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Lecture 9 Properties of Point Estimators and Methods of Estimation Relative efficiency: If we have two unbiased estimators of a parameter, and , we say that is relatively more efficient than if ( ) . Definition: Given two unbiased estimators and of , the efficiency of relative to , denoted eff( , ), is given by ( ) Example: Let be a random sample of size n from a population with mean μ and variance . Consider ̂ , ̂ , ̂ . Find eff(̂ ,̂ ) and eff(̂ ,̂ ). Solution:

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Page 1: Properties of Point Estimators and Methods of Estimationolgac/sta255_2013/notes/sta255_Lecture9.pdfLecture 9 Properties of Point Estimators and Methods of Estimation Relative efficiency:

Lecture 9

Properties of Point Estimators and Methods of

Estimation

Relative efficiency: If we have two unbiased estimators of a

parameter, and , we say that is relatively more efficient

than if ( ) .

Definition: Given two unbiased estimators and of , the

efficiency of relative to , denoted eff( , ), is given by

( )

Example: Let be a random sample of size n from a

population with mean µ and variance . Consider

,

,

.

Find eff( , ) and eff( , ).

Solution:

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Consistency: We toss a coin n times. The probability of having

heads is p. Tosses are independent. Let Y = # of heads.

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Definition: An estimator is a consistent estimator of θ, if

→ , i.e., if converges in probability to θ.

Theorem: An unbiased estimator for is consistent, if

→ ( ) .

Proof: omitted.

Example: Let be a random sample of size n from a

population with mean µ and variance . Show that

is a consistent estimator of µ.

Solution:

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Sufficiency:

Example: Consider the outcomes of n trials of a binomial

experiment, .

Page 6: Properties of Point Estimators and Methods of Estimationolgac/sta255_2013/notes/sta255_Lecture9.pdfLecture 9 Properties of Point Estimators and Methods of Estimation Relative efficiency:

Definition: Let denote a random sample from a

probability distribution with unknown parameter . Then the

statistic is sufficient for if the conditional

distribution of , given U, does not depend on .

How to find it?

Definition: Let be sample observations taken on

corresponding random variables whose distribution

depends on . Then if are discrete (continuous)

random variables, the likelihood of the sample,

, is defined to be the joint probability (density)

function of .

Page 7: Properties of Point Estimators and Methods of Estimationolgac/sta255_2013/notes/sta255_Lecture9.pdfLecture 9 Properties of Point Estimators and Methods of Estimation Relative efficiency:

Theorem (Factorization Criterion): Let U be a statistic based on the

random sample . Then U is a sufficient statistic for the

estimation of if and only if

.

Proof: omitted.

Example: Let be a random sample, and

{

.

Show that is a sufficient statistic for .

Solution:

Page 8: Properties of Point Estimators and Methods of Estimationolgac/sta255_2013/notes/sta255_Lecture9.pdfLecture 9 Properties of Point Estimators and Methods of Estimation Relative efficiency:

Example: (#9.49) Let be a random sample from

U . Show that is sufficient for

.

Solution:

Page 9: Properties of Point Estimators and Methods of Estimationolgac/sta255_2013/notes/sta255_Lecture9.pdfLecture 9 Properties of Point Estimators and Methods of Estimation Relative efficiency:

How to find estimators?

There are two main methods for finding estimators:

1) Method of moments.

2) The method of Maximum likelihood.

Method of Moments (MoM)

The method of moments is a very simple procedure for finding an

estimator for one or more parameters of a statistical model. It is

one of the oldest methods for deriving point estimators.

Recall: the moment of a random variable is

The corresponding sample moment is

The estimator based on the method of moments will be the solution

to the equation .

Page 10: Properties of Point Estimators and Methods of Estimationolgac/sta255_2013/notes/sta255_Lecture9.pdfLecture 9 Properties of Point Estimators and Methods of Estimation Relative efficiency:

Example: Let . Use MoM to estimate .

Solution:

Example: Let . Find Mom estimators of

and .

Solution:

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Maximum Likelihood Estimators (MLEs)

Suppose the likelihood function depends on k parameters

. Choose as estimates those values of the parameters that

maximize the likelihood .

l(θ) = ln(L(θ)) is the log likelihood function. Both the likelihood

function and the log likelihood function have their maximums at

the same value of . It is often easier to maximize l(θ).

Example: A binomial experiment consisting of n trials resulted in

observations , where if the trial is a success

and otherwise. Find the MLE of p, the probability of a

success.

Solution:

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Example: Let . Find the MLEs of and .

Solution:

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More Examples...

Example 1: Suppose that X is a discrete random variable with the

following probability mass function:

X 0 1 2 3

P(X) 2 /3 /3 2( )/3 /3

Where is a parameter. The following 10 independent

observations

3, 0, 2, 1, 3, 2, 1, 0, 2, 1

were taken from such a distribution. What is the maximum

likelihood estimate of .

Solution:

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Example 2: The Pareto distribution has a probability density

function

, for x ≥α , θ > 1

where α and θ are positive parameters of the distribution. Assume

that α is known and that is a random sample of size n.

a) Find the method of moments estimator for θ.

b) Find the maximum likelihood estimator for θ. Does this

estimator differ from that found in part (a)?

c) Estimate θ based on these data:

3, 5, 2, 3, 4, 1, 4, 3, 3, 3.

Solution:

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Example 3: Suppose that form a random sample from a

uniform distribution on the interval (0, ), where parameter > 0

is unknown. Find MLE of .

Solution:

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Example 4: Suppose that form a random sample from a

uniform distribution on the interval , where the value of

the parameter is unknown . What is the MLE for

?

Solution:

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Example 5: Let be an i.i.d. collection of Poisson( )

random variables, > 0. Find the MLE for .

Solution:

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Example 6: Let be a random sample from geometric

distribution with

Find the estimator for p.

Solution: