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Tabla de excel para resolver red abierta
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TUBO DIÁMETRO LONGITUD F C TANQUE COTA1 0.3 2000 0.0234205 1484.61521 A 902 0.2 1000 0.02616492 5347.4698 B 803 0.5 3000 0.02053681 185.055396 C 60
CHW 100 NUDO J 70
ITERACIÓN 1TUBO C PÉRDIDAS Q
1 1484.61521 20 0.097645922 5347.4698 10 0.033615083 185.055396 10 0.20676205
SUMATORIA -0.07550106ITERACIÓN 2
1 1484.61521 24.8297688 0.10974462 5347.4698 14.8297688 0.041585953 185.055396 5.1702312 0.14479922
0.00653133ITERACIÓN 3
1 1484.61521 24.4867993 0.10892342 5347.4698 14.4867993 0.041063813 185.055396 5.51320069 0.14990941
7.78008E-05ITERACIÓN 4
1 1484.61521 24.4826242 0.108913372 5347.4698 14.4826242 0.041057423 185.055396 5.51737579 0.1499707
8.76575E-08
ITERACIÓN 1Q/H DELTA Z COTA CORR
0.0048823
-4.8297688 65.17023120.003361510.020676210.02892001
ITERACIÓN 20.00441988
0.34296949 65.51320070.002804220.028006330.03523043
ITERACIÓN 30.00444825
0.00417509 65.51737580.002834570.027190990.03447381
ITERACIÓN 40.0044486
4.70524E-06 65.51738050.002834940.027181530.03446507