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7-1 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii
ICS141: Discrete Mathematics for Computer Science I
Dept. Information & Computer Sci., University of Hawaii
Jan Stelovsky based on slides by Dr. Baek and Dr. Still
Originals by Dr. M. P. Frank and Dr. J.L. Gross Provided by McGraw-Hill
7-2 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii
Lecture 7
Chapter 1. The Foundations 1.6 Introduction to Proofs
Chapter 2. Basic Structures 2.1 Sets
7-3 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Proof Terminology n A proof is a valid argument that establishes
the truth of a mathematical statement n Axiom (or postulate): a statement that is
assumed to be true n Theorem
n A statement that has been proven to be true n Hypothesis, premise
n An assumption (often unproven) defining the structures about which we are reasoning
7-4 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii More Proof Terminology n Lemma
n A minor theorem used as a stepping-stone to proving a major theorem.
n Corollary n A minor theorem proved as an easy
consequence of a major theorem. n Conjecture
n A statement whose truth value has not been proven. (A conjecture may be widely believed to be true, regardless.)
7-5 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Proof Methods n For proving a statement p alone
n Proof by Contradiction (indirect proof): Assume ¬p, and prove ¬p → F.
7-6 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Proof Methods n For proving implications p → q, we have:
n Trivial proof: Prove q by itself. n Direct proof: Assume p is true, and prove q. n Indirect proof:
n Proof by Contraposition (¬q → ¬p): Assume ¬q, and prove ¬p.
n Proof by Contradiction: Assume p ∧ ¬q, and show this leads to a contradiction. (i.e. prove (p ∧ ¬q) → F)
n Vacuous proof: Prove ¬p by itself.
7-7 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Direct Proof Example n Definition: An integer n is called odd iff n=2k+1
for some integer k; n is even iff n=2k for some k. n Theorem: Every integer is either odd or even, but
not both. n This can be proven from even simpler axioms.
n Theorem: (For all integers n) If n is odd, then n2 is odd.
Proof: If n is odd, then n = 2k + 1 for some integer k.
Thus, n2 = (2k + 1)2 = 4k2 + 4k + 1 = 2(2k2 + 2k) + 1. Therefore n2 is of the form 2j + 1 (with j the integer 2k2 + 2k), thus n2 is odd. ■
7-8 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Indirect Proof Example: Proof by Contraposition
n Theorem: (For all integers n) If 3n + 2 is odd, then n is odd.
n Proof: (Contrapositive: If n is even, then 3n + 2 is even) Suppose that the conclusion is false, i.e., that n is even. Then n = 2k for some integer k. Then 3n + 2 = 3(2k) + 2 = 6k + 2 = 2(3k + 1). Thus 3n + 2 is even, because it equals 2j for an integer j = 3k + 1. So 3n + 2 is not odd. We have shown that ¬(n is odd) → ¬(3n + 2 is odd), thus its contrapositive (3n + 2 is odd) → (n is odd) is also true. ■
7-9 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Vacuous Proof Example
n Show ¬p (i.e. p is false) to prove p → q is true.
n Theorem: (For all n) If n is both odd and even, then n2 = n + n.
n Proof: The statement “n is both odd and even” is necessarily false, since no number can be both odd and even. So, the theorem is vacuously true. ■
7-10 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Trivial Proof Example n Show q (i.e. q is true) to prove p → q is true.
n Theorem: (For integers n) If n is the sum of two prime numbers, then either n is odd or n is even.
n Proof: Any integer n is either odd or even. So the conclusion of the implication is true regardless of the truth of the hypothesis. Thus the implication is true trivially. ■
7-11 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Proof by Contradiction
n A method for proving p. n Assume ¬p, and prove both q and ¬q for
some proposition q. (Can be anything!) n Thus ¬p → (q ∧ ¬q) n (q ∧ ¬q) is a trivial contradiction, equal to F n Thus ¬p → F, which is only true if ¬p = F n Thus p is true
7-12 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Rational Number
n Definition: The real number r is rational if there exist integers p and q with q ≠ 0 such that r = p/q. A real number that is not rational is called irrational.
7-13 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Proof by Contradiction Example
n Theorem: is irrational. n Proof: n Assume that is rational. This means there are
integers x and y (y ≠ 0) with no common divisors such that = x/y. Squaring both sides, 2 = x2/y2, so 2y2 = x2. So x2 is even; thus x is even (see earlier). Let x = 2k. So 2y2 = (2k)2 = 4k2. Dividing both sides by 2, y2 = 2k2. Thus y2 is even, so y is even. But then x and y have a common divisor, namely 2, so we have a contradiction. Therefore, is irrational. ■
2
2
2
2
7-14 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Proof by Contradiction n Proving implication p → q by contradiction
n Assume ¬q, and use the premise p to arrive at a contradiction, i.e. (¬q ∧ p) → F (p → q ≡ (¬q ∧ p) → F)
n How does this relate to the proof by contraposition?
n Proof by Contraposition (¬q → ¬p): Assume ¬q, and prove ¬p.
7-15 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Proof by Contradiction Example: Implication
n Theorem: (For all integers n) If 3n + 2 is odd, then n is odd.
n Proof: Assume that the conclusion is false, i.e., that n is even, and that 3n + 2 is odd. Then n = 2k for some integer k and 3n + 2 = 3(2k) + 2 = 6k + 2 = 2(3k + 1). Thus 3n + 2 is even, because it equals 2j for an integer j = 3k + 1. This contradicts the assumption “3n + 2 is odd”.
This completes the proof by contradiction, proving that if 3n + 2 is odd, then n is odd. ■
7-16 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Circular Reasoning n The fallacy of (explicitly or implicitly) assuming
the very statement you are trying to prove in the course of its proof. Example:
n Prove that an integer n is even, if n2 is even. n Attempted proof:
Assume n2 is even. Then n2 = 2k for some integer k. Dividing both sides by n gives n = (2k)/n = 2(k/n). So there is an integer j (namely k/n) such that n = 2j. Therefore n is even. n Circular reasoning is used in this proof.
Where? Begs the question: How do you show that j = k/n = n/2 is an integer,
without first assuming that n is even?
7-17 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii
Chapter 2
Basic Structures: Sets, Functions, Sequences, and Sums
7-18 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii 2.1 Sets
n A set is a new type of structure, representing an unordered collection (group) of zero or more distinct (different) objects. The objects are called elements or members of the set.
n Notation: x ∈ S
n Set theory deals with operations between, relations among, and statements about sets.
n Sets are ubiquitous in computer software systems. n (E.g. data types Set, HashSet in java.util)
7-19 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Basic Notations for Sets n For sets, we’ll use variables S, T, U,… n We can denote a set S in writing by listing all of
its elements in curly braces: n {a,b,c} is the set whose elements are a, b, and c
n Set builder notation: n For any statement P(x) over any domain,
{x | P(x)} is the set of all x such that P(x) is true
n Example: {1, 2, 3, 4} = {x | x is an integer where x > 0 and x < 5 } = {x∈Z | x > 0 and x < 5 }
7-20 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Basic Properties of Sets n Sets are inherently unordered:
n No matter what objects a, b, and c denote, {a, b, c} = {a, c, b} = {b, a, c} = {b, c, a} = {c, a, b} = {c, b, a}.
n All elements are distinct (unequal); multiple listings make no difference! n If a = b, then {a, b, c} = {a, c} = {b, c} =
{a, a, b, a, b, c, c, c, c}. n This set contains (at most) 2 elements!
7-21 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Definition of Set Equality
n Two sets are declared to be equal if and only if they contain exactly the same elements.
n In particular, it does not matter how the set is defined or denoted.
n Example: The set {1, 2, 3, 4} = {x | x is an integer where x > 0 and x < 5} = {x | x is a positive integer where x2 < 20}
7-22 ICS 141: Discrete Mathematics I – Fall 2011
University of Hawaii Infinite Sets n Conceptually, sets may be infinite
(i.e., not finite, without end, unending). n Symbols for some special infinite sets:
N = {0, 1, 2,…} the set of Natural numbers. Z = {…, –2, –1, 0, 1, 2,…} the set of Zntegers. Z+ = {1, 2, 3,…} the set of positive integers. Q = {p/q | p,q ∈ Z, and q ≠ 0} the set of Rational numbers. R = the set of “Real” numbers.
n “Blackboard Bold” or double-struck font is also often used for these special number sets.