 ) xave v

    t=

    r

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    !) "cce%er$tion

    c&an'e in ve!ocit$Ave acce!eration =time interva!

    vat

    =

    r

    0

    instantaneo#s acce!eration = !imt

    vat

    =

    r

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    *(estions+

    *s t&e o!!oin' statement tr#e or a!se? If the velocity of an object is zero, then the acceleration must also be zero.

    -an a stationar$ car be acce!eratin'?

    .&at is t&e acce!eration o a car movin'at a constant 100 km/& a!on' a strai'&troad?

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    *s t&e direction o t&e disp!acement,ve!ocit$ and acce!eration a!a$s t&esame?

    .&at is t&e direction o t&e disp!acement,ve!ocit$ and acce!eration o a car t&atcomes to a stop d#e to its brakes?

    *(estions+

    2 7 F f lli bj t

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    2-7 Free falling objects

    +ravitational acceleration, g"

    ' body close to the earths sur!acee-periences an acceleration calledgravitational acceleration g// with asie o! ,8m$s2 and in a directionpointing to the centre o! the earth.