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SPECTROSCOPY Spectral Distribution of Radiant Energy Wave Number (cycles/cm) X-Ray UV Visible IR Microwave 200nm 400nm 800nm WAVELENGTH(nm)

Spectrometry Ir

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Page 1: Spectrometry Ir

SPECTROSCOPY

Spectral Distribution of Radiant Energy

 Wave Number (cycles/cm)

X-Ray UV Visible IR Microwave

200nm 400nm 800nm

WAVELENGTH(nm)

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V = Wave Number (cm-1)

Wave Length

C = Velocity of Radiation (constant) = 3 x 1010 cm/sec.

= Frequency of Radiation (cycles/sec)

 

The energy of photon:

h (Planck's constant) = 6.62 x 10-27 (Ergsec)

V =C

E = h = hC

C=

C =

SPECTROSCOPY

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DISPERSION OF POLYCHROMATIC LIGHT WITH A PRISM

Polychromatic Ray

Infrared

RedOrange

YellowGreen

Blue

Violet

Ultraviolet

monochromatic Ray

SLITPRISM

Polychromatic Ray Monochromatic Ray

Prism - spray out the spectrum and choose the certain wavelength( that you want by slit.

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SPECTROSCOPY

1. Spectrophotometer - an instrument which can measure the optical density of a sample at any wavelength.

 

Light Lens Slit Monochromator

Sample Detector Quantitative Analysis

Slits

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2. Fluorometer - measures the intensity of fluorescent light emitted by a sample exposed to UV light under specific conditions.

Emit fluorescent lightas energy decreases

Ground state

Sample

90C

DetectorUV Light Source

Monochromator Monochromator

Antibonding

Antibonding

Nonbonding

Bonding

BondingEnergy

'

'

'

''

n->n

n->'

Electron's molecular energy levels

Fluorometer

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BEER LAMBERT LAW

Glass cell filled with concentration of solution (C)

IILight

0

As the cell thickness increases, the intensity of I (transmitted intensity of light ) decreases.

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R- Transmittance

R = I0 - original light intensity

I- transmitted light intensity

 

% Transmittance = 100 x

Absorbance (A) or optical density (OD) = Log

= Log = 2 - Log%T

Log is proportional to C (concentration of solution) and is

also proportional to L (length of light path through the solution).

I I0

I I0

I0

I

1 T

I I0

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A CL = KCL by definition and it is called the Beer Lambert Law.

A = KCL

K = Specific Extinction Coefficient ---- 1 g of solute per liter of solution

 

A = ECL

E = Molar Extinction Coefficient ---- Extinction Coefficient of a solution containing 1g molecule of solute per 1 liter of solution

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E =Absorbance x Liter

Moles x cm

E differs from K (Specific extinction Coefficient) by a factor of molecular weight.

UNITS

  A = ECL

A = No unit (numerical number only)

E = LiterCm x Mole

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L = Cm

C = Moles/Liter

A = KCL

A = No unit C = Gram/Liter L = Cm

A = ECL = (Liter

Cm x Mole) x

Mole

Literx Cm

K=Liter

Cm Gram

A = KLC = (Liter

Cm x GramGramLiter x Cm) x

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STEPS IN DEVELOPING A SPECTROPHOTOMETRIC ANALYTICAL METHOD

1. Run the sample for spectrum

2. Obtain a monochromatic wavelength for the maximum absorption wavelength.

3. Calculate the concentration of your sample using Beer Lambert Equation: A = KCL

Wavelength (nm)

Absorbance

0.0

2.0

200 250 300 350 400 450

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SPECTROPHOTOMETR READINGS

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ULTRAVIOLET SPECTRUM

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Slope of Standard Curve = AC

1 2 3 4 5

1.0

0.5

Concentration (mg/ml)

Absorbance at 280 nm

There is some A vs. C where graph is linear.

NEVER extrapolate beyond point known where becomes non-linear.

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SPECTROMETRIC ANALYSIS USING STANDARD CURVE

1 2 3 4

0.4

0.8

1.2Absorbance at 540 nm

Concentration (g/l) glucose

Avoid very high or low absorbencies when drawing a standard curve. The best results are obtained with 0.1 < A < 1. Plot the Absorbance vs. Concentration to get a straight line

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CELLS

UV Spectrophotometer

Quartz (crystalline silica)

 Visible Spectrophotometer

Glass

 IR Spectrophotometer

NaCl

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LIGHT SOURCES

 UV Spectrophotometer

1. Hydrogen Gas Lamp

2. Mercury Lamp

Visible Spectrophotometer

1. Tungsten Lamp

IR Spectrophotometer

1. Carborundum (SIC)

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CHEMICAL STRUCTURE & UV ABSORPTION

Chromophoric Group ---- The groupings of the molecules which contain the electronic system which is giving rise to absorption in the ultra-violet region.

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CHROMOPHORIC STRUCTURE

Group Structure nmCarbonyl > C = O 280

Azo -N = N- 262

Nitro -N=O 270

Thioketone -C =S 330

Nitrite -NO2 230

Conjugated Diene -C=C-C=C- 233

Conjugated Triene -C=C-C=C-C=C- 268

Conjugated Tetraene -C=C-C=C-C=C-C=C- 315

Benzene 261

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UV SPECTROMETER APPLICATION

Protein

Amino Acids (aromatic)

Pantothenic Acid

Glucose Determination

Enzyme Activity (Hexokinase)

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FLUOROMETER APPLICATION

Thiamin (365 nm, 435 nm)

Riboflavin

Vitamin A

Vitamin C

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VISIBLE SPECTROPHOTOMETER APPLICATION

Niacin

Pyridoxine

Vitamin B12

Metal Determination (Fe)

Fat-quality Determination (TBA)

Enzyme Activity (glucose oxidase)

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EXAMPLES

1. A solution of purified DNA isolated from Escherichia coli gives an absorbance of 0.793 at 260 M in a 1 Cm cell at pH 4.5. If E1%1Cm is 197, calculate the concentration of the solution in milligrams per milliliter.

 

2. Calculate the Molar Extinction Coefficient E at 351 nm for aquocobalamin in 0.1 M phosphate buffer. pH = 7.0 from the following data which were obtained in 1 Cm cell.

Solution C x 105 M Io I

A 2.23 93.1 27.4

B 1.90 94.2 32.8

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3. The molar extinction coefficient (E) of compound x is:

3 x 103 Liter/Cm x Mole

If the absorbance reading (A) at 350 nm is 0.9 using a cell of 1 Cm, what is the concentration of compound x in sample?

 

4. The concentration of compound Y was 2 x 10-4 moles/liter and the absorption of the solution at 300 nm using 1 Cm quartz cell was 0.4. What is the molar extinction coefficient of compound Y?

 

5. Calculate the molar extinction coefficient E at 351 nm for aquocobalamin in 0.1 M phosphate buffer. pH =7.0 from the following data which were obtained in 1 Cm cell.

Solution C x 105 M I0 I

A 2.0 100 30

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Question 6.Question 6.

A = 0.01A = 0.01E = 10000L / mole x cmE = 10000L / mole x cmL = 1cmL = 1cmA = ECLA = ECL

0.01= 10000L/mole X Cm X C (Concentration) x 1Cm0.01= 10000L/mole X Cm X C (Concentration) x 1Cm

C = mole / LiterC = mole / Liter

C = X mole / Liter = X mole (236 g/mole) / Liter (1000 CmC = X mole / Liter = X mole (236 g/mole) / Liter (1000 Cm33) x PPM (10) x PPM (10-6-6 g/Cm g/Cm33))= = XX mole mole (236 (236 gg / / molemole) / ) / LiterLiter x 1 x 1 LiterLiter / 1000 / 1000 CmCm33 x ( PPM) 10 x ( PPM) 10-6-6 gg / / CmCm33))=x PPM=x PPM

PPM = 1ug / PPM = 1ug / CmCm33

1ug = 1ug = 1010-6-6 g g