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Revision of Absolute Equations
Mathematics Course ONLY
(Does not include Ext 1 & 2)
By I Porter
Introduction
The absolute value of a number x in R, written | x |, is given by the non-negative number that defines its magnitude.
Since x is a real number, it can be represented by a point on the number line. It is useful to regard | x | as the distance of a point x from the origin, 0, since distance is a measureby positive numbers, the | x | is positive for all x ≠ 0.
0 1 2 3 4-1-2-3-4x
|-3| = 3 units
|2| = 2 units
Examples: Draw a diagram to represents | -3 | and | 2 | on the same diagram.
More generally, | x - y | may be considered as the distance between two points x and yOn the same number line and hence | x - y | is a positive number if x > y or if x < y.
[Introduction continued]
More generally, | x - y | may be considered as the distance between two points x and yOn the same number line and hence | x - y | is a positive number if x > y or if x < y.
Two important theorem you should know.
(a) | xy | = | x | . | y |
(b) | x + y | ≤ | x | + | y | , (the triangle inequality)
and | x + y | = | x | + | y | , when and only when x & y are eitherboth are zero or both have the same sign.
More simply put, the contents of | … | could be POSITIVE or NEGATIVE.
Examples: Solve the following:
a) | 2x - 5 | = x + 23
- (2x - 5) = x + 23 + ( 2x - 5 ) = x + 22
-2x + 5 = x + 23
-3x + 5 = 23
-3x = 18
x = -6
2x - 5 = x + 22
x - 5 = 22
x = 27
Solve2x - 5 = 0
x = 2.5(2x - 5) is negative for x < 2.5(2x - 5) is positive for x ≥ 2.5
Both solution are allowed, hencex = -6 or x = 27.
[looking for x < 2.5] [looking for x ≥ 2.5]
b) | 5 - 4x | = 2x - 7
Solve5 - 4x = 0
x = 1.25(5 - 4x) is negative for x > 1.25 (5 - 4x) is positive for x ≤ 1.25
[looking for x > 1.25] [looking for x ≤ 1.25]
- ( 5 - 4x ) = 2x - 7 + ( 5 - 4x ) = 2x - 7
- 5 + 4x = 2x - 7
- 5 + 2x = - 7
2x = - 2
x = - 1
5 - 4x = 2x - 7
5 - 6x = - 7
- 6x = - 12
x = 2
Both answer are NOT allowed.The equation has no solution.
But x must be ≤ 1.25 But x must be > 1.25
Test your answers by substitution.
Exercise: Solve the following.
There are 4 possible number of solutions:0 (zero) solutions1 (one) solution2 (two) solutions∞ (infinite) number of solutions.
a) | 4x + 1 | = 29 b) | 5x - 1 | = 3x - 15
c) | 12 - 3x | = 20 - x d) | 10 - x | = x
Positive sol. x ≥ -1/4 x = 7
Negative sol. x < -1/4 x = -71/2
Positive sol. x ≥ 1/5
Negative sol. x < 1/5
x = -7, not allowed
x = 2, not allowed
Both are solutions. There is NO solution.
Positive sol. x ≤ 4
Negative sol. x > 4
x = -4
x = 8
Both are solutions.
Positive sol. x ≤ 10
Negative sol. x > 10
x = 5
x = has no solution
There is a single solution x = 5.
Inequality Examples.Solve and graph number line solution for the following:
a) | 2x + 5 | < 17
Solve2x + 5 = 0
x = -2.5(2x + 5) is negative for x ≥ -2.5(2x + 5) is positive for x < -2.5
- ( 2x + 5) < 17 + ( 2x + 5 ) < 17
[Negative sol.] [Positive sol.]
2x + 5 > -17
2x > -22
x > -11
2x + 5 < 17
2x < 12
x < 6 (allowed) (allowed)
-11 0 6x
Solution: -11 < x < 6
b) | 5x + 1 | ≥ 3x +15
Solve5x + 1 = 0
x = - 0.2(5x + 1) is negative for x < -0.2(5x + 1) is positive for x ≥ -0.2
[Negative sol.] [Positive sol.]
- ( 5x + 1 ) ≥ 3x +15
- 5x - 1 ≥ 3x +15
- 8x - 1 ≥ 15
- 8x ≥ 16
x ≤ -2
+ ( 5x + 1 ) ≥ 3x +15
5x + 1 ≥ 3x +15
2x + 1 ≥ 15
2x ≥ 14
x ≥ 7
Solution: x ≤ -2 OR x ≥ 7
-2 0 7x
(allowed) (allowed)
c) | 5 - 4x | < 2x - 7
Solve5 - 4x = 0
x = 1.25(5 - 4x) is negative for x > 1.25 (5 - 4x) is positive for x ≤ 1.25
[looking for x > 1.25] [looking for x ≤ 1.25]
- ( 5 - 4x ) < 2x - 7 + ( 5 - 4x ) < 2x - 7
- 5 + 4x < 2x - 7
- 5 + 2x < - 7
2x < - 2
x < - 1
5 - 4x < 2x - 7
5 - 6x < - 7
- 6x < - 12
x > 2
Both answer are NOT allowed.The equation has no solution.
But x must be ≤ 1.25 But x must be > 1.25
Test your answers by substitution.
d) | 12 - x | ≤ x
Solve12 - x = 0
x = 12(5 - 4x) is negative for x > 12 (5 - 4x) is positive for x ≤ 12
[looking for x > 125] [looking for x ≤ 12]
- ( 12 - x ) ≤ x
x - 12 ≤ x
- 12 ≤ 0
A true statement,but not an answer!
+ ( 12 - x ) ≤ x
12 - x ≤ x
- 2x ≤ -12
x ≥ 6 (allowed)
(NOT allowed) (NOT allowed)
Solution: x ≥ 6
-12 0 6x
Exercise: Solve and graph number line solution for the following:
a) | 4x + 6| ≥ 14 x ≤ -5 or x ≥ 2
b) | 2x - 5| < x + 10 x > 12/3 or x < 15
c) | 20 - x| > 2x + 5 x < 5 or x < -25 (not allowed)
d) | x + 5| ≤ 2x x ≥ 5 or x ≥ -5/3 (not allowed)
12/30 15x
-25 0 5x
-5 0 2x
-5/3 0 6x