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A P R I L I S , 1 9 3 7 P H Y S I C A L R E V I E W V O L U M E 5 1
The Helium Wave Equation*
.T. H. GRONWALL**
Columbia University, New York, N. Y.
(Received February 3, 1937)
This paper represents an attempt to solve the equation V 2 ^+(l /z)^ z +(l /4r) ( jE— 7 ) ^ = 0, which is the Gronwall form of the wave equation for helium Estates. The equation V2u + (l/z)ug = 0 is separable in polar coordinates (r, (3, <p), and has solutions umk:=r2m~k sinfc (3vmk (sin2 0)eik<p
= r2m~kwmk((3, <p), where the vmks are Jacobi polynomials, and the wmkS form a complete orthogonal set of surface functions. The function \p is expanded as \f/ — ^2\pmk(r^)wmki resulting in an
mTc infinite system of ordinary linear differential equations for the ^mfc's.
EDITOR'S INTRODUCTION
AFTER persistent effort, the late T. H. Gronwall of Columbia University succeeded in putting the wave equation for helium S states into a remarkably simple form.1 He then made an ex
tensive study of the equation in order to learn something about the nature of the solutions. Many calculations had been made when death intervened, and the notes were left behind in an unordered state. Largely owing to the difficulty of arranging them, they were still unpublished in October, 1936, when they came into my hands through the courtesy of Dr. F. Bohnenblust. They have since proved very valuable for my own research, and so it is felt that the essential results should be published. Those results which are to be used in the following paper have been checked, but the unused results, such as the formulae for matrix elements in the Appendix, have not. (The derivation or verification is easy but tedious, and is hence left to any reader who may be sufficiently concerned.) For the sake of clarity and brevity, I have made several insertions, which are indicated by enclosure within curly brackets. Finally, it is a pleasure to express my appreciation of the opportunity to use freely the unpublished work of Gronwall, and to thank Professor E. Hille for permission to publish it.
WAVE EQUATION
The wave equation for S states of the helium atom may be written1-2 in the form
vV+ : —+ :(-+ : :+- rV=°> C1) 1 ' — • — ^(r-<y)1* 2Z(r~x)U
i a f l/E +-(-H
z dz r\A [_2(r+y)1* [2{r-y)J 2Z(r-x)>
where ^x — r^-\-Y22 — r\2
2 — 2Y\f2 cos 0, 4.y=zn2 — r2
2, 4s = 4Xarea of A with sides rh r2, rn = 2rir2 sin 0, Ar = 4:(x2+y2+z2^ = ri2+r2
2.
Here Y\ and r2 refer to the electron-nucleus distances, 0 denotes the angle between the corresponding radius vectors, and ri2 denotes the interelectronic distance. Since the range of 0 is 0 — 0 — 7r, the domain of x, y, and z is the upper half-space z^O. {It may be noted that tan 6 = (z/x), so that 6 is the angle in the xz plane from the x axis to the projection of the radius vector r upon this plane. Also, if we let a = tan~x (r2/ri), it follows that 2a is the angle from the y axis to the radius vector. For cos 2a = 2 cos2 a—\ ; cos a = [Vi/C^+f^2)*]; and cos 2a= [(>i2 — r2
2)/{r\*+r22)~]= (y/r).}
* Edited by J. H. Bartlett, Jr., University of Illinois, Urbana, Illinois. ** Dr. T. H. Gronwall died May 9, 1932. This paper together with other manuscripts was then transferred from the
physics department of Columbia University where this work was done to the care of Dr. E. Hille of Princeton University. 1 T. H. Gronwall, Annals of Mathematics 33, 279 (1932). 2 The rational units of length and energy of Hylleraas are used. See Zeits. f. Physik 54, 347 (1929).
655
656 T. H. G RON WALL
The variational problem corresponding to Eq. (1) is
5 f **2+&r*+*»*—( —+ + V 2 F dx dy dz = 0. J I A 4 [2(r+y)]» [_2{r~-y)J 2Z(r-x)*J J
{In order that this problem have a meaning, the integral must exist. Such a requirement is sufficient to exclude the so-called "second solutions" for hydrogen 5 states.3 We shall, therefore, adopt this as a necessary boundary condition on the (univalent) function ^, which will also be required to be of class C2, except perhaps on the (+#) and y axes, where \p might conceivably become infinite.}
Introducing polar coordinates, with the z axis as the pole,
x = r cos <psm fi9
y = r sin <p sin 0, 3 = rCOSj3,
we have
8 I I I i ^ 2 + - ^ 2 + ^ 2 ~ ~ ( — h - J^2 \sb ds sin |8 cos p dp d<p = Q,
Jo Jo Jo L s2sin20 s2 \ 4 s/ J
where
/ = [ 2 ( l + s i n ^s in /3) ] -*+[2( l - s in <p sin 0 ] -* - ( l / 2Z) [ l - - cos psin 0]-*, and r = s2.
The corresponding differential equation is
* . .+ (5A)* .+ (4A* sin2 j 8 ) ^ ^ + ( 4 / 5 8 ) ( ^ + 2 cot 2fth) + pS+ ( 4 / A ) > = 0. (2)
BASIC ORTHOGONAL FUNCTIONS
To find an appropriate orthogonal system on the half-sphere, we consider the equation uss+(5/s)u8+(4:/s2sin2p)utp<p+(4/s2)(um+2cot2pu0)=O. (3)
Substituting
u = s^-^^k<pgmk(t)f * = sin*0,
where m and & are integers, ni^k^O, we find
Now, writing gmk{t) — tkl2v(m, k, /), the preceding equation gives
/(l-/>«+[*+l-(*+2)^>+(w+l)(m-*)w = 0. (4) {This equation may be recognized as the hypergeometric equation in the usual form.}
The only solution of (4) which is finite both at t = 0 and t = 1 is the Jacobi polynomial F(k — m, m-\-1, £ + 1 , t), m^k^O (multiplied by a constant).
Now4
/ Jo
i
thF{k-m, m+1, ife-f 1, t)F(k-Mf, ni'+l, k + l9 t)dt
^{l/2m + \-k)lV{m-k+\)Y{k + \)/V{m-\-\)Jh 3 The editor (J. H. B.) desires to thank Professor R. Courant for informing him of this. 4 This follows from Jordan, Cours d'Analyse III, 242, Eq. (45, 46) upon making a = 7 = £-f-l and n = m — k.
H E L I U M W A V E E Q U A T I O N 657
We also have (Jordan4)
F(k-m, m + 1, k + 1, /) = [ r (* + l ) / r ( w + i ) ] r * ( i / * ) " ^ * [ / ~ ( l - O m " * ] .
Writing
v(m k t) = ZT(m+l)/T(k + l)T(m-k + l)2F(k-m9 m+lt k + U t)9 O^k^tn,
we find
Nmm>k= I th{m k t)v(mf k t)dt=(l/2m+l-k)&mm> (5)
and
m-fc {m + v) ! <w*o = Ci/r(w--*+i)]r*(rf/(/Ow"*Dm(i--0,,l"*]s=a E ( - ) * — — - — . >. (6)
*=o ? !(&+*>) \{m—k — v)! (z>(ra & 0) = [m l/k \(m — k) !1,
From (6) (7) U(m * 1) = ( — ) m ~ k ,
{vt(m k 0) = -l(m+l) \/(k + l) l(m-k-l) 12, and by (4) ' (8)
\vt(m k l) = (-)m-k(m + l)(m — k).
EXPANSION IN TERMS OF ORTHOGONAL FUNCTIONS
The variational problem in terms of / may be written as
5 f f f [ ( l / 4 ) * . * + ( l A * W (9) ^ 0 *^0 ^ 0
Expand t=Y,Cmk$mk(s)gmk(t)™* k<p, (10)
where the cosines belong to the para terms and the sines to the ortho terms. In the following treatment, we shall consider only the para terms.
Setting eh — 2 for & = 0, and ek—l for &>0, we obtain
•»2TT „ l
Jo Jo
inky m' kgmkgm' k + (l/s2)\pmkr<m>k{(k2/t)g
mm'k t /0
mky m'kgmkgm' k+{l/s2)^mk^m'k{2m-k){2m + 2-k)gmkgm'k] mm'k Jo
= £(ir6kc\k/2m + l-k)t(\/4)(fmk)H(l/s2)(2m-k)(2m+2-k)t*m^. mk
We have integrated by parts, used the differential equation for gmk and Eq. (5).
6 5 8 T . H . G R O N W A L L
The potential energy may be treated in like manner. Let us write
I d<p d#2[{2(l + /*sin *>)}-*+{2(1-/* sin *>)}-*-(l/2Z){l-/*cos *>}"*] Jo Jo
= ]£ a(mkrnfk')cmkCm>k'$midm'k>.
mkm'k'
/^2TT „l
Then a(mkmrkf)=\ dtp \ dt[_{2(l-\-t*sin <£>)}~~H—• ~\gmkgm'kf cos &<p cos k'<p. Jo Jo
To simplify, we observe that, n being an integer,
J^»27T ^ » 2 T T
(1+/1 sin <p)-kin(pd<p = eSniril2 I (1 - /* cos <p)-kin*dip o Jo
and I (1 —/* sin <p)-hin<pd(p = eniril2 I (1 —/* cos (p)~hin(pd(p. Jo Jo
It follows that
a ( ^ , m ,^) = ( ^ c o s ( | ^ - ^ | 7 r / 2 ) - ( l / 2 Z ) ) / ( m ^ m / ^ ; I*-* ' ! )
+ (v2cos((^ + ^ ) ^ / 2 ) - ( l / 2 Z ) ) 7 ( m ^ m , ^ ; ^ + ^ ) ,
where I (ink m'k'; n) = (1/2) J d<p I dl(\ —ft cos <£>)~~̂mfc&m'/c' cos n<p. Jo Jo
The variational problem is now, putting c2mk= (2ra + l — k)/irejCi
«• f {L[(V4)(^/c) 2+(^ - X) a(mk ™'k')\l/mk'll'm'k'CmkCm>k'}s*ds==0.
mk m'k'
The corresponding Euler equations are, if we number the functions by setting n = ^m(m+l)+kf
and if we set A(mk m'kf) = 2ircmkcm>k'a(/rnk mfkf),
( l / 4 ) ( s V / ) ' - ( 2 m - £ ) ( 2 m + 2 - ^ ^ (11) n'
{This is an infinite system of ordinary linear differential equations of the second order. We should like to find a solution which is finite everywhere.} Substitute ^n — e~iV~E)sfn(s), and let p = 2( — Ey*s, obtaining
A (MI!) P2fn"+(5P-p2)fn'-4(2?n-k)(2ni+2-k)fn-(5/2)pfn + Z P/„* = 0. (12)
»' 7 r ( - E ) *
(The primes on / denote differentiation re p.)
Let b(nri)=A(nri)/Tr(-E)* and set fn = flcn^p\ (13) v=0
The recursion formula is then
(^-4w + 2*)(y+4+4m-2*)cn<»'> = (y+t)(;n<»'-1>-E6»»^»'(^1). (14)
H E L I U M W A V E E Q U A T I O N 659
{Gronwall attempted to cutoff the series (13) by setting cn(p) = 0. He calculated A nn> for n, n' = 0,1, 2
and solved the equations (14) for v{ — E)K If this procedure were significant, then one might expect to obtain three eigenvalues of helium in this manner. However, it is not clear which three they would be, except that they would be of 1S type. If it be assumed that they are the three lowest, and if one substitutes the experimentally observed values, then the resulting values of v do not agree with one another. For this and other reasons, we therefore omit the reproduction of the calculations.
Gronwall also expanded the cniv) in factorial series of the form
M=0
and determined relations between the cn*s.
APPENDIX
1. Recursion formulae for the functions v(mkt)
iv(m, k, t) = -[_(m+l)(m-irl-k)/(2m~\-l-k)(2m+2-k)2v(m+X, k, t) + H2m2+2m(l-k)+k(k-l)2/(2m-k)(2m+2-k)}v(mkt) -tm(m-k)/(2m-k)(2m+l-k)2v(m-l)k,t)f
t(l-t)v,(m1kJ) = l(m + l)(m-k)(m^l-k)/(2m + l~k)(2m+2-k)']v(m-{-l1k,t) -lk(m-\-l)(m-k)/(2m-k)(2m+2-k)2v(m k t) — [m(m-\-l){m — k)/(2m—k)(2m-{-l— k)2v(m — 1, k, t),
tv'{m k t) + (m+l)v(m k t) + t(m + l)/(2m+2-k)y(m+l, k, t)-t(m + l-k)/(2m+2-k)2v,(m k t)=0, tv'(m k t) — (m — k)v(m k t) — [m/{2m — k)'}v,(m k t)Jr[_{m — k)/{2m — k)"}of{m — \, k, t)=0,
v(m,k-lJ) = l(m+l)/(2m+2-k)2v(m+ltkft)-l(m+l-k)/{2m+2-k)2v(mkt)t
tv(m, k + 1, t) — — \^{m — k)/{2m — k)~\v{m k t) + [m,/2m — ¥]v(m-~l, k, t) — Ckvirn k t)-\-Dkv{m — 1, &, /).
2. Expression for /(m, k m% kf, n) in terms of the v's
Integrate with respect to <p.
OO /ry \ j
(i -** cos <p)-*=L ~rrf12 cosV <p>
(IS)
(16)
(17)
(18)
(19)
(20)
2*vv\v\
Consequently
where
We have
so that
where
This gives
i j 0 (1 -0 cos ri-W^Ec^,
( 2 » + 4 J U ) !
2Sn+w /*!(n+/*)!(»+2/i)!
%+ (1+/«)(»+1+M)
and c0 = (2n)\
2Sn n\n\
(1 -** cos <p)-k™vd<p = tnl*Fn(t), o
23n nlni \ 4 4 /
I(m k, mf kf; n) = §\(n+h+k'V*Fn(t)v{m k t)v(mf kf t)dt.
For the problem at hand, we require the knowledge of I(m k, m' kf; n) only for n = k-\-¥ and n-
(21)
660 T . H . G R O N W A L L
3. Formula for /(m, k, 0, 0, k)
By (21), I(tnt k, 0, 0, k) = f\kFkv(m, k t)dt.
But tkFk^ll6/(2k+l)(2k-\-3)']Ltk+1(l-t)Fk,J from the differential equation. Hence
(l/\6)(2k+\)(2k+3)I(m & 0 0 &) = f\[tk+1(l -t)Fk'Jdt.
Integrate by parts and observe that
dFk tk^{l-t)-f-+l/^2 as /->1
at
and F ^ [ r ( ^ + l ) / r ( ^ + J ) r ( ^ + ^ ) ] l o g ( l - / ) as t-»l.
Then J ^ ^ K l - O W d * ^
Therefore, I{m k 0 0 k) = [ 8 \ 2 ( - ) " - * ] / ( 4 w - 26+1) ( 4 m - 2 6 + 3 ) . (22)
4. Formula for I{m klOk)
I(mk 10 k) = rtkFkv(mkt)v(l 0t)dt= fW*z/(m k t)(l-2t)dt=*I(m k 0 0 /) - 2 f V + 1 7 > ( r a kt)dt.
But tv(m k t) =Av(m + l, k t)+Bv(m k t) + Cv(m-l, k / ) . (Cf. Eq. (15)) and hence
I(mk 10 k) = (l-2B)I(m £ 0 0 0 + 4 / ( w + l, & 0 0 t) + CI(m- 1, kOOt). (23)
5. Formulae for I(m k, m! m!'; ri)
First we may note that v(m' m' t) = 1. Then
I[m k m' m', k-\-m') — I tk+m'Fk+m>v(ni k t)dt.
Consider w' = l. tFk+l= likFk-(2k-l)Fk_l}/(2k+l). Then, applying formula (20)
f\k+1Fk+lv(m k t)dt=(U/2k + l)f1tkFkv(m k t)dt-t(2k- l ) / (2^ + l)]j^V-1FA ;_i^(m k t)dt
= [ 4 ^ ( 2 & 4 - l ) ] / ( w £ 0 0 & ) - [ ( 2 £ - l ^ ^
and
I{mk, 1 1 k+\)^(4k/2k + l)I{mk00k)-l(2k-l)/{2k-\-l)^Ck^lI(m,k-l}00,k--'l)
+Dk^I(m-lfk-l,00k-l)~]f (24)
I(m m, m' m', m-\-m') = 8V2/(2w+l)(2n+3), n — m-\-m\ (25)
If 7(w w, ra' w', w — mf) = /(ra' , n), n = m — m\ then
/ 2w + l \ / 2 w + 3 \ ( mrjr )( m'-\-—-— jJ(tn', n) = (l/y/2)-{-mf(m'-\-n) J(m'— 1, w), (26)
so that the successive J's may be found. In particular,
J(0, n) = 8v2/(2w+l)(2w+3), (27)
J r(l ,») = C16/(2»+S)(2»+7)]{(l />^) + 1 6 ( ^ + l ) / v 2 ( 2 » + l ) ( 2 « + 3 ) } . (28)
6. Recursion formula for I(m k m! k' n)
One may derive the following:
( 2 » + l ) / 2 m + l - i k ) [ ( m + l ) / ( m + l , k+1, m', kf, n+l)-(m-k)I(n, ife+1, m', &', » + l ) ]
= 4nl(m,k1mf,k,
fn) (29)
- [ ( 2 w - l ) / ( 2 m + l - £ ) ] [ m / ( m - l , £ - l , r a ' , &', w - 1 ) - ( w - £ - f l ) J ( m , fc-1, m', jfe'f w - 1 ) ] ,
{Gronwall actually computed only the first few i ' s . It might be useful to know their asymptotic properties in general (for large values of the indices) for the solution of the system (12).}