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8/12/2019 Preliminary&Secondary Treatment_Group 2.pptx
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Wastewater TreatmenAran ~ Miranda ~ Riego ~ Santos ~ Sy
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Why Treat Wastewater?
To protect the wildlife that call those environments
Causes a demand for dissolved oxygen (lower DO le
streams)
Increases suspended solids or sediments in stream
(turbidity increase)
In some cases, wastewater can be clean enough for
particular purposes
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Why Treat Wastewater?
Wastewater treatment is important to remov
constituents or contaminants that could harmor the environment.
Common constituents in domestic wastewate Organics
Solids
Nutrients Pathogens
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What happens to treated Wastew
Treated wastewater (effluent) may bedischarged to a nearby water body suchstream or lake.
It may also be reused, for example, for ir
or industrial processes.
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Preliminary Treatment
Mechanical screens remove materials like rags, stic
Grit removal processes remove grit, sand and granumaterials.
Grit removal is the forced separation of gritty mater
sand, egg shells, seeds, etc.) from wastewater.
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Materials removed
fats, oils, and greases (aka FOG)
sand, gravels and rocks (aka grit)
larger settleable solids including human
and
floating materials
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Primary Treatment
A physical process.
Wastewater flow is slowed down and suspen
solids settle to the bottom by gravity.
The material that settles is called sludge or b
Primary treatment reduces the suspended s
the B.O.D. of the wastewater.
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Primary Treatment
Sludge from the primary sedimentation tankpumped to the sludge thickener.
From the primary treatment tanks water is p
the trickling filter for secondary treatment.
Sludge is scraped from the bottom of the tank
hopper, and is pumped from the tank for pro
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Primary Sedimentation
Primary sedimentation is the oldest and m
used form of wastewater treatment.
Sedimentation describes the tendency of floasuspended particles to settle to the bottom oby gravity.
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SECONDARY TREATMENT PROCESS
Activated sludge Trickling filter
Non-electric secondary filtration (FilterPod)
Oxidation ponds
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Biological Wastewater Treatm
Principal Goals
Many of the microbes present in wastewater are befact, many wastewater treatment technologies are d
on these beneficial microorganisms for remediation
wastewater so that it won't detrimentally impact th
environment. One of the primary goals of biological
is the removal of organic material from wastewaterexcessive oxygen consumption won't become a prob
it is released to the environment.
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Waste
DO
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TRICKLING FILTER
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TRICKLING FILTER
A trickling filter consists of a bed of highly permeable media on whose
mixed population of microorganisms is developed as a slime layer.
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TRICKLING FILTER
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TRICKLING FILTER
Pros:
Low construction cost
Cheap oxygen delivery
Non-electric systems available
Cons:
Temperature Dependent
Vulnerable to congestion, which can lead to flooding and system failure, low oxygen
restricted water flow
Can occupy a larger area than activated sludge
High Maintenance on some older types
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COMMON PROBLEMS
Pondingis normally the result of:
(a) excessive organic loading without a correspondin
recirculation rate,
(b) use of media which is too small,
(c) clogging of underdrain system,
(d) non-uniform media size or breaking up of media,
(e) trash or debris in filter voids
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COMMON PROBLEMS
Odors
Since the trickling filter is an aerobic process, no seshould exist.
If foul odors are present, anaerobic conditions arlikely cause.
Anaerobic conditions usually predominate next tosurface.
If the surface of the slime growth is aerobic, odorminimal.
If odors are present, corrective action shouldimmediately or the condition could get worse.
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COMMON PROBLEMS
It can be eliminated by:
Check the ventilation of the filter for clogging and stoppages.
Check the underdrain system for clogging and stoppages.
Increase recirculation rate; this usually provides added oxyg
filter and may increase sloughing.
Keep wastewater in filter; do not allow it to splash on expose
weeds, or grass.
Add odor-masking agents.
Pre-chlorination at primary tank influent or at the dosing tan
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COMMON PROBLEMS
Weather Problems.
Cold weather can cause an occasional build-up of ice on the
distributor arms and orifices, resulting in operating problem
efficiency.
During cold temperatures, the organism's metabolic proces
and as a result efficiency decreases.
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COMMON PROBLEMS
It can be eliminated by:
Decrease the recirculation rate to prevent splashing at distrib
but maintain sufficient flow to keep the filter working.
Adjust orifices at splash plates to reduce the spraying effect.
Construct wind screens or covers to reduce heat loss.
Break up any ice build-up.
Partially open flap gates at end of distributor arm to allow fo
water rather than a spray of water.
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Secondary Treatment- Aerati
After leaving the primary clarifiers, the sewage g
one of the aeration tanks. The contents of the aeration tanks, which require
balance of food and oxygen, are commonly referremixed liquor suspended solids (MLSS) or activated activated sludge converts organic substances inproducts and a settleable floc which is settled
secondary clarifiers. Raw sewage can be introducedlocations and be aerated and mixed for varying lengand intensity.
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Aeration Tank
Waste Water
from 1stClarifier
Microbes
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PROCESS (ACTIVATED SLUDG
Biochemical Oxygen Demand and
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Biochemical Oxygen Demand andEutrophication
Biochemical oxidation reactions involve the conver
organic material using oxygen and nutrients into cadioxide, water and new cells. The equation that expis:
Organic material + O2 + nutrients CO2 + H2O + newnutrients + energy
It can be seen from this equation that organisms us
breakdown carbon-based materials for assimilationcell mass and energy. A common measure of this oxbiochemical oxygen demand (BOD).
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Soft and Hard BOD
The time-course for the removal of the organic carbon vthe ability of the activated sludge bacteria to ingest it.
Small molecular weight compounds will start to be remthe sewage immediately after it has entered theactivatetanks. Their removal may be completed in 1 2 hours. Tof compounds is often referred to as the readily biodegSoft BOD. Other, higher molecular weight compounds wseveral hours to be
degraded and removed. Yet other compounds are morerecalcitrant, and may still be present after several daysreadily biodegradable BOD is often referred to as Hard
The net result is that larger, complex organic carbon mobe not be degraded because the treatment time
available (the hydraulic retention time) is not sufficientthey will therefore pass out in the effluent.
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Calculations-Food to Microorganism
The number of microorganisms which are used t
aeration chamber is carefully controlled and isthe food to microorganism ratio (F/Microorganisms will most efficiently break down matter in water if they are present in the right prop
If the appropriate food to microorganism ratio ithen there will be efficient B.O.D. removal in the a
manufacturer, Clow, suggests that the bestmicroorganism ratio is about 0.6.
C l l h F/M R
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Calculating the F/M Ratio
In order to calculate the proper amount of microorg
be added to the aeration basin, you will need to usefollowing formula:
(For the units of the formula to cancel out, you shou
aware that the F/M ratio has no units and the constactually has the units "lb/(Million Gallons per Day(mg/L)".) The formula for the F/M ratio can also be as:
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So let's calculate the pounds of microbes which need
to the aeration basin of a plant over the span of a dahas a capacity (or flow) of 18,000 gallons per day. the water is 200 mg/L. You want to achieve a F/M radetermine the pounds of microbes, first you must mall of the units match. You should notice that you haof 18,000gallons/day while you need your flow
units MGD. So you will need to convert the units:
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Now all of your units match and you can simply pluginto the formula:
So you will need to add 50.04 pounds of microbes tobasin for the day.
R t d A ti t d Sl d
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Returned Activated Sludge
But how do you add 50.04 lbs of microbes to th
basin? You do not have pure microbes available. Ihave a mixture of sludge and microbes from the clamixture is known as Returned Activated Sludgeo
RAS has some typical properties. When dried, 10RAS weighs 5 grams. When cooked at 550C, 10RAS weighs 3 grams. And, most important
calculations, 2% of RAS is microbes. So, if you haveof RAS, 2 grams of this is made up of microbes.
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Thank You!