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7/30/2019 SPICE_CH2_PROBLEMS.pdf
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SPICE for Power Electronics and Electric Power
CHAPTER 2 - PROBLEMS
2.1 TheRLCcircuit of Figure P2.1 is to be simulated to calculate and plot the transient response
from 0 to 2 msec with an increment of 10 sec. The voltage across resistorR is the output. Theinput and output voltages are to be plotted on an output file. The results should also be available
for display and as hard copy using the .PROBE command.
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Answer
Time
0s 0.4ms 0.8ms 1.2ms 1.6ms 2.0ms
V(1) V(3)
-10V
-5V
0V
5V
10V
Vout
Vin
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2.3 Repeat Problem 2.1 for the circuit of Figure P2.3, where the output is the current is through
the circuit.
Answer
Time
0s 0.4ms 0.8ms 1.2ms 1.6ms 2.0ms
V(1) V(2)
-20V
-10V
0V
10V
Vout
Vin
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The circuit redrawn with nodal assignment is given by
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Time
0s 0.4ms 0.8ms 1.2ms 1.6ms 2.0ms
I(R1)
-8.0A
-7.0A
-6.0A
-5.0A
-4.0A
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Time
0s 0.4ms 0.8ms 1.2ms 1.6ms 2.0ms
V(1) V(3)
-0.4V
0V
0.4V
0.8V
1.2V
OUTPUT
INPUT
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Time
0s 0.4ms 0.8ms 1.2ms 1.6ms 2.0ms
V(1) V(2)
0V
0.4V
0.8V
1.2V
OUTPUT
INPUT
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ANSWER
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Time
0s 0.4ms 0.8ms 1.2ms 1.6ms 2.0ms
I(R1)
-2.0A
0A
2.0A
OUTPUT
I(IS)
-2.0A
0A
2.0A
INPUT
V(2)
-400V
0V
400V
SEL>>
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Time
0s 0.4ms 0.8ms 1.2ms 1.6ms 2.0ms
V(2)
-20V
0V
20V
OUTPUT
V(1)
-400V
0V
400V
SEL>>
INPUT
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SOLUTION
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Frequency
10Hz 100Hz 1.0KHz 10KHz 100KHz
VP(1,2)
-100d
0d
100d
SEL>>
PHASE ANGLE
VM(1,2)
0V
5V
10V
MAGNITUDE
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Frequency
10Hz 100Hz 1.0KHz 10KHz 100KHz
VP(2)
-1.0d
-0.5d
0d
SEL>>
PHASE ANGLE
VM(2)
1.998KV
2.000KV
2.002KV
MAGNITUDE
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Frequency
100Hz 300Hz 1.0KHz 3.0KHz 10KHz 30KHz 100KHz
VP(2)
-100d
0d
100d
SEL>>
PHASE ANGLE
VM(2)
0V
250V
500V
MAGNITUDE
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Frequency
100Hz 300Hz 1.0KHz 3.0KHz 10KHz 30KHz 100KHz
VP(2,3)
-100d
0d
100d
SEL>>
PHASE ANGLE
VM(2,3)
0V
0.5V
1.0V
MAGNITUDE