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7/25/2019 vectors.pptx
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Ch 3 Working with Vectors
To describe motion correctly, we have toknow relative to what does the objectmove.
Consider a passenger walking on a movingbus. The bus moves 80 m in 10 s. Duringthat time the passenger walks m !rom theback o! the bus to the !ront.
The velocity o! the bus relative to the road is" #.......#..The velocity o! the passenger relative to the bus is"
####...The velocity o! the passenger relative to the road is"
####...
8,0 m$s0, m$s
8, m$s
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Vb= 8m/s
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Vb= 8m/s
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Vb= 8m/s
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Vb= 8m/s
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Vp= 0,5 m/s
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vp= 0,5 m/svb= 8 m/s
vres= vb+ vp ?
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vp= 0,5 m/s
vb= 8 m/s
(vres)2= (vb)
2+ (vp)2
= 64 + 0,25
= 64,25
vres= 8,02 m/s
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%calar
&ector
' scalar is a (uantity speci)ed
only by its magnitude, like
mass, energy.
' vector is a (uantity which isspeci)ed by both magnitude
and direction, like !orce.
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Displacement, 2 km, 45 Velocity, 60 km/h, N
Force, 12 N, down
2km
some more e!amples o" #ectors$
V = 1000 km/h, S
W = 50 N, down
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%!ample 1
A
B
A B
R A B
%!ample 2
A B
A
BR A B
%!ample &
A B
A
B
R A B
'ddin( and s)*tractin( o" #ectors$
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A
B
Determine$
R A BR A B
AB
R A B A
B
B
( )A B= +
R
'ddin( as opposed to s)*tractin(
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A
B
R A B
+he arallelo(ram method$
R
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R
y x
Rx
yR
R R Rx y
R Rx cos
sinyR R =
-plittin( a #ector into components$
1tan
y
x
R
R
=
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Rx
yR
-plittin( a #ector into components$
The two components Rxand Rywill have
the same e*ect as the original vector R.
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%plit the !ollowing !orce into twoperpendicular components such that#
cosmg
sinmg
one component is perpendicular tothe incline plane, and
the other component is parallel to
the incline plane.
mg
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cosmg
sinmg
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! "#er$ge #e%ocit&
distance coveredAve speed =time taken
peed is a sca!ar "#antit$, b#t ve!ocit$ isa vector % &avin' sie and direction
disp!acementAve ve!ocit$ =time taken
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!3 'nst$nt$neo(s #e%ocit&
0
instantaneo#s ve!ocit$ = !imt
xv
t
=
r
x
tt1
t2
x1
x2 ) xave v
t=
r
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!) "cce%er$tion
c&an'e in ve!ocit$Ave acce!eration =time interva!
vat
=
r
0
instantaneo#s acce!eration = !imt
vat
=
r
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*(estions+
*s t&e o!!oin' statement tr#e or a!se? If the velocity of an object is zero, then the acceleration must also be zero.
-an a stationar$ car be acce!eratin'?
.&at is t&e acce!eration o a car movin'at a constant 100 km/& a!on' a strai'&troad?
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*s t&e direction o t&e disp!acement,ve!ocit$ and acce!eration a!a$s t&esame?
.&at is t&e direction o t&e disp!acement,ve!ocit$ and acce!eration o a car t&atcomes to a stop d#e to its brakes?
*(estions+
2 7 F f lli bj t
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2-7 Free falling objects
+ravitational acceleration, g"
' body close to the earths sur!acee-periences an acceleration calledgravitational acceleration g// with asie o! ,8m$s2 and in a directionpointing to the centre o! the earth.