ESTANCIA NATIONAL HIGH SCHOOL

Paper 3b

POWERPOINTPRESENTATION

By:

ADA MAE I. ROBLES

ALGEBRA(Special Products and Factoring,

Rational Algebraic Expressions,

And Sets)

ESTANCIA NATIONAL HIGH SCHOOL

Paper 3b - PowerPoint Presentation

DIRECTIONS: Answer the following then choose the letter of the correct answer.

1.) The simplest form of 18𝑥3𝑦5

27𝑥4𝑦2 is _________.

a.2𝑦3

3𝑥b.

6𝑦3

9𝑥

c.6𝑥

9𝑦3 d.2𝑥

3𝑦3

To reveal the solution CLICK HERE

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ESTANCIA NATIONAL HIGH SCHOOL

Paper 3b - PowerPoint Presentation (Answer Key)

ANSWER KEY:

1.) The simplest form of 18𝑥3𝑦5

27𝑥4𝑦2 is _________.

Solution:

18𝑥3𝑦5

27𝑥4𝑦2 =9∙2∙𝑥3∙𝑦2∙𝑦3

9∙3∙𝑥3∙𝑥∙𝑦2 =𝟐𝒚𝟑

𝟑𝒙

Answer: a

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Paper 3b - PowerPoint Presentation

2.) Factor 16𝑥8 − 625𝑦16 completely.

a. (4𝑥2−25𝑦4)(4𝑥2 + 25𝑦4)

b. (4𝑥4−25𝑦8)(4𝑥4 + 25𝑦8)

c. (2𝑥2+5𝑦4) 2𝑥2 − 5𝑦4 (4𝑥4 + 25𝑦8)

d. (2𝑥2+5𝑦4) 2𝑥2 − 25𝑦4

(2𝑥2+5𝑦4) 2𝑥2 + 25𝑦4

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Paper 3b - PowerPoint Presentation (Answer Key)

2.) Factor 16𝑥8 − 625𝑦16 completely.

Solution:

To factor, use difference of two squares:

16𝑥8 − 625𝑦16 = 4𝑥4 + 25𝑦8 4𝑥4 − 25𝑦8

= 𝟒𝒙𝟐 + 𝟐𝟓𝒚𝟖 𝟐𝒙𝟐 + 𝟓𝒚𝟒 𝟐𝒙𝟐 − 𝟓𝒚𝟒

Answer: c

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Paper 3b - PowerPoint Presentation

3.) What is the surface area of the given cube? (x+3y)cm

a. 6𝑥 + 18𝑦 𝑐𝑚2

b. (𝑥2+6𝑥𝑦 +9𝑦2)𝑐𝑚2

c. (6𝑥2+26𝑥𝑦 + 54𝑦2)𝑐𝑚2

d. (𝑥3+9𝑥2𝑦 + 27𝑥𝑦2 + 27𝑦3)𝑐𝑚2

To reveal the solution CLICK HERE

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Paper 3b - PowerPoint Presentation (Answer Key)

3.) What is the surface area of the given cube?Solution: (x+3y)cm

Use the formula 𝐴 = 𝑠2, we have, 𝐴 = (𝑥 + 3𝑦)2,

then, use special product “square of a binomial”

𝐴 = 𝑥2 + 2 𝑥 3𝑦 + 𝑦2 thus, 𝑨 = 𝒙𝟐 + 𝟔𝒙𝒚 + 𝒚𝟐

Answer: b

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Paper 3b - PowerPoint Presentation

4.) Given the function f(x) = 4x2 + 1,

evaluate the following: f (-2), f (1), and f (1

2).

a. −17, 5, 2 respectively

b. 17, 5, 2 respectively

c. 17, 5, 5 respectively

d. −17, 5, 5 respectively

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Paper 3b - PowerPoint Presentation (Answer Key)

4.) Given the function f(x) = 4x2 + 1, evaluate the following:

f (-2), f (1), and f (1

2).

Solution:

Substitute the value of x in the given function.

𝑓 𝑥 = 4𝑥2 + 1 𝑓 𝑥 = 4𝑥2 + 1 𝑓 𝑥 = 4𝑥2 + 1

𝑓 −2 = 4 4 + 1 𝑓 1 = 4(1)2 + 1 𝑓1

2= 4(

1

2)2 + 1

𝑓 −2 = 4(−2)2 + 1 𝑓 −2 = 4(1) + 1 𝑓1

2= 4(

1

4) + 1

𝑓 −2 = 16 + 1 = 𝟏𝟕 𝑓 −2 = 4 + 1 = 𝟓 𝑓 −2 = 1 + 1 = 𝟐

Answer: b

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Paper 3b - PowerPoint Presentation

5.) Simplify: 𝑦−5

𝑦+3=

𝑦+6

𝑦−2.

a. 𝑦 =7

4b. 𝑦 =

−7

4

c. 𝑦 =1

2d. 𝑦 =

−1

2

To reveal the solution CLICK HERE

G O O D L U C K !!!

ESTANCIA NATIONAL HIGH SCHOOL

Paper 3b - PowerPoint Presentation (Answer Key)

5.) Simplify: 𝑦−5

𝑦+3=

𝑦+6

𝑦−2

Solution: 𝑦 − 5 𝑦 − 2 = 𝑦 + 3 𝑦 + 6

𝑦2 − 7𝑦 + 10 = 𝑦2 + 9𝑦 + 18

𝑦2 − 𝑦2 − 7𝑦 − 9𝑦 = 18 − 10−16𝑦 = 8

Answer: d 𝑦 =8

−16=

−𝟏

𝟐

THANK YOU!