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Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

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Page 1: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot
Page 2: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Review

• Ways to “see” data– Simple frequency distribution– Group frequency distribution– Histogram– Stem-and-Leaf Display– Describing distributions– Box-Plot

• Measures of central tendency– Mean – Median– Mode

Page 3: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Review

• Measures of variability– Range– IQR– Standard deviation

Page 4: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Compute a standard deviation with the Raw-Score Method

• Previously learned the deviation formula– Good to see “what's going on”

• Raw score formula – Easier to calculate than the deviation formula– Not as intuitive as the deviation formula

• They are algebraically the same!!

Page 5: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Raw-Score Formula

-1

Page 6: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 1: Create a table

Coffee X

X2

4 10 22 2 6

Page 7: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 2: Square each value

CoffeeX

X2

4 1610 10022 4842 46 36

Page 8: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 3: Sum

CoffeeX

X2

4 1610 10022 4842 46 36

X = 44 X2 = 640

Page 9: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 4: Plug in values

N = 5

X = 44

X2 = 640

-1

Page 10: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 4: Plug in values

N = 5

X = 44

X2 = 640

5 - 15

Page 11: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 4: Plug in values

N = 5

X = 44

X2 = 640

5 - 1544

Page 12: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 4: Plug in values

N = 5

X = 44

X2 = 640

5 - 1544

640

Page 13: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 5: Solve!

5 - 1544

6401936

Page 14: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 5: Solve!

4544

6401936387.2

Page 15: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 5: Solve!

5544

6401936387.263.2

Answer = 7.95

Page 16: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• You are interested in how citizens of the US feel about the president. You asked 8 people to rate the president on a 10 point scale. Describe how the country feels about the president -- be sure to report a measure of central tendency and the standard deviation.

8, 4, 9, 10, 6, 5, 7, 9

Page 17: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Central Tendency

8, 4, 9, 10, 6, 5, 7, 9

4, 5, 6, 7, 8, 9, 9, 10

Mean = 7.25

Median = (4.5) = 7.5

Mode = 9

Page 18: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Standard Deviation X X2

8 64

4 16

9 81

10 100

6 36

5 25

7 49

9 81

= 58 = 452

-1

Page 19: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Standard Deviation X X2

8 64

4 16

9 81

10 100

6 36

5 25

7 49

9 81

= 58 = 452

-1

45258 8

8 - 1

Page 20: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Standard Deviation X X2

8 64

4 16

9 81

10 100

6 36

5 25

7 49

9 81

= 58 = 452

-1

58452 8

8 - 1

Page 21: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Standard Deviation X X2

8 64

4 16

9 81

10 100

6 36

5 25

7 49

9 81

= 58 = 452

-1

452 420.5

7

Page 22: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Standard Deviation X X2

8 64

4 16

9 81

10 100

6 36

5 25

7 49

9 81

= 58 = 452

-1

2.12

Page 23: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot
Page 24: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Variance

• The last step in calculating a standard deviation is to find the square root

• The number you are fining the square root of is the variance!

Page 25: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Variance

S 2 =

Page 26: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Variance

- 1S 2 =

Page 27: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice• Below are the test score of Joe and Bob.

What are their means, medians, and modes? Who tended to have the most uniform scores?

• Joe

80, 40, 65, 90, 99, 90, 22, 50• Bob

50, 50, 40, 26, 85, 78, 12, 50

Page 28: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• Joe

22, 40, 50, 65, 80, 90, 90, 99

Mean = 67

• Bob

12, 26, 40, 50, 50, 50, 78, 85

Mean = 48.88

Page 29: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• Joe

22, 40, 50, 65, 80, 90, 90, 99

Median = 72.5

• Bob

12, 26, 40, 50, 50, 50, 78, 85

Median = 50

Page 30: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• Joe

22, 40, 50, 65, 80, 90, 90, 99

Mode = 90

• Bob

12, 26, 40, 50, 50, 50, 78, 85

Mode = 50

Page 31: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• Joe

22, 40, 50, 65, 80, 90, 90, 99

S = 27.51; S2 = 756.80

• Bob

12, 26, 40, 50, 50, 50, 78, 85

S = 24.26; S2 = 588.55

Thus, Bob’s scores were the most uniform

Page 32: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Review

• Ways to “see” data– Simple frequency distribution– Group frequency distribution– Histogram– Stem-and-Leaf Display– Describing distributions– Box-Plot

• Measures of central tendency– Mean – Median– Mode

Page 33: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Review

• Measures of variability– Range– IQR– Standard deviation – Variance

Page 34: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

What if. . . .

• You recently finished taking a test that you received a score of 90 and the test scores were normally distributed.

• It was out of 200 points

• The highest score was 110

• The average score was 95

• The lowest score was 90

Page 35: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Z-score

• A mathematical way to modify an individual raw score so that the result conveys the score’s relationship to the mean and standard deviation of the other scores

• Transforms a distribution of scores so they have a mean of 0 and a SD of 1

Page 36: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Z-score

• Ingredients:

X Raw score

Mean of scores

S The standard deviation of scores

Page 37: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Z-score

Page 38: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

What it does

• x - Tells you how far from the mean you are and if you are > or < the mean

• S Tells you the “size” of this difference

Page 39: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Example

• Sample 1:

X = 8

= 6

S = 5

Page 40: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Example

• Sample 1:

X = 8

= 6

S = 5

Z score = .4

Page 41: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Example

• Sample 1:

X = 8

= 6

S = 1.25

Page 42: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Example

• Sample 1:

X = 8

= 6

S = 1.25

Z-score = 1.6

Page 43: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Example

• Sample 1:

X = 8

= 6

S = 1.25

Z-score = 1.6

Note: A Z-score tells you how many SD above or below a mean a specific score falls!

Page 44: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• The history teacher Mr. Hand announced that the lowest test score for each student would be dropped. Jeff scored a 85 on his first test. The mean was 74 and the SD was 4. On the second exam, he made 150. The class mean was 140 and the SD was 15. On the third exam, the mean was 35 and the SD was 5. Jeff got 40. Which test should be dropped?

Page 45: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• Test #1

Z = (85 - 74) / 4 = 2.75

• Test #2

Z = (150 - 140) / 15 = .67

• Test #3

Z = (40 - 35) / 5 = 1.00

Page 46: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

Time(sec)

Distance(feet)

Rachel 30 6

Joey 40 8

Ross 25 4

Monica 45 10

Chandler 33 9

Page 47: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Which challenge did Ross do best? Which did Monica do best?

Time(sec)

Distance(feet)

Rachel 30 6

Joey 40 8

Ross 25 4

Monica 45 10

Chandler 33 9

Page 48: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

Time (sec)

Distance (feet)

Rachel 30 6

Joey 40 8

Ross 25 4

Monica 45 10

Chandler 33 9

= 34.6 = 7.4

S = 7.96 S = 2.41

Page 49: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

Time (sec)

Distance (feet)

Rachel 30 -.58 6

Joey 40 .68 8

Ross 25 -1.21 4

Monica 45 1.31 10

Chandler 33 -.20 9

= 34.6 = 7.4

S = 7.96 S = 2.41

Page 50: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

Time (sec)

Distance (feet)

Rachel 30 -.58 6 -.58

Joey 40 .68 8 .25

Ross 25 -1.21 4 -1.66

Monica 45 1.31 10 1.08

Chandler 33 -.20 9 .66

= 34.6 = 7.4

S = 7.96 S = 2.41

Page 51: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Ross did worse in the throwing challenge than the endurance and Monica did better in the endurance than the throwing challenge.

Time (sec)

Distance (feet)

Rachel 30 -.58 6 -.58

Joey 40 .68 8 .25

Ross 25 -1.21 4 -1.66

Monica 45 1.31 10 1.08

Chandler 33 -.20 9 .66

= 34.6 = 7.4

S = 7.96 S = 2.41

Page 52: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot
Page 53: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Shifting Gears

Page 54: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Question

• A random sample of 100 students found:– 56 were psychology majors– 32 were undecided– 8 were math majors– 4 were biology majors

• What proportion were psychology majors?

• .56

Page 55: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Question

• A random sample of 100 students found:– 56 were psychology majors– 32 were undecided– 8 were math majors– 4 were biology majors

• What is the probability of randomly selecting a psychology major?

Page 56: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Question

• A random sample of 100 students found:– 56 were psychology majors– 32 were undecided– 8 were math majors– 4 were biology majors

• What is the probability of randomly selecting a psychology major?

• .56

Page 57: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Probabilities

• The likelihood that something will occur

• Easy to do with nominal data!

• What if the variable was quantitative?

Page 58: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Extraversion

BFISUR

4.88

4.63

4.38

4.13

3.88

3.63

3.38

3.13

2.88

2.63

2.38

2.13

1.88

1.63

1.38

1.13

Co

un

t50

40

30

20

10

0

Page 59: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

BFIOPN

5.00

4.80

4.60

4.40

4.20

4.00

3.80

3.60

3.40

3.20

3.00

2.80

2.60

2.40

2.20

2.00

1.60

Co

un

t

40

30

20

10

0

Openness to Experience

Page 60: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

BFISTB

4.88

4.50

4.25

4.00

3.75

3.50

3.25

3.00

2.75

2.50

2.25

2.00

1.75

1.50

1.25

Co

un

t40

30

20

10

0

Neuroticism

Page 61: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Probabilities

Normality frequently occurs in many situations of psychology, and other sciences

Page 62: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

COMPUTER PROG

• http://www.jcu.edu/math/isep/Quincunx/Quincunx.html

• http://webphysics.davidson.edu/Applets/Galton/BallDrop.html

• http://www.ms.uky.edu/~mai/java/stat/GaltonMachine.html

Page 63: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Next step

• Z scores allow us to modify a raw score so that it conveys the score’s relationship to the mean and standard deviation of the other scores.

• Normality of scores frequently occurs in many situations of psychology, and other sciences

• Is it possible to apply Z score to the normal distribution to compute a probability?

Page 64: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Theoretical Normal Curve

-3 -2 -1 1 2 3

Page 65: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Theoretical Normal Curve

-3 -2 -1 1 2 3

Page 66: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Theoretical Normal Curve

-3 -2 -1 1 2 3

Page 67: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Theoretical Normal Curve

-3 -2 -1 1 2 3

Note: A Z-score tells you how many SD above or below a mean a specific score falls!

Page 68: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Theoretical Normal Curve

-3 -2 -1 1 2 3

Z-scores -3 -2 -1 0 1 2 3

Page 69: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

We can use the theoretical normal distribution to determine the probability of an event. For example, do you know the probability of getting a Z score of 0 or less?

-3 -2 -1 1 2 3

Z-scores -3 -2 -1 0 1 2 3

.50

Page 70: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

We can use the theoretical normal distribution to determine the probability of an event. For example, you know the probability of getting a Z score of 0 or less.

-3 -2 -1 1 2 3

Z-scores -3 -2 -1 0 1 2 3

.50

Page 71: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

With the theoretical normal distribution we know the probabilities associated with every z score! The probability of getting a score between a 0 and a 1 is

-3 -2 -1 1 2 3

Z-scores -3 -2 -1 0 1 2 3

.3413 .3413

.1587 .1587

Page 72: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

What is the probability of getting a score of 1 or higher?

-3 -2 -1 1 2 3

Z-scores -3 -2 -1 0 1 2 3

.3413 .3413

.1587 .1587

Page 73: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

These values are given in Appendix Z

-3 -2 -1 1 2 3

Z-scores -3 -2 -1 0 1 2 3

.3413 .3413

.1587 .1587

Page 74: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

-3 -2 -1 1 2 3

Z-scores -3 -2 -1 0 1 2 3

.3413 .3413

.1587 .1587

Mean to Z

Page 75: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

-3 -2 -1 1 2 3

Z-scores -3 -2 -1 0 1 2 3

.3413 .3413

.1587 .1587

Smaller Portion

Page 76: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

-3 -2 -1 1 2 3

Z-scores -3 -2 -1 0 1 2 3

.84

.1587

Larger Portion

Page 77: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• What proportion of the normal distribution is found in the following areas (hint: draw out the answer)?

• Between mean and z = .56?

• Above z = 2.25?

• Above z = -1.45

Page 78: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• What proportion of the normal distribution is found in the following areas (hint: draw out the answer)?

• Between mean and z = .56?.2123

• Above z = 2.25?

• Above z = -1.45

Page 79: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• What proportion of the normal distribution is found in the following areas (hint: draw out the answer)?

• Between mean and z = .56?.2123

• Above z = 2.25?.0122

• Above z = -1.45

Page 80: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• What proportion of the normal distribution is found in the following areas (hint: draw out the answer)?

• Between mean and z = .56?.2123

• Above z = 2.25?.0122

• Above z = -1.45.9265

Page 81: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Practice

• What proportion of this class would have received an A on the last test if I gave A’s to anyone with a z score of 1.25 or higher?

• .1056

Page 82: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Example: IQ

• Mean IQ = 100

• Standard deviation = 15

• What proportion of people have an IQ of 120 or higher?

Page 83: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 1: Sketch out question

-3 -2 -1 1 2 3

Page 84: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 1: Sketch out question

-3 -2 -1 1 2 3

120

Page 85: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 2: Calculate Z score

-3 -2 -1 1 2 3

120

(120 - 100) / 15 = 1.33

Page 86: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 3: Look up Z score in Table

-3 -2 -1 1 2 3

120

Z = 1.33

.0918

Page 87: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Example: IQ

• A proportion of .0918 or 9.18 percent of the population have an IQ above 120.

• What proportion of the population have an IQ below 80?

Page 88: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 1: Sketch out question

-3 -2 -1 1 2 3

Page 89: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 1: Sketch out question

-3 -2 -1 1 2 3

80

Page 90: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 2: Calculate Z score

-3 -2 -1 1 2 3

80

(80 - 100) / 15 = -1.33

Page 91: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 3: Look up Z score in Table

-3 -2 -1 1 2 3

80

Z = -1.33

.0918

Page 92: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Example: IQ

• Mean IQ = 100

• SD = 15

• What proportion of the population have an IQ below 110?

Page 93: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 1: Sketch out question

-3 -2 -1 1 2 3

Page 94: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 1: Sketch out question

-3 -2 -1 1 2 3

110

Page 95: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 2: Calculate Z score

-3 -2 -1 1 2 3

(110 - 100) / 15 = .67

110

Page 96: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 3: Look up Z score in Table

-3 -2 -1 1 2 3

Z = .67

110

.7486

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Example: IQ

• A proportion of .7486 or 74.86 percent of the population have an IQ below 110.

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Finding the Proportion of the Population Between Two

Scores• What proportion of the population have IQ

scores between 90 and 110?

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Step 1: Sketch out question

-3 -2 -1 1 2 3

11090

?

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Step 2: Calculate Z scores for both values

• Z = (X - ) /

• Z = (90 - 100) / 15 = -.67

• Z = (110 - 100) / 15 = .67

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Step 3: Look up Z scores

-3 -2 -1 1 2 3

.67-.67

.2486 .2486

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Step 4: Add together the two values

-3 -2 -1 1 2 3

.67-.67

.4972

Page 103: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

• A proportion of .4972 or 49.72 percent of the population have an IQ between 90 and 110.

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• What proportion of the population have an IQ between 110 and 130?

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Step 1: Sketch out question

-3 -2 -1 1 2 3

110 130

?

Page 106: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 2: Calculate Z scores for both values

• Z = (X - ) /

• Z = (110 - 100) / 15 = .67

• Z = (130 - 100) / 15 = 2.0

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Step 3: Look up Z score

-3 -2 -1 1 2 3

.67 2.0.4772

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Step 3: Look up Z score

-3 -2 -1 1 2 3

.67 2.0.4772

.2486

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Step 4: Subtract

-3 -2 -1 1 2 3

.67 2.0

.2286

.4772 - .2486 = .2286

Page 110: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

• A proportion of .2286 or 22.86 percent of the population have an IQ between 110 and 130.

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Page 112: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Finding a score when given a probability

• IQ scores – what is the range of IQ scores we expect 95% of the population to fall?

• “If I draw a person at random from this population, 95% of the time his or her score will lie between ___ and ___”

• Mean = 100• SD = 15

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Step 1: Sketch out question

? 100 ?

95%

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Step 1: Sketch out question

? 100 ?

95% 2.5%2.5%

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Step 1: Sketch out question

? 100 ?

95% 2.5%2.5%

Z = 1.96Z = -1.96

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Step 3: Find the X score that goes with the Z score

• Z score = 1.96

• Z = (X - ) / • 1.96 = (X - 100) / 15

• Must solve for X

• X = + (z)()

• X = 100 + (1.96)(15)

Page 117: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

Step 3: Find the X score that goes with the Z score

• Z score = 1.96• Z = (X - ) / • 1.96 = (X - 100) / 15

• Must solve for X• X = + (z)()• X = 100 + (1.96)(15)• Upper IQ score = 129.4

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Step 3: Find the X score that goes with the Z score

• Must solve for X

• X = + (z)()

• X = 100 + (-1.96)(15)

• Lower IQ score = 70.6

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Step 1: Sketch out question

70.6 100 129.4

95% 2.5%2.5%

Z = 1.96Z = -1.96

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Finding a score when given a probability

• “If I draw a person at random from this population, 95% of the time his or her score will lie between 70.6 and 129.4”

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Practice

• GRE Score – what is the range of GRE scores we expect 90% of the population to fall?

• Mean = 500

• SD = 100

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Step 1: Sketch out question

? 500 ?

90% 5%5%

Z = 1.64Z = -1.64

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Step 3: Find the X score that goes with the Z score

• X = + (z)()• X = 500 + (1.64)(100)• Upper score = 664

• X = + (z)()• X = 500 + (-1.64)(100)• Lower score = 336

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Finding a score when given a probability

• “If I draw a person at random from this population, 90% of the time his or her score will lie between 336 and 664”

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Practice

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Practice

• The Neuroticism Measure

= 23.32

S = 6.24

n = 54

How many people likely have a neuroticism score between 18 and 26?

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Practice

• (18-23.32) /6.24 = -.85

• area = .3023

• ( 26-23.32)/6.26 = .43

• area = .1664

• .3023 + .1664 = .4687

• .4687*54 = 25.31 or 25 people

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Page 129: Review Ways to “see” data –Simple frequency distribution –Group frequency distribution –Histogram –Stem-and-Leaf Display –Describing distributions –Box-Plot

SPSS

PROGRAM:

https://citrixweb.villanova.edu/Citrix/XenApp/auth/login.aspx

BASIC “HOW TO”

http://www.psychology.ilstu.edu/jccutti/138web/spss.html

SPSS “HELP” is also good

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SPSS PROBLEM #1

• Page 65• Data 2.1

• Turn in the SPSS output for

• 1) Mean, median, mode• 2) Standard deviation• 3) Frequency Distribution• 4) Histogram