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Section 7.3 – Using Chemical Formulas They allow chemists to calculate a number of characteristic values for a given compound.

Section 7.3 – Using Chemical Formulas

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Section 7.3 – Using Chemical Formulas. They allow chemists to calculate a number of characteristic values for a given compound. Formula Mass. - PowerPoint PPT Presentation

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Page 1: Section 7.3 – Using Chemical Formulas

Section 7.3 – Using Chemical Formulas

They allow chemists to calculate a number of characteristic values for a given compound.

Page 2: Section 7.3 – Using Chemical Formulas

Formula Mass

Like individual atoms, the formula mass of any molecule, formula unit, or ion is the sum of the average atomic masses of all the atoms represented in its formula. Reported in amu (atomic mass units).

Page 3: Section 7.3 – Using Chemical Formulas

Example – Water (H2O)

1 H atom = 1.0079 amu 1 O atom = 15.9994 amu 1 water molecule =

(2 x 1.0079) + (1 x 15.9994)

= 18.0152 amu/molecule

Page 4: Section 7.3 – Using Chemical Formulas

Remember The Mole?

The mass of 6.022 x 1023 particles.

Page 5: Section 7.3 – Using Chemical Formulas

Molar Mass

Calculated by summing the masses of the elements present in a mole (6.022 x 1023 particles) of the molecules, formula units, or ions of a compound. Reported in grams.

Page 6: Section 7.3 – Using Chemical Formulas

Example – Water (H2O)

1 mole H atoms = 1.0079 grams

1 mole O atoms = 15.9994 grams

1 mole water molecules =

(2 x 1.0079) + (1 x 15.9994)

= 18.0152 g/mole H2O

Page 7: Section 7.3 – Using Chemical Formulas

Notice

The molar mass and the formula mass are numerically equal; one is reported in amu, the other in grams.

Page 8: Section 7.3 – Using Chemical Formulas

EXAMPLE

Find the formula mass for KClO3

Find the formula mass for Ca(NO3)2

Find the molar mass for Al2S

Find the molar mass for Ba(OH)2

Page 9: Section 7.3 – Using Chemical Formulas

Molar Mass As A Conversion Factor

See p. 224 To convert moles to

grams:# mol x g/mol = g To convert mass to

moles:grams x 1/molar mass

= moles

Page 10: Section 7.3 – Using Chemical Formulas

EXAMPLES

What is the mass in grams of 2.50 mol of oxygen gas (O2)?

How many moles of compound are there in 6.60g (NH4)2SO4

How many molecules are there in 25.0g of H2SO4?

Page 11: Section 7.3 – Using Chemical Formulas

Percentage Composition

Often useful to know this, it is the percentage by mass of each element in a compound. There are two ways to determine it:

Page 12: Section 7.3 – Using Chemical Formulas

By Mass

Mass of element in a sample divided by the mass of the sample multiplied by 100. The percentage will be the same regardless of the sample size.

Page 13: Section 7.3 – Using Chemical Formulas

Or By Moles (Easier)

Mass of the element in 1 mol divided by the molar mass of the compound multiplied by 100.

Page 14: Section 7.3 – Using Chemical Formulas

EXAMPLES

Find the percentage compositions of:– PbCl2 Ba(NO3)2

– Magnesium Hydroxide is 54.87% oxygen by mass. How many grams of oxygen are in 175 g of the compound. How many moles of oxygen is this?

Page 15: Section 7.3 – Using Chemical Formulas

Info. You Will Need For Later

Hydrates are salts that crystallize from a water solution and trap water (known as water of hydration) in the crystal structure.

Page 16: Section 7.3 – Using Chemical Formulas

Na2CO3•10H2O

This means that 10 moles of water are trapped within each mole of the sodium carbonate salt.

Page 17: Section 7.3 – Using Chemical Formulas

Assignment – Due Friday

7.3 Worksheet 7.3 Textbook

Problems