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TYPES OF JOINTS
•WELDED JOINTS
– Fillet welding
– Butt welding
•BOLTED JOINTS
– Bearing type Carbon steel / High strength
– Friction type HSFG
•RIVETED JOINTS
– Mild steel
– High strength steel
1
BOLTED JOINTS Bearing Type:
2
Clamping
Force, P0
Contact
Pressure, P0
T
Frictional
Force T
T
T
XBearing
Stress
Notice slip in bearing
type of connection
Dr S R
Satish
Kumar
, IIT
3
Bolt Shear Transfer – Free Body Diagram
(a) Bearing
Connection
(b) Friction
Connection
T
Frictional Force
TClamping Force,
PO
Bearing stresses
Tension
in bolt
T
T
T
Clamping Force,
PO
FORCE TRANSFER MECHANISM
BOLTED JOINTS Bearing Type:
4
Clamping
Force, P0
T
T
XBearing
Stress
Contact
Pressure, P0
T
T
Frictional
Force T
Notice no slip is observed in-
between plates in HSFG
Connection
Friction Type:
MERITSWelded Joints
– Transfer of forces between elements more direct
– Requires little additional elements like gussets
–Shorter length of joints
– No reduction in member strength due to bolt holes etc.
– Rigid connections easy to achieve
5
DEMERITS
Requires skilled manpower
Requires special equipment
not easy to achieve at difficult locations
less ductile
prone to defects & fatigue cracks under cyclic loading
6
MERITS & DEMERITSBolted Connections
Bearing Type
– Easy to install even at difficult locations
– Economical
– Does not require highly skilled manpower
– Slip causes flexible joint
– Joint size larger
7
BOLTED JOINTS
8
Analysis of Bolt Groups
Combined Shear and Moment in-Plane
Combined Shear and Moment out-of-plane
Beam and Column Splices
Beam to Column Connections
Beam to Beam Connections
Truss Connections
Fatigue Behaviour
9
• Designed more conservatively than members because they are more
complex to analyse and discrepancy between analysis and design is
large
• In case of overloading, failure in member is preferred to failure in
connection
• Connections account for more than half the cost of structural steel
work
• Connection design has influence over member design
• Similar to members, connections are also classified as idealised types
Effected through rivets, bolts or weld
• Codal Provisions10
Concentric
Connections
(a) (b)
Moment
Connections
(a) (b)
TYPES OF JOINTS
Classification based on type of resultant force transferred
11
Shear Connections
a) Lap
Connection
b) Butt
Connection
support(a)
(b)
Tension Connection and Tension plus Shear Connection
TYPES OF JOINTS -!
Single
shear
Double
shear
Classification based on type of force in the bolts
12
BOLTS AND BOLTING
Bolt Grade: Grade 4.6 :- fu = 40 kgf/mm2 and fy = 0.6*40 = 24 kgf/mm2
Bolt Types: Black, Turned & Fitted, High Strength Friction Grip
Black Bolts:
usually Gr.4.6,
made snug tight,
ductile and cheap,
only static loads
Turned & Fitted;
Gr.4.6 to 8.8,
Close tolerance drilled holes,
0.2% proof stress
HSFG Bolts:
Gr.8.8 to 10.9,
less ductile,
excellent under dynamic/fatigue loads13
snug-tight
position
¾ turn
position
Tightening of HSFG bolts
Feeler
gauge
TIGHTENING OF HSFG BOLTS
1) Turn-of-nut Tightening
2) Calibrated Wrench Tightening
3) Alternate Design Bolt Installation
4) Direct Tension Indicator Method
(a) Standard (b) Oversized
(c )Short Slot (d) Long slot
Hole types for HSFG bolts
14
Bolt Shear Transfer – Free Body Diagram
(a) Bearing Connection
(b) Friction
Connection
T
Frictional Force
TClamping Force,
PO
Bearing stresses
Tension
in bolt
T
T
T
Clamping Force, PO
FORCE TRANSFER MECHANISM
15
(b) HSFG
Connection
Bearing type
connection
2
T
T T
2
T
T
o
T
o
To+
T
To+
T
Proof Load
Po
Bolt force
B kN
Applied load 2T
(kN)
HSFG
Bearing
type
( c) External Tension
versus bolt force
BOLTS UNDER TENSION AND PRYING EFFECT
(d) Prying Effect
Q Q
B
A
bn
T+Q
2T
T+Q16
BOLTED STEEL JOINTS
Bolts in tension
Bolts in shear
6 x 200 =1200 kN
FAILURE MODES OF BOLTS IN SHEAR
Hole tearout
Bolt shear
Hole bearing
FAILURE OF CONNECTIONS
(a) Shearing of Bolts
(b) Bearing on Bolts
(c) Tension capacityZone of
plastificat
ion
Shear Connections with Bearing Bolts
Tnb = 0.90 fub An < fyb Asb (γmb / γm0)
3
sbsnbnu
nsb AnAnf
V
Vnpb = 2.5 kb d t f’u
19
20
(b) HSFG
Connection
Bearing
type
connection
2
T
T T
2
T
T
o
T
o
To+
T
To+
T
Proof Load
Po
Bolt
force
B kN
Applied load 2T
(kN)
HSFG
Bearin
g type
( c) External
Tension
versus bolt
force
BOLTS UNDER TENSION AND PRYING EFFECT
(d) Prying Effect
Q Q
B
A
bn
T+
Q
2
T
T+
Q
FAILURE OF CONNECTIONS
Shear Connections with HSFG Bolts
(a) Slip Resistance
(b) Bearing on Plates
Vnsf = µf. ne. Kh. Fo
Pbg = pbgd t 1/3 e t pbg
Kh =1.0 (clearance hole)
= 0.45 (untreated surfaces)
ne = no of effective interfaces
Fo= proof load
21
COMBINED SHEAR AND TENSION
(a) Bearing Bolts
(a) HSFG Bolts
0.1
22
db
b
db
sb
T
T
V
V
0.1
22
df
f
df
sf
T
T
V
V
22
Block Shear
BLOCK SHEAR FAILURE
T
A
B C)()( 5.06.0 BCeyABey ApApT
Capacity=Shear Capacity of AB + Tension Capacity of BC
3
Tdb = ( Avg fy /( m0) + 0.9Atn fu /m1 )3
3
Tdb = (0.9Avn fu /( m1) + Atg fy /m0 )3
or
23
24
GENERAL ISSUES IN CONNECTION DESIGN
M =
Td
Standard Connections
(a) moment connection
(b) simple connection
eV
T
C
dV
(a) (b)
Assumptions in traditional analysis
• Connection elements are assumed to
be rigid compared to the connectors
• Connector behaviour is assumed to
be linearly elastic
• Distribution of forces arrived at by
assuming idealized load paths
• Provide stiffness according to the
assumed behaviour
• ensure adequate ductility and rotation
capacity
• provide adequate margin of safety
25
COMBINED SHEAR AND MOMENT IN PLANE
Bolt group eccentrically
loaded in shear
Pri
Rmi
O
x’
y’
• Bolt shear due to Px and Py
Rxi = Px/n and Ryi = Py/n
• M = Px y’ + Py x’
• Rmi = k ri
Mi = k ri2
MR = k ri2 = k ri
2
• Bolt shear due to M
Rmi=M ri/ ri2
22sincos imiyiimixii RRRRR
2
22
2
22 )()( ii
iy
ii
ixi
yx
Mx
n
P
yx
My
n
PR
Combined shear
26
27
COMBINED SHEAR AND MOMENT OUT-OF-PLANE
Bolt group resisting out-of-plane moment
Ti
d l
i
L
iN
Ad/
6
L
i
(a) (b) (c)
C
Ti = kli where k = constant
M = Ti Li = k li Li
Ti = Mli/ li Li
Shear assumed to be shared equally and bolts
checked for combined tension+(prying)+shear28
BEAM AND COLUMN SPLICE
Bolted Beam Splice
(a)Conventional
Splice
(b) End-Plate
Splice
Strength, stiffness and ease in erection
Assumptions in
Rolled-section
& Plate Girders
Column Splices – bearing type or HSFG moment splices29
BEAM-TO-COLUMN CONNECTIONS
(a) Simple – transfer only shear at nominal eccentricity
Used in non-sway frames with bracings etc.
Used in frames upto 5 storeys
(b) Semi-rigid – model actual behaviour but make analysis
difficult (linear springs or Adv.Analysis). However lead
to economy in member designs.
(c) Rigid – transfer significant end-moments undergoing
negligible deformations. Used in sway frames for
stability and contribute in resisting lateral loads and
help control sway.
30
V
BEAM-TO-COLUMN CONNECTIONS
Simple beam-to-column connections a) Clip and seating angle
b) Web cleats c) Curtailed end plate
e(a) (b) (c)
(a) Economical when automatic saw and drill lines are available
Check end bearing and stiffness of seating angle
Clip angle used for torsional stability
(b) If depth of cleats < 0.6d design bolts for shear only
(c) Eliminates need to drill holes in the beam. Limit depth and thickness
t < /2 (Gr.8.8) and /3 (Gr.4.6)31
BEAM-TO-COLUMN CONNECTIONS
Rigid beam-to-column connections
a) Short end plate
b) Extended end plate
c) Haunched
column web
stiffenersdiagonal
stiffener
web
plate
(a) (b) (c)
32
BEAM-TO-BEAM AND
TRUSS CONNECTIONS
(a) Apex Connection
Truss Connections
(b) Support connection
Gusset Plate
Splice
plate
GussetPlate e
suppor
t
Beam-beam connections similar to beam-column connections
Moment continuity may be obtained between secondary beams
Check for torsion in primary beams
33
FATIGUE BEHAVIOUR
Fatigue leads to initiation and growth of cracks under fluctuating stresses
even below the yield stress of the material (High-cycle fatigue)
Fatigue cracks grow from points of stress concentrations
To avoid stress concentrations in bolted connections
• Use gusset plates of proper shape
• Use match drilling
• Use HSFG bolts
Fatigue also depends on range of stress fluctuations and reversal of stress
• pre-tensioned HSFG avoid reversals but lead to fretting corrosion
Fatigue design carried out by means of an S-N curve on a log-log scale
Components are designed below the endurance limit
34
Thank You
35
36
Design Example 1: Design a bolted connection
between a bracket 8 mm thick and the flange of
an ISHB 400 column using HSFG bolts, so as to
carry a factored vertical load of 100 kN at a
distance of 200 mm from the face of the column
as shown in Fig. E1.
Solution:
1) Bolt force:
Px = 0; Py = 100 kN;
Total eccentricity x’=200+250/2=325 mm
M = Pyx’ = 100x325 = 32500 kN-mm
TRY THE ARRANGEMENT SHOWN IN FIG. E1
NOTE: MINIMUM PITCH = 60 MM AND
MINIMUM EDGE DIST. = 60 MM
37
2) Bolt capacity
Try M20 HSFG bolts
Bolt capacity in single shear = μf n Kh Fo = 0.48 × 1.0 × 177 =
85 kN
ISHB 400 flange is thicker than the bracket plate and so
bearing on the
bracket plate will govern.
Bolt capacity in bearing = d t pbg = 20 × 8 × 650 × 10-3 = 104
kN
∴ Bolt value = 85 kN > 81.79 safe.
38
Design Example 2: Design a
bolted splice for an ISMB 450
section to transfer a factored
bending moment of 150 kN-m
and a factored shear of 100 kN.
Assume that the flange splices
carry all of the moment and that
the web splice carries only the
shear.
39
SOLUTION:
1) FLANGE SPLICES :
FLANGE FORCE =BM/(D-TF) =
150 × 103/(450-17.4) = 346.7 KN
40
Slip resistance per bolt = 0.33 × 183 = 60.4 kN
Bearing resistance on flange per bolt = 20 ×17.4 × 650 × 10-3 = 226.2 kN
Bolt value = 60.4 kN
Use 3 rows of 2 bolts at a pitch of 60 mm
Flange capacity = (250/1.10) × 1844 × 10-3 = 400.9 kN > flange force OK
Try 150 mm wide splice plate
Thickness of splice plate required
= 346.7 × 103/1.0 × 250(150-2 × 22)/1.10 = 15.8 mm Use 16 mm
Use flange splice plate of size 400×150 × 1641
2) Web Splice
For M20 HSFG bolts of Gr.8.8 in double shear Slip resistance per
bolt = 2 ×60.4 = 120.8 kN
Try 8 mm thick web splice plates on both sides of the web.
Bearing Resistance per bolt = 20 × 9.4 × 650 × 10-3 =122.2 kN
Bolt value = 120.8 kN
Try 3 bolts at 100 mm vertical pitch and 45 mm from the center
of joint.
Horizontal shear force on bolt due to moment due to
eccentricity= 100 × 45 × 100/(2 × 1002) = 22.5 kN
Vertical Shear force per bolt = 100/3 = 33.3 kN
Resultant shear force = √(22.52+33.32) = 40.2 kN < 120.8 (bolt
cap) OK
Use web splice plate of size 270×160×8 - 2 nos. 42
DESIGN EXAMPLE 3: DESIGN A SEATING ANGLE
CONNECTION FOR AN ISMB 400 BEAM TO AN ISHB 200
COLUMN SO AS TO TRANSFER A SHEAR OF 200 KN.
43
1) Seating Angle
The support reaction acts as a UDL over length (b+ 2.5h2) on
the web
Length of bearing required at root line of beam (b+2.5 h2)
= V/(twpyw)= 200 × 103/(8.9 × 250/1.10) = 98.9 say 100 mm
Length of bearing on cleat = b = 100-2.5 h2 =25 mm
end clearance of beam from the face of the column c=
5mm
allow tolerance d = 5 mm
minimum length of angle leg required for seating = b+c+d
= 35 mm
Try ISA 110×110×15 angle of length w = bf = 140 mm 44
Distance from end of bearing on cleat to
root of angle (A to B) = b + c + d - (t+r) of angle;
= 25 + 5 + 5 – 25 = 10 mm
assuming the load to be uniformly distributed over the
bearing length b
moment at the root of angle =(200/10)× 102/2 = 1.0 kN-m
Moment capacity = (250/1.1)×(140×152/4) ×10-6
= 1.79 kN-m > 1.0 kN-m OK
Shear Capacity of outstanding leg of cleat
= [(250/1.10)/1.732]× 140×15×10-3
= 275.5 kN >200 kN OK
45
2) Connection of seating angle to column flange
Bolts required to resist only shear
Try 4 bolts of 22 mm dia and grade 4.6, capacity = 52.7kN/bolt
Total shear capacity = 4×52.7=210.8 kN > 200 kN OK
3) Provide nominal clip angle of ISA 50 × 50 × 8 at the top
46
Design Example 4: Design a bolted web cleat
beam-to-column connection between an ISMB
400 beam and an ISHB 200 @ 40 kg/m column.
The connection has to transfer a factored shear
of 150 kN. Use bolts of diameter 20 mm and
grade 4.6.
47
1) THE RECOMMENDED GAUGE DISTANCE FOR COLUMN FLANGE IS 100
MM.
THEREFORE REQUIRED ANGLE BACK MARK IS 50 MM.
USE WEB CLEATS OF ISA 90X90X8 GIVING GAUGE
G = 50+50+8.9=108.9 MM
(G FOR ISHB200 IS 100 MM )OK 48
2) Connection to web of beam- Bolt capacity
shear capacity of bolt in double shear = 2×160×245×10-3=78.4 kN
bearing capacity of bolt on the beam web = 418×20×9.0×10-3=
75.24 kN
bolt value = 75.24 kN
Try 4 bolts as shown in the Figure with vertical pitch of 75 mm
Assuming the shear to be acting on the face of the column, its
eccentricity
with the centre of the bolt group will produce horizontal shear forces
in
the bolts in addition to the vertical shear.
49
horizontal shear force on top bolt due to moment due to
eccentricity e
= Px e ri/Σ ri2
= 150×50×112.5/2(37.52+112.52) = 30.0 kN
vertical shear force per bolt = 150/4 = 37.5 kN
resultant shear = √(30.02+37.52) = 48.0 kN < bolt value Safe !
50
3) Connection to column flange: Bolt capacity
shear capacity of bolt in single shear = 160×245×10-3 = 39.2 kN
bearing capacity of bolt on column flange = 418×20×9.0×10-3=
75.24 kN
bolt value = 39.2 kN
Try 6 bolts as shown in the Fig.E5 with vertical pitch of 75 mm
4) Check bolt force
Similar to the previous case, the shear transfer between the beam
web and the angle cleats can be assumed to take place on the
face of the beam web.
51
However, unlike the previous case, no relative rotation is possible between the angle and the beam web.
Assuming centre of pressure 25 mm below top of cleat (point A),
horizontal shear force on bolt due to moment due to eccentricity e
=(V/2)exri/Σri2
= (150×50/2)× 200/(502+1252+2002) =12.9 kN
vertical shear force per bolt = 150/6 = 25.0 kN
resultant shear = √(12.92+25.02) = 28.13 kN < bolt value OK
Use 2 Nos ISA 90x90x8 of length 375 mm as angle cleats
ISA 90x90x8 Length 375mm
52
DESIGN EXAMPLE 5: DESIGN A BOLTED END PLATE
CONNECTION BETWEEN AN ISMB 400 BEAM AND
AN ISHB 200 @ 40 KG/M COLUMN SO AS TO
TRANSFER A
HOGGING FACTORED BENDING MOMENT OF 150
KN-M AND A VARTICAL FACTORED SHEAR OF 150
KN. USE HSFG BOLTS OF DIAMETER 20 MM AND
GRADE 10.9.
53
1) bolt forces taking moment about the centre of the bottom flange and neglecting the contribution of bottom bolts and denoting the force in the top bolts by F
4F× 384 = 150× 103
F = 97.6 kN
tension capacity of M20 bolt = 0.9Fo = 159.3 kN
allowable prying force Q = 159.3-97.6 = 61.7 kN
54
2) design for prying action
try 30 mm thick end plate of width be = 180 mm
distance from the centre line of bolt to prying force n is
the minimum of edge distance or 1.1T√βPo/Py = 1.1× 30 √(2× 512/250) = 55.66 mm
n = 40 mm
assuming 10 mm fillet weld,
distance from center line of bolt to toe of fillet weld b = 60-10 = 50 mm;
moment at the toe of the weld = Fb-Qn = 97.6×50-61.7×40 = 2412 N-m
effective width of end plate per bolt w = be/2 = 180/2 = 90 mm
moment capacity =(fy/1.10)×(wT2/4) =(250/1.10)(90×302/4)=4402 N-m > 2412 N-m Safe !
55
56
THANK YOU
57