Root Locus

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  • The root locus is the path of the closed-loop poles of a system as a parameter of the system is varied. Each point on the root locus satisfies the angle condition, += 180)12()()( ksHsG . Using this relationship, rules for sketching and finding points on the root locus were developed and are now summarized:

    Basic rule for sketching the root locus: 1. Number of branches The number of branches of the root locus equals the number of closed-loop poles.

    2. Symmetry The root locus is symmetrical about the real axis.

    3. Real-axis segments On the real axis, for 0>K the root locus exists to the left of an odd number of real-axis, finite open-loop poles and/or finite open-loop zeros.

    4. Starting and ending points The root locus begins at the finite and infinite poles of )()( sHsG and ends at the finite and infinite zeros of )()( sHsG .

    5. Behavior at infinity The root locus approaches straight lines as asymptotes as the locus approaches infinity. Further, the equations of the asymptotes are given by the real-axis intercept and angle in radians as follows:

    zeros finite#poles finite#)12(

    zeros finite#poles finite#zeros finitepoles finite

    +=

    =

    pi

    ka

    a

    6. Real axis breakaway and break-in points The root locus breaks away for the real axis at a point where the gain is maximum and breaks in to the real axis at a point where the gain is minimum.

    7. Calculation of j axis crossings The root locus crosses the j - axis at the point where += 180)12()()( ksHsG . Routh-Hurwitz or a search of the j - axis for + 180)12( k can be used to find the j - axis crossing.

    8. Angles of departure and arrival The root locus departs from complex, open-loop poles and arrives at complex, open-loop zeros at angles that can be calculated as follows. Assume a point close to the complex pole or zero. Add all angles drawn from all open-loop poles

    and zeros to this point. The sum equals + 180)12( k . The only unknown angle is that drawn from the close pole or zero, since the vectors drawn from

    all other poles and zeros can be considered drawn to the complex pole or zero that is close to the point. Solving for the unknown angle yields the angle of departure or arrival.

    9. Plotting and calibrating the root locus All points on the root locus satisfy the relationship += 180)12()()( ksHsG . The gain, K , at any point on the root locus is given by

    lengths zero finitelengths pole finite1

    )()(1

    ===

    MsHsGK

  • Sketching a root locus and finding critical points Problem 1: page 397 example 8.7 Sketch the root locus for the system shown in Figure 8.19(a)

    )(sR

    )4)(2()204( 2

    ++

    +

    ss

    ssK)(sC

    Closed-loop transfer function,

    )208()46()1()204(

    )204()4)(2()204(

    )4)(2()204(1

    )4)(2()204(

    )(2

    2

    2

    2

    2

    2

    KsKsKssK

    ssKssssK

    ss

    ssKss

    ssK

    sT

    ++++

    +=

    ++++

    +=

    ++

    ++

    ++

    +

    = .

    Open-loop transfer function, )4)(2/()204()()( 2 +++= ssssKsHsKG . The system has finite zeros; 42 j The poles are located on the s-plane at 4,2 .A segment of the root locus exists on the real axis between 42 and .

    Number of asymptotes = 0.

    The break-away point is estimated by evaluating )204()86(

    )204()4)(2(

    2

    2

    2 +

    ++=

    +

    ++=

    ss

    ss

    ss

    ssK , between 4=s and 2=s .

    Differentiating K with respect to s, and settling the derivative equal to zero yields,

    01522410

    0)204()42)(86()62)(204(

    42/)204(62/86

    )204()86(

    2

    2

    22

    2

    2

    2

    2

    =

    =

    +

    +=

    =+=

    ==

    +

    ++=

    ss

    ss

    ssssss

    dsdK

    sdsdvssvsdsdussu

    ss

    ssK

    Solving for s, we find [email protected])10(2)152)(10(42424

    24

    ,

    22

    21 =

    =

    =

    a

    acbbss

    The characteristic equation is 0)208()46()1( 2 =++++ KsKsK . Therefore, the Routh table 2s K+1 K208 + 0 1s K46 0 0 0s ( )[ ] ( ) KKKK 20846/)208(46 +=+ 0 0

    From row 1s , 5.1K-6,4K-,046 > K . Hence, the limiting value of gain for stability is 5.1=K , and the roots of the auxiliary equation are, (from row 2s ): 899.32.15,,0832.5s 212 jss ===+ .