Question 1

No Mark Scheme Score

KB0603 – Measuring Using Number

1 (a) Able to record all 6 readings for the number of tortoises in the second captured and the number of tortoises marked in the second capture. Sample answer:

Area for tortoises captured

Kawasan kura-kura ditangkap

Number of tortoises in the second capture / unit

Bilangan kura-kura dalam tangkapan kedua

Number of tortoises marked in the second

capture / unit Bilangan kura-kura

yang bertanda dalam tangkapan kedua

Riverside

Persisiran sungai

20 15

Mangrove swamp side

Persisiran paya bakau

18 17

Lakeside Persisiran tasik

19 16

3

Able to list 5 - 3 readings correctly 2

Able to list 2 - 1 readings correctly 1

No response or incorrect response 0

KB0601 - Observation

1 (b) (i) Able to state two different observations based on the following criteria: [Observation must have values / type for MV and RV from Table 2 or comparison between two readings] MV: Area for tortoise capture Kawasan kura-kura ditangkap RV: Number of tortoise in second capture / Number of tortoises marked in the second captured Bilangan kura-kura dalam tangkapan kedua / Bilangan kura- kura yang bertanda dalam tangkapan kedua Sample answers: 1. If the tortoise caught from riverside, the number of tortoise in the second captured is 20 units / number of tortoises marked in the second captured is 15 units. Jika kura-kura ditangkap daripada persisiran sungai, bilangan kura-kura dalam tangkapan kedua ialah 20 / bilangan kura-kura dalam tangkapan kedua yang bertanda ialah 15 2. If the tortoise caught from lakeside, the number of tortoise in the second captured is 19 units / number of tortoises marked in the second captured is 16 units. Jika kura-kura ditangkap daripada persisiran tasik, bilangan kura-kura dalam tangkapan kedua ialah 19 / bilangan kura-kura dalam tangkapan kedua yang bertanda ialah 16

3

Able to state one observation correctly and one-two inaccurate observations. Sample answers: 1. If the tortoise caught from riverside, the number of tortoise marked in the

second captured higher // inversely. Jika kura-kura ditangkap daripada persisiran sungai, bilangan kura ditangkap adalah lebih tinggi

2. The number of tortoise captured in the second capture influenced by the area for tortoise captured / catchment area. Bilangan kura-kura ditangkap dalam tangkapan kedua dipengaruhi oleh kawasan kura-kura ditangkap.

2

Able to state one correct observation Or Able to state two different observations at idea level. Sample answers: 1. The number of tortoise captured in the second capture // marked in second

captured is different. Bilangan kura-kura ditangkap dalam tangkapan kedua adalah berbeza

1

No response or wrong response 0

KB0604 - Making inference

1(b)(ii) Able to make two inferences correctly. Note: Inference must match observation. P1: Food source from catchment area // Temperature of catchment area // Humidity Sumber makanan daripada kawasan tangkapan / Suhu kawasan tangkapan // Kelembapan P2: Population size of tortoise. Populasi saiz kura-kura Sample answers: 1. More food source at riverside // Low temperature // high humidity, more

population size of tortoise. Lebih banyak sumber makanan di persisiran sungai // suhu rendah // kelembapan tinggi, lebih besar saiz populasi.

2. Less food source at lakeside, less population size of tortoise. Kurang sumber makanan di persisiran tasik // suhu tinggi, lebih kecil saiz populasi.

3

Able to make one correct inferences and one inaccurate inference inaccurately. Sample answers: 1. More food source at river.

Lebih makanan di persisiran sungai 2. Less population of tortoise at lakeside.

Kurang populasi kura-kura di persisiran tasik.

2

Able to state one correct inference and one-two inference at idea level. Sample answers: 1. Different population of tortoise.

Populasi kura-kura berbeza 2. Population of tortoise depends on catchment area.

Populasi kura-kura bergantung kepada kawasan tangkapan.

1

No response OR wrong response 0

Scoring

Score Correct Inaccurate Idea Wrong

3 2 - - -

2 1 1 - - - 2 - -

1

1 - 1 - - - 2 - - 1 1 - 1 - - 1

0 - 1 - 1 - - 1 1

KB0610 - Controlling variables

1(c) Able to state all 3 variables and the methods to handle the variable correctly. Sample answers:

Variables Method to handle the variable correctly Manipulated variable: Capture area for tortoise Kawasan tangkapan kura-kura

Use different area to catch tortoise // Menggunkan kawasan tangkapan kura-kura yng berbeza Catch tortoise from riverside, mangrove swamp side and lakeside Menangkap kura-kura daripada kawasan persisiran sungai, persisiran paya bakau dan persisiran tasik

Responding variable: 1. Number of tortoise in

second captured // Number of marked tortoise in second captured Bilangan kura-kura dalam tangkapan pertama // Bilangan kura-kura yang bertanda dalam tangkapan pertama

2. Population (size) of tortoise Saiz populasi kura-kura

Count and record the number of tortoise in second captured // number of marked tortoise in second captured Mengira dan merekod bilangan kura-kura dalam tangkapan kedua // bilangan kura-kura yang bertanda dalam tangkapan kedua Calculate population size of tortoise using formula = No.of tortoise in the 1st capture X No.of tortoise in the 2ndcapture

Number of marked tortoise in the second captured

Mengira saiz populasi kura-kura mengunakan formula = Bil. Kura2 dlm tangkapan per1 X Bil. Kura2 dlm tangkapan ke2

Bilangan kura-kura yang bertanda dalam tangkapan kedua

3

Constant variable 1. Number of tortoise in

the first captured. Bilangan kura-kura dalam tangkapan pertama

2. Type of tortoise. Jenis kura-kura

3. Day for recaptured. Hari untuk tangkap semula

1. Same number of tortoise catch in the first

captured is 25. Bilangan kura-kura dalam tangkapan pertama ialah 25.

2. Catch the same type of tortoise. Menangkap jenis kura-kura yang sama iaitu kura-kura Dura

3. The tortoise is recaptured after seven days released. Tangkap semula kura-kura selepas tujuh hari

6 ticks

4 - 5 ticks 2

1 - 3 ticks 1

0 tick 0

KB0611 - Making hypothesis

1 (d) Able to state hypothesis following all criteria. P1: Manipulated variable (Catchment area) Kawasan tangkapan P2: Responding variable (Number of tortoise marked in second capture // Population size of tortoise) Bilangan kura-kura yang bertanda dalam tangkapan kedua // Saiz populasi kura-kura P3: Relationship Sample answers: 1. The number of tortoise marked in the second captured from riverside is

higher than mangrove swamp side and lakeside / vice versa. Bilangan kura-kura yang bertanda dalam tangkapan kedua daripada persisiran sungai adalah lebih tinggi berbanding persisiran paya bakau dan persisiran tasik / dan sebaliknya

2. The population size of tortoise at the riverside is higher than from mangrove swamp side and lakeside / vice versa. Saiz populasi kura-kura di persisiran sungai adalah lebih tinggi berbanding persisiran paya bakau dan persisiran tasik / dan sebaliknya

3

Able to make a hypothesis relating the manipulated variable and the responding variable inaccurately. Sample answers: 1. Number of tortoises marked in the second capture depends on the catchment

area. Bilangan kura-kura yang bertanda dalam tangkapan kedua bergantung kepada kawasan tangkapan

2

Able to make a hypothesis at idea level. Sample answers: 1. Different area causes different tortoises

Kawasan yang berbeza menyebabkan kura-kura yang berbeza 2. Area affects / influence number of tortoises.

Kawasan mempengaruhi bilangan kura-kura

1

No response or incorrect response P3 is not given if there is no P1 or P2

0

KB0606 – Communication

1 (e)(i) Able to construct a table correctly based on the following aspects: (T): The titles with units correctly. (D): All the data Number of tortoises in first, second and mark in the second captured. Bilangan kura-kura dalam tangkapan pertama, kedua dan bertanda dalam tangkapan kedua. (C): Population size of the tortoises. Saiz populasi kura-kura Sample answer:

REJECT (C) if reading in decimals.

Catchment area of the

tortoise Kawasan

tangkapan kura-kura

Number of tortoises in

the first captured

(unit) Bilangan kura-kura

dalam tangkapan pertama

(unit)

Number of tortoises in the second

capture (unit) Bilangan kura-kura

dalam tangkapan

kedua (unit)

Number of marked

tortoises in the second

capture (unit) Bilangan kura-kura

yang bertanda dalam

tangkapan kedua (unit)

Population size of

tortoises (unit) Saiz

populasi kura-kura

(unit)

Riverside Persisiran

sungai

25 20 15 33

Mangrove swamp side Persisiran paya bakau

25 18 17 26

Lakeside Persisiran

tasik

25 19 16 30

3

Any two correct 2

Any one correct 1

No response or incorrect response. 0

KB0607 – Relationship between space and time

1 (e)(ii) Able to draw the bar chart correctly with the following criteria: Criteria: P (paksi) : Uniform scales on both axis, label bar. Y axis, Population size of tortoise X axis, Area captured T (titik) : All 3 points transferred correctly. B (bentuk) : Same size for the bars and bars are separated.

3

Any two criteria correct 2

Any one criteria correct 1

No response or incorrect response 0

Area tortoise

captured

10

20

30

Riverside Mangrove

swamp side Lakeside

Population of tortoise,unit

Saiz populasi kura-kura,unit

Area tortoise captured Kawasan tangkapan

Mangrove swamp side

Persisiran paya bakau

Lakeside Persisiran

tasik

Riverside Persisiran sungai

10

20

30

Population size against the area of tortoise captured Saiz populasi kura-kura melawan kawasan tangkapan kura-kura

KB0608 – Interpreting data

1 (f) Able to explain the relationship between the catchment area and population size of tortoises based on the bar chart and the following aspects: R - able to state the relationship (Population size & area) E1 - amount of food sources E2 - temperature // humidity Sample answers: 1. The population size of tortoises at riverside increase / higher than population

size of tortoises at mangrove swamp side and lakeside because more amount of food sources and low temperature // more / high humidity / wet area. Saiz populasi kura-kura di persisiran sungai meningkat / lebih tinggi saiz populasi berbanding persisiran paya bakau dan persisiran tasik kerana lebih banyak sumber makanan dan suhu rendah // kelembapan tinggi.

(1R + Any 2E)

Note: If R1 wrong, reject E1 & E2

3

Able to interpret the relationship incompletely Sample answers: 1. The population of tortoises at riverside increase / higher than population of

tortoises at mangrove swamp side and lakeside because more amount of food sources. Populasi kura-kura di persisiran sungai meningkat / lebih tinggi berbanding populasi kura-kura di persisiran paya bakau dan persisiran tasik kerana jumlah makanan banyak.

Two aspects including R1 Example: R1 + E1 / R1 + E2 Note: Relationship at idea level is not accepted. e.g: The population of tortoise influenced by the catchment area BUT Explanation can be accepted.

2

Able to interpret the relationship at idea level. Sample answer: 1. The population size of tortoises at riverside increase / higher than population

size of tortoises at mangrove swamp side and lakeside. Saiz populasi kura-kura di persisiran sungai meningkat / lebih tinggi berbanding saiz populasi di persisiran paya bakau and persisiran tasik.

Only R1 stated

1

No response or incorrect response or wrong relationship. 0

KB0609 – Defining by operation

1 (g) Able to define operationally the population size of tortoise based on the result of this experiment. P1 : Number or tortoise in riverside, mangrove swamp side and lakeside P2 : Number of tortoise marked in second captured P3 : The population of tortoise depends on the catchment area // hypothesis statement Sample answer: Population size of tortoise is number of tortoise in riverside, mangrove swamp side and lakeside shown by the number of tortoise marked in second captured depends on the catchment area. Saiz populasi kura-kura ialah bilangan kura-kura di persisiran sungai, persisiran paya bakau dan persisiran tasik ditunjukkan melalui bilangan kura-kura yang bertanda dalam tangkapan kedua dipengaruhi oleh kawasan tangkap

3

Any two correct 2

Any one correct 1

No response or incorrect response Theoretical explanation. 0

KB0605 - Predicting

1(h) Able to predict and explain the outcome of the experiment correctly with the following aspects: P : Population size of tortoise increase / any suitable value more than 33 E1: Increase humidity E2: Low temperature Sample answer: 1. The population size of tortoise will increase because more / increase of humidity

and low temperature after rain. Saiz populasi kura-kura akan meningkat kerana kelembapan bertambah / meningkat dan suhu rendah selepas hujan

Must Correct Prediction

P + 2E’s

3

P + Any 1 E

2

P only

1

No response or incorrect response 0

KB0602 – Classifying

1 (i) Able to classify all factors into two groups correctly in table: 6 ticks

Biotic factor Faktor biotik

Abiotic factor Faktor abiotik

Parasite Parasit

Predator

Pemangsa

Decomposer Pengurai

Humidity Kelembapan

pH value Nilai pH

Topography Topografi

3

3-5 ticks 2

1-2 ticks 1

0 tick 0

Question 2

KB061201 – (KB061203 – Statement of Identified Problem)

No Mark Scheme Score

2(i) Sample answers: 1. Does at different enzyme concentration has the highest rate of amylase

reaction on white tablecloths with porridge spill? Adakah perbezaan kepekatan enzim mempunyai kadar tindakbalas amilase paling tinggi ke atas kain alas meja berwarna putih yang terkena tumpahan bubur?

2. Does at 2%, 4% and 5% concentration of amylase enzyme has the lowest rate of amylase reaction on white tablecloths with porridge spill? Adakah 2%, 4% dan 5% kepekatan enzim lipase mempunyai kadar tindakalas lipase ke atas kain alas meja berwarna putih yang terkena tumpahan bubur?

3. What is the effect of different enzyme concentration on the rate of amylase reaction on white tablecloths with porridge spill? Apakah kesan perbezaan kepekatan enzim ke atas kadar tindakbalas lipase ke atas kain alas meja berwarna putih yang terkena tumpahan bubur?

4. Do different enzyme concentration affect the rate of amylase reaction on white tablecloths with porridge spill? Adakah kepekatan enzim mempengaruhi kadar tindakbalas amilase ke atas kain alas meja berwarna putih yang terkena tumpahan bubur?

3

Able to state the problem statement of the experiment with any 2 criteria Sample answer 1. Does the enzyme concentration affect the enzyme activity?

Adakah kepekatan enzim mempengaruhi aktiviti enzim? 2. What is the effect of enzyme concentration on the rate of enzyme activity?

Apakah kesan kepekatan enzim ke atas kadar tindakbalas aktiviti enzim?

2

Able to state the problem statement of the experiment with any 1 criteria Sample answer 1. What is the rate of reaction?

Apakah kadar tindakbalas? 2. Does enzyme concentration affect the enzyme?

Adakah kepekatan enzim mempengaruhi enzim?

1

KB061202 (KB061203 – Making Hypothesis)

No. Mark Scheme Score

2 (ii) Able to state the hypothesis correctly based on 3 criteria: P1 : Manipulated variable (Enzyme concentration) P2 : Responding variable (Rate of enzyme activity) P3 : Relationship of variable Sample answers: 1. Rate of amylase reaction on white tablecloths with porridge spill at 5% of

amylase enzyme concentration is the highest. Kadar tindakbalas amilase ke atas kain alas meja berwarna putih yang terkena tumpahan bubur pada kepekatan 5% enzim amylase adalah paling tinggi.

2. Rate of amylase reaction on white tablecloths with porridge spill at 2% of amylase enzyme concentration is the highest. Kadar tindakbalas amilase ke atas kain alas meja berwarna putih yang terkena tumpahan bubur pada kepekatan 2% enzim amilase adalah paling rendah.

3. The higher the amylase enzyme concentration, the higher rate of enzyme activity. Semakin tinggi kepekatan enzim amilase, semakin tinggi kadar aktiviti enzim

3

Able to state the hypothesis correctly based on 2 criteria: Sample answers: 1. The rate of amylase activity depends on enzyme concentration.

Kadar aktiviti amilase bergantung kepada kepekatan enzim.

2. 2. The enzyme activity affected by enzyme concentration 3. Kadar aktiviti enzim dipengaruhi oleh kepekatan enzim.

2

Able to state the hypothesis correctly based on 1 criteria: Sample answers: 1. The enzyme activity changes.

Perubahan ektiviti enzim

1

(KB061203-Controlling variable)

No. Mark Scheme Score

2 (iii) Able to state all three variables correctly. Sample answers: 1. Manipulated variable:

Enzyme concentration Kepekatan enzim

2. Responding variable: Rate of enzyme reaction / time taken for iodine solution to remain yellow Kadar tindakbalas enzim / masa yang diambil untuk larutan iodin kekal kuning

3. Controlled variable: Volume of saliva / volume of starch suspension / concentration of starch suspension / pH value / temperature Isipadu air liur / isipadu ampaian kanji / kepekatan ampaian kanji / nilai pH / suhu

3

Able to state any two variables correctly 2

Able to state any one variables correctly 1

No response or incorrect response 0

KB061205 (KB061203 - Listing of Materials and Apparatus)

No. Mark Scheme Score

2 (iv) Sample answers:

Apparatus Materials Beakers (√) Test tube (√) Syringes (√) Droppers (√) Glass rods (√) White tiles (with grooves) Thermometer (√) Test tube rack (√) Stopwatch (√) *water bath (√) (√) compulsory for 8A

2%, 3%, 4% and 5% of starch suspension / plain rice porridge (√)

Saliva suspension (√) Iodine solution (√) Distilled water (√) compulsory for 4M

*Bunsen burner + tripod stand + wire gauze + distilled water + beaker =

Water bath = 1 Apparatus + 1 Material

8A + 4M

3

Able to list 3 materials and any 7 - 5 apparatus related to the experiment 3M + 7 - 5A

2

Able to list 2-1 materials and any 4 - 1 apparatus related to the experiment 2-1 M + 4-1A

1

Wrong response or no response

0

KB061204 (KB061203 - Method / procedure of investigation) - 3m

No. Mark Scheme Score

2 (v) Notes: K1: Preparation of materials and apparatus (all 3) K2: Operating the constant variable (any 1) K3: Operating the responding variable (any 1) K4: Operating the manipulated variable (any 1) K5: Steps to increase reliability of results accurately / precaution (any 1) Able to describe all the 5’K’ Sample answer: 1. Mouth is rinsed with warm water.

Mulut dibilas dengan air suam 2. Saliva is collected by using a beaker.

Air liur dikumpul dengan menggnakan bikar 3. The saliva is diluted with an equal volume of distilled water.

Air liur dicairkan dengan jumlah air suling yang sama 4. 5 ml of 2% starch suspension is put into a test tube by using a

syringe, labelled A1. 5ml ampaian kanji 2% diletakkan ke dalam tabung uji dengan menggunakan picagari dan dilabelkan A1.

5. 2 ml of saliva is added into another test tube by using a second syringe, labelled A2. 2ml air liur ditambah ke dalam tabung uji dengan menggunakan picagari dan dilabelkan A2

6. Test tube A1 and A2 are immersed into water bath at 370C. Tabung uji A1 dan A2 direndam ke dalam kukus air pada 370C.

7. The test tubes are left for 5 minutes. Tabung uji dibiarkan selama 5 minit

8. A dry piece of white tile with groove tile is prepared. Jubin putih lekuk disediakan

9. A drop of iodine solution is placed into each groove. Setitis larutan iodine diletakkan ke dalam setiap jubin lekuk

10. After 5 minutes, starch suspension from test tube A1 is poured into the in test tube A2. Selepas 5 minit, ampaian kanji daripada tabung uji A1 diisi ke dalam tabung uji A2.

11. The mixture is stirred by using a glass rod. Campuran dikacau menggunakan rod kaca

12. The stopwatch is started immediately. Jam randik dimulakan serta-merta

13. A drop of mixture from test tube A2 is placed into first groove on the tile contain iodine solution. Sati titisan campuran daripada tabung uji A1 diisi ke dalam jubin lekuk yang mengandungi larutan iodine.

14. The iodine test is repeated every minutes for 10 minutes. Ujian iodine diulang setiap minit selama 10 minit.

15. Measure and record the time taken for iodine solution to remain yellow by using a stopwatch Masa untuk larutan iodin kekal kuning diukur dan direkodkan

K5

K1

K1

K2/K1

K2/K1

K1

K1/K2

K1

K2/K1

K1

K1

K1

K1

K1

K4

3

dengan menggunakan jam randik. 16. Calculate and record the rate of enzyme reaction by using a

formula: Rate of reaction = ________________1____________________ Time taken for iodine solution to remain yellow Mengira dan merekod kadar tindakbalas enzim dengan menggunakan formula : Kadar tindakbalas = 1_____________________

Masa yang diambil untul larutan iodin kekal kuning 17. Steps 1 – 16 are repeated by using different concentration of

amylase at 3%, 4% and 5%. 18. Langkah 1-16 diulang dengan menggunakan kepekatan enzim

yang berbeza pada 3%, 4% dan 5%. 19. All the data is recorded in the table / tabulate data.

Semua data direkodkan di dalam jadual. 20. The experiment is repeated twice to get the average reading.

Eksperimen diulang dua kali untuk mendapatkan bacaan purata

K4

K3

K1

K5

Any 3-4 ‘K’

2

Any 1-2 ‘K’

1

No response or incorrect response

0

KB061203 – Planning Investigation (KB061203 - Data Presentation) - 2m

No. Mark Scheme Score

2 (vi) Sample answer:

Enzyme concentration

(%) Kepekatan enzim (%)

Time taken for iodine solution to remain yellow / time taken for the

hydrolysis of starch to be completed (min)

Masa yang diambil untuk warna kuning kekal kuning / masa untuk

hidrolisis kanji lengkap (min)

Rate of enzyme reaction

(1 / min) / (min-1) Kadar tindakbalas

enzim (1/min) / (min-1)

2

3

4

5

2

Able to construct a table to record data based on one aspect only

1

No response or incorrect response

0

END OF SCHEME