8/9/2019 U.P Calculations

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Experiment 01

Just write down practical yield of your on

group.

Experiment 02

Just write down practical yield of your on

group.

Experiment 03

Perform calculation for this experiment theoretical and

percentage yield

Experiment 04

Just write down practical yield of your on

group.

Experiment 5- Preparation of nitroen!ene

"#eoretical calculations

$alanced %#emical E&uation

%alculation of '(imiting )eactant '

Given reagents :-

Benzene = 15ml , itric acid = 1!ml , "ensity of #enzene =$%!&'5g(ml

"ensity of nitric acid =1%51g(ml

)asses of #oth components :-

$en!ene

)ass = $%!&'5*15

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1+%15g

*itric acid

)ass = 1%51x1!

&%1!g

+oles calculations ,-

)ole of #enzene = 1+%15(&!

)ole of #enzene = $%1'!moles

)ole of nitric acid = &%1!('+

)ole of nitric acid = $%+

toic#iometric ratio ,-

Benzene : itric acid

1 : 1

i/en moles ,-

Benzene : itric acid

$%1'! : $%+

.o proved that #enzene is limiting reactant

/alculations al0ays #ased on limiting reactant

"#eoretical yield ,-

moles of nitro #enzene produced = $%1'! moles

mass of nitro #enzene produced = $%1'!x1+

$%''gms

ctual yield ,-

0eight of your product that o#tained in la#

age yield = 2actual yield(theoretical yield3x1$$

- Preparation of

oxalic acid

"#eoretical calculations

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E&uation ,

%1222113*3 6%72.223*2112

i/en amounts ,

%ane ugar used *itric cid used

5 grams 20 ml

+ole %alculations,

For Sugar

65gm786342 gm8mole7 0.014 moles.

For Nitric Acid

625 cm37961.51 g8cm37 3:.:5 gm.

63:.:5 gm7863 gm8mole7 0. molestoic#iometric ratio,-

1 , 3

0.02::

i/en ratio

0.014 , 0.

0.0243

o; ugar is limiting reactant.

"#eoretical

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Practical yield ,-

ctual yield ,-

0eight of your product that o#tained in la#

age yield = 2actual yield(theoretical yield3x1$$

:- preparation of et#yl

acetate

toic#iometric calculations

Balanced Chemical Equation

%alculation of 'limiting reactant>

i/en )eagent,-

4thyl alcohol = 5 ml , cetic acid = 5

ml

"ensity of 4thyl alcohol = $%&!6 g(cm+

"ensity of cetic acid = 1%$6 g(cm+

+asses of components,-4thyl alcohol mass = $%&!6 7 5 = 16%&5 g m%

cetic acid mass = 1%$6 7 5 = '%5 g m%

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+oles calculation,-

)oles of cetic acid = '%5 ('$

)oles of cetic acid = $%+&$ moles

)oles of 4thyl alcohol = 16%&5('

)oles of 4thyl alcohol = $%!! moles

toic#iometric ratio ,-

4thyl alcohol : cetic acid

1 : 1

$%!! : $%+&$

.o it proves that 4thyl alcohol is limitingreactant%

/alculation al0ays #ased on limitingreactant

"#eoretical yield,-

)oles of ethyl acetate produced = $%!!7!! = +&%&+ g m%

ctual yield:-8eight of product that 0ill o#tain%

age yield = 2ctual yield( 9heoretical yield3 71$$

Experiment 0=

*ot#ing in calculation ecause ir

+eesam s# said t#at experiment didn?t

perform

(ea/e calculation side of experiment

empty

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Experiment 0@

*ot#ing in calculation ecause ir

+eesam s# said t#at experiment didn?tperform

(ea/e calculation side of experiment

empty

Aate of eac# experiment as

$1 1+-$6-$1 #ae lit

$ $-$6-$1 iodofom

$+ &-$6-$1 sod% .ulphate

$ $-1$-$1 picric acid

$5 1!-1$-$1 nitro#enzene

$' 5-1$-$1 oxalic acid

$& $!-1$-$1 ethyl esetate

$! -11-$1 ethyl #rmide

$6 1+-1-$1 glacial acetic acid

ir +eesam li s# said to meBrite done calculation in note ooC y

#and not printed form

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Experiment 3?s calculation performance

are left for your own practice so

complete it

Dn case of any little disturance contact

to

Engineer a! #ulam +ustafa

6Aecent way re&uire to discuss any t#ing

ecause it is enecial for all7