Priliminary concept of Structural Analysis

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    Lecture 4: PRELIMINARY CONCEPTS OF

    STRUCTURAL ANALYSIS

    Introduction

    In this class we will focus on the structural analysis of framed structures. We will learn

    about the flexibility method first, and then learn how to use the primary analytical tools

    associated with the stiffness method. Framed structures consist of components with

    lengths that are significantly larger than cross-sectional areas. Both analytical methods

    are applicable to structures of all types, but the stiffness method dominates, and the

    structural analysis of machine components that fall outside the definition of framed

    structures are treated in another course. We will concentrate on :

    Beams

    Plane trusses

    Space trusses

    Plane frames

    Grids

    Space frames

    Loads on these elements consist of concentrated forces, distributed loads and/or couples.

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    Lecture 4: PRELIMINARY CONCEPTS OF

    STRUCTURAL ANALYSIS

    Continuous Beam

    Loads on a beam are applied in a plane containing an axis of symmetry

    Beams have one or more points of support referred to as reactions but in this course they

    will be more often referred to as nodes. NodesA, B, andCrepresent reactions. NodeD

    identifies a location on the beam (the free end) where we wish to extract information.

    Beams deflect in the plane of the loads. Internal forces consist of shear forces, bending

    moments, torques (take CVE 513), and axial loads

    Shear Moment Axial load

    V M A Actions

    y x Displacements (translations, rotations)

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    All structural components are in same plane. Forces act in the plane of structure.

    External forces and reactions to those forces are considered to act only at the nodes and

    result in forces in the members which are either tensile or compressive forces. Thus all

    members are two force members.

    Loads acting on members are replaced by statically equivalent forces at the joints. Sothe momentM1, the distributed loadw and the forceP4 would have to be replaced by

    equivalent joint loads to conduct an analysis.

    Joints are assume hinged, so no bending moments are transmitted through a joint and

    absolutely no twisting moments can be applied to the truss (consider a gusset plate).

    Plane TrussTruss stabilizing mechanical floor

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    Space Truss

    Forces and structural elements are no longer

    confined to a plane. A space frame truss is athree-dimensional framework of members

    pinned at their ends. A tetrahedron shape is the

    simplest space truss, consisting of six members

    which meet at four joints. Large planar

    structures may be composed from tetrahedronswith common edges. Space trusses are

    employed in the base structures of large free-

    standing power line pylons

    As in planar trusses only axial tensile orcompressive forces can be developed.

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    Grid

    Elements can intersect at rigid or flexible connections

    All forces are normal to the plane of the structure. Typically used to support roofs with

    no internal column support (think of indoor sports arenas).

    All couples have their vectors in the plane of the grid. Torques can be sustained.

    Each member is assumed to have two axes of symmetry so that bending and torsion can

    occur independently of one another (see unsymmetrical bending in CVE 513)

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    Plane Frame

    Joints are no longer required to be hinges. They can be rigid, or they can sustain rotation.

    Forces and deflection are contained in the plane X-Y.

    All couples have moment vectors parallel to Z-axis.

    Internal resultants consist of bending moments, shearing forces and axial forces.

    Joints may transfer moment

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    Lecture 4: PRELIMINARY CONCEPTS OF

    STRUCTURAL ANALYSIS

    Space Frame

    Most general type of framed structure.

    No restrictions on location of joints, directions of members, or directions of loads.

    Members are assumed to have two axes of symmetry for the same reason grids have

    two axes of symmetry.

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    Displacements Translations and Rotations

    When a structure is subjected to loads it deforms and as a consequence points in the

    original configuration displace to new positions (the mathematics describing this

    process are discussed in detail in CVE 513 and CVE 604)

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    Actions And Displacements

    The terms action and displacement are used to describe two fundamental concepts in

    engineering mechanics. An action is most commonly a single force or a moment.

    An action may also be a combination of forces, moments, or distributed loads. We will talk

    about this more when we discuss the concept of equivalent joint loads.

    Out of necessity forces, moments and distributed loads must be related to corresponding

    displacements at their point of application (and elsewhere) in a unique manner. We need anotation that allows for this correspondence.

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    Lecture 4: PRELIMINARY CONCEPTS OF

    STRUCTURAL ANALYSIS

    Consider the following notation and the subscripts in the figure below:

    The letterA is used to denote actions -this includes concentrated forces and

    couples. Internal forces and moments at reactions are also considered actions.

    The letterD is used to denote displacements -this includes translations and

    rotations.

    Consider the beam shown below subjected to several actions producing several

    displacements:

    At each node there are three possible displacements for this two dimensional structure:

    two translations and a rotation.

    Clearly three actions are identified as

    well as three displacements.

    Intuitively the actions and

    displacements are associated with

    nodes located at the points ofapplication ofA1,A2, andA3. A2 and

    A3 are applied at the same node.

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    If we can determine the quantitiesD11 throughD33 then by superposition each displacement

    can be written as follows:

    3332313

    2322212

    1312111

    DDDD

    DDDD

    DDDD

    Each action may

    contribute to each

    displacement identified.

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    Lecture 4: PRELIMINARY CONCEPTS OF

    STRUCTURAL ANALYSIS

    Equilibrium

    The objectives of any structural analysis is the determination of reactions at supports and

    internal actions (bending moments, shearing forces, etc.). A correct solution for any of thesequantities must satisfy the equations of equilibrium:

    In the stiffness method of analysis the equilibrium conditions at the joints of the structure are

    the basic equations that are solved.

    000 ZYX MMM

    000 ZYX FFF

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    Compatibility

    The continuity of the displacements throughout the structure must be satisfied in a correct

    structural analysis. This is sometimes referred to as conditions of geometry.

    As an example, compatibility conditions must be satisfied at all points of support. If a

    horizontal roller support is present then the vertical displacement must be zero at that support.

    We always impose compatibility at a joint. If two structural elements frame into a joint then

    there displacements and rotations at the connection must be the same or consistent with each

    other.

    We apply a much more rigorous mathematical definition in CVE 604 for compatibility. It is

    simply noted here that strain is a function of displacement. There are 6 components of strain

    and only 3 components of displacement at a point in a three dimensional analysis. A

    compatible displacement field will produce an appropriate state of strain at a point.

    Flexibility methods use equations that express the compatibility of the displacements.

    Understanding this issue as it applies to structural analyses give the student a better feel as

    to how a structure behaves and an ability to judge the correctness of a solution.

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    Lecture 4: PRELIMINARY CONCEPTS OF

    STRUCTURAL ANALYSIS

    Static And Kinematic Indeterminacy

    There are two types of indeterminacy to consider depending on whether actions or

    displacements are of interest. When actions are the unknowns which is typical for theflexibility method, then static indeterminacy is of paramount interest. From your early

    undergraduate education this meant that there were an excess of unknowns relative to the

    number of equations of static equilibrium

    The beam in (a) isstatically

    indeterminate to

    the first degree.

    The truss in (c) is

    statically

    indeterminate to

    second degree.

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    One of these four unknown is referred to as a static redundant. The number of static

    redundant represents the degree of static indeterminacy of the structures

    3

    4

    )(

    NESE

    NUA

    RMRHUAActionsUnknown BAAA

    Let

    NUA = Number of unknown actions

    NESE = Number of equations of static equilibrium

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    A distinction may also be made between external and internal indeterminacy. The

    beam in the previous slide is externally statically indeterminate to the first degree.

    The truss below is determinate from the standpoint that we could calculate thereactions given the loads applied. However, we would be unable to find the internal

    forces in the cross members. The truss is internally indeterminate to the second

    degree.

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    Lecture 4: PRELIMINARY CONCEPTS OF

    STRUCTURAL ANALYSIS

    Two Dimensional Trusses

    Degree of static indeterminacy = (b + r) - (2j)

    b = number of members

    r = number of reactions

    j = number of joints (this includes

    the joints at the reactions)

    Criteria In Determining Static Indeterminacy

    Two Dimensional Beams

    Degree of static indeterminacy = r - (c + 3)

    r = number of reactions

    c = number of internal conditions (c = 1 for a hinge; c = 2 for a roller; andc = 0 for a

    structure with no geometric instability)

    Three Dimensional Trusses

    Degree of static indeterminacy = (b + r) - (3j)

    b = number of members

    r = number of reactions

    j = number of joints (this includes the

    joints at the reactions)

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    Two Dimensional Frames

    Degree of static indeterminacy = (3b + r) - 3j

    b = number of members

    r = number of reactions

    j = number of jointsc = number of internal conditions

    Three Dimensional Frames

    Degree of indeterminacy = (6b + r) - 6j

    b = Number of members

    r = Number of reactions

    j = Number of joints

    c = Number of internal conditions

    Criteria In Determining Static Indeterminacy (continued)

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    Lecture 4: PRELIMINARY CONCEPTS OF

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    For the stiffness method the displacements at the joints are unknown quantities. Thus

    kinematic indeterminacy is important here. When a structure is subjected to loads each joint

    may undergo translations and/or rotations. At supports some displacements will be known,

    others will not. The number of unknown joint displacements corresponds to the kinematicindeterminacy of structure. Reconsider the beams and the truss from the previous slide.

    The beam in (a) is

    kinematically

    indeterminate to the

    second degree.

    The beam in (b) is

    kinematically

    determinate. All jointdisplacements are

    known, i.e., they are all

    zero (displacements

    and rotations).

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    Lecture 4: PRELIMINARY CONCEPTS OF

    STRUCTURAL ANALYSIS

    Consider the beam in Figure (a). At joint A the beam is fixed and cannot undergo any joint

    displacement. However at joint B the beam is free to translate in the horizontal direction

    and rotate in the plane of the beam. Thus the beam is kinematically indeterminate to the

    second degree.

    The truss in in (c) can undergo two displacements at each joint. Although rotations can take

    place at each joint, since moments cannot be sustained at truss joints, rotations have no

    physical significance in this problem. The truss is kinematically indeterminate to the ninth

    degree.

    Often structural members are very stiff in the axial direction. Thus very little axial

    displacement will take place. Removing the axial load or deformation from the system ofunknowns can reduce the degree of indeterminacy of the structure.

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    Lecture 4: PRELIMINARY CONCEPTS OF

    STRUCTURAL ANALYSIS

    Mobile Structures

    When the number of reactive forces is greater than the number of equations of static

    equilibrium for the entire structure taken as a free body, the structure is statically

    indeterminate

    However a problem can appear to be statically determinate when it is not. Consider the

    beam above. This is a planar problem. Thus in general there are three equations of

    statics available namely

    But the summation of forces in the x-direction is not applicable, and the structure is

    mobile.

    000 ZYX MFF