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8/7/2019 PCRailway Engineering Lab update!!
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(Generally tunnels are provided
(Alignment on either side of tunnel is steeper
(not more than ruling grade) shorter tunnel(To achieve the objective of as straight & Level
track as possible, length of track is increased
& grades are kept upto ruling grades, this iscalleddevelopment.
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Direction ofTravel is reversed
for a shortdistance
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(To gain elevation up or down hill, alignment
makes a half circle loop into valley followed
by half circle loop round the hill side
(Excessive cutting & filling is avoided
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Zig zag railway at Lithgow
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(When zig zag development is not feasible for
very steep slopes
(To stop train gradually, without using brakes,vertical curve is provided
(Train stops at switch point (station yards)
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(Track rises on a steady curve until it has
completed a 360 degree loop, passing over
itself until it gains height(Train does not need to stop & reverse
direction
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(Suitable
for narrow
valleys(Swings
around
slope of
valley
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(Curves around slopes of a hill
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(Estimate of traffic in terms of passengers &
wagons
(Possibility of development of naturalresources
(Places of tourism
(Traffic history
(2 3 tentative routes are marked
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(Topography(Towns, existing facilities, crossings(
Geological characteristics(Maximum flood levels(Availability of material(Probable radii of curves
(Total track length(Approximate earth work(Approx. cost of construction of each probable
line
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(2 3 routes are selected for preliminary
survey
(Recommends only one route(Data collected:
(Elevations (levels)
(River crossings
(Existing track
(Land ownership
(Climatic conditions
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(Topographic map is completed
(Longitudinal section of alignment
(Typical cross sections(Length of track
(Gradients
(Cost of subgrade
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(Preliminary survey Paper location (grades,
curves, contours, crossings, etc)
(Finally decided alignment is surveyed in detail(From paper to ground pegs are fixed at
regular intervals
(Demarcation of land width
(Centreline of culverts, bridges
(Position of buildings
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( Geometry Science of properties & relations of lines, surfaces & solids
DesignFinal layout or plan
Geometric Design
Deals with the geometry of track alignment in vertical & horizontalplanes.
Horizontal plane: straight portion, curves, degree, radius
Vertical Plane: Vertical curve, gradient
Combination: Superelevation
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(Superelevation (Cant) Difference in heightbetween the inner & outer rails on the curve
(Equilibrium speed the speed at which the effectof centrifugal force is exactly balanced by the
superelevation provided.
(Maximum permissible speed Highest speed
which may be allowed on a curved track taking intoconsideration the radius of curvature, actual cant,
cant deficiency, cant excess & length of transition
curve
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(Cant Deficiency when a train travels on a
curved track at a speed higher than the
equilibrium speed then cant deficiency occurs.
(Cant Excess when a train travels on a curved
track at a speed lower than the eq. speed, cant
excess occurs
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(Cant Gradient (& Cant Deficiency
Gradient) the amount by which a cant (or
deficiency of cant) is reduced or increased in agiven length of transition
Examples:
1. A gradient of1 in 500 means that cant (or cant
deficiency) of1 mm is attained (or lost) in every 500
mm length of transition
2. 1 in 60
3. 1 in 360Department of Transportation Engineering & Management, UET Lahore 33
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(Rate of Change of Cant (or Cant deficiency)
o The rate at which the cant (or cant deficiency) is
increased with time while passing over the transition
curve.
Examples:
1. 40 mm per second means that a vehicle when travelling
at maximum permitted speed will experience a change incant (or cant deficiency) of 40 mm in each second of
travel over the transition.
2. 2 per second
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( R= Radius of curve (m)
( C= Length ofChord (m)
( V = Versine on chord length C (m)
( By geometry,
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A B
F
D
O
ER
C V
R
CV
CRV
VNeglecting
CVRV
CCCVRV
OBAOODOF
8
42
""4
2
422)2(
2
2
2
22
2
!
!
!
!v!
v!v
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Transition Curve36
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(What is Transition?
Change from one state or condition to another
(Requirement1. Straight section throughout is not always
possible
2. Curves may be introduced to by pass
obstacles or avoid cutting
3. Suppose a curve is provided with a tangent,
what will happen?
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(Increase the radius of curvature graduallyfrom that of the original circular curve until
the radius is infinitely large at the point wherecurve merges into the straight(Increase in curvature must be
Continuous
UniformRapid
(Superelevation: from no cant to full cantgradually within length of transition curve
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(ThreeWays:Case A:Case A: Full cant may be continued through the
whole length of the circular curve & the runoffinthe cant located entirely on the tangent at each
end
Case BCase B Full cant may be applied through thecentral portion of the circular curve & diminish to
zero at the two tangent pointsCase C:Case C: The cant may be located partly on
tangent & partly on the curve having its meanvalue at the tangent points.
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(No matter which of these three are adopted,
the cant is correct at only one point in the run-
off, at all other points it is either too great ortoo small.
(This excess ordeficiency of cant produces &
accounts for the objectionable lurches,
resistances & shocks which are noticeable to
passengers when a train travelling at speed
enters or leaves a curve
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Department of Transportation Engineering & Management, UET Lahore41
W
GNo curve, no
centrifugal force, radial
acceleration & trainweight are balanced
equally on both rails
Start ofSimple
circular curve
Case ACase A(1) Far(1) Farbefore thebefore the
tangenttangentpoint: nopoint: nocantcantappliedapplied
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Up to the tangent pointload on low rail is
greater than on thehigh rail (zero
centrifugal force)
W
e
Axle springs of low rail aredepressed & high rail
extended
Case A:Case A:(2)(2)SomewhatSomewhatbefore the tangentbefore the tangentpoint cant is startedpoint cant is started
being applied andbeing applied andreaches toreaches to
maximum value atmaximum value attangent pointtangent point
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Train
Horizontal centrifugal forcecombined with the vertical gravity
force results in equal loads on therails if equation shown holds true
Case A:Case A:(3) Just after(3) Just aftertangent point istangent point is
passedpassed
W
C
LURCH!! Axle springs of low
rail extended & high raildepressed
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Train
5/8 of train load is takenby the outer rail just
beyond the tangentpoint; line of action of
resultant force displaced
Start ofSimple
circular curve
Case BCase B(1) Just(1) Justbeyondbeyond
tangent pointtangent point
W
T
C
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PC PT
Point of fullsuperelevation
T
W
C
Inward LURCH!! Resultant
force swings back to centre
Case BCase B(2) Point of full(2) Point of fullsuperelevationsuperelevation
is reachedis reached
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(Before the tangent point the load on inner rail
is higher than on outer one & then are
equalized once the point of full superelevationis arrived.
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Before the
tangent
point
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(Increase the radius of curvature graduallyfrom that of the original circular curve untilthe radius is infinitely large at the point wherecurve merges into the straight
(Increase in curvature must beContinuous
UniformRapid Superelevation: from no cant to full cant
gradually within length of transition curve
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(Amount of cant at any point correspond to
radius at that point
(Three conditions govern design:
Length
Rate of increase in radius
Rate of increase in superelevation
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(Cubic spiral
(Lemniscate
(Clothoid(Cubic Parabola Used for railways
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0 1 827
64
125
216
343
512
729
1000
0 1 2 3 4 5 6 7 8 9 10
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(If r denotes the radius of curvature at any point
whose ordinates are x, y then,
(When x = 0, r = infinity (no curvature)
(When x = L, r = R (Radius ofCircularCurve)
(As y = cx3 Y = x3/6RL
(Where Y is the offset from tangent to any point on
transition curve
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(Several ways to determine the length of
transition curve, two of them are:
1. Relating length to the cantfor the givenradius R& maximum (or avg.) speed by
attaining this cant at a certain rate (cant
gradient)
2. Relating length to the radius of circular
curve & speed of train upon it
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(1949: Track committee of the Railway Executive of
British railways recommended that 1 in 300 should beadopted as the steepest permissible cant gradient
(
6
as maximum permissible cant(2 per second as the max. permissible rate of gain &loss of cant (& of cant deficiency)
5Important: Rate of gain or loss of cant involves thespeed of a train & therefore the cant gradient variesaccording to this rate of gain or loss
5For any given rate: lower the speed steeper the cantgradient
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BRITISH RECOMMENDATIONS
Based on max. cant gradient (1 in 300);L = 25 e
Based on rate of gain of cant (& ofdeficiency) of 2 per second;
L = 0.65 e Vmax
L = 0.65 D Vmax
L = length of transition in feet e = cant in inches D = deficiency of cant in inches Vmax = Max. permissible speed in m.p.h.
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INDIAN RECOMMENDATIONS
Based on arbitrary cant gradient (1 in 720);L = 7.20 e
Based on rate of change of cant deficiency;
L = 0.073 D Vmax
Based on rate of change of superelevation;
L = 0.073 e Vmax
L = length of transition in metres e = cant in cms. D = deficiency of cant in cms. Vmax = Max. permissible speed in k.m.p.h.
Greatest of the following within each set of recommendations
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(Due to centrifugal force on train, it has
angular acceleration on curve
(On transition curve, with change in radius theangular acceleration changes.
(What should be the rate of change of angular
acceleration which is unnoticeable to
passengers?
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0 1 827
64
125
216
343
512
729
1000
0 1 2 3 4 5 6 7 8 9 10
l
r
v
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( Ifl= length in feet of any element of the transition curve
whose radius = rin feet and v is the linear velocity in ft./sec.
of the train the angular acceleration is v2/r
( Time taken to move overlis l/v, the rate of change in angularacceleration is
(When r = R, the above expression will be equal to 1 and this is
a maximum.
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To fit the transitioncurve, circular curve is to
be shiftedinwards by acertain distance called
shift
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(ATC = Original Tangent & CircularCurve
(TS = Shift s or the amount by which the
curve is displaced inwards in order tointroduce transition curve ABP
(P = Point of change from transition to circular
curve
(B = Mid point ofTS & AT = TD
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( Y = 8TB = 4TS end ordinate is four times the shift( Versine = SV = C2/8R( Because VS = 3TS,
3 Shift = s =C2/24RorL2/24Rwhere L = Length of transition curveDepartment of Transportation Engineering & Management, UET Lahore 60
A T
C
S
B
PR
V
Q
D
C/2 C/2
Y
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(Find out the length of transition curve for a
four degree Broad Gauge circular curved track
having a cant of 15 cm. The maximumpermissible speed on the curve is 90 kmph.
(Find out the shift & offset at every 15 m
interval of length of curve
(Draw the transition curve
Assume maximum permissible cant deficiency as
75 mm
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Length of Transition CurveBasis Value Units
Cant gradient 108.00 metres
Rate of change
of cant deficiency49.28 metres
Rate of change
of superelevation98.55 metres
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(Shift = L2/24R
= 1082/24 x 4/1750
= 1.11 metres
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Interval(m)
Offsets(cm)
15 1.19
30 9.52
45 32.14
60 76.19
75 148.81
90 257.14
105 408.33
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Department of Transportation Engineering & Management, UET Lahore 65
1.1
.52
32.14
76.1
148.81
257.14
408.33
0
5
10
15
20
25
30
35
40
45
5055
60
65
70
75
80
85
0
5
100
105
0.00 50.00 100.00 150.00 200.00 250.00 300.00 350.00 400.00 450.00
R = 437.5 metres
ORIGINALCIRCULAR
CURVE
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(READ THIS TOPIC FROMGUPTAS
BOOK
(Effect of change of Gradients(Summit curves
(Valley curves
(Length of Vertical Curve
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hhDL
R
LB
v!
v
!
)(2
125)( 2
Rigid Wheel Base Distance between two adjoining axleswhich are held in a rigid frameDue to this rigidity, there is a tendency of outer wheels of
front axle to tilt the rail outwards hence widening the gaugefrom its actual valueTo prevent this, gauge is widened by engineers on curves