shear strength in soils

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    CE 240

    Soil Mechanics & FoundationsLecture 11.1

    Shear Strength of Soil I

    (Das, Ch. 11)

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    Shear strength in soils Introduction

    Definitions

    Mohr-Coulomb criterion

    Introduction

    Lab tests for getting the shear strength

    Direct shear test

    Introduction Procedure & calculation

    Critical void ratio

    Class Outlines

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    Shear Strength The strength of a material is the

    greatest stress it can sustain;

    So that the unit of strength is the same

    as stress (Pa in SI unit system);

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    Significance of Shear Strength

    The safety of any geotechnical structureis dependent on the strength of the soil;

    If the soil fails, the structure founded onit can collapse.

    Understanding shear strength is thebasis to analyze soil stability problemslike:

    lateral pressure on earth retainingstructures (Chs. 12, 13),

    slope stability (Ch. 14), and

    bearing capacity (Ch. 15).

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    Shear Failure in Soils

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    Slope Failure in Soils

    Failure due to inadequatestrength at shear interface

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    Static: Transcosna Grain Elevator

    Canada (Oct. 18, 1913)

    West side of foundation sank 24-ft

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    Bearing Capacity Failure

    D i F d ti f il b li f ti

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    Dynamic: Foundation failure by liquefaction

    after the 1964 Niigata Earthquake. (USGS)

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    Dynamic: Lateral Spreading caused by the 1906 San

    Francisco Earthquake at Moss Landing, CA

    (USGS Professional Paper 993)

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    Shear Strength in Soils

    The shear strength of a soil is its resistance toshearing stresses.

    It is a measure of the soil resistance to

    deformation by continuous displacement of itsindividual soil particles

    Shear strength in soils depends primarily on

    interactions between particles Shear failure occurs when the stresses between

    the particles are such that they slide or roll past

    each other

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    Shear Strength in Soils

    (cont.) Soil derives its shear strength from two

    sources: Cohesion between particles (stress

    independent component)

    Cementation between sand grains

    Electrostatic attraction between clay particles

    Frictional resistance between particles (stressdependent component)

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    Shear Strength of Soils: Cohesion

    Cohesion (C), is a measure of the forces thatcement particles of soils

    Dry sand with no cementation

    Dry sand with some cementation Soft clay

    Stiff clay

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    Shear Strength of Soils; Internal

    Friction Internal Friction angle (), is the measure of the

    shear strength of soils due to friction

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    Mohr-Coulomb Failure Criteria

    This theory states that a material fails

    because of a critical combination ofnormal stress and shear stress, and not

    from their either maximum normal orshear stress alone.

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    Mohr-Coulomb Failure

    Criterion

    ShearStrength,S

    =

    C

    Normal Stress, n = = h

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    ' '

    tan (11.2)

    tan ' (11.3)

    f n n

    f n n

    c c

    c c

    = + = +

    = + = +

    f

    whereshear strength

    c = cohesion; c =effective cohesion

    = angle of internal friction; = effective angle of internal friction

    = coefficient of friction; ' = effective coefficient of frictio

    =

    n.

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    =tan

    0.51-0.58

    0.58-0.70

    0.70-0.78

    0.58-0.700.70-0.84

    0.84-1.00

    0.67-1.110.49-0.70

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    Mohr-Coulomb shear failure criterion

    1

    1

    33n

    f

    1

    3

    2

    f=c+

    n

    c

    Failed Zone

    (, )

    ff

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    From trigonometric equalities we have

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    Way 1: Increase the normal

    stress in one direction

    1

    1 major principle stress

    n

    f3 3

    Minor principle stress

    Confining stress

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    Way 2: directly apply the shear stress

    Consider the following situation:

    - A normal stress is appliedvertically and held constant- A shear stress is then applied

    until failureShear

    stress

    Normal stress n

    Normal stress n

    D t i ti f Sh St th P t

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    Determination of Shear Strength Parameters

    The shear strength parameters of a soil aredetermined in the lab primarily with two types

    of tests: 1) Direct Shear Test; and 2) Triaxial

    Shear Test.(1) (2)

    Soil

    Normal stress n

    Shear stress 3

    3

    1

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    Direct Shear Test

    Direct shear test is Quick and Inexpensive

    Shortcoming is that it fails the soil on adesignated plane which may not be theweakest one

    Used to determine the shear strength ofboth cohesive as well as non-cohesive

    soils

    ASTM D 3080

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    Direct Shear Test (cont.)

    The test equipment consistsof a metal box in which thesoil specimen is placed

    The box is split horizontallyinto two halves

    Vertical force (normalstress) is applied through ametal platen

    Shear force is applied bymoving one half of the boxrelative to the other tocause failure in the soilspecimen

    Soil

    Normal stress n

    Shear stress 3

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    Direct Shear Test

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    Direct Shear Test

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    Direct Shear Test

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    Direct Shear Test Data

    Shearstress

    Residual Strength

    Peak Strength

    Direct Shear Test Data:

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    Direct Shear Test Data:

    Volume change

    H

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    Direct Shear Test: Procedure

    1.Measure inner side or diameter of shear box and find thearea

    2.Make sure top and bottom halves of shear box are in

    contact and fixed together.3.Weigh out 150 g of sand.

    4.Place the soil in three layers in the mold using the funnel.

    Compact the soil with 20 blows per layer.5.Place cover on top of sand

    6.Place shear box in machine.

    7.Apply normal force. The weights to use for the three runsare2 kg, 4 kg, and 6 kg if the load is applied through a lever arm,or 10 kg, 20 kg, and 30 kg, if the load is applied directly.

    Note: Lever arm loading ratio 1:10 (2kg weight = 20 kg)

    Direct Shear Test: Procedure

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    Direct Shear Test: Procedure

    8. Start the motor with selected speed (0.1 in/min) so thatthe rate of shearing is at a selected constant rate

    9. Take the horizontal displacement gauge, verticaldisplacement gage and shear load gage readings.

    Record the readings on the data sheet.

    10. Continue taking readings until the horizontal shear loadpeaks and then falls, or the horizontal displacement

    reaches 15% of the diameter.

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    Calculations

    1. Determine the dry

    unit weight, d

    2. Calculate the void

    ratio, e

    3. Calculate the normal

    stress & shearstress

    1=d

    wGse

    A

    V

    A

    N== ;

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    Figures

    Peak Stress

    s3

    s2

    s1

    Shear

    stress,s

    N3 = 30 kg

    N2 = 20 kg

    N1 = 10 kg

    Horizontal displacement, H

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    Figures (cont)

    S

    hear

    Stres

    s,s

    (psf)

    C

    (1,s1)

    (3,s3)(2,s2)

    Normal Stress , psf

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    Figures (cont)

    Verticaldisplacemen

    t

    Horizontal displacement

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    Reading Assignment:

    Das, Ch. 11

    HW: Problem 11.1