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Topic 2: Viscoelasticity and Diffusion
“Viscosity” world “Elasticity” world
Strain rate Strain
i
k
k
iik
x
u
x
u
i
k
k
iik
x
v
x
v
Stress sik = {force}i per unit {area}┴k
Elastic stress ikikaa aaik GB
s 2
13
Young modulus E
Shear modulus
Bulk modulus
Poisson ratio
)1(2
EG
)21(3
EB
You’ll remember from last year 1B:
etc.;3211 sss E
BE
621
||
Viscous shear stress & pressure
ikikik p s 2
Incompressibilty
0div kk kkv
Only shear deformations allowed
32
33
Non-linear elasticity and non-Newtonian fluids
Newtonian Hookean
Shear stress s
Shea
r m
od
ulu
s G
(s)
Creep, plastic flow
Stress
stiffening
Strain rate d/dt
Vis
cosi
ty
Shear
thinning
Shear
stiffening
Yield
stress
For a Hookean solid or a Newtonian fluid, the elastic modulus or the viscosity are strictly a constant. For a higher deformation or a greater shear rate – the system just breaks down…
However many complex systems do not obey this simple linearity.
Examples of different types of complex solids and fluids:
There is a great richness of behaviour depending on the internal structure, at higher deformations / rates of flow.
An additional complexity occurs in the time-domain: some materials behave like solids at high strain rates, but liquids at low. Such materials are known as viscoelastic.
34
A typical elastic, viscous and viscoelastic response
• A viscoelastic material is, as the name suggests, one which shows a combination of viscous and elastic effects.
• Polymeric fluids and some disordered solids are examples.
• The elastic aspect leads to energy storage. Its contribution to a shape change will be lost once the stress is removed.
• The viscous aspect leads to energy dissipation, and irreversible shape changes associated with the flow.
• Rate effects are very important for these materials.
Creep experiment
A constant load is applied and the
resulting strain is measured.
1 = immediate elastic deformation 2 = delayed elastic deformation 3 = plastic flow (permanent deformation)
J(t) (t)
so
time
Applied stress (load)
time
Resulting strain (deformation)
Viscoelastic creep
1
1
2
3
35
A typical elastic, viscous and viscoelastic response
• A viscoelastic material is, as the name suggests, one which shows a combination of viscous and elastic effects.
• Polymeric fluids and some solids are examples.
• The elastic aspect leads to energy storage. Its contribution to a shape change will be lost once the stress is removed.
• The viscous aspect leads to energy dissipation, and irreversible shape changes associated with the flow.
• Rate effects are very important for these materials.
Stress relaxation experiment
A fixed extension (strain) is applied
and the resulting stress is measured.
s1 = instant stress (glassy response) seq = equilibrium stress (rubbery response) Ds(t) = stress relaxation
o
ttG
s )()(
time
Applied strain (deformation)
time
Resulting stress
Viscoelastic relaxation
s1
seq Ds
36
Storage and dissipation of energy
So both the creep compliance J(t) and the elastic modulus G(t) vary with time
Elastic response: G =Geq. =1/Jeq.
Viscous response: G =∙(t) J =(1/∙t
Approach to equilibrium = relaxation = viscous flow = energy dissipation
Hence the “effective viscosity” is also a function of time – or a function of frequency in an oscillating test
o
ttG
s )()(
time from onset
Modulus G(t)
Energy dissipation Log[time]
Modulus G(t)
37
Boltzmann Superposition Principle To describe the general response of a
system, must allow for details of loading history.
This can be done using the Boltzmann linear superposition theory.
Proposals:
1. Creep is a function of the whole sample loading history.
2. Each loading step makes an independent contribution to total loading history.
3. Total final deformation is the sum of each contribution.
Input
Response
Time
Str
ess
Str
ain
Ds1
Ds2
Ds3
e (t)1
e (t)2
e (t)3
1 2 3
t
dudu
udutJt
)()()(
s
And for a general creep experiment with
increments of stress ds at times n
In the same way, for stress relaxation, with incremental steps of strain d
taking place at times t’< t, we have:
t
dd
dtdt
tdttGtdttGt '
'
)'()'()'()'(lim)(
0
s
38
Pure elasticity and pure viscosity
The “retarded” linear response – the sum over the whole history of
applying deformation and relaxation:
Pure elastic system: no relaxation, no dissipation – no retardation:
G(t-t’) = G0
Pure viscous system:
t
dtdt
tdttGt '
'
)'()'()(
s
)(''
)'()( 00 tGdt
dt
tdGt
t
s
time
Resulting stress
)(''
)'()'()( tdt
dt
tdttt
t
s
)'()'( ttttG
39
Viscoelasticity in oscillating regime
Consider applying a sinusoidal deformation:
Then using this in:
gives:
where we have defined the complex modulus G*
(think of the analogy with complex impedance Z*(w) in V(w)-I(w)
Pure elastic:
Pure viscous:
t
dtdt
tdttGt '
'
)'()'()(
s
tiet w 0)(
tit
ti eGdtettGit ww wws 0
'
0 )(*')'()(
)(FT)()(*0
tGideGiG i
www w
'tt
00
0)(* GdeGiG i
ww w
www w ideiG i
0)()(*
''' GiG
40
Example in question sheet:
Torsional rod rheometer
Apply sinusoidal strain:
= oexp(iwt)
s = soexp(i(wt+))
Complex Modulus
If there is an oscillatory driving force, then
real part G‘ = storage modulus
(This gives the part of the strain in phase with the driving force)
imaginary part G ‘‘ = loss modulus
(This represents the out of phase component of linear response).
This is a generic description for all systems with a retarded linear response:
The real and imaginary parts of a complex linear-response modulus are related by the Kramers-Kronig relations.
s
w ieiGGG
0
0''')(*
one end
cylindrical (disk) sample radius r, height h
rod rigidly clamped at
one end
moment of inertia I
Set in oscillatory motion
ti
ti
ti
eIZV
eHM
eEP
w
w
w
ww
ww
ww
0
0
00
)(*)(
)(*)(
)(*)(
M
41
Maxwell fluid
)/exp()( 0 tGtG
Simplest models of viscoelasticity
0G
How is related to G0 and ?
Kelvin-Voigt solid
s /
eq.
0 1)( teG
t
0G
Glassy
Rubbery
2
1
42
Examples of viscoelastic behaviour
Polyisobutylene - overview
Theory: crosslinked rubber
Silicone – loss mechanisms
Plastic flow
Yield point
Examples of viscoelastic behaviour
Metallic glass / chocolate / sintered granular system
Initial elastic response
(high modulus)
High shear rate
Low shear rate
44
Einstein in 1905 (5 key papers)
In 1905 the atomic hypothesis was not fully accepted.
Despite Brownian motion having been known about for 75 years, its significance was not appreciated (nor understood).
The kinetic theory of gases was thought of as a 'mechanical analogue', but implied reversibility.
The 2nd law of thermodynamics required irreversibility.
Einstein understood that taking a statistical approach, and assuming atoms existed, reconciled the paradox.
His paper on Brownian motion, the second of the 5, was written in April 1905.
A macroscopic particle – such as the
pollen particle of Brown – would be
buffeted by the atoms/molecules in the
surrounding water.
The particle would undergo diffusion and
measuring the diffusion constant (or
equivalently the displacement) should
show an increase with t (not linear).
Perrin's subsequent experiments on
sedimentation showed how all this
hung together.
Microscopic origin of fluctuations
The origin of fluctuations of all thermodynamic quantities is, of
course, the random thermal motion of particles in the medium
(the energy of which we called “heat”).
Fluctuations are an essential element of Nature, since they are the
mechanism by which the system explores its available phase space; the
statistical summation of quantities such as partition function requires this to
achieve equilibrium.
On the other hand, thermal fluctuations make the value of any system
parameter, or the dynamical trajectory of a particle, uncertain. No individual
observation has any value, only the probabilities and the averages do.
We now study the Brownian motion, which is the simplest and
most transparent effect that allows us to explore microscopic
origins of thermal fluctuations. The classical experiments of
Robert Brown tracked the motion of small (1mm) particles in
water. 45
Brownian motion
The free particles should move according to the dynamical
equation v
dt
dvm
where the friction drag coefficient for a
sphere of radius a in a fluid of viscosity
has the Stokes’ form: 6pa
Movement in a viscous fluid is dissipative, so if a particle
starts with a velocity v0, that will decay as
Yet Robert Brown has recorded particles moving continuously,
following a random-walk trajectory:
tmevv )/(
0
This type of motion is called stochastic.
It clearly requires an additional force to
act on the particle, which we shall call
the stochastic force x(t) (sometimes it
is called the random noise)
46
Stochastic force
The dynamical equation of free particle changes into
)(tvdt
dvm x
where the stochastic force may have a typical
time-dependence (in a 1D projection):
If we zoom in, there is a characteristic
time scale between collisions of our
particle with molecules of water, which
are in thermal motion. t
x(t)
x(t) in water at room-T:
s10~ 13
T
Let us finish by defining the
statistical characteristics of
such a stochastic force:
It is pretty clear that: const)(but0)( 2 tt xx
0)()()()(also 2121 tttt xxxx This is the definition of “white noise”,
complete lack of correlation between
different pulses! 47
Langevin equation
The stochastic equation has a generic form: start with the
dynamical equation (generic Newton’s) and add the stochastic
force to all other forces present. Even for a free particle we
must include friction, to provide the sink for the energy
delivered by the collisions.
)(tvdt
dvm x
t
ttmtm dttm
eevtv0
]')[/()/(
0 ')'(1
)( x
Either work out the solution from the Green function of
the corresponding homogeneous equation – or just
check it by direct differentiation.
The general solution:
As with the stochastic force itself, there is no meaning in the
value of the (also stochastic) particle velocity v(t). Only the
averages make sense. Clearly 0)( tv
48
Mean square velocity, #1
t
ttmtm dttm
eevtv0
]')[/()/(
0 ')'(1
)( x
The general solution:
t
ttmttm
tt
tmtmtm dtdtttm
eedttm
eevevv0
21212
])[/(])[/(
00
')/()/(2
0
)/(22
0
2 )()(1
')'(1
2 21 xxx
Taking the
average:
t
ttmttm
t
tm dtdtttm
eeevv0
21212
])[/(])[/(
0
)/(22
0
2 )()(1
21 xx
)( 21 tt
t
ttmtm dtem
evv0
1
])[/(2
2
)/(22
0
2 1
tmtm em
evv )/(2)/(22
0
2 12
Decay of the
initial condition mv
2
2
Maxwell distribution of the velocity gives:
m
Tkv B2
TkB2
49
Mean square velocity, #2 The mean kinetic energy:
2
0
][)/(2
22
x dm
)(e
mvmt
tm
As before, the only object that needs “averaging” is x(t) under the integral:
2121
][)/(
0
][)/(
0
21
2
1xx
dd)()(ee
m
tmt
tmt
421
0
][)/(2 1
de
m
tm
Long times: steady-
state mean K.E. TkB
2
1
Equipartition The important result we just found says that the
mean-square intensity of the random force is
proportional to temperature kBT (that’s expected)
but also the dissipative friction constant !
This is one of many forms of Fluctuation-Dissipation Theorem
50
Fluctuation-Dissipation relationship
Intensity of the random
noise (thermal motion of
molecules): the energy supplied to the particle
2x
TkB2 Dissipation of energy of
the particle due to the
friction drag against the same medium
ap 6
The Langevin equation has the underlying relaxation dynamics,
with the characteristic time of velocity decay
)(tvdt
dvm x x(t)
/mV
The equilibrium (Maxwell) distribution of velocities in the ensemble of such particles is established after this time scale.
v(t)
52
Velocity correlation function
Correlation functions in general measure the extent to which there is any correlation between a quantity at two separate times.
It can be applied to position, force, velocity etc, and can be defined in the same way as for the velocity correlation function.
The larger the value of the function is, the greater the extent of correlation.
For random motion, the velocity correlation function equals <v2(0)> for t~0, and = 0 at large t, when all correlation is lost.
)/exp()0()()0( 2 mtvtvv <v2(0)>
t
<v2(0)>e-t/m
<v(0
)v(t
)>
Velocity correlation function
For timescales shorter than V the velocity retains correlation, but not for time scales much longer than this.
For a sphere of radius 10nm (typical size for a large polymer) in water,
this leads to V = m/ ~10-10 s. 1mm particles in water: m/ ~ 2·10-8 s
DTk
dtem
Tkdttvv
B
mtB
0
/
0
)()0(
Overdamped limit If our “observation window” is much wider than the velocity
relaxation time V, then the particle effectively has no
acceleration, and we are left with the balance of forces,
viscous vs. stochastic:
)(1
or0 tdt
dx(t)v x
x Which we can easily solve
to produce the expression
x
d)(tx
t
0
1)(The stochastic expression for the
particle position x(t) is useless!
We can, however, build other quantities which can be evaluated
and studied. For example, the mean square displacement:
2121
0 0
2
2 )()(1
)( xx
ddtx
t t
53
Mean square displacement )()()( 2121 tttt xx
tDtdtx
t
21
)(21
0
2
2
This represents diffusion, and defines the diffusion constant D
As before, averaging under the integral:
The F.D. relationship:
Gives the Einstein relation between the
diffusion constant of a particle, and its
kinetic friction:
TkB2
/BTkD
a
TkD
p6
B
For a spherical particle with the
Stokes form of the friction drag
54
55
Typical values for D in water
Molecule T(oC) MW
(g / mol)
D
(m2 s-1)
Oxygen 25 32 2 x 10-9
Sucrose 25 342 5 x 10-10
Myosin 20 493,000 1 x 10-11
DNA 20 6,000,000 1.3 x 10-12
Tobacco mosaic
virus
20 50,000,000 3 x 10-12
Random walk
Let us consider the simple example of free diffusive motion
along one axis, the variable x(t), as a sequence of random
steps: to the left and to the right:
Steps of length a occur at time intervals
Dt. The total of N steps is made: t=N·Dt
)!(!
!
2
1),(
NNN
NNNP
N
If we count the number of steps to the right, N+ , and to the
left, N=NN+ , then we can find the probability P(x) as that
of making N+ steps out of the total of N – in any order!
The total displacement after N steps is x(t),
but the total length traveled is L=N·a
Use the Stirling formula,
as always: NNNeN ln!
taD
D
2
2
tD
x
Na
x
ee
42
2
2
2Where we defined
the constant:
x(t)
Random walk Diffusion
The sequence of ±steps along one axis is an example of
diffusive motion!
Steps of length a occur at time intervals Dt.
tD
dxe
dxexdxxPxx
tDx
tDx
2)(
4
42
222
2
The average displacement <x(t)> =0, of course. But the
mean square displacement is determined by the Gaussian
probability P(x) as the variance:
x(t)
taD
D
2
2
Compare the Einstein relation for the diffusion constant,
with our “counting states” result: dividing the elementary
step length by the time to make this step
/BTkD
57
Free diffusion equation
The sequence of ±steps along one axis.
),1(),1(),1(),1()1,( NkPkkwNkPkkwNkP
The transition probability of making a step from the position k
to (k+1) is w(k,k+1)=1/2. Obviously, w(k,k-1)=1/2 too. Now, the
probability to end up in a position k after N+1 steps is made of
two parts:
x(t)=k·a
Subtract P(k,N) from both sides, and use the fact that w(k-1,k)+w(k+1,k)=1
),(][),1(),1(),()1,( NkPwwNkPwNkPwNkPNkP
t
tkP
t
NkPNkP
D
),(),()1,(
2
22
2
2 ),(
2
),(
2
1),1(),(2),1(
2
1
x
txP
t
a
k
tkP
tNkPNkPNkP
t
D
D
D
Diffusion equation: 2
22 ),(
2
),(
x
txP
t
a
t
txP
D
58
This, as the random walk, is completely
generic to the stochastic system that has
equal ±½ probabilities of a step.
If you recall that P(x,t) represents the concentration c(x,t) (or density) of
particles, then we realize that empirically this relation has been known long
ago: Fick (1885) empirically described mass diffusion by assuming that the
flux of particles is proportional to the gradient of concentration:
),( txcDJ
2
22 ),(
2
),(
x
txP
t
a
t
txP
D
Conservation of mass implies the continuity relation: to
increase c(x,t) you need “influx” ),(),( txJtxc
dt
d
Also, notice a remarkable analogy between the free diffusion and the
Schrödinger equation for a free quantum particle:
2
22
2 xmti
Not surprisingly, the early quantum theory was
considering ideas of “imaginary time”, or an
effective imaginary diffusion constant: miD 2/
Free diffusion equation
60
Diffusion Control
Diffusion may limit:
Growth of 2nd phase particles
Supply of nutrients to organisms
Colloidal aggregation
Consider spherically symmetric growth, so work in spherical coordinates.
Assume steady state so dc/dt=0.
Diffusion equation becomes
As usual the solution depends on boundary conditions.
Example 1: Diffusion of molecules which react at the surface.
If these are transformed/lost during the reaction, then c(r = a) = 0. If the concentration well away from particle is c , the solution is:
For such a concentration profile, the flux is
given by
01 2
2
2
dr
dcr
dr
d
rc
r
acrc 1)(
2)(
r
aDc
dr
dcDrJ
a
61
Hence the number of collisions at the surface per unit time is:
The rate seen here sets radius a(t)
growing at a ~ t1/2, which is the fastest possible rate at which any diffusion-limited process can occur
If the reaction at the surface itself is rate limiting, the process will be slower.
If the diffusing molecule is a nutrient to an organism, then we also have to think about its consumption and this will be proportional to the volume.
Thus if e.g. a bacterium were too large, it would not get sufficient supply of the nutrients by diffusion, and so this will set an upper limit on size.
Example 2: Growth of particles at late stages post-nucleation
After the initial spinodal decomposition, in many systems (with conserved order parameter) there is an evaporation/condensation mechanism.
The smaller particles are unstable with respect to the larger ones, and material diffuses to the surface of larger particles, causing growth.
Process known as Ostwald ripening or coarsening.
The growth of the average cluster size follows
This is known as the Lifshitz-Slyozov law, and applies to a wide range of coarsening systems (droplets, polycrystals, phase decomposition in mixtures).
acDaaJaN pp 44)()( 2
3/1tr
Diffusion Control
Confined Brownian motion
Previously the free particle “started” with a
velocity v0 and no reference position in space.
After a characteristic time =(m/) the initial
velocity is “forgotten” and the Maxwell distr. P(v)
is established. But there is still no reference
position in space, and the diffusion continuously
spreads the particle “envelope”:
Let us now look how the thermal noise affects the system with
a potential energy, using the examples of a particle on a spring
Dtx 22
)(txdt
dxx
When the particle is confined by the potential U=½ x2 around
the equilibrium at x=0, the situation changes.
The overdamped Langevin eq.
The solution is obvious, from the analogy
with the earlier free Langevin eq. for the
velocity!
t
ttt dtteextx0
]')[/()/(
0 ')'(1
)( x
x TkB22
with
62
Particle in a potential well First of all, there is now a new time scale in the problem, x/, which
determines how long does it take for the particle to “forget” its initial position
and adopt the equilibrium distribution.
t
ttt dtteextx0
]')[/()/(
0 ')'(1
)( x
Finding the m.s. <x2> follows the same steps
as we made in the evaluation of the m.s. <v2>
We have seen this very recently!
t
tttt
t
t dtdttteeexx0
21212
])[/(])[/(
0
)/(22
0
2 )()(1
21 xx
tt eexx )/(2)/(22
0
2 12
After the time t >> x
Tkx B
2
2
The m.s. deviation of x from zero is the m.s. fluctuation
about the equilibrium. <x2> then is given by our general
relation:
eq
2
Y
XTkX B
D Here the force conjugate to the displacement
x is just the spring force f=ax 63
Diffusion and drift Consider our earlier scheme of deriving the free
diffusion equation from analysing the probabilities
of ±steps, with transition probabilities w±=½.
Let us now consider a constant bias:
w(k,k+1)=1/2 and w(k,k-1)=1/2.
x(t)=k·a
subtracting P(k,N) from both sides, and forming the discrete derivatives:
),(][),1(),1(),()1,( NkPwwNkPwNkPwNkPNkP
k
tkP
tk
tkP
tt
tkP
t
NkPNkP
D
D
D
),(2),(
2
1),(),()1,(2
2
Diffusion with a
constant drift: x
txP
t
a
x
txP
t
a
t
txP
D
D
),(2),(
2
),(2
22
),1(),1(),1(),1()1,( NkPkkwNkPkkwNkP
Starting from the balance:
64
Diffusion in external potentials With a constant drift “force” the diffusion
equation adopts a modified form. There is a
general solution of this, but let us look at the
steady state - the equilibrium distribution.
x
txPC
x
txPD
t
txP
),(),(),(2
2
)()(
:)()(
0 eq
eqeq
2
eq
2
xPD
C
x
xP
x
xPC
x
xPD
xDCePP /
0eq
Example: Sedimentation by gravity: V=mgz, force f=mg
which will follow if we take C=mg/
Tkmgz
BePP
0eq
This suggests that a general diffusion equation of motion in an arbitrary
external potential V(x) would take the form
),(
1),(),(
force),(),(txP
x
V
x
txPD
xtxP
x
txPD
xt
txP
In different sources this modified diffusion equation is often called the
Fokker-Planck equation. However, strictly speaking, the F-P equation is
for the joint probability P(v,x,t) – whereas this reduced form has the name
of Smoluchowski equation (1906)
Flux of probability We now see how the equilibrium distribution
arises as the limiting (t→) steady state of
generalised diffusion:
P
x
V
x
PD
xt
txP
1),(
dxx
V
DP
P
1eq
Tk
xV
BePP)(
0eq
The probability distribution P(x,t) is a continuous field with a fixed
normalisation. As all such fields, it must satisfy the continuity relation:
),(div),(
txJt
txP
P(x,t)
),(),(f),( )()(
txPex
eDtxPx
txPDJ
xVxV
Here the flux of probability J(x,t)
has to be defined as:
For the force-free diffusion: ),( txcDJ
66
Escape over potential barrier, #1 Consider a system in a metastable state,
separated by a potential barrier D from
reaching its thermodynamical equilibrium.
The generic question is:
How long would it have to “wait” for a sufficiently
large thermal fluctuation to take it over the barrier?
)()()(
xPex
eDJxVxV
The classical Kramers problem (1940): steady-state current of particles
(or states) from A to B. The constant flux is given by
V(x)
D
A B x0
Integrate both sides between A and B:
BA
B
A
xPeDdseJxVsV
)()()(
If the potential well at B is deep
)()(
A
B
A
xPDdseJsV
Assuming the basic shape of potential barrier: V(x)=D ½kC (x-x0)2 ,
the integral gives the approximate steepest-descent result:
)(42
021 )(
A
C
BTkxsTkxPDeJdseeJ
TkBCB
D
D
k
pk
We have obtained the steady-state flux to
carry our system from A to B (over the
energy barrier towards its true equilibrium):
V(x)
D
A B x0
The rate of this escape (i.e. the inverse life-time at A) is by definition the
ratio of the flux to the {number of particles present at A}, which in turn is
given by
A
BA
x
AAAA
TkxPdxexPNdxexPdN AAV
k
pk 4)()(:)(
2
21
)(4
A
B
CTkxPeDJ
Tk
B
D
p
k
The rate of escape over the barrier D:
D
D
TkCATk
CA
BA
BB eeD
N
J
Tk p
kkkk
p 44
1
This is a very important (and famous) result explaining the so-called
Arrhenius law, empirically relating the life time of any metastable state to
the Boltzmann exponential with the energy barrier (found anywhere from
biology/chemistry to mechanical engineering).
Escape over potential barrier, #2
69
Observing Brownian Motion
0 100 200 300 400 500 600
0
50
100
150
200
250
300
350
400
450
15 20 25 30 35 40
30
35
40
45
50
70
Using particle tracking for “microrheology”
The mean square displacement as a function of time can be followed eg. during some process.
(d is dimensionality, a is particle radius, is lag time)
We have seen that viscoelasticity can be treated as a complex viscosity.
p
a
Tkdr B
62)(2
<r2>
)(6
2)(2 srsa
TkdsG B
p
“generalised Stokes Einstein equation”
What happens with Brownian motion in a complex fluid (viscoelastic medium)?
A generalised version of the Stokes-Einstein equation allows the complex moduli
to be determined by tracking the motion of the particles.
(r2(s) is the Laplace transform of r2 (t),
s is a Laplace frequency,
G(s) is related to G*(w) with s=iw )
71
Motion of beads within cells
Fluorescence image of an individual
human dermal fibroblast cell showing
clustering of the beads in the perinuclear
region, with a few beads in the periphery of
the cell.
Two dimensional mean square
displacements of beads in this cell. A
selection of particles have been
highlighted in red, for clarity. The slopes
exhibit significant scatter, which we
attribute to local variations in the rheology
according to cytoskeletal arrangements.
Note: resolution of position ! 10nm is possible optically