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Ratio and Ratio and Proportion Proportion 7-1 7-1

Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

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Page 1: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

Ratio and ProportionRatio and ProportionRatio and ProportionRatio and Proportion

7-17-1

Page 2: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

EXAMPLE 1 Simplify ratios

SOLUTION

64 m : 6 ma.

Then divide out the units and simplify.

b. 5 ft20 in.

b. To simplify a ratio with unlike units, multiply by a conversion factor.

a. Write 64 m : 6 m as 64 m6 m

.

= 323

= 32 : 3

5 ft20 in. = 60

20 = 31= 5 ft

20 in.12 in.1 ft

Simplify the ratio.

64 m6 m

Page 3: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

GUIDED PRACTICE for Example 1

SOLUTION

Then divide out the units and simplify.

24 3

= 81

= 8 : 1

Simplify the ratio.

1. 24 yards to 3 yards

Write 24 yards : 3 yards as 24 3

Page 4: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

GUIDED PRACTICE for Example 1

2. 150 cm : 6 m

SOLUTION

To simplify a ratio with unlike units, multiply by a conversion factors.

= 14 = 1 : 4

Simplify the ratio.

150cm 6m = 150

6 1m100cm

Page 5: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

EXAMPLE 4 Solve proportions

SOLUTION

a. 510

x16=

Multiply.

Divide each side by 10.

a. 510

x16=

= 10 x5 16

= 10 x80

= x8

Write original proportion.

Cross Products Property

Solve the proportion.ALGEBRA

Page 6: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

EXAMPLE 4 Solve proportions

Subtract 2y from each side.

1y + 1

23y

b. =

= 2 (y + 1)1 3y

= 2y + 23y

=y 2

Distributive Property

SOLUTION

b. 1y + 1 = 2

3y

Write original proportion.

Cross Products Property

Page 7: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

GUIDED PRACTICE for Example 4

5. 2 x

5 8=

SOLUTION

Write original proportion.

Cross Products Property

Multiply.

Divide each side by 5 .

2 x

5 8=

= 5 x2 8

= 5 x16

=x 16 5

Page 8: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

GUIDED PRACTICE for Example 4

6. 1x – 3

43x=

SOLUTION

Write original proportion.

Cross Products Property

Multiply.

Subtract 4x from each side.

1x – 3

43x=

3x 4(x – 3)=

3x 4x – 12=

3x – 4x – 12=

– x = – 12

x = 12

Page 9: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

GUIDED PRACTICE for Example 4

7.

y – 3 7

y14=

SOLUTION

Write original proportion.

Cross Products Property

Multiply.

Subtract 7y from each side and add 42 to each side.

14y – 42 7y=

14y – 7y 42=

y = 6

y – 3 7

y14=

=14(y – 3) 7 y

Subtract , then divide

Page 10: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

EXAMPLE 2 Use a ratio to find a dimension

SOLUTION

Painting

You are planning to paint a mural on a rectangular wall. You know that the perimeter of the wall is 484 feet and that the ratio of its length to its width is 9 : 2. Find the area of the wall.

Write expressions for the length and width. Because the ratio of length to width is 9 : 2, you can represent the length by 9x and the width by 2x.

STEP 1

Page 11: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

EXAMPLE 2 Use a ratio to find a dimension

STEP 2

Solve an equation to find x.

Formula for perimeter of rectangle

Substitute for l, w, and P.Multiply and combine like terms.

Divide each side by 22.

=2l + 2w P=2(9x) + 2(2x) 484= 48422x

Evaluate the expressions for the length and width. Substitute the value of x into each expression.

STEP 3

The wall is 198 feet long and 44 feet wide, so its area is198 ft 44 ft = 8712 ft .2

= 22x

Length = 9x = 9(22) = 198Width = 2x = 2(22) = 44

Page 12: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

EXAMPLE 3 Use extended ratios

Combine like terms.

SOLUTION

Triangle Sum Theorem

Divide each side by 6.= 30x=6x 180= 180

ox + 2x + 3x o oo

ALGEBRA The measures of the angles in CDE are in the extended ratio of 1 : 2 : 3. Find the measures of the angles.

Begin by sketching the triangle. Then use the extended ratio of 1 : 2 : 3 to label the measures as x° , 2x° , and 3x° .

The angle measures are 30 , 2(30 ) = 60 , and 3(30 ) = 90.o o o o o

ANSWER

Page 13: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

GUIDED PRACTICE for Examples 2 and 3

3. The perimeter of a room is 48 feet and the ratio of its length to its width is 7 : 5. Find the length and width of the room.

SOLUTION

Write expressions for the length and width. Because the ratio of length is 7 : 5, you can represent the length by 7x and the width by 5x.

STEP 1

Page 14: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

GUIDED PRACTICE for Examples 2 and 3

STEP 2

Solve an equation to find x.

Formula for perimeter of rectangle

Substitute for l, w, and P.Multiply and combine like terms.

=2l + 2w P=2(7x) + 2(5x) 48= 4824x= 2x

Evaluate the expressions for the length and width. Substitute the value of x into each expression.

STEP 3

Length = 7x + 7(2) = 14 ftWidth = 5x + 5(2) = 10 ft

Page 15: Ratio and Proportion 7-1. EXAMPLE 1 Simplify ratios SOLUTION 64 m : 6 m a. Then divide out the units and simplify. b. 5 ft 20 in. b. To simplify a ratio

GUIDED PRACTICE for Examples 2 and 3

Begin by sketching the triangle. Then use the extended ratio of 1 : 3 : 5 to label the measures as x° , 2x° , and 3x° .

Triangle Sum Theorem

SOLUTION

Combine like terms.

Divide each side by 9.= 20x=9x 180=x + 3x + 5x 180o o oo

4. A triangle’s angle measures are in the extended ratio of 1 : 3 : 5. Find the measures of the angles.

x

3x 5x

The angle measures are 20 , 3(20 ) = 60 , and 5(20 ) = 100.o o o o o

ANSWER