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SCHOLASTIC APTITUDE TEST (SAT)
PREP
PRACTICE PROBLEMS
VERSION 4
QUANTITATIVE COMPARISON QUESTIONS
SAT
12 > 8
A Column A >
Column A Column B Answers
3 x 4 3 + 5 A B C D E
EXAMPLE
Compare the values shown in each column. Select among these choices:
A If Column A is greater
B If Column B is greater
C If Columns are equal
DIf more information is needed to determine relationship
E An E response will be treated as an omission
SAT
10 + 8 80
A Column A >
Column A Column B Answers
1 + 1 8 10
1 + 1 9 11 A B C D E
1.
11 + 9 99
18 80
20 99
22.5 % 22.2 %
SAT
1 2
D Neither Column >
Column A Column B Answers
x 1x A B C D E
2.
2 1
x < 1
– 1 2
– 2 1
SAT
34X .5217.68
A Column A >
Column A Column B Answers
52 % of 34 17 A B C D E
3.
17
SAT
3 x – 6
B Column B >
Column A Column B Answers
3 ( x – 2 ) 3 x – 4 A B C D E
4.
3 x – 4
SAT
6
B Column B >
Column A Column B Answers
6 The sum of the integers A B C D E
5.
11 or 7
The product of two integers is 10.
10 • 1 or 5 • 2
–10 • –1 or –5 • –2
– 11 or –7
D Neither Column is >
SAT
22
32
B Column B >
Column A Column B Answers
x2
y2 x2 y2 A B C D E
6.
22 32
x and y are nonzero integers.
49
36
1 2
2
1 2
3
94
136
1 2 • 1 2 2 3
D Neither Column is >
SAT
34X .5217.68
D Neither Column is >
Column A Column B Answers
AB BC A B C D E
7.
17
• •• •A B C D
SAT
12
B Column B >
Column A Column B Answers
x xy A B C D E
8.
1 • 2 2 1
x > 0y > 1
12
11
SAT
X 5
B Column B >
Column A Column B Answers
X 5 (x3) 2 A B C D E
9.
X 6
x > 1
SAT
1y
D Neither Column is >
Column A Column B Answers
1y
y2
yA B C D E
10.
y1
y ≠ 0
SAT
A = s 2 = 6 2 = 36
C Column are =
Column A Column B Answers
The number of square units in the area of a
square with side 6
The number of units in the perimeter of a square
with side 9A B C D E
11.
P = 4 s = 4 • 9 = 36
SAT
93
A Column A is >
Column A Column B Answers
Bill’s mode test score Bill’s median test score A B C D E
12.
91.5
Bill’s math test scores are the following:88 , 82,94, 93, 85, 90, 93, 98
SAT
A = r 2
A Column A is >
Column A Column B Answers
The area of the circle The area of the rectangle A B C D E
13.
A = l • w
3
A = 3 2
A = 9
A = 9 • 3
A = 27
3
9
SAT
y
D Neither Column is >
Column A Column B Answers
1 – y 1 + y
1 – 1 1 + y A B C D E
14.
1
y > 0
SAT
P = 2 x + 2 y = 32Or
x + y = 16
B Column B is >
Column A Column B Answers
The area of ABCD The area of a square with perimeter 32 A B C D E
15.
Square with Perimeter = 4s = 32 s = 8
A = 8 2 = 64
ABCD is a rectangle with perimeter 32.AB > BC
A = x • y15 • 1 = 15 , 14 • 2 = 28, 13 • 3 = 39, 12 • 4 = 48, 11 • 5 = 55, 10 • 6 = 60, 9 • 7 = 63
PRACTICE PROBLEMS
VERSION 4
STUDENT – PRODUCED RESPONSE QUESTIONS
16. In this figure, if line p is parallel to line q, what is the value of y?
180⁰ – 65⁰ = 115⁰
115⁰ = y⁰
Corresponding <‘s
SAT
65⁰
y⁰
p
q
r
65⁰
17. What is ¼ percent of 16 ?
x = 1 % • 16 4x = 1 1 • 16 4 100
x = 16 = 1 = .04 400 25
SAT
18. Each of these fractions is in its simplest form reduced form and a is an integer greater than 1 and less than 50. Grid in one possible value of a?
3 , 5 , 14a a a
To be in simplest form “a” would have to be a number that has no prime factors in common with 3, 5, 14
11, 13, 17, 19, 23, 29, 31, 37, 41, 43 and 47
SAT
19. If there are 36 men and 24 women in a group, women make up what fraction of the entire group?
36 + 24 = 60 [total]
24 = 260 5
SAT
20. What is the value of 3 x + 5 when x = 9 ? 4
3 x + 5 = 3 (9) + 5 = 32 = 8 4 4 4
SAT
21. If the positive integer x leaves a remainder of 2 when divided by 6, what will the remainder of be when x + 8 is divided by 6 ?
x = # + 2 R6
8 = 1 + 2 R6
14 = 2 + 2 R 6
20 = 3 + 2 R 6
SAT
x + 8 = # + ? R 6
8 + 8 = 2 + 4 R 6
14 + 8 = 3 + 4 R 6
20 + 8 = 4 + 4 R 6
22. Jim deposited 15% of last week’s take-home pay into a savings account. If he deposited $ 37.50, what was last week’s take-home pay?
.15 = 137.50 x
.15 x = 37.50
x = 37.50 = 250 .15
SAT
23. What is the area of the triangle in this figure ?
SAT
•
• •
( 2 , 3 )
( 4 , 0 )( –2 , 0 )
Area of Triangle = 1/2 b • h
A = 1/2 ( 6 ) • ( 3 )
A = 9
24. A square is divided in half to form two congruent rectangles, each with a perimeter 25. What is the area of the original square ?
A = x 2
SAT
x
x
x
½ x
½ x
24 = 2 x + 2 (½ x)
24 = 2 x + 2 (½ x)24 = 2 x + x24 = 3 x8 = x
A = 8 2 = 64