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Transcription and Translation
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Transcription and Translation
1. What is transcription? Explain whathappens during transcription.
2. What is translation? Explain what
happens during translation.3. Explain how transcription and translation
are related to DNA replication.
4. If you begin with a parent DNA strand ofA A T G C A G T, what will thecomplementary mRNA strand be? (Thinkabout it before you answer.)
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Compared structures of DNA and
RNA
A. DNA-Deoxyribonucleic acid
1. Bases-cytosine, guanine, adenine and
thymine
2. Double stranded
3. Function-store genetic information
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B. RNA-Ribonucleic acid
1. Base-Cytosine, guanine, adenine and uracil
2. Single stranded
3. Functions-a. rRNA-ribosomal RNA (makes up about 60% of
ribosomal structure
b. mRNA-messenger RNA (record information from
DNA and carry it to ribosomes)c. tRNA-transfer RNA (delivers amino acids to
proteins at the ribosome to extend the chains)
Compared structures of DNA and
RNA
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RNA
nucleotide
DNA
nucleotide
http://upload.wikimedia.org/wikipedia/en/2/2c/RNA_chemical_structure.GIFhttp://upload.wikimedia.org/wikipedia/en/2/2c/RNA_chemical_structure.GIF7/28/2019 transcriptionandtranslation-100505182952-phpapp02
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Comparison of RNA and DNA
sugars
Deoxyribose
Ribose
http://en.wikipedia.org/wiki/Image:Ribofuranose-2D-skeletal.pnghttp://upload.wikimedia.org/wikipedia/commons/9/94/Deoxyribose.svg7/28/2019 transcriptionandtranslation-100505182952-phpapp02
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Compared
structures ofDNA and RNA
http://upload.wikimedia.org/wikipedia/commons/0/04/NA-comparedto-DNA_thymineAndUracilCorrected.png7/28/2019 transcriptionandtranslation-100505182952-phpapp02
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Reading Quiz (Orange book-Chapter 6)
1. Transcription is the process of making:a. RNA b. tRNA c. mRNA d. rRNA
2. An intron is found in:
a. DNA b. RNA c. mRNA d. tRNA
3. The enzyme used in transcription is:
a. RNA primase b. RNA polymerase
c. DNA polymerase d. a and b are both correct
4. How many bases make a codon?a. 1 b. 2 c. 3 d. 4
5. Translation occurs in the:
a. nucleus b. cytoplasm c. both
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Transcription
A. Transcription=the synthesis of mRNA
from a DNA template
B. Occurs in the 53 direction (if you dont
know what this means go back and look
it up!!)
C. Involves RNA polymerase
D. mRNA, tRNA and rRNA must all be
transcribed for protein synthesis to take
place
http://www-class.unl.edu/biochem/gp2/m_biology/animation/gene/gene_a2.htmlhttp://www-class.unl.edu/biochem/gp2/m_biology/animation/gene/gene_a2.html7/28/2019 transcriptionandtranslation-100505182952-phpapp02
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E. mRNA
-the sequence of mRNA nucleotides determinethe primary sequence of the polypeptides
F. tRNA-carries the amino acids to mRNA
-tRNA folds in on itself
-see p. 305 figure 17.12
G. rRNA
-major components of ribosomes
Transcription (three types of
RNA)
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Transcription (Initiation)
A. RNA polymerase binds to the promoter site
B. Promoter=region of DNA where RNApolymerase attaches and initiates transcription
-Determines which strand of DNA will serve as thetemplate
C. RNA polymerase -hooks together RNAnucleotides as they base pair along the DNA
templateD. Transcription unit -area of DNA that will betranscribed
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E. Transcription initiation complex -thearea where transcription factors and RNA
polymerase are bound to the promoter
F. TATA box -promoter DNA sequence-the actual sequence is 5'-TATAAA-3'
-RNA polymerase binding site
G. After polymerase is bound to the promoterDNA, the two DNA strands unwind and the
enzyme starts transcribing the template
strand
Transcription (Initiation)
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Transcription (RNA strand
elongation)
A. RNA polymerase moves along DNA
template
B. It unwinds 10-20 DNA bases at a time
C. RNA polymerase adds nucleotides in the
53 direction
D. As RNA polymerase moves along, theDNA double helix reforms
E. The new section of RNA peels away as
the double helix reforms
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Transcription (termination)
A. Transcription stops when RNApolymerase reaches a section of DNAcalled the terminator
B. Terminator sequence = AAUAAAC. Next, the RNA strand is released and
RNA polymerase dissociates from the
DNAD. The RNA strand will go through more
processing
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Sense vs. Antisense DNA strands
A. The DNA double helix has two strands
B. Only one of them is transcribed
C. The transcribed strand is the antisensestrand
D. The non transcribed strand is the sense
strandE. mRNA is comp lementary to the
anitsense strand
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RNA splicing (in eukaryotes)
A. In eukaryotes RNA transcripts have long non-coding stretches of nucleotides
-these regions will not be translated
B. The non-coding sections are dispersed betweencoding sections
C. Introns-non-coding sections of nucleic acidfound between coding regions
D. Exons-coding regions of nucleic acids(eventually these are expressed as aminoacids)
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E. RNA polymerase transcribes introns and
exons,
-this is pre-mRNA
F. Pre-mRNA never leaves the cells nucleus
G. The introns are excised and exons are
joined together to form mRNAH. pre-mRNA
I. Mature mRNA
RNA splicing (in eukaryotes)
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Translation
A. Translation-forming of a polypeptide
-uses mRNA as a template for a.a.
sequence
-4 steps (initiation, elongation,
translocation and termination)
-begins after mRNA enters cytoplasm-uses tRNA (the interpreter of mRNA)
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B. Ribosomes
-made of proteins and rRNA
-each has a large and small subunit
-each has three binding sites for tRNA onits surface
-each has one binding site for mRNA
-facilitates codon and anticodon bonding
-components of ribosomes are made inthe nucleus and exported to the cytoplasm
where they join to form one functional unit
Translation
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B. Ribosomes (continued)
-the three tRNA binding sites are:
1. A site=holds tRNA that is carryingthe next amino acid to be added
2. P site= holds tRNA that is carrying
the growing polypeptide chain
3. E site= where discharged tRNAs
leave the ribosome
#8. Translation
http://www.cellsalive.com/cells/cell_model.htmhttp://www.cellsalive.com/cells/cell_model.htm7/28/2019 transcriptionandtranslation-100505182952-phpapp02
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Ribosomal structure
EP A
Large subunit
Peptidyl-tRNA binding site
Aminoacyl-tRNA binding site
mRNA
5
Exit
site
Small subunit
3
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C. The genetic code
Four RNA nucleotides are arranged 20
different ways to make 20 different amino
acids Nucleotide bases exist in triplets
Triplets of bases are the smallest units that
can code for an a.a. 3 bases = 1 codon = 1 a.a.
There are 64 possible codes (64=43)
Translation
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C. The genetic code
Most of the 20 a.a. have between 2 and 4possible codes
The mRNA base triplets are codons In translation the codons are decoded into
amino acids that make a polypeptide chain
It takes 300 nucleotides to code for a
polypeptide made of 100 amino acids (Why?)
Translation
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C. The genetic code (continued)
61 of 64 codons code for a.a.
Codon AUG has two functions
-codes for amino acid methionine (Met)-functions as a start codon
mRNA codon AUG starts translation
The three unaccounted for codons act asstop codons (end translation)
Translation
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D. How it works
DNA (antisense)
A C C A A A C C GmRNA (transcription)
U G G U U U G G C
polypeptide (translation)Trp - Phe - Gly-
Translation
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E. More on tRNA tRNA is transcribed in the nucleus and must enter the
cytoplasm
tRNA molecules are used repeatedly
Each tRNA molecule links to a particular mRNAcodon with a particular amino acid
When tRNA arrives at the ribosome it has a specific
amino acid on one end and an anticodon on the other
Anticodons (tRNA) bond to codons (mRNA)p. 304 (red book)
Translation
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Where the a.a. attaches
Hydrogen bonds
Anticodon
=
tRNA diagrams
Although we
draw tRNA in
a clovershape its
true 3-D
conformation
is L-shaped.
http://upload.wikimedia.org/wikipedia/commons/f/f1/3d_tRNA.pnghttp://upload.wikimedia.org/wikipedia/commons/f/f1/3d_tRNA.pnghttp://upload.wikimedia.org/wikipedia/commons/f/f1/3d_tRNA.pnghttp://upload.wikimedia.org/wikipedia/commons/f/f1/3d_tRNA.pnghttp://upload.wikimedia.org/wikipedia/commons/f/f1/3d_tRNA.pnghttp://upload.wikimedia.org/wikipedia/commons/f/f1/3d_tRNA.pnghttp://upload.wikimedia.org/wikipedia/commons/f/f1/3d_tRNA.png7/28/2019 transcriptionandtranslation-100505182952-phpapp02
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Translation (Initiation)
A. Initiation
1. Brings together mRNA, tRNA (w/ 1sta.a.) and ribosomal subunits
2. Small ribosomal subunit binds to mRNAand an initiator tRNA
-start codon= AUG
-start anticodon-UAC-small ribosomal subunit attaches to 5end of mRNA
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B. Initiation2. (continued)
-downstream from the 5 end is thestart codon AUG (mRNA)
-the anticodon UAC carries the a.a.Methionine
3.After the union of mRNA, tRNA and
small subunit, the large ribosomal subunitattaches
4. Initiation is complete
#9. Translation (Initiation)
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B. Initiation
5. The intitiator tRNA and a.a. will sit in the
P site of the large ribosomal subunit
6. The A site will remain vacant and ready
for the aminoacyl-tRNA
Translation (Initiation)
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Translation (Initiation)
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Translation (Elongation)A. Amino acids are added one by one to the first
amino acid (remember, the goal is to make apolypeptide)
B. Step 1- Codon recognition
a. mRNA codon in the A site forms hydrogenbonds with the tRNA anitcodon
C. Step 2- Peptide bond formation
a. The ribosome catalyzes the formation of the
peptide bonds between the amino acids (theone already in place and the one beingadded)
b. The polypeptide extending from the P site
moves to the A site to attach to the new a.a.
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A. The tRNA w/ the polypeptide chain in the
A site is translocated to the P site
B. tRNA at the P site moves to the E site
and leaves the ribosome
C. The ribosome moves down the mRNA in
the 53 direction
Translation (Translocation)
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A. Happens at the stop codon
B. Stop codons are UAA, UAG and UGA
-they do not code for a.a.
C. The polypeptide is freed from the ribosome andthe rest of the translation assembly comes
apart
D.Animation (you move it)E.Animation (you watch it)
F.Animation (McGraw-Hill)
Translation (Termination)
http://repository.uwlax.edu/~Bob/lo_biology/stc_01_translation/conceptual/c_02_trna.htmhttp://student.ccbcmd.edu/biotutorials/protsyn/translat.htmlhttp://highered.mcgraw-hill.com/olcweb/cgi/pluginpop.cgi?it=swf::535::535::/sites/dl/free/0072437316/120077/micro06.swf::Protein%20Synthesishttp://highered.mcgraw-hill.com/olcweb/cgi/pluginpop.cgi?it=swf::535::535::/sites/dl/free/0072437316/120077/micro06.swf::Protein%20Synthesishttp://highered.mcgraw-hill.com/olcweb/cgi/pluginpop.cgi?it=swf::535::535::/sites/dl/free/0072437316/120077/micro06.swf::Protein%20Synthesishttp://highered.mcgraw-hill.com/olcweb/cgi/pluginpop.cgi?it=swf::535::535::/sites/dl/free/0072437316/120077/micro06.swf::Protein%20Synthesishttp://student.ccbcmd.edu/biotutorials/protsyn/translat.htmlhttp://repository.uwlax.edu/~Bob/lo_biology/stc_01_translation/conceptual/c_02_trna.htm7/28/2019 transcriptionandtranslation-100505182952-phpapp02
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Gene expression
A. Jacob and Monad (1961)
-studied control of protein synthesis in E.coliand lactose digesting enzymes
-found that E. colido not produce lactosedigesting enzymes when grown in amedium without lactose
-when bacteria were placed in a lactoseenvironment, enzymes were found withinminutes
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B. Genes can be switched on or off as
necessary
-a gene that is on will be transcribed
-in E.coli, the enzyme lactase will be
produced if the gene is on
-if the gene is off mRNA will not be
created and translation can not occur
Gene expression
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C. The operon model
-proposed by Jacob and Monad
-explains how genes switch on and off-operon=promoter, operator and structural
genes
-lac operon is found inE.coli
Gene expression
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D. The lac operon
Gene expression
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D. The lac operon (no lactose)
-lactose is absent, repressor is active,
operon is off, no mRNA is produced, RNA
polyermase cannot bind because it is
blocked by the repressor that has bound to
the operator
Gene expression
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D. The lac operon (lactose is present)
-lactose is present, repressor is inactive, operon
is on, mRNA is transcribed, RNA polymerase
binds to operator-an isomer of lactose binds to the repressor and
changes its shape
-this prevents it from binding to the operator
-lactase is produced
Gene expression
#11 C
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#11. Compare Transcription in
Eukaryotes and Prokaryotes
Link
http://www.phschool.com/science/biology_place/biocoach/transcription/tctlpreu.htmlhttp://www.phschool.com/science/biology_place/biocoach/transcription/tctlpreu.html