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Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

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Page 1: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Permissible UFLS Time Delays

UFLS SDT August 25-27, 2008 Meeting

Presented by: Rob O’Keefe

Page 2: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Calculated Rate of Hz Decline

 Rate of decline primarily a function of generation deficit and aggregate inertia

 M dw/dt = Pgen – Pload (acceleration equation)

[M is angular momentum, w is angular velocity]

 M = GxH / 180xf (MW-sec**2 / degree), where G = MVA, f = 60 Hz *

dw/dt = (Pgen – Pload) x 180x60 / (GxH) (degrees / sec**2)

 dw/dt = (Pgen – Pload) x 180x60 / (GxHx360) (Hz / sec)

* See Stevenson, eq. 14.7, p. 375. 

Page 3: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Calculated Rate of Hz Decline (cont.)

dw/dt = (Pgen – Pload) x 180x60 / (GxHx360) (Hz / sec)

[RFC MVA weighted average H = 3.96, round to 4.0]

 dw/dt = (Pgen – Pload) x 7.5 / G (Hz / sec)

Assuming 85 % PF…

 dw/dt = (Pgen – Pload) x 6.375 / Pg (Hz / sec)

 Example: 10 % generation deficit causes a .6375 Hz / sec rate

Page 4: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Observed Rate of Hz Decline by Simulation 

Approximately .7 Hz / sec at 14 % generation deficit (.5 Hz / sec at 10 % deficit)

Simulation also includes load and governing effects

Rate = .05 x % deficit (Hz / sec)

Page 5: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Series 1 – No UFLS, 14 percent generation deficit. Island frequency in Hz.

Page 6: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Maximum Permissible UFLS Time Delays 

Goal is to prevent triggering more UFLS stages than necessary to remove the generation deficit or generation-load imbalance

Therefore, when remaining generation-load imbalance is <= the UFLS program step size, time delay must not exceed time required for the next UFLS stage to trigger

The shortest permissible delay is calculated when imbalance = step size x (# steps –1)

This is because an initial imbalance larger than the UFLS program step size will cause a faster Hz / sec rate and will trigger next stages before previously triggered stages shed their load (which is okay until Hz approaches last stage)

Delay should be set so last stage theoretically does not trigger in this case

Page 7: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Example: 3 X 10% steps, 0.4 Hz increment between steps Answer = 36 cycles or .6 seconds total delay

Initial imbalance = -20% (Rate = .05 x 20% = 1.0 Hz/sec) 

Time (seconds)

Stage 1 trigger 0

Stage 1 dump .6

Stage 2 trigger .4

Stage 2 dump 1.0

Stage 3 trigger .4 + .2 (a) + .4 (b) = 1.0

(a) 1.0 Hz/sec x .2 sec = .2 Hz [from .4 to .6 seconds]

(b) .50 Hz/sec x .4 sec = .2 Hz [from .6 to 1.0 seconds]

Page 8: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Example: 3 X 10% steps, 0.3 Hz increment between steps Answer = 27 cycles or .45 seconds total delay

Initial imbalance = -20% (Rate = .05 x 20% = 1.0 Hz/sec) 

Time (seconds)

Stage 1 trigger 0

Stage 1 dump .45

Stage 2 trigger .3

Stage 2 dump .75

Stage 3 trigger .3 + .15 (a) + .30 (b) = .75

(a) 1.0 Hz/sec x .15 sec = .15 Hz [from .30 to .45 seconds]

(b) .50 Hz/sec x .30 sec = .15 Hz [from .45 to .75 seconds]

Page 9: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

3 Step UFLS Program

Permissible Delay (sec) =

( Rate2 / Rate1 ) x ( 2 x Increment / Rate2 - Increment / Rate1)

Rate1 = .05 Hz/sec x Step size (%) x 2

Rate2 = .05 Hz/sec x Step size (%) x 1

Increment = .3 Hz, Step size = 10%, Delay = 27 cycles (MAIN)

Increment = .4 Hz, Step size = 10%, Delay = 36 cycles (MAAC)

Page 10: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Example: 4 X 7% steps, 0.3 Hz increment between steps, delay = .57143 seconds or 34.3 cycles

Initial imbalance = -21% (Rate = .05 x 21% = 1.05 Hz/sec)

 

Time (seconds)

Stage 1 trigger 0

Stage 1 dump .57143

Stage 2 trigger .28572

Stage 2 dump .85715

Stage 3 trigger .28572 + .28572 (a) = .57143

Stage 3 dump 1.14286

Stage 4 trigger .57143 + .28572 (b) + .28572 (c) = 1.14286

(a) 1.05 Hz/sec x .28572 sec = .30 Hz [from .28572 to .57143 seconds]

(b) .70 Hz/sec x .28572 sec = .20 Hz [from .57143 to .85715 seconds]

(c) .35 Hz/sec x .28572 sec = .10 Hz [from .85715 to 1.14286 seconds]

Page 11: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

4 Step UFLS Program

Permissible Delay = Rate2 x Rate3 / ( Rate2 x Rate3 – Rate1 x Rate3 + Rate1 x Rate2 ) x ( Increment / Rate1 - 2 x Increment / Rate2 + 3 x Increment / Rate3 – Increment x Rate2 / ( Rate1 x Rate3 ) )

Rate1 = .05 Hz/sec x Step size (%) x 3

Rate2 = .05 Hz/sec x Step size (%) x 2

Rate3 = .05 Hz/sec x Step size (%) x 1

Increment = .3 Hz, Step size = 7%, Delay = 34.3 cycles

Page 12: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Example: 5 X 5% steps, 0.2 Hz increment between steps, delay = 29.46 cycles or .491 seconds

Initial imbalance = -20% (Rate = .05 x 20% = 1.0 Hz/sec)

 

Time (seconds)

Stage 1 trigger 0

Stage 1 dump .491

Stage 2 trigger .2

Stage 2 dump .691

Stage 3 trigger .4

Stage 3 dump .891

Stage 4 trigger .4 + .091 (a) + ,14533 (b) = .63633

Stage 4 dump 1.12733

Stage 5 trigger .63633 + .05467 (c) + .20 (d) + .23633 (e) = 1.12733

(a) 1.0 Hz/sec x .091 sec = .091 Hz [from .4 to .491 seconds]

(b) .75 Hz/sec x .14533 sec = .109 Hz [from .491 to .63633 seconds]

(c) .75 Hz/sec x .05467 sec = .041 Hz [from .63633 to .691 seconds]

(d) .50 Hz/sec x .20 sec = .10 Hz [from .691 to .891 seconds]

(e) .25 Hz/sec x .23633 sec = .059 Hz [from .891 to 1.12733 seconds]

Page 13: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Example: 5 X 6% steps, 0.2 Hz increment between steps, delay = 24.55 cycles or .4091 seconds

Initial imbalance = -24% (Rate = .05 x 24% = 1.2 Hz/sec)

 

Time (seconds)

Stage 1 trigger 0

Stage 1 dump .4091

Stage 2 trigger .16667

Stage 2 dump .57576

Stage 3 trigger .33333

Stage 3 dump .74243

Stage 4 trigger .33333 + .07577 (a) + .1212 (b) = .5303

Stage 4 dump .9394

Stage 5 trigger .5303 + .04546 (c) + .16667 (d) + .19697 (e) = .9394

(a) 1.2 Hz/sec x .07577 sec = .09092 Hz [from .33333 to .4091 seconds]

(b) .90 Hz/sec x .1212 sec = .10908 Hz [from .4091 to .5303 seconds]

(c) .90 Hz/sec x .04546 sec = .04091 Hz [from .5303 to .57576 seconds]

(d) .60 Hz/sec x .16667 sec = .10 Hz [from .57576 to .74243 seconds]

(e) .30 Hz/sec x .19697 sec = .05909 Hz [from .74243 to .9394 seconds]

Page 14: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

5 Step UFLS Program

Permissible Delay = Rate2 x Rate4 / (Rate2 x Rate4 – Rate1 x Rate4 + Rate1 x Rate2) x ( 2 x Increment / Rate1 – 3 x Increment / Rate2 + 4 x Increment / Rate4 – Increment x ( Rate3 + Rate2) / ( Rate1 x Rate4 ) )

Rate1 = .05 Hz/sec x Step size (%) x 4

Rate2 = .05 Hz/sec x Step size (%) x 3

Rate3 = .05 Hz/sec x Step size (%) x 2

Rate4 = .05 Hz/sec x Step size (%) x 1

Increment = .2 Hz, Step size = 5%, Delay = 29.46 cycles (ECAR)

Page 15: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Conclusion:

Permissible time delays specified under R2.6 are overly conservative and larger values (to within some percentage of the permissible delays in the examples given) should be acceptable

Could we…

(1) Specify a variable permissible time delay in R2.6 using the formulas as a function of UFLS program # steps, step size and step increment with some margin applied, or

(2) Set a time delay value in R2.6 that is comfortably within the examples given for MAAC, ECAR and MAIN legacy UFLS programs?

Page 16: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Of historical interest only…the following slide was a first attempt to determine UFLS time delays considering only generation deficits equal to the step size and time to trigger next stage

It does not consider generation deficits larger than the step size

Page 17: Permissible UFLS Time Delays UFLS SDT August 25-27, 2008 Meeting Presented by: Rob O’Keefe

Maximum Permissible UFLS Time DelaysAssumptions: Aggregate H=4, L-G imbalance <= UFLS step

0

10

20

30

40

50

60

70

0 0.1 0.2 0.3 0.4 0.5 0.6

Hz Increment Between UFLS Steps

Tim

e in

Cyc

les

10%

8%

7%

6%

5%

UFLS

Step

Size