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Proc. Indian Acad. Sci. (Math. Sci.) Vol. 124, No. 3, August 2014, pp. 457–469. c Indian Academy of Sciences On quadratic variation of martingales RAJEEVA L KARANDIKAR and B V RAO Chennai Mathematical Institute, H1, SIPCOT IT Park, Siruseri 603 103, India E-mail: [email protected]; [email protected] MS received 10 February 2013; revised 21 May 2013 Abstract. We give a construction of an explicit mapping : D([0, ), R) D([0, ), R), where D([0, ), R) denotes the class of real valued r.c.l.l. functions on [0, ) such that for a locally square integrable martingale (M t ) with r.c.l.l. paths, (M.(ω)) = A.(ω) gives the quadratic variation process (written usually as [M,M] t ) of (M t ). We also show that this process (A t ) is the unique increasing process (B t ) such that M 2 t B t is a local martingale, B 0 = 0 and P((B) t =[(M) t ] 2 , 0 <t< ) = 1. Apart from elementary properties of martingales, the only result used is the Doob’s max- imal inequality. This result can be the starting point of the development of the stochastic integral with respect to r.c.l.l. martingales. Keywords. Doob–Meyer decomposition; martingales; quadratic variation. Mathematics Subject Classification. 60G44, 60G17, 60H05. 1. Introduction The Doob–Meyer decomposition of square of a (square integrable) martingale was a landmark result that led to the development of stochastic integration with respect to a martingale (as outlined by Doob). Meyer [7, 8] showed that there exists a unique natural increasing process (A t ) such that A 0 = 0 and M 2 t A t is a martingale. This decompo- sition plays a central role in the theory of stochastic integration [9, 10]. There have been several attempts, including in recent times, at giving simpler proofs of the Doob–Meyer decomposition for pedagogical reasons (see [1, 2, 11]). In every exposition of stochastic integration for semimartingales (which may have jumps), the Doob–Meyer decomposition remains the first important step. The unusual definition of the natural increasing process due to Meyer lead to further study and was characterized to be the same as a predictable increasing process. Let (M t ) be a square integrable martingale with respect to a filtration (F t ). The unique predictable increasing process (A t ) such that A 0 = 0 and M 2 t A t is a martingale has been called the compensator of M 2 t also the predictable quadratic variation of the martingale M and has subsequently been denoted as M,Mt . 457

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  • Proc. Indian Acad. Sci. (Math. Sci.) Vol. 124, No. 3, August 2014, pp. 457469.c Indian Academy of Sciences

    On quadratic variation of martingales

    RAJEEVA L KARANDIKAR and B V RAO

    Chennai Mathematical Institute, H1, SIPCOT IT Park, Siruseri 603 103, IndiaE-mail: [email protected]; [email protected]

    MS received 10 February 2013; revised 21 May 2013

    Abstract. We give a construction of an explicit mapping

    : D([0,),R) D([0,),R),where D([0,),R) denotes the class of real valued r.c.l.l. functions on [0,) suchthat for a locally square integrable martingale (Mt ) with r.c.l.l. paths,

    (M.()) = A.()gives the quadratic variation process (written usually as [M,M]t ) of (Mt ). We alsoshow that this process (At) is the unique increasing process (Bt ) such that M2t Bt isa local martingale, B0 = 0 and

    P((B)t = [(M)t ]2, 0 < t < ) = 1.Apart from elementary properties of martingales, the only result used is the Doobs max-imal inequality. This result can be the starting point of the development of the stochasticintegral with respect to r.c.l.l. martingales.

    Keywords. DoobMeyer decomposition; martingales; quadratic variation.

    Mathematics Subject Classification. 60G44, 60G17, 60H05.

    1. Introduction

    The DoobMeyer decomposition of square of a (square integrable) martingale was alandmark result that led to the development of stochastic integration with respect to amartingale (as outlined by Doob). Meyer [7, 8] showed that there exists a unique naturalincreasing process (At ) such that A0 = 0 and M2t At is a martingale. This decompo-sition plays a central role in the theory of stochastic integration [9, 10]. There have beenseveral attempts, including in recent times, at giving simpler proofs of the DoobMeyerdecomposition for pedagogical reasons (see [1, 2, 11]). In every exposition of stochasticintegration for semimartingales (which may have jumps), the DoobMeyer decompositionremains the first important step. The unusual definition of the natural increasing processdue to Meyer lead to further study and was characterized to be the same as a predictableincreasing process.

    Let (Mt ) be a square integrable martingale with respect to a filtration (Ft ). The uniquepredictable increasing process (At ) such that A0 = 0 and M2t At is a martingale has beencalled the compensator of M2t also the predictable quadratic variation of the martingaleM and has subsequently been denoted as M,Mt .

    457

  • 458 Rajeeva L Karandikar and B V Rao

    For a simple predictable process f given by

    ft () =m1

    j=0aj ()1(sj ,sj+1](t),

    where aj is a Fsj measurable bounded r.v. for 0 j < m; 0 = s0 < si < < sm,m 1, the stochastic integral can be defined as

    Xt = t

    0f dM =

    m1

    j=0aj (Mtsj+1 Mtsj ).

    It is easy to check that (Xt) is a martingale and using that M2t M,Mt is a martingale,one checks that X2t Bt is a martingale, where

    Bt =m1

    j=0a2j

    (M,Mtsj+1 M,Mtsj) =

    t

    0f 2s dM,Ms .

    Using Doobs maximal inequality, one can deduce

    E

    (sup

    0st

    s

    0f dM

    2)

    4E( t

    0f 2s dM,Ms

    ). (1.1)

    The process M,Mt can be shown to be the limit in probability

    Ant =

    j=0E((Mttnj+1 Mttnj )2 | Ftnj ),

    where 0 = tn0 < tn1 < < tnm < are a sequence of partitions of [0,) such thattnj as j for each n and n = supj |tnj+1 tnj | 0 as n .

    Meyer [9] introduced [M,M]t via Mc,Mc and Ms (where Mc is the continuousmartingale part of M) and showed that it is the limit in probability of

    Bnt =

    j=0(Mttnj+1 Mttnj )2.

    He also showed that for a continuous martingale M , [M,M]t = M,Mt .For a continuous local martingale M , it was shown in Karandikar [3] that for suitably

    chosen sequence of random partitions {ni : i 0} the quadratic variation

    Qnt =

    j=0(Mtnj+1 Mtnj )2 (1.2)

    converges almost surely to M,Mt . The random partitions were defined as follows: n0 =0 and for each n, {ni : i 1} is defined inductively by

    ni+1 = inf{t ni : |Mt Mni | 2n}.

  • On quadratic variation of martingales 459

    The proof relied on the theory of stochastic integration. Subsequently, in Karandikar[4], the formula was derived using only Doobs maximal inequality. Thus this could be thestarting point for the development of stochastic calculus for continuous semimartingaleswithout bringing in any results from general theory of processes (see [5]).

    The almost sure convergence of Qnt to M,Mt also gives a pathwise formula forthe quadratic variation of a continuous local martingale. It also directly shows that for acontinuous local martingale M , the process M,Mt does not depend upon the underly-ing filtration and nor does it depend upon the underlying probability measure (see [6]).Indeed, in [6], a pathwise formula for [M,M]t when M is an r.c.l.l. martingale wasobtained, but the proof depended upon the theory of stochastic integration.

    In this article, we show (once again using only Doobs maximal inequality) that for anysquare integrable r.c.l.l. martingale (Mt), the processes Qnt defined by

    Qnt =

    j=0(Mtnj+1 Mtnj )2

    converge almost surely uniformly on t [0, T ] for all T < to the quadratic variation[M,M]t and that Xt = M2t [M,M]t is a martingale.Once we have shown the existence of [M,M]t , one can get an estimate analogous to(1.1) for simple predictable processes f :

    E

    (sup

    0st

    s

    0f dM

    2)

    4E( t

    0f 2s d[M,M]s

    )(1.3)

    and this instead of (1.1) could be used as a starting point for developing stochastic cal-culus for locally square integrable martingales, bypassing completely the Doob Meyerdecomposition. This approach is being taken in a book under preparation.

    We give an explicit construction of a mapping on the set of r.c.l.l. functions on [0,)such that for a r.c.l.l. martingale M ,

    (M()) = [M,M]()yields the quadratic variation of M .

    2. The quadratic variation map

    Let D([0,),R) denote the space of r.c.l.l. functions on [0,). For D([0,),R),(t) denotes the left limit at t (for t > 0) and (0) = 0 and (t) = (t) (t).We will now define quadratic variation () of a function D([0,),R).

    For each n 1, let {tni () : i 1} be defined inductively as follows: tn0 () = 0 andhaving defined tni (), let

    tni+1() = inf{t > tni () : |(t) (tni ())| 2n

    or |(t) (tni ())| 2n}.

    Note that for each D([0,),R) and for n 1, tni () as i (if limi tni () =t < , then the function cannot have a left limit at t). Let

    n()(t) =

    i=0

    ((tni+1() t) (tni () t)

    )2.

  • 460 Rajeeva L Karandikar and B V Rao

    Since tni () increases to infinity, for each and t fixed, the infinite sum appearing aboveis essentially a finite sum and hence n() is itself an r.c.l.l. function. The space D =D([0,),R) is equipped with the topology of uniform convergence on compact subsets(abbreviated as ucc). Let D denote the set of D such that n() converges in the ucctopology and

    () ={

    limn n(), if D,0, if D.

    Here are some basic properties of the quadratic variation map .

    Lemma 2.1. For D,(i) () is an increasing function,(ii) ()(t) = ((t))2 for all t (0,),(iii) st ((s))2 < for all t (0,),(iv) let ()(t) = ()(t) 0 0,()(t) = 0 implies that (t) = 0.

    On the other hand, let t > 0 be a discontinuity point for . Let us note that by thedefinition of tnj (),

    |(u) (v)| 2.2n u, v [tnj (), tnj+1()). (2.5)

    Thus for n such that 2.2n < ()(t), t must be equal to tnk () for some k 1 since(2.5) implies (v) 2.2n for any v j (tnj (), tnj+1()). Let sn = tnk1(), wheret = tnk () and s = lim infn sn. We will prove that

    limn

    (sn) = (t), limn

    n()(sn) = ()(t). (2.6)

  • On quadratic variation of martingales 461

    If s = t , then sn t for all n 1 implies sn t and (2.6) follows from the uniformconvergence of n() to () on [0, t].

    If s < t , using (2.5) it follows that |(u) (v)| = 0 for u, v (s, t) and hencethe function (u) is constant on the interval (s, t) and implies that sn s. Also,(s) = (t) and ()(s) = ()(t). So if is continuous at s, once againuniform convergence of n() to () on [0, t] shows that (2.6) is valid in this case too.

    It remains to consider the case s < t and (s) = > 0. In this case, for n such that2.2n < , sn = s and uniform convergence of n() to () on [0, t] shows that (2.6)is true in this case as well.

    We have, for large n,

    n()(t) = n()(sn) + ((sn) (t))2 (2.7)

    and hence (2.6) yields

    ()(t) = ()(t) + [(t)]2

    completing the proof of (ii).(iii) follows from (i) and (ii) since for an increasing function that is non-negative at

    zero, the sum of jumps up to t is at most equal to its value at t :

    0

  • 462 Rajeeva L Karandikar and B V Rao

    Proof. For (i), it can be checked from the definition that

    n()(t sk) = n(k)(t) , t . (2.9)

    Since k D, it follows that n()(t) converges uniformly on [0, sk] for every k andhence using (2.9) we conclude that D and that (2.8) holds.

    For (ii), note that being a continuous function,(tni+1() t) (tni () t)

    2n

    for all i, n and hence we have

    n()(t) =

    i=0

    ((tni+1() t) (tni () t)

    )2

    2n

    i=0

    (tni+1() t) (tni () t)

    2n Var[0,T ]().

    This shows that ()(t) = 0 for t [0, T ].

    3. Quadratic variation of a martingaleThe next lemma connects the quadratic variation map and r.c.l.l. martingales.

    Lemma 3.3. Let (,F , P ) be a complete probability space and let (Ft ) be a filtrationwith F0 containing all null sets in F .

    Let (Nt ,Ft ) be an r.c.l.l. martingale such that E(N2t ) < for all t > 0. Suppose thereis a constant C < such that with

    = inf{t 0 : |Nt | C or |Nt| C}

    one has

    Nt = Nt .Let

    [N,N]t () = [(N.())](t).Then ([N,N]t ) is an (Ft ) adapted r.c.l.l. increasing process such that Xt := N2t [N,N]tis also a martingale.

    Proof. Let n() and tni () be as in the previous section.Ant () = n(N.())(t), ni () = tni (N.()),Y nt () = N2t () N20 () Ant (). (3.10)

  • On quadratic variation of martingales 463

    It is easy to see that {ni : i 1} are stopping times (for each n by induction on i) and that

    Ant =

    i=0(Nn

    i+1t Nni t )2.

    Further, for each n, ni () increases to as i . We will first prove that for each n, (Y nt ) is an (Ft ) martingale. Using the identity b2

    a2 (b a)2 = 2a(b a), we can write

    Ynt = N2t N20

    i=0(Nni+1t Nni t )2

    =

    i=0(N2ni+1t N

    2ni t )

    i=0(Nn

    i+1t Nni t )2

    = 2

    i=0Nni t (Nni+1t Nni t ).

    Let us define

    Xn,it = Nni t (Nni+1t Nni t ).

    Then

    Ynt = 2

    i=0X

    n,it . (3.11)

    Noting that for s < , |Ns | C and for s , Ns = N , it follows that

    (Nni+1t Nni t ) > 0 implies that |Nni t | C.

    Thus, writing C(x) = max{min{x,C},C} (x truncated at C), we have

    Xn,it = C(Nni t )(Nni+1t Nni t ) (3.12)

    and hence, Xn,it is a martingale. Using the fact that Xn,it is Ftni+1 measurable and that

    E(Xn,it |Ftni ) = 0, it follows that for i = j,

    EXn,it X

    n,jt = 0 (3.13)

    Also, using (3.12) and the fact that N is a martingale, we have

    E(Xn,it )

    2 C2E{Nni+1t N.ni t }2

    = C2E{N2ni+1t N2ni t }. (3.14)

  • 464 Rajeeva L Karandikar and B V Rao

    Using (3.13) and (3.14), it follows that for s r ,

    E

    (r

    i=sX

    n,it

    )2 C2E{N2nr+1t N

    2ns t }. (3.15)

    Since ni increases to as i tends to infinity, E(N2ns t ) and E(N2nr+1t ) both tend toE[N2t ] as r, s tend to and hence

    ri=1 X

    n,it converges in L2(P). In view of (3.11), one

    has

    2r

    i=1X

    n,it Ynt in L2(P) as r

    and hence (Y nt ) is an (Ft )-martingale for each n 1.For n 1, define a process (Nn) by

    Nnt = N(ni ) if ni t < ni+1.

    Observe that by the choice of {ni : i 1}, one has

    |Nt Nnt | 2n for all t . (3.16)

    For now, let us fix n. For each , let us defineE() = {ni () : i 1} {n+1i () : i 1}. (3.17)

    It may be noted that for such that t Nt() is continuous, each nj () is necessarilyequal to ni+1() for some i, but this need not be the case when t Nt() has jumps.Let 0() = 0 and for j 0, let

    j+1() = inf{s > j () : s E()}.It can be verified that

    {i : i 1} = {ni : i 1} {n+1i : i 1}. (3.18)To see that each i is a stop time, fix i 1, t < . Let Akj = {(nk t) = (n+1j t)}.Since nk ,

    n+1j are stopping times, Akj Ft for all k, j . It is not difficult to see that

    {i t} =i

    k=0({nik t}

    Bk),

    where B0 = and for 1 k i,

    Bk =

    0

  • On quadratic variation of martingales 465

    Using (3.18) and using the fact that Nnt = Ntnj for nj t < nj+1, one can write Ynand Yn+1 as

    Ynt =

    j=02Nntj {Ntj+1 Ntj },

    Y n+1t =

    j=02Nn+1tj {Ntj+1 Ntj }.

    Hence

    Yn+1t Ynt = 2

    j=0Z

    n,jt , (3.19)

    where

    Zn,jt = (Nn+1tj Nntj )(Ntj+1 Ntj ).

    Also, using (3.16) one has

    |Nn+1t Nnt | |Nn+1t Nt | + |Nt Nnt | 2(n+1) + 2n 2.2n (3.20)

    and hence (using that (Ns) is a martingale), one has

    E[(Zn,jt )2]4

    22nE[(Ntj+1 Ntj )2]=

    422n

    E[(Ntj+1)2 (Ntj )2].(3.21)

    It is easy to see that E(Zn,jt |Ftnj ) = 0 and Zn,jt is Ftnj+1 measurable. It then follows

    that for i = j ,

    E[Zn,jt .Zn,it ] = 0and hence (using (3.21))

    E(Y n+1t Ynt )2 = 4E

    j=0Z

    n,jt

    2

    = 4E

    j=0(Z

    n,jt )

    2

    1622n

    j=0E[(Ntj+1)2 (Ntj )2]

    1622n

    E[(Nt )2]. (3.22)

  • 466 Rajeeva L Karandikar and B V Rao

    Thus, recalling that Yn+1t , Y nt are martingales, it follows that Yn+1t Ynt is also amartingale and thus invoking Doobs maximal inequality, one has (using (3.22))

    E[supsT |Yn+1s Yns |2] 4E(Y n+1T YnT )2

    6422n

    EN2T . (3.23)

    Thus, for each n 1 (writing X2 for the L2(P) norm : X2 =

    (E[X2])),

    [supsT |Yn+1s Yns |] 2 82n

    NT 2. (3.24)

    It follows that

    =

    n=1supsT

    |Yn+1s Yns | < a.s.

    (as 2 < by (3.24)). Hence (Y ns ) converges uniformly in s [0, T ] for every T a.s.to an r.c.l.l. process, say (Ys). As a result, (Ans ) also converges uniformly in s [0, T ] forevery T < a.s. to say (As) with Yt = N2t N20 At . Further, (3.4) also implies thatfor each s, convergence of Yns to Ys is also in L2 and thus (Yt ) is a martingale.

    Since Ans converges uniformly in s [0, T ] for all T < a.s., it follows that

    P( : N() D) = 1and At = [N,N]t . We have already proven that Yt = N2t N20 [N,N]t is a martingale.This completes the proof.

    We are now in a position to prove an analogue of the DoobMeyer decompositiontheorem for the square of an r.c.l.l. locally square integrable martingale.

    Theorem 3.4. Let (,F , P ) be a complete probability space and let (Ft ) be a filtrationwith F0 containing all null sets in F . Let (Mt ,Ft ) be an r.c.l.l. locally square integrablemartingale i.e. there exist stopping times n increasing to such that for each n, Mnt =Mtn is a martingale with E[(Mtn)2] < for all t, n.

    Let

    [M,M]t () = [(M.())](t).Then

    (i) ([M,M]t ) is an (Ft ) adapted r.c.l.l. increasing process such that Xt = M2t [M,M]t is also a local martingale.

    (ii)P([M,M]t = (Mt)2, t > 0) = 1.

    (iii) If (Bt ) is an r.c.l.l. adapted increasing process such that B0 = 0 andP(Bt = (Mt)2, t > 0) = 1

    and Vt = M2t Bt is a local martingale, then P(Bt = [M,M]t , t) = 1.

  • On quadratic variation of martingales 467

    (iv) If M is a martingale and E (M2t)< for all t, then E ([M,M]t ) < for all t and

    Xt = M2t [M,M]t is a martingale.(v) If E ([M,M]t ) < for all t then E

    (M2t

    )< for all t, (Mt ) is a martingale and

    Xt = M2t [M,M]t is a martingale.Proof. For k 1, let k be the stopping time defined by

    k = inf{t > 0 : |Mt | k} k k.

    Then Mkt = Mtk is a martingale satisfying conditions of Lemma 3.3 with C = kand = k and hence Xkt = (Mkt )2 [Mk,Mk]t is a martingale, where [Mk,Mk]t =(Mk ())t . Also,

    P({ : Mk () D}) = 1, k 1. (3.25)

    Since Mkt = Mtk , it follows from Lemma 2.2 that

    P({ : M() D}) = 1 (3.26)and

    P({ : [Mk,Mk]t () = [M,M]tk()()}) = 1.

    It follows that Xtk = Xkt a.s. and since Xk is a martingale for all k, it follows that Xt isa local martingale. This completes the proof of part (i). Part (ii) follows from Lemma 2.1.For (iii), note that

    Ut = [M,M]t Btis a continuous process and recalling Xt = M2t [M,M]t and Vt = M2t Bt are localmartingales, it follows that Ut = Vt Xt is also a local martingale with U0 = 0. Bypart (i) above, Wt = U2t [U,U ]t is a local martingale. On the other hand, Ut being adifference of two increasing functions has bounded variation, VarT (U) < . Since U iscontinuous, by Lemma 2.2,

    [U,U ]t = 0 t .

    Hence Wt = U2t is a local martingale. Now if k are stop times increasing to such thatWtk is a martingale for k 1, then we have

    E[Wtk ] = E[U2tk ] = E[U20 ] = 0and hence U2tk = 0 for each k. This yields Ut = 0 a.s. for every t . This completes theproof of (iii).

    For (iv), we have proven in (i) that Xt = M2t [M,M]t is a local martingale. Let k bestop times increasing to such that Xkt = Xtk are martingales. Hence, E[Xkt ] = 0, or

    E([M,M]tk

    ) = E(M2tk ) E(M20 ). (3.27)

  • 468 Rajeeva L Karandikar and B V Rao

    Invoking Doobs maximal inequality, we have

    E

    [supst

    |M2s |]

    4E[M2t ] < . (3.28)

    Now, M2tk are dominated by the integrable function supst |M2s | and hence M2tkconverges to M2t in L1. By monotone convergence theorem,

    E([M,M]tk) E ([M,M]t ) . (3.29)Thus from (3.27),

    E ([M,M]t ) = E[M2t ] E[M20 ]

    and convergence in (3.29) is in L1. It follows that Xkt converges to Xt in L1(P) and hence(Xt) is a martingale.

    For (v) let k be as in part (iv). One has using (3.27) and that [M,M]t is increasing,

    E[M2tk ] = E[M20 ] + E([M,M]tk) E[M20 ] + E([M,M]t ).

    Now using Fatous lemma, one gets

    E[M2t ] E[M20 ] + E([M,M]t ) < .Now we can invoke part (iv) to complete the proof.

    It may be noted that we have not assumed that the underlying filtration is right-continuous.

    Remark. We conclude with an observation that we cannot get a mapping

    : D([0,),R) D([0,),R)

    such that for any martingale M ,

    (M.()) = M,M.(). (3.30)Let = R and F = B(R), the Borel -field on R. Let X() = and let P denote theprobability measure on (,F) such that X has Gaussian distribution with mean 0 andvariance 2. Let M be defined by

    Mt() = X()1[1,)(t).It is easy to see that M is a martingale with respect to its canonical filtration and

    [M,M]t () = X2()1[1,)(t)while

    M,Mt () = 21[1,)(t).

  • On quadratic variation of martingales 469

    Thus if a mapping satisfying (3.30) exists, then(M())t = 21[1,)(t) a.s.P . (3.31)

    On the other hand, it is well known and easy to see that for any 0 < 1, 2 < , theprobability measures P1 and P2 are mutually absolutely continuous contradicting (3.31).

    Thus for a martingale M , while the -path of the quadratic variation process[M,M] () can be computed using only the path M() of the martingale, the path ofpredictable quadratic variation M,M() cannot be computed or expressed in a similarfashion.

    References

    [1] Bass R F, The DoobMeyer decomposition revisited, Canad. Math. Bull. 39 (1996) 138150

    [2] Beiglbock M, Schachermayer W and Veliyev B, A short proof of the DoobMeyertheorem, Stoch. Process. Appl. 122 (2012) 12041209

    [3] Karandikar R L, Pathwise solution of stochastic differential equations, Sankhya A 43(1981) 121132

    [4] Karandikar R L, On quadratic variation process of a continuous martingales, Ill. J. Math.27 (1983) 178181

    [5] Karandikar R L, Stochastic integration w.r.t. continuous local martingales, Stoch. Pro-cess. Appl. 15 (1983) 203209

    [6] Karandikar R L, On pathwise stochastic integration, Stoch. Process. Appl. 57 (1995)1118

    [7] Meyer P A, A decomposition theorem for supermartingales, Ill. J. Math. 6 (1962) 193205

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    On quadratic variation of martingalesAbstractIntroductionThe quadratic variation mapQuadratic variation of a martingaleReferences