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7/24/2019 Pressure Compensated Temperature
1/1
Pressure Compensated Temperature
Temperaturein F
100 105 110 120 130 140
Temperaturein K
310.927778 313.7056 316.4833 322.0389 327.5944 333.15 338.7
Butane 50% 25.12 27.11 29.22 33.78 38.85 44.44 50Pentane 50% 7.79 8.54 9.35 11.16 13.22 15.56 18
Ptotal PSI 32.91 35.65 38.57 44.94 52.06 59.99 68
Ptotal PSI 32.91 35.65 38.57 44.94 52.06 59.99 68.78T in F 100 105 110 120 130 140 150
P !ompen"ate# T $ T 267.8659 &157.664 ' lo( )PSI*
Can you fit the data into this formula
T PC = Tmeas+ (A-K log P)
using Excel or Polymath
The ans!er is
T PC = Tmeas+ (267.8659 157.664log P)