40
atography (Separations) Spectrometry red (IR) Spectroscopy ar Magnetic Resonance (NMR) Spectroscopy Crystallography (visual solid state molecular str Analytical Chemistry

Chromatography (Separations) Mass Spectrometry Infrared (IR) Spectroscopy Nuclear Magnetic Resonance (NMR) Spectroscopy X-ray Crystallography (visual solid

Embed Size (px)

Citation preview

• Chromatography (Separations)

• Mass Spectrometry

• Infrared (IR) Spectroscopy

• Nuclear Magnetic Resonance (NMR) Spectroscopy

• X-ray Crystallography (visual solid state molecular structure)

Analytical Chemistry

QuickTime™ and aTIFF (Uncompressed) decompressorare needed to see this picture.

Molecular Vibrations [IR]

Molecular Rotations [Rotational Spectroscopy]

Nuclear Spin "Flipping" [NMR]

Electronic Excitations [UV/Vis Spectroscopy]

Scattering [X-ray Crystallography]

The Electromagnetic Spectrum

• Identify the environment of hydrogen and carbon atoms

• Identify atom connectivity

• Identify stereochemical relationships

Nuclear Magnetic Resonance (NMR) Spectroscopy

The spin state of a nucleus is affected by an applied magnetic field

Nuclear Magnetic Resonance (NMR) Spectroscopy

α-state

β-state

B0

Add EnergyEnergy released

(& detected)

Nuclear Magnetic Resonance (NMR) Spectroscopy

Effect of Field Strength

An NMR Spectrometer

O

CH3H3C

1H NMR of Acetone

O

OH3CCH3

1H NMR of Methyl Acetate

Electron Density Maps

Electron Shielding

Electron Shielding

0 ppm4681012 2

X H

X = N, O, S

O

HR

O

ORH

R C

H

H

HC C

H

HC C H

HX C

H

H

H

X = N, O, S, halogen

Common NMR Shifts

0 ppm4681012 2

"alkyl" regionnear N,O,S,halogen"olefin" region

"aromatic" (benzene) regionaldehydes

acids

Common NMR Shifts

O

OH3CCH3

O

H3C OCH3

1H NMR of Methyl Acetate

1H NMR of Neopentyl Bromide

1H NMR of Neopentyl Bromide

O

OH3CCH2

CH3

3

2

3

1H NMR of Ethyl Acetate

What are these strange signals?

Integral ratios

Hydrogen nuclei will couple to each other if:

•They are not chemically equivalent

•They are 2 or 3 bonds apart

•Double bonds can cause coupling through 4 bonds

H

H H

H

H H

2 bonds 3 bonds 4 bonds

coupling coupling no coupling

Proton Coupling

Me O CH3

O H HThese 3 hydrogens are identical - 1 signal

These 2 hydrogens will couple to the methyl group

B0

Add to Beff

Identical, no effect on Beff

Subtract from Beff

Higher Beff Lower Beff

Split

CH3 CH3

Proton Coupling

Me O CH3

O H H

These 2 hydrogens are identical - 1 signal

These 3 hydrogens will couple to the methylene group

B0

Add to Beff

Subtract from Beff

Split

CH2Add to Beff

Subtract from Beff

CH2

Proton Coupling

O

OH3CCH2

CH3

3

2

3

1H NMR of Ethyl Acetate

Multiplicity

Determining Hydrogen Atom Relationships

•If the structures are identical – Homotopic (no coupling)

•If the structures are enantiomers – Enantiotopic (no coupling)

•If the structures are diastereomers – Diastereotopic (coupling is possible)

The Substitution Test: For any pair of H’s, substitute each separately with an X and compare the two structures.

H

HClCl

X

HClCl

H

XClCl

identical = homotopic

H

HClMe

X

HClMe

H

XClMe

enantiomers = enantiotopic

H

XClMe

H

XClMe

Determining Hydrogen Atom Relationships

MeMe

HO H

H H

MeMe

HO H

X H

MeMe

HO H

H X

diastereomers = diastereotopic

diastereomers = diastereotopicMe Me

HH

Me Me

HX

Me Me

XH

Determining Hydrogen Atom Relationships

The coupling constant (J) is the distance between two adjacent peaks of a split NMR signal in hertz (Hz)

Coupled protons have the same coupling constant

Coupling Constants

HH

H

H

H

H

6-12 Hz0-3 Hz 12-18 Hz

H

H

H

H

1-3 Hz6-8 Hz 0-1 Hz

(usually not observed)

H

H

Useful Coupling Constants

Olefin Geometry Through Coupling Constants

A Splitting Diagram for a Doublet of Doublets

A Quartet Vs. A Doublet Of Doublets

Dry, ultra-pure ethanol

Ethanol with trace acid

Coupling With “Exchangeable” Protons

Molecular Ion = 74 [C4H10O]

Four Different (But Similar) Compounds

1

9

Unknown #1

1

2

1

6

Unknown #2

2 1

3

4

Unknown #3

1

1

8

Unknown #4

86

89 (5%)

Putting It All Together - Identifying Unknown Compounds

Putting It All Together - Identifying Unknown Compounds

1

36

Putting It All Together - Identifying Unknown Compounds