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3.205 L3 11/2/06
Solutions to the Diffusion Equation
1
Solutions to Fick’s Laws
Fick’s second law, isotropic one-dimensionaldiffusion, D independent of concentration
!
"c
"t= D
"2c
"x2
Linear PDE; solution requires one initialcondition and two boundary conditions.
23.205 L3 11/2/06
Figure removed due to copyright restrictions.See Figure 4.1 in Balluffi, Robert W., Samuel M. Allen, and W. Craig Carter.Kinetics of Materials. Hoboken, NJ: J. Wiley & Sons, 2005. ISBN: 0471246891.
Steady-State Diffusion
When the concentration field is independent of time and D is independent of c, Fick’
!
"2c = 0
s second law is reduced to Laplace’s equation,
For simple geometries, such as permeation through a thin membrane, Laplace’s equation can be solved by integration.
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Examples of steady-state profiles
(a) Diffusion through a flat plate
(b) Diffusion through a cylindrical shell
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Figure removed due to copyright restrictions.See Figure 5.1 in Balluffi, Robert W., Samuel M. Allen, and W. Craig Carter.Kinetics of Materials. Hoboken, NJ: J. Wiley & Sons, 2005. ISBN: 0471246891.
Figure removed due to copyright restrictions.See Figure 5.2 in Balluffi, Robert W., Samuel M. Allen, and W. Craig Carter.Kinetics of Materials. Hoboken, NJ: J. Wiley & Sons, 2005. ISBN: 0471246891.
Error function solution…
Interdiffusion in two semi-infinite bodies
Solution can be obtained by a “scaling” method that involves a single variable,
!
" # x 4Dt
!
c "( ) = cx
4Dt
#
$ %
&
' ( = c +
)c
2erf
x
4Dt
#
$ %
&
' (
53.205 L3 11/2/06
Figure removed due to copyright restrictions.See Figure 4.2 in Balluffi, Robert W., Samuel M. Allen, and W. Craig Carter.Kinetics of Materials. Hoboken, NJ: J. Wiley & Sons, 2005. ISBN: 0471246891.
erf (x) is known as the error function and is defined by
!
erf x( ) "2
#e$% 2
d%0
x
&
An example:
!
c x < 0,0( ) = 0;c x > 0,0( ) =1;c "#,t( ) = 0; c #,t( ) =1; D =10"16
t = 102, 103, 104, 105
Application to problems with fixed c at surface
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Movie showing time dependence of erf solution…
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Superposition of solutions
When the diffusion equation is linear, sums of solutions are also solutions. Here is an example that uses superposition of error-function solutions:
Two step functions, properly positioned, can be summed to give a solution for finite layer placed between two semi-infinite bodies.
83.205 L3 11/2/06
Figure removed due to copyright restrictions.See Figure 4.4 in Balluffi, Robert W., Samuel M. Allen, and W. Craig Carter.Kinetics of Materials. Hoboken, NJ: J. Wiley & Sons, 2005. ISBN: 0471246891.
Superposed error functions, cont’d
The two step functions (moved left/right by Δx/2):
!
cleft =c0
21+ erf
x+"x 2
4Dt
#
$ %
&
' (
)
* + ,
- .
cright = /c0
21+ erf
x /"x 2
4Dt
#
$ %
&
' (
)
* + ,
- .
and their sum
!
clayer =c0
2erf
x+"x 2
4Dt
#
$ %
&
' ( ) erf
x )"x 2
4Dt
#
$ %
&
' (
*
+ , -
. /
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Superposed error functions, cont’d
An example:
!
c "#,t( ) = 0; c #,t( ) = 0; c x $ "%x / 2,0( ) = 0;c "%x / 2 < x < %x / 2( ) =1;
c x & %x / 2,0( ) = 0;%x = 2'10"6;D =10"16
t = 101, 103, 104, 105
Application to problems with zero-flux planeat surface x = 0
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Movie showing time dependence of superimposed erf solutions…
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The “thin-film” solution The “thin-film” solution can be obtained from the
previous example by looking at the case where Δx is very small compared to the diffusion distance, x, and the thin film is initially located at x = 0:
!
c x,t( ) =N
4"Dte#x
24Dt( )
where N is the number of “source” atoms per unit area initially placed at x = 0.
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Diffusion in finite geometries
Time-dependent diffusion in finite bodies can soften be solved using the separation of variables technique, which in cartesian coordinates leads to trigonometric-series solutions.
A solution of the form
!
c x, y, z, t( ) = X x( ) "Y y( ) "Z z( ) "T t( )
is sought.
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Substitution into Fick’s second law gives two ordinary-differential equations for one-dimensional diffusion:
!
dT
dt= "#DT
d2X
dx2
= "#X
where λ is a constant determined from the boundary conditions.
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Example: degassing a thin plate in a vacuum
!
c 0 < x < L,0( ) = c0; c 0,t( ) = c L,t( ) = 0
The function X(x) turns out to be the Fourier series representation of the initial condition—in this case, it is a Fourier sine-series representation of a constant, c0:
with
!
Xnx( ) = a
nsin n"
x
L
#
$ %
&
' (
n=1
)
*
!
an =2c0
Lsin n"
#
L
$
% &
'
( )
0
L
* d#
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degassing a thin plate, cont’d
The function T(t) must have the form:
!
Tnt( ) =T
n
°exp "
n2# 2
L2Dt
$
% &
'
( )
and thus the solution is given by KoM Eq. 5.47:
!
c x,t( ) =4c0"
1
2 j +1sin 2 j +1( )"
x
L
#
$ % &
' ( exp )
2 j +1( )2" 2
L2
Dt#
$ %
&
' (
*
+ , ,
-
. / /
j=0
0
1
163.205 L3 11/2/06
degassing a thin plate, cont’d
Example:
!
c 0,t( ) = 0; c L,t( ) = 0; c 0 < x < L,0( ) =1
L =10"5;D =10"16
173.205 L3 11/2/06
Other useful solution methods
Estimation of diffusion distance from
!
x " 4Dt
Superposition of point-source solutions to get solutions for arbitrary initial conditions c(x,0)
Method of Laplace transforms Useful for constant-flux boundary conditions, time-dependent boundary conditions
Numerical methods Useful for complex geometries, D = D(c), time-dependent boundary conditions, etc.
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