PCRailway Engineering Lab update!!

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    Department of Transportation Engineering & Management, UET Lahore 2

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    Department of Transportation Engineering & Management, UET Lahore 3

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    (Generally tunnels are provided

    (Alignment on either side of tunnel is steeper

    (not more than ruling grade) shorter tunnel(To achieve the objective of as straight & Level

    track as possible, length of track is increased

    & grades are kept upto ruling grades, this iscalleddevelopment.

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    Direction ofTravel is reversed

    for a shortdistance

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    (To gain elevation up or down hill, alignment

    makes a half circle loop into valley followed

    by half circle loop round the hill side

    (Excessive cutting & filling is avoided

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    Zig zag railway at Lithgow

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    (When zig zag development is not feasible for

    very steep slopes

    (To stop train gradually, without using brakes,vertical curve is provided

    (Train stops at switch point (station yards)

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    (Track rises on a steady curve until it has

    completed a 360 degree loop, passing over

    itself until it gains height(Train does not need to stop & reverse

    direction

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    (Suitable

    for narrow

    valleys(Swings

    around

    slope of

    valley

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    (Curves around slopes of a hill

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    (Estimate of traffic in terms of passengers &

    wagons

    (Possibility of development of naturalresources

    (Places of tourism

    (Traffic history

    (2 3 tentative routes are marked

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    (Topography(Towns, existing facilities, crossings(

    Geological characteristics(Maximum flood levels(Availability of material(Probable radii of curves

    (Total track length(Approximate earth work(Approx. cost of construction of each probable

    line

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    (2 3 routes are selected for preliminary

    survey

    (Recommends only one route(Data collected:

    (Elevations (levels)

    (River crossings

    (Existing track

    (Land ownership

    (Climatic conditions

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    (Topographic map is completed

    (Longitudinal section of alignment

    (Typical cross sections(Length of track

    (Gradients

    (Cost of subgrade

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    (Preliminary survey Paper location (grades,

    curves, contours, crossings, etc)

    (Finally decided alignment is surveyed in detail(From paper to ground pegs are fixed at

    regular intervals

    (Demarcation of land width

    (Centreline of culverts, bridges

    (Position of buildings

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    ( Geometry Science of properties & relations of lines, surfaces & solids

    DesignFinal layout or plan

    Geometric Design

    Deals with the geometry of track alignment in vertical & horizontalplanes.

    Horizontal plane: straight portion, curves, degree, radius

    Vertical Plane: Vertical curve, gradient

    Combination: Superelevation

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    (Superelevation (Cant) Difference in heightbetween the inner & outer rails on the curve

    (Equilibrium speed the speed at which the effectof centrifugal force is exactly balanced by the

    superelevation provided.

    (Maximum permissible speed Highest speed

    which may be allowed on a curved track taking intoconsideration the radius of curvature, actual cant,

    cant deficiency, cant excess & length of transition

    curve

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    (Cant Deficiency when a train travels on a

    curved track at a speed higher than the

    equilibrium speed then cant deficiency occurs.

    (Cant Excess when a train travels on a curved

    track at a speed lower than the eq. speed, cant

    excess occurs

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    (Cant Gradient (& Cant Deficiency

    Gradient) the amount by which a cant (or

    deficiency of cant) is reduced or increased in agiven length of transition

    Examples:

    1. A gradient of1 in 500 means that cant (or cant

    deficiency) of1 mm is attained (or lost) in every 500

    mm length of transition

    2. 1 in 60

    3. 1 in 360Department of Transportation Engineering & Management, UET Lahore 33

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    (Rate of Change of Cant (or Cant deficiency)

    o The rate at which the cant (or cant deficiency) is

    increased with time while passing over the transition

    curve.

    Examples:

    1. 40 mm per second means that a vehicle when travelling

    at maximum permitted speed will experience a change incant (or cant deficiency) of 40 mm in each second of

    travel over the transition.

    2. 2 per second

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    ( R= Radius of curve (m)

    ( C= Length ofChord (m)

    ( V = Versine on chord length C (m)

    ( By geometry,

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    A B

    F

    D

    O

    ER

    C V

    R

    CV

    CRV

    VNeglecting

    CVRV

    CCCVRV

    OBAOODOF

    8

    42

    ""4

    2

    422)2(

    2

    2

    2

    22

    2

    !

    !

    !

    !v!

    v!v

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    Transition Curve36

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    (What is Transition?

    Change from one state or condition to another

    (Requirement1. Straight section throughout is not always

    possible

    2. Curves may be introduced to by pass

    obstacles or avoid cutting

    3. Suppose a curve is provided with a tangent,

    what will happen?

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    (Increase the radius of curvature graduallyfrom that of the original circular curve until

    the radius is infinitely large at the point wherecurve merges into the straight(Increase in curvature must be

    Continuous

    UniformRapid

    (Superelevation: from no cant to full cantgradually within length of transition curve

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    (ThreeWays:Case A:Case A: Full cant may be continued through the

    whole length of the circular curve & the runoffinthe cant located entirely on the tangent at each

    end

    Case BCase B Full cant may be applied through thecentral portion of the circular curve & diminish to

    zero at the two tangent pointsCase C:Case C: The cant may be located partly on

    tangent & partly on the curve having its meanvalue at the tangent points.

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    (No matter which of these three are adopted,

    the cant is correct at only one point in the run-

    off, at all other points it is either too great ortoo small.

    (This excess ordeficiency of cant produces &

    accounts for the objectionable lurches,

    resistances & shocks which are noticeable to

    passengers when a train travelling at speed

    enters or leaves a curve

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    W

    GNo curve, no

    centrifugal force, radial

    acceleration & trainweight are balanced

    equally on both rails

    Start ofSimple

    circular curve

    Case ACase A(1) Far(1) Farbefore thebefore the

    tangenttangentpoint: nopoint: nocantcantappliedapplied

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    Up to the tangent pointload on low rail is

    greater than on thehigh rail (zero

    centrifugal force)

    W

    e

    Axle springs of low rail aredepressed & high rail

    extended

    Case A:Case A:(2)(2)SomewhatSomewhatbefore the tangentbefore the tangentpoint cant is startedpoint cant is started

    being applied andbeing applied andreaches toreaches to

    maximum value atmaximum value attangent pointtangent point

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    Train

    Horizontal centrifugal forcecombined with the vertical gravity

    force results in equal loads on therails if equation shown holds true

    Case A:Case A:(3) Just after(3) Just aftertangent point istangent point is

    passedpassed

    W

    C

    LURCH!! Axle springs of low

    rail extended & high raildepressed

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    Train

    5/8 of train load is takenby the outer rail just

    beyond the tangentpoint; line of action of

    resultant force displaced

    Start ofSimple

    circular curve

    Case BCase B(1) Just(1) Justbeyondbeyond

    tangent pointtangent point

    W

    T

    C

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    PC PT

    Point of fullsuperelevation

    T

    W

    C

    Inward LURCH!! Resultant

    force swings back to centre

    Case BCase B(2) Point of full(2) Point of fullsuperelevationsuperelevation

    is reachedis reached

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    (Before the tangent point the load on inner rail

    is higher than on outer one & then are

    equalized once the point of full superelevationis arrived.

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    Before the

    tangent

    point

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    (Increase the radius of curvature graduallyfrom that of the original circular curve untilthe radius is infinitely large at the point wherecurve merges into the straight

    (Increase in curvature must beContinuous

    UniformRapid Superelevation: from no cant to full cant

    gradually within length of transition curve

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    (Amount of cant at any point correspond to

    radius at that point

    (Three conditions govern design:

    Length

    Rate of increase in radius

    Rate of increase in superelevation

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    (Cubic spiral

    (Lemniscate

    (Clothoid(Cubic Parabola Used for railways

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    0 1 827

    64

    125

    216

    343

    512

    729

    1000

    0 1 2 3 4 5 6 7 8 9 10

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    (If r denotes the radius of curvature at any point

    whose ordinates are x, y then,

    (When x = 0, r = infinity (no curvature)

    (When x = L, r = R (Radius ofCircularCurve)

    (As y = cx3 Y = x3/6RL

    (Where Y is the offset from tangent to any point on

    transition curve

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    (Several ways to determine the length of

    transition curve, two of them are:

    1. Relating length to the cantfor the givenradius R& maximum (or avg.) speed by

    attaining this cant at a certain rate (cant

    gradient)

    2. Relating length to the radius of circular

    curve & speed of train upon it

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    (1949: Track committee of the Railway Executive of

    British railways recommended that 1 in 300 should beadopted as the steepest permissible cant gradient

    (

    6

    as maximum permissible cant(2 per second as the max. permissible rate of gain &loss of cant (& of cant deficiency)

    5Important: Rate of gain or loss of cant involves thespeed of a train & therefore the cant gradient variesaccording to this rate of gain or loss

    5For any given rate: lower the speed steeper the cantgradient

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    BRITISH RECOMMENDATIONS

    Based on max. cant gradient (1 in 300);L = 25 e

    Based on rate of gain of cant (& ofdeficiency) of 2 per second;

    L = 0.65 e Vmax

    L = 0.65 D Vmax

    L = length of transition in feet e = cant in inches D = deficiency of cant in inches Vmax = Max. permissible speed in m.p.h.

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    INDIAN RECOMMENDATIONS

    Based on arbitrary cant gradient (1 in 720);L = 7.20 e

    Based on rate of change of cant deficiency;

    L = 0.073 D Vmax

    Based on rate of change of superelevation;

    L = 0.073 e Vmax

    L = length of transition in metres e = cant in cms. D = deficiency of cant in cms. Vmax = Max. permissible speed in k.m.p.h.

    Greatest of the following within each set of recommendations

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    (Due to centrifugal force on train, it has

    angular acceleration on curve

    (On transition curve, with change in radius theangular acceleration changes.

    (What should be the rate of change of angular

    acceleration which is unnoticeable to

    passengers?

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    0 1 827

    64

    125

    216

    343

    512

    729

    1000

    0 1 2 3 4 5 6 7 8 9 10

    l

    r

    v

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    ( Ifl= length in feet of any element of the transition curve

    whose radius = rin feet and v is the linear velocity in ft./sec.

    of the train the angular acceleration is v2/r

    ( Time taken to move overlis l/v, the rate of change in angularacceleration is

    (When r = R, the above expression will be equal to 1 and this is

    a maximum.

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    To fit the transitioncurve, circular curve is to

    be shiftedinwards by acertain distance called

    shift

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    (ATC = Original Tangent & CircularCurve

    (TS = Shift s or the amount by which the

    curve is displaced inwards in order tointroduce transition curve ABP

    (P = Point of change from transition to circular

    curve

    (B = Mid point ofTS & AT = TD

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    ( Y = 8TB = 4TS end ordinate is four times the shift( Versine = SV = C2/8R( Because VS = 3TS,

    3 Shift = s =C2/24RorL2/24Rwhere L = Length of transition curveDepartment of Transportation Engineering & Management, UET Lahore 60

    A T

    C

    S

    B

    PR

    V

    Q

    D

    C/2 C/2

    Y

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    (Find out the length of transition curve for a

    four degree Broad Gauge circular curved track

    having a cant of 15 cm. The maximumpermissible speed on the curve is 90 kmph.

    (Find out the shift & offset at every 15 m

    interval of length of curve

    (Draw the transition curve

    Assume maximum permissible cant deficiency as

    75 mm

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    Length of Transition CurveBasis Value Units

    Cant gradient 108.00 metres

    Rate of change

    of cant deficiency49.28 metres

    Rate of change

    of superelevation98.55 metres

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    (Shift = L2/24R

    = 1082/24 x 4/1750

    = 1.11 metres

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    Interval(m)

    Offsets(cm)

    15 1.19

    30 9.52

    45 32.14

    60 76.19

    75 148.81

    90 257.14

    105 408.33

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    1.1

    .52

    32.14

    76.1

    148.81

    257.14

    408.33

    0

    5

    10

    15

    20

    25

    30

    35

    40

    45

    5055

    60

    65

    70

    75

    80

    85

    0

    5

    100

    105

    0.00 50.00 100.00 150.00 200.00 250.00 300.00 350.00 400.00 450.00

    R = 437.5 metres

    ORIGINALCIRCULAR

    CURVE

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    (READ THIS TOPIC FROMGUPTAS

    BOOK

    (Effect of change of Gradients(Summit curves

    (Valley curves

    (Length of Vertical Curve

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    hhDL

    R

    LB

    v!

    v

    !

    )(2

    125)( 2

    Rigid Wheel Base Distance between two adjoining axleswhich are held in a rigid frameDue to this rigidity, there is a tendency of outer wheels of

    front axle to tilt the rail outwards hence widening the gaugefrom its actual valueTo prevent this, gauge is widened by engineers on curves