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Name: ___________________________________ Block: ___________ Date: _________________________
1
Science 10: Physics!
What is acceleration? What is acceleration? Turn to your neighbour and see if you can come up with a definition: What would you need to know in order to measure acceleration? List here: Acceleration is the rate of change in velocity. Velocity and acceleration are vectors, so we need to include the magnitude of the change in velocity of the moving object and indicate the change in direction of the object’s velocity. The object with the greater acceleration, changes its velocity in a shorter time interval or has greater change in velocity during the same time interval. Change velocity faster = greater acceleration. Positive or negative acceleration? Driving a car in the positive direction… When the car’s speed is increasing, the car has a positive acceleration. When the car’s speed is decreasing, the car has a negative acceleration.
Positive and Negative AccelerationWhenever the velocity of an object changes, its motion isnot uniform, and we say that the object is accelerating.Acceleration occurs when the speed of an object changes,or its direction of motion changes, or both.
Positive accelerationWhen you think of acceleration, you probably think ofsomething speeding up. However, an object that isslowing down is also changing its velocity and thereforeis accelerating. In straight-line motion, acceleration canbe either positive or negative.
Imagine you are driving along a straight, level road at 40 km/h. Sinceyour velocity is constant, you are travelling with a relatively uniform motionand passengers in your car will be experiencing a smooth ride. If you need to speed up to 60 km/h, you must press on the accelerator pedal(Figure 9.6). Suppose the forward motion of the car is represented aspositive (!). When the car’s speed is increasing, the car has a positiveacceleration.
Negative accelerationIf you need to slow down, you press on the brake pedal (Figure 9.6).Again, suppose the forward motion of the car is represented as positive (!).When the car’s speed is decreasing, the car has a negative acceleration.
Acceleration is the rate of change in velocity. Therefore, the directionof the acceleration is the same direction as the change in velocity. If anobject’s acceleration is in the same direction as its velocity, the object’sspeed increases (Figure 9.7A). If the acceleration is in an oppositedirection to its velocity, the object’s speed decreases (Figure 9.7B).Acceleration that is opposite to the direction of motion is sometimescalled deceleration (Figure 9.8 on the next page).
Chapter 9 Acceleration is the rate of change in velocity. • MHR 385
Figure 9.6 A more common name forthe accelerator pedal is the gas pedal.
brake pedal accelerator pedal
If forward motion is represented aspositive, the speed of this car is decreasingso the car has negative acceleration (B).
If forward motion is represented as positive,the speed of this car is increasing so thecar has positive acceleration (A).
Figure 9.7 The speed of both cars is changing, so they are both accelerating.
acceleration
velocity
acceleration
velocity
A B
BCS10_C09_F 3/9/08 2:53 PM Page 385
If a car is driving forward and increases its velocity from +2 m/s to +6 m/s. If forward motion is positive, then the change in velocity is + 4 m/s. If forward motion is positive, then the change in velocity is positive.
If a car’s velocity as it travels backward changes from – 1m/s to – 4 m/s, the change is velocity is – 3 m/s. If a car is increasing its speed going backwards then the velocity is negative and the change in velocity is negative.
386 MHR • Unit 3 Motion
DirectionPositive (!) and negative (") acceleration are also dependent upon thedirection of an object’s motion. Suppose a car driving forward increasesits velocity from 2 m/s to 6 m/s (Figure 9.9A). If forward motion ispositive (!), then the change in velocity would be !4 m/s. Because thechange in velocity is positive (!), which represents forward, theacceleration must also be forward.
Suppose that a different car is increasing its speed going backward(Figure 9.9B). If we define forward motion as positive (!), thenbackward motion must be negative ("). If the car’s velocity as it travelsbackward changes from "1 m/s to "4 m/s, the change in velocitywould be "3 m/s. Because the change in velocity is negative ("), whichrepresents backward, the direction of the change in velocity, andtherefore acceleration, must also be backward.
Figure 9.9A Since the carspeeds up in a forwarddirection, its sign ispositive (!).
Figure 9.9B Since the carspeeds up in a backwarddirection, its sign isnegative (").
Find out more about theeffects of acceleration onthe human body. Startyour search atwww.bcscience10.ca.
Conduct an Investigation 9-1Don page 388
Suggested Activity
Figure 9.8 A parachute reduces the landing run of a space shuttle, reducing wear on the brakes andproviding increased directional stability.
BCS10_C09_F 3/9/08 2:54 PM Page 386
386 MHR • Unit 3 Motion
DirectionPositive (!) and negative (") acceleration are also dependent upon thedirection of an object’s motion. Suppose a car driving forward increasesits velocity from 2 m/s to 6 m/s (Figure 9.9A). If forward motion ispositive (!), then the change in velocity would be !4 m/s. Because thechange in velocity is positive (!), which represents forward, theacceleration must also be forward.
Suppose that a different car is increasing its speed going backward(Figure 9.9B). If we define forward motion as positive (!), thenbackward motion must be negative ("). If the car’s velocity as it travelsbackward changes from "1 m/s to "4 m/s, the change in velocitywould be "3 m/s. Because the change in velocity is negative ("), whichrepresents backward, the direction of the change in velocity, andtherefore acceleration, must also be backward.
Figure 9.9A Since the carspeeds up in a forwarddirection, its sign ispositive (!).
Figure 9.9B Since the carspeeds up in a backwarddirection, its sign isnegative (").
Find out more about theeffects of acceleration onthe human body. Startyour search atwww.bcscience10.ca.
Conduct an Investigation 9-1Don page 388
Suggested Activity
Figure 9.8 A parachute reduces the landing run of a space shuttle, reducing wear on the brakes andproviding increased directional stability.
BCS10_C09_F 3/9/08 2:54 PM Page 386
Name: ___________________________________ Block: ___________ Date: _________________________
2
Change in velocity Change in velocity is calculated by subtracting the initial velocity from the final velocity. Δv = vf -‐ vi Part 1: You are riding a bicycle. Give an example in words, and with numbers, of (a) a positive change in velocity You are riding a bicycle travelling forward at 6 m/s. You are late, so you increase your velocity to 9 m/s forward. Δv = vf -‐ vi = + 9 m/s – ( + 6 m/s) = + 3 m/s You are speeding up by 3 m/s in the original direction. Your initial forward direction is positive, so your change in velocity is positive when you speed up. (b) a negative change in velocity You are riding a bicycle forward at 9 m/s, you slow down to 2 m/s. Δv = vf -‐ vi = + 2 m/s – ( + 9 m/s) = -‐7 m/s You are slowing down by 7 m/s in the original direction. Your initial forward direction is positive, so your change in velocity is negative when you slow down. (c) constant velocity If your initial and final velocities are equal, your change in velocity, Δv, would be zero. Part 2: Using your examples from part 1, find the acceleration if the change in velocity occurred in a 10 s time interval. a = Δv/Δt a) b) c) Determining motion from a velocity-‐time graph
Chapter 9 Acceleration is the rate of change in velocity. • MHR 395
Time (s)
Velo
city
(m/s
[nor
th])
0 t 1 t 2 t 3
Velocity vs. Time
Figure 9.12 The graph shows motion with positiveacceleration (0 to t1), zeroacceleration (t1 to t2), andnegative acceleration (t2 to t3).
Determining Motion from a Velocity-Time GraphFigure 9.12 represents the motion of a school bus that has three differentmotions with uniform acceleration. Table 9.2 summarizes the motiondepicted by the graph.
Assume that the positive direction has been chosen to be north. Noticethe following information shown on the graph.– During the time interval 0 to t1, the school bus has a constant
positive acceleration, which indicates that it increases its velocity [N]at a constant rate.
– From t1 to t2, the school bus has a zero acceleration, which indicatesthat it maintains a constant velocity [N]. In other words, the schoolbus heads north with a constant speed.
– During the time interval t2 to t3, the school bus has a constantnegative acceleration, which indicates that it uniformly decreases itsvelocity [N] until it stops. During this negative acceleration, thepassengers are still moving forward while slowing down.
– During the complete 0 to t3 time interval, the school bus has beenmoving north, and therefore its final displacement would be northfrom where it started.
Reading Check1. What does the slope of a velocity-time graph represent?2. State what a straight line on a velocity-time graph indicates about:
(a) an object’s change in velocity (b) an object’s acceleration
Table 9.2 Motion of a School Bus
Time interval 0 to t1 t1 to t2 t2 to t3
Acceleration Positive [N] Zero Negative [S]
Velocity Starts from rest Travels north at Slows down to a and increases speed a constant speed stop at a constantat a constant rate rate while stilltravelling north travelling north
BCS10_C09_F 3/11/08 5:38 PM Page 395
Chapter 9 Acceleration is the rate of change in velocity. • MHR 395
Time (s)
Velo
city
(m/s
[nor
th])
0 t 1 t 2 t 3
Velocity vs. Time
Figure 9.12 The graph shows motion with positiveacceleration (0 to t1), zeroacceleration (t1 to t2), andnegative acceleration (t2 to t3).
Determining Motion from a Velocity-Time GraphFigure 9.12 represents the motion of a school bus that has three differentmotions with uniform acceleration. Table 9.2 summarizes the motiondepicted by the graph.
Assume that the positive direction has been chosen to be north. Noticethe following information shown on the graph.– During the time interval 0 to t1, the school bus has a constant
positive acceleration, which indicates that it increases its velocity [N]at a constant rate.
– From t1 to t2, the school bus has a zero acceleration, which indicatesthat it maintains a constant velocity [N]. In other words, the schoolbus heads north with a constant speed.
– During the time interval t2 to t3, the school bus has a constantnegative acceleration, which indicates that it uniformly decreases itsvelocity [N] until it stops. During this negative acceleration, thepassengers are still moving forward while slowing down.
– During the complete 0 to t3 time interval, the school bus has beenmoving north, and therefore its final displacement would be northfrom where it started.
Reading Check1. What does the slope of a velocity-time graph represent?2. State what a straight line on a velocity-time graph indicates about:
(a) an object’s change in velocity (b) an object’s acceleration
Table 9.2 Motion of a School Bus
Time interval 0 to t1 t1 to t2 t2 to t3
Acceleration Positive [N] Zero Negative [S]
Velocity Starts from rest Travels north at Slows down to a and increases speed a constant speed stop at a constantat a constant rate rate while stilltravelling north travelling north
BCS10_C09_F 3/11/08 5:38 PM Page 395