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SOLUTION EXAMPLE 2 Using Congruent Polygons JKL TSR . = Find m S. Corresponding angles are congruent. 31 + m K + 25 = 180 K and S are corresponding angles, so they have the same measure. Find m K. Sum of angle measures is 180 . Add. = 180 m K + 56 m K + 56 – 56 = 180 – 56 Subtract 56 from each side. m K = 124 Simplify.

SOLUTION

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JKL. TSR. Find m S. =. K and S are corresponding angles, so they have the same measure. Find m K. 180. Sum of angle measures is 180. 31 + m K + 25. =. m K + 56. 180. =. m K + 56 – 56. 180 – 56. =. 124. m K. =. EXAMPLE 2. Using Congruent Polygons. SOLUTION. - PowerPoint PPT Presentation

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Page 1: SOLUTION

SOLUTION

EXAMPLE 2 Using Congruent Polygons

JKL TSR .= Find m S.

Corresponding angles are congruent.

31 + m K + 25 = 180

K and S are corresponding angles, so they have the same measure. Find m K.

Sum of angle measures is 180 .

Add.= 180 m K + 56

m K + 56 – 56 = 180 – 56 Subtract 56 from each side.

m K = 124 Simplify.

Page 2: SOLUTION

EXAMPLE 2 Using Congruent Polygons

ANSWER

Because m K = m S, m S = 124

Page 3: SOLUTION

GUIDED PRACTICE for Example 2

Find the value using the triangles in Example 2.

2. length of ST

KJ ST = 10 cm

ANSWER

Page 4: SOLUTION

GUIDED PRACTICE for Example 2

Find the value using the triangles in Example 2.

3. m T

m S = m T = 31

ANSWER

Page 5: SOLUTION

GUIDED PRACTICE for Example 2

Find the value using the triangles in Example 2.

4. m R

m R = 25

ANSWER