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CHAPTER 7: PROBABILITY II Students will able to understand the concept of: Probability of an event Probability of the complement of an event Probability of combined events MATHEMATICS FORM 5 Oleh: Pn. Azlina Binti Md. Ali Guru Cemerlang Matematik

Probability II form 5

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CHAPTER 7: PROBABILITY II

CHAPTER 7: PROBABILITY II

Students will able to understand the concept of:

Probability of an eventProbability of the complement of an eventProbability of combined events

MATHEMATICS FORM 5Oleh:Pn. Azlina Binti Md. AliGuru Cemerlang Matematik1PREVIOUS LESSONListing:Sample spaceOutcomes Chap 7: Form 5TRY THIS:Jasmin rolled a fair dice. List the sample space

Answer:

Sample space = {1, 2, 3, 4, 5, 6}

A box contains 8 cards as shown below. Siti randomly picks one of the cards from the box

List the sample spaceMALYASIAAswer:Sample space (S) = {M, A1, L, A2, Y, S, I, A3}Chap 7: Form 5List the sample space when chosen a letter from the word MALAYSIA. Aswer:Sample space (S) = {M, A, L, Y, S, I}List the sample space when a fair coin is tossed.Aswer:Sample space (S) = {Head, Tail}

Chap 7: Form 5CALCULATE THE PROBAILITYChap 7: Form 5CONCEPT OF PROBABILITYA box contained 3 blue and 2 yellow balls. A ball is picked at random from the box. Find the probability of pickinga blue ball.a yellow ball

Chap 7: Form 5A tray has 9 white marbles and 12 yellow marbles. A marble is picked at random from the tray.What is the probability of picking a yellow marble?If 6 more white marbles are put into the tray, find the probability of picking a white marble.

Chap 7: Form 5Chap 7: Form 5The table below shows the number of members in three different clubs. A member is picked randomly from the clubs

If the probability of picking a member from the computer club is , find the value of xClubScienceMathematicsComputerNumber of members180X210Chap 7: Form 5

PROBABILITY OF THE COMPLEMENT OF AN EVENTChap 7: Form 5Chap 7: Form 5Chap 7: Form 5PROBABILITY OF THE COMBINED EVENTS (or , and)2 METHOD:

METHOD 1: By listing the outcomes, draw a tree diagram

METHOD 2: By calculation

A coin and a dice are tossed together. Find the probability of getting:Head or even number.Head and even number

Chap 7: Form 5METHOD 1: By listing the outcomes, draw a tree diagramHT123456123456H1H2H3H4H5H6T1T2T3T4T5T6There fore the sample space of the experiment is:-

S = { H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6 }Chap 7: Form 5S = { H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6 }n(S) = 12

From the sample space, find the probability of getting:Head or even number.Head and even numberChap 7: Form 5A box contained a blue and 2 yellow balls. 2 balls are picked from the box one by one after replacement. Find the probability of pickingBlue or yellow ball.2 yellow ballsSolution:Y1BY1BY2Y1BY2Y1BY2Y2(B, Y1)(B, B)(B, Y2)(Y1, Y1)(Y1, B)(Y1, Y2)(Y2, Y1)(Y2, B)(Y2, Y2)There for the sample space of the experiment is:-

S = { (B,B), (B,Y1), (B,Y2), (Y1,B), (Y1,Y1), (Y1,Y2), (Y2,B), (Y2,Y1), (Y2,Y2) }S = { (B,B), (B,Y1), (B,Y2), (Y1,B), (Y1,Y1), (Y1,Y2), (Y2,B), (Y2,Y1), (Y2,Y2) } n(S) = 9

From the sample space, find the probability of getting:Blue or yellow ball.2 yellow ballsChap 7: Form 5Chap 7: Form 5A box contained 1 blue and 2 yellow balls. 2 balls are picked from the box one by one without replacement. Find the probability of pickingBlue or yellow ball.2 yellow ballsSolution:Y1BY1Y2BY2Y1BY2(B, Y1)(B, Y2)(Y1, B)(Y1, Y2)(Y2, Y1)(Y2, B)There for the sample space of the experiment is:-

S = {(B,Y1), (B,Y2), (Y1,B), (Y1,Y2), (Y2,B), (Y2,Y1), }S = { (B,Y1), (B,Y2), (Y1,B), (Y1,Y2), (Y2,B), (Y2,Y1)} n(S) = 6

From the sample space, find the probability of getting:Blue or yellow ball.2 yellow ballsChap 7: Form 5PROBABILITY OF THE COMBINED EVENTS (or , and)Chap 7: Form 5If A and B are mutually exclusiveIf A and B are not mutually exclusiveIf A and B are independent eventsMETHOD 2: By calculationA coin and a dice are tossed together. Find the probability of getting:Head or even number.Head and even number

HTEOEOH,EH,OT,ET,O

Chap 7: Form 5Chap 7: Form 5A box contained a blue and 2 yellow balls. 2 balls are picked from the box one by one after replacement. Find the probability of pickingBlue or yellow ball.2 yellow ballsSolution:YBBYBY(B, B)(B, Y)(Y, B)(Y, Y)

Chap 7: Form 5A box contained a blue and 2 yellow balls. 2 balls are picked from the box one by one without replacement. Find the probability of pickingBlue or yellow ball.2 yellow ballsSolution:YBYBY(B, Y)(Y, B)(Y, Y)

There are 5 red roses and 6 yellow roses in the garden. 2 roses are plucked at random. Find the probability of plucking:1 red rose and 1 yellow rose.Both are yellow rosesAt least one red roseChap 7: Form 5