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Today in Precalculus
• Turn in graded worksheet• Notes: Simulating circular motion –
Ferris Wheels• Homework
Example 11)Set up parametric equations that will form a circle
x = cost
y = sint
2) Change the amplitude for the radius of the Ferris wheel.
x = 50cost
y = 50sint
3) Adjust the y equation (the vertical equation) for the center of the wheel (vertical shift).
x = 50cost
y = 50sint + 65
Ferris Wheels4) Include a phase shift so the wheel starts its rotation at the bottom (this will be the same for all equations)
x = 50cos(t – π/2)
y = 50sin(t – π/2) + 65
5) Change the period to reflect the time it takes for one revolution
One revolution is 2π radians,
so if it takes 18 seconds for one revolution then the period is 2π/18 or π/9
x = 50cos(π/9t – π/2)
y = 50sin(π/9t – π/2) + 65
Ferris WheelsTo view the graph:
t: 0, at least 47
x: -60, 60 (greater than the radius on each side)
y =0, 120 (at least diameter plus suspended height)
(to see it as a circle, zoom – zsquare)
Either trace graph, use table, or the equations to find position at 47 seconds.
So they are 32.139ft to the left of center and 103.302ft high.
Example 2Nikko is riding on a Ferris wheel that has a diameter of 122ft and is suspended so the bottom of the wheel is 12ft above the ground. The wheel makes one complete revolution every 20 seconds. Where is Nikko after 12 seconds?
radius = 61 x = 61cos(2π/20t – π/2) = 61cos(π/10t – π/2) y = 61sin(2π/20t – π/2) + 73 = 61sin(π/10t – π/2) + 73
t: 0,20x: -65,65y: 0, 140
At 12 seconds, Nikko is 35.855 feet to the left of center and 122.350 feet high.
Homework
Finish worksheet