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12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
2
Subject-PHYSICS Part : 1
SECTION-A
(NEXT THIRTY QUESTIONS: SINGLE CHOICE – ONLY ONE CORRECT ANSWER)
Q1 In the figure the electric lines on the right have twice the separation of those on the left. If a charge particle
takes time t to move a distance x in left region, then it will take time to travel the same distance in the right
side region is:
(a.)
2t
(b.) t (c.) t2 (d.) t2
Sol. (c)
Q2
A surface has the area vector .)ˆ3ˆ2( 2mjiA
The flux of an electric field through it if the field is
:ˆ4mViE
(a.) mV -8 (b.) mV -12 (c.) mV -20 (d.) Zero
Sol. (a)
mVjiiAE -8)ˆ3ˆ2(.ˆ4.
Q3 A long, hollow conducting cylinder is kept coaxially inside another long, hollow conducting cylinder of larger
radius. Both the cylinders are initially electrically neutral (a.) A potential difference appears between the two cylinders when a charge density is given to the inner cylinder. (b.) A potential difference appears between two cylinders when a charge density is given to the outer cylinder. (c.) No potential difference appears between the two cylinders when a uniform line charge is kept along the axis of
the cylinders. (d.) No potential difference appears between the two cylinders when same charge density is given to both the
cylinders.
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Sol. (a)
When charge is given to inner cylinder, an electric field will be in between the cylinders. So there is potential
difference between the cylinders.
Q4 Figure shows three paths along which we can move positively charged sphere A closer to positively charged
sphere B which is fixed in a plane. If 21 , WW and 3W are the work done along the three respective paths, then
(a.)
321 WWW (b.) 231 WWW (c.)
321 WWW (d.) 213 WWW
Sol. (c)
Work done, .)( qVVW ABAB In all the three cases, potential difference is same and so .321 WWW
Q5 Two small spheres each having the charge Q are suspended by insulating threads of length L from a hook.
This arrangement is taken in space where there is no gravitational effect, then the angle between the two
suspensions and the tension in each will be
(a.)
2
2
0 )2(41,180
LQ
(b.)
2
2
041,90
LQ
(c.)
2
2
0 241,180
LQ
(d.)
2
2
041,180
LQ
Sol. (a)
In the absence of gravitational force, the only force acts on the spheres is electrostatic repulsion and so the
angle between two suspension becomes .180 So force between the sphere .)2(4
12
2
0 LQF
Q6 In the electric field of a point charge ,q a certain charge is carried from point A to DCB ,, and .E Then the
work done
(a.) is least along the path AB (b.) is least along the path AD (c.) is zero along all the paths ADACAB ,, and AE (d.) is least along AE
Sol. (c)
The potential difference between either of EDCB ,,, and A is zero, and so work done along all the paths is
zero.
Q7 Four equal charges Q are placed at the four corners of a square of each side is .a Work done in removing a
charge Q from its centre to infinity is
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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(a.) 0 (b.)
aQ
0
2
42
(c.)
aQ
0
22
(d.)
aQ
0
2
2
Sol. (c)
Q8 The displacement of a charge Q in the electric field kejeieE ˆˆˆ
321 is .ˆˆˆ jbiar The work done is
(a.) )( 21 beaeQ (b.) 22
21 )()( beaeQ (c.) 22
21 )( baeeQ (d.) )()( 22
21 baeeQ
Sol. (a)
Q9 Three charges qQ , and q are placed at the vertices of a right angled isosceles triangle as shown. The net
electrostatic energy of the configuration is zero if Q is equal to
(a.)
2 q
(b.)
222 q
(c.) q2 (d.) q
Sol. (b)
Q10 The spatial distribution of the electric field due to charges ),( BA is shown in figure. Which one of the
following statements is correct?
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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(a.) A is +ve and B – ve and |||| BA (b.) A is –ve and B + ve; |||| BA
(c.) Both are +ve but BA (d.) Both are –ve but BA
Sol. (a)
Spacing between the lines of field increases from A to ,B and so magnitude of charge at B will be less than .A
Q11 A square surface of side L meters is in the plane of the paper. A uniform electric field
E (volt/m), also in the
plane of the paper, is limited only to the lower half of the square surface, (see figure). The electric flux in SI
units associated with the surface is
(a.) Zero (b.) 2EL (c.)
02 2/ EL (d.) 2/2EL
Sol. (a)
.090cos EA
Q12 Two thin wire rings each having a radius R are placed at a distance d apart with their axes coinciding. The
charges on the two rings are Q and .Q The potential difference between the centres of the two rings is
(a.) Zero (b.)
220
114 dRR
Q
(c.) 204/ dQR (d.)
220
112 dRR
Q
Sol. (d)
Q13 Two concentric shells are having radii R and ,2R charges 1q and 2q and potentials V3 and V respectively.
Now outer shell is earthed, (a.) Potential difference between shell increases (b.) Potential difference between shell decreases (c.) Potential of inner sphere will become V2 (d.) Potential of inner sphere will become V5.2
Sol. (c)
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Previously, if 1V and 2V are the potentials of inner and outer shells due to own charge respectively, then
VVV 321
VVV 31 or VV 21
When outer shell is earthed, its potential becomes zero, and so potential of inner becomes VVV 202,1
Q14 In an isolated parallel plate capacitor of capacitance ,C the four surface have charges 321 ,, QQQ and 4Q as
shown. The potential difference between the plates is
(a.)
CQQQQ
24321
(b.)
CQQ
232
(c.)
CQQ
232
(d.)
CQQ
241
Sol. (c)
Q15 For the circuit shown, which of the following statements is true?
(a.) With 1S closed, VVVV 20,15 21 (b.) With 3S closed, VVV 2521
(c.) With 1S and 3S closed 021 VV (d.) With 1S and 3S closed, VVVV 20,30 21
Sol. (d)
Charges on the capacitors will redistribute only when all the three switches will be closed.
Q16 Plates of area A are arranged as shown. The distance between each plate is ,d the net capacitance is
(a.)
dA0
(b.)
dA07
(c.)
dA06
(d.)
dA05
Sol. (a)
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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The equivalent circuit is shown in figure
Thus .0
dACCab
Q17 What is equivalent time constant of following RC circuit?
(a.) RC5.1 (b.) RC3 (c.) RC2 (d.)
2RC
Sol. (a)
The effective circuit is shown in figure.
The effective resistance across C is
Q18 In the circuit shown in figure, find the steady state charge on capacitor .1C
(a.) C2 (b.) C3 (c.) C4 (d.) Zero
Sol. (c)
At steady state, the current in the resistors are shown in figure.
If q be the charge on each of the capacitor, then 06
323
8 qq
Cq 4
Q19 The figure here shows conduction electrons moving leftward through a wire. Select the quantity/(ies) which
have direction rightward:
(a.)
dvi, (b.) ji, (c.) dvEj ,, (d.) ji, and E
Sol. (d)
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
8
The direction of i and j are opposite of the direction of motion of electron, and the direction of electrons are
opposite to that of .
E
Q20 Figure shows a rectangular solid conductor of edge lengths LL 2, and .3L A certain potential difference V is
to be applied between pairs of opposite faces of the conductor as shown in figure: left-right, top-bottom and
front-back. In which pair current is maximum
(a.) left-right (b.) top-bottom (c.) front-back (d.) equal in all
Sol. (b)
As ,ALR
and so it is least along top-bottom. Current will be maximum.
Q21 For the shown circuit the effective resistance between the points A and B will be
(a.) R2 (b.) R4 (c.) R (d.) 2/R
Sol. (c)
Q22 A meter bridge is set up as shown, to determine an unknown resistance X using a standard 10 ohm resistor.
The galvanometer shows null point when tapping-key is at 52 cm mark. The end corrections are 1 cm and 2
cm respectively for the ends A and .B The determined value of X is
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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(a.) 2.10 ohm (b.) 6.10 ohm (c.) 8.10 ohm (d.) 1.11 ohm
Sol. (b)
At null point
Q23 A torch bulb rated as VW 5.1,5.4 is connected as shown in the figure. The e.m.f. of the cell needed to make
the bulb glow at full intensity is
(a.) V5.4 (b.) V5.1 (c.) V67.2 (d.) V5.13
Sol. (d)
Q24 In the circuit shown below, the cell has an e.m.f. of V10 and internal resistance of 1 ohm. The other
resistances are shown in the figure. The potential difference BA VV is
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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(a.) V6 (b.) V4 (c.) V2 (d.) V2
Sol. (d)
)()( 00 ABBA VVVVVV
4121
.2V
Q25 The equivalent resistance between A and B is
(a.)
321 RRR (b.) 2R (c.)
142
42 RRR
RR
(d.)
41
41
RRRR
Sol. (d)
The effective circuit is shown in figure
41
41
RRRRRAB
Q26 Two infinitely long conducting wires carry currents, as shown in figure. If the horizontal wire carrying current
produces a magnetic field B at the point ),0,,2( ddP then the resultant magnetic field at this point is
(a.) kB ˆ2 (b.) kB ˆ2 (c.) kB ˆ2 (d.) Zero
Sol. (a)
Given .)2(.2
0
dB
Magnetic field due to A4 wire, .2
)4(2
' 0 Bd
B
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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So, resultant magnetic field BBB 2 along – ve z -axis.
Q27 A vertical straight conductor carries a current vertically upwards. A point P lies to the east of it at a small
distance and another point Q lies to the west at the same distance. The magnetic field at P is
(a.) greater than at Q (b.) Same as at Q
(c.) less than at Q (d.) greater or less than at Q depending upon the strength of the current
Sol. (b)
As the distance of the points P and Q is equal from the wire and so magnetic field is also equal.
Q28 The magnetic induction at the centre O in the figure shown is
(a.)
21
0 114 RR
i
(b.)
21
0 114 RR
i
(c.) )(
4 210 RRi
(d.)
)(4 210 RRi
Sol. (a)
Q29 A part of a long wire carrying a current i is bent into a circle of radius r as shown in figure. The net magnetic
field at the centre O of the circular loop is
(a.)
ri
40
(b.)
ri
20
(c.) )1(
20
ri
(d.)
)1(2
0
ri
Sol. (c)
,2
.2
00
ri
riB
out of plane of paper.
Q30 Wires 1 and 2 carrying currents 1i and 2i respectively are inclined at an angle to each other. What is the
force on a small element d of wire 2 at a distance of r from wire 1 (as shown in figure) due to the magnetic
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
12
field of wire 1
(a.)
tan2 21
0 diir
(b.)
sin2 21
0 diir
(c.)
cos2 21
0 diir
(d.)
sin4 21
0 diir
Sol. (c)
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
13
Subject-CHEMISTRY Part : 2
SECTION-A
(NEXT THIRTY QUESTIONS: SINGLE CHOICE – ONLY ONE CORRECT ANSWER)
Q1 If the same type of atoms are packed in hexagonal closest packing (HCP) and cubical closest packing (CCP)
separately, then
(a.) Density of HCP will be greater than CCP (b.) Density of HCP will be smaller than CCP (c.) Density of HCP will be equal to CCP (d.) Density of HCP may be equal or greater than or smaller than CCP depending upon the temperature of the system
Sol. (c)
Q2 In the closest packing of atoms, there are
(a.) One tetrahedral void and two octahedral voids per atom (b.) Two tetrahedral void and one octahedral voids per atom (c.) Two of each tetrahedral and octahedral void (d.) Three of each tetrahedral and octahedral void
Sol. (b)
Q3 In spinel structure, oxides ions are cubical-closest packed, whereas 1/8th of tetrahedral holes are occupied by
cations 2A and 1/2 of octahedral holes are occupied by cations 3B ions. The general formula of the
compound having spinel structure is (a.)
42BOA (b.) 42OAB (c.) OBA 42 (d.) OBA 24
Sol. (b)
Q4 In an antiferromagnetic material
(a.) All the magnetic moment vectors are aligned in one direction (b.) Half of the magnetic moment vectors point in one direction and the rest in opposite direction (c.) All the magnetic moment vectors are randomly oriented (d.) Is characterized by a very large magnetic moment
Sol. (b)
Q5 The mole fraction of a solute in carbon tetrachloride is .235.0 The molality of the solution is about
(a.) 1kgmol2.0 (b.) 1kgmol5.1 (c.) 1kgmol0.1 (d.) 1kgmol5.0
Sol. (a)
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Q6 Which of the following behaviors is true for an ideal binary liquid solution?
(a.) Plot of totalp versus Ay (mole fraction of A in vapour phase) is linear
(b.) Plot of totalp versus By is linear
(c.) Plot of total/1 p versus Ay (or By ) is linear
(d.) Plot of total/1 p versus Ay (or By ) is nonlinear
Sol. (c)
Q7 The vapour pressure of pure benzene and toluene are 160 Torr and 60 Torr, respectively. The mole fraction of
benzene in vapour phase in contact with equimolar solution of benzene and toluene would be
(a.) 50.0 (b.) 84.0 (c.) 73.0 (d.) 27.0
Sol. (c)
Q8 Arrange the following ( 1.0 molal) solution in the increasing order of freezing point.
(I) Soln of 243 )(POCa ; (II) Soln of 42SONa ; (III) Soln of glucose
(a.) I > II > III (b.) I > III > I (c.) III > II > I (d.) III > I > II
Sol. (c)
Larger the sum of stoichiometric number of ions of the molecule, larger ions it produces in solution, and thus
larger decrease in freezing point. Consequently, the freezing point is the lowest.
Q9 A solution of sucrose in g100 of water boils at C.100.25 If this solution is boiled till its temperature is
C,101 the mass of water evaporated from the solution is
(a.) g25 (b.) g50 (c.) g75 (d.) g85
Sol. (c)
Q10 A solution of sodium sulphate in water is electrolysed using inert electrodes. The respective products at the
cathode and anode are
(a.) 22 O,H (b.)
22 H,O (c.) Na,O2 (d.) 22 SO,O
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Sol. (a)
OH2 is reduced in preference to Na and OH2 is oxidized in preference to .SO24
Q11 The time required to coat a metal surface of 2cm80 with mm0.005 thick layer of silver (density
3cmg10.5 ) with the passage of A3 current through a silver nitrate solution is
(a.) s125 (b.) s130 (c.) s135 (d.) s140
Sol. (a)
s0.125)molg(108A)(3
(1))molC(96500g)10.50.005(80MI
vF)(VMIvmF
t 1
1ee
Q12 The conductivity of M0.001 crotonic acid is .cmS3.83 1 If ,molcmS126(NaCl)Λ 12m
12m molcmS426(HCl)Λ and m (sodium salt of crotonic acid) = ,molcmS83 12 then the ionization
constant of crotonic acid is
(a.) M10 3 (b.) M10 5 (c.) M10 7 (d.) M10 8
Sol. (c)
Q13 The standard potentials at K298 are
V,0.6762Zn)|(ZnE 2 V,0.740Cr)|(CrE 3
00.0Pt)|H|(HE 2 and V0.770Pt)|Fe,(FeE 23
Which is the strongest reducing agent? (a.) (s)Zn (b.) (s)Cr (c.) (g)H2 (d.) (aq)Fe2
Sol. (a)
The smaller the value of reduction potential, lesser the reduction tendency of the ion and larger the oxidation
tendency of the corresponding metal. Larger oxidation tendency implies stronger reducing agent.
Q14 Given V0.337Cu)|(CuE 2 and V.0.136Sn)|(SnE 2 Which of the statements is correct?
(a.) 2Cu ions can be reduced by (g)H2 (b.) Cu can be oxidized by H
(c.) 2Sn can reduced by (g)H2 (d.) Cu can reduce 2Sn
Sol. (a) 2Cu has larger tendency to reduce than .H 2Sn has lesser tendency to reduce than .H
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Hence, 2Cu ion can be reduced by (g).H2
Q15 When toluene is treated with 2Cl at high temperature without the use of any catalyst, the product obtain is
(a.) Only o chlorotoluene (b.) Only m chlorotoluene
(c.) Only p chlorotoluene (d.) A mixture of ortho–and para–chlorotoluenes
Sol. (d)
At low temperature in the presence of a catalyst ),(FeCl3 electrophilic substitution at benzene ring takes place.
Q16 Which of the following orders regarding the boiling points of the given alkyl chloride is correct?
(a.) CCl)(CHCHClCHCHCHCl)(CHCH 33323323
(b.) CCl)(CHCHClCHCHCHCl)(CHCH 33323323
(c.) CCl)(CHCHClCHCHCHCl)(CHCH 33323323
(d.) CCl)(CHCHClCHCHCHCl)(CHCH 33323333
Sol. (a)
Boiling point decreases with increasing branching of the alkyl group.
Q17 Which of the following is an example of Sandmeyer reaction?
(a.)
(b.)
(c.)
(d.)
Sol. (d)
The major product is 2-butene ).CHCHCH(CH 33
Q18 The order of reactivity for the 2SN reaction involving replacement of X by a nucleophile in alkyl halide is
(a.) 21CH3 (b.) 21CH3 (c.) 21CH3 (d.) 21CH3
Sol. (b)
The rate decreases with increasing bulk of alkyl group.
Q19 In the reaction of p chlorotoluene with 2KNH in liquor ammonia, the major product is
(a.) o-toluidine (b.) m-toluidine (c.) p-toluidine (d.) p-chloroaniline
Sol. (b)
The reaction proceeds via elimination-addition mechanism. The major product is m-toluidine
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
17
Q20 The compound which gives the most stable carbonium ion on dehydration is
(a.) |
CH
OHCHCHCH
3
23
(b.)
3
3
3
CH|
OHCCH
CH|
(c.) OHCHCHCHCH 2223 (d.) |
OH
CHCHCHCH 323
Sol. (b)
3 carbonium ion is most stable.
Q21 The reaction of ROH with R’MgX produces
(a.) RH (b.) R’H (c.) R – R (d.) R’ – R’
Sol. (b)
HR'ROMgXMgXR'ROH
Q22 Which of the following statements is correct?
(a.) The reaction OHROH HOHRO lies far towards the left side
(b.) The reaction SHR'NaRONaSR'ROH is feasible
(c.) ,RS in a protic solvent, acts as a stronger nucleophile than RO
(d.) The bond angle HOR in methanol is smaller than that of HSR in methanethiol
Sol. (c)
(a) The differences in acidities and basicities are slight, all species are present at equilibrium.
(b) ROH is a weaker acid than SHR' and also SR' is a weaker base than .RO Hence, the reaction will
not be feasible as the reactants contain weaker acid and weaker base as compared to the products.
(c) Because of the bigger size of S, the negative charge on it is more easily polarised which makes it easier for
the nucleophilic attack. The nucleophilic nature of RO is also diminished in a protic solvent because
there will be more stronger hydrogen bonding due to the large negative charge density on the smaller sized
O atom.
(d) The bond angles are 109 and 96 for HOC and H,SC respectively. The oxygen involves 3sp
hydrid orbitals while sulphur involves p orbitals for bonding with C and H atoms.
Q23
The reaction is known as (a.) Wurtz reaction (b.) Riemer-Tiemann reaction (c.) Schotten-Baumann reaction (d.) Kolbe reaction
Sol. (d)
Q24 The reaction of 32CHPhOCH with one equivalent of HI produces
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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(a.) OHCHCHPhI 23 (b.) 33CHCHPhI (c.)
3266 CHICHHC (d.) 32CHICHPhOH
Sol. (d)
Aryl ethers do not cleave on the aromatic side, but only on the alkyl side.
Q25
The reaction of with OHCH3 in (i) acid ,H and (ii) base ,OCH3 respectively, give
(a.) OH)CHC(OCH)(CH 2323 and 3223 OCHCH(OH)CH)(CH
(b.) OH)CHC(OCH)(CH 2323 and OH)CHC(OCH)(CH 2323
(c.) 32323 OCH)CHC(OCH)(CH and OHC(OH)CH)(CH 223
(d.) OHC(OH)CH)(CH 223 and 32323 OCH)CHC(OCH)(CH
Sol. (a)
There occurs cleavage of ether linkage in oxiranes (cyclic three membered ring including oxygen). In acid-
catalyzed reaction, nucleophile 3OCH from OHCH3 attaches to the more substituted carbon where as in
base-catalyzed reaction, it is attached to the less substituted carbon.
Q26 Which reagent on condensation with benzaldehyde product phenylhydrazone?
(a.) OHNH2 . (b.) 256 NHHC (c.)
22 NNHCONHH (d.) 256 NHNHHC
Sol. (d)
Phenylhydrazine )NHNHH(C 256 produces phenylhydrazone.
Q27 The Cannizzaro reaction is not given by
(a.) Trimethylactaldehyde (b.) Benzaldehyde (c.) Acetaldehyde (d.) Formaldehyde
Sol. (c)
CHOCH3 contains α hydrogen atom. It will not show Cannizzaro reaction.
Q28 In the Cannizzaro ,PhCOOHCHPhCHO2Ph 22OH the slowest step is
(a.) The attack of OH at the carbonyl group (b.) The transfer of hydride to the carbonyl group
(c.) The abstraction of proton from the carboxylic acid (d.) The deprotonation of OHCHPh 2
Sol. (b)
Transfer of hydride to carbonyl group is the slowest step.
Q29 Which of the following tests distinguishes acetophenone from propionaldehyde?
(a.) Baeyer test (b.) Iodoform test (c.) Tollens test (d.) Lucas test
Sol. (b)
563 HCOCCH does not react with .NaHSO3
Q30 The reduction potential of hydrogen electrode will be positive if
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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(a.) M1][Hatm,1)p(H2 (b.) M2][Hatm,1)p(H2
(c.) M1][Hatm,2)p(H2 (d.) M1.5][Hatm,2.5)p(H2
Sol. (b)
][Hp
lnF
RTE1/2H
PtHH2
2
The combination atm1)p(H2 and M2][H will make PtHH 2
E positive.
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Subject-MATHEMATICS Part : 3
SECTION-A
(NEXT THIRTY QUESTIONS: SINGLE CHOICE – ONLY ONE CORRECT ANSWER)
Q1
If 03111
1211111
cccbb
a where 0,0,0 cba then 111 cba is
(a.) 4 (b.) 3 (c.) 2 (d.) 1
Sol. (b)
Take cba ,, common from 321 ,, RRR respectively.
311111
12111
1111
ccc
bbb
aaaabc
Apply 3211 RRRR
ccc
bbbcbaabc
131111
11211111
1113
Now apply
233 CCC and 122 CCC & expand
011132
cbaabc
As 0,0,0 cba
3111 cba
Q2 The system of equation 1822,2245,2254 zyxzyxzyx is
(a.) Inconsistent (b.) Consistent and determinate (c.) Consistent but dependent (d.) Has infinite solution
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Sol. (a)
The system is ,BAX where
122
,,822245254
Bzyx
XA
0822245254
||
A
1A does not exis. We find ..adj A
Cofactor are 9,18,18,18,36,36,18,36,36
91818183636
183636C
91818183636183636
.adj TCA
We have 063126126
)adj(
BA
Thus .0|| A But .0)adj( BA Therefore the system has no solution.
Q3
If )(sin)(sin)(sin)(sin)(sin)(sin)(cos)(cos)(cos
)(
xxxxxx
xf and ,5)2( f then
20
1
)(r
rf equals
(a.) 5 (b.) 10 (c.) 100 (d.) 50
Sol. (c)
Clearly )(0)(' xfxf constant
But 5)2( f
5)( xf
1002055)(20
1
20
1
rr
rf
Q4 If A is square matrix of order 22 such that
1021;A2 BI and ,ABAC then 2009)(C
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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(a.) AA
10220091
(b.)
AA
10
220091 (c.) AA
2009021
(d.)
AA
20090220091
Sol. (a)
Q5 Which of the following is correct
(a.) If A and B are square matrices of order 3 such that ,3||,1|| BA then the determinant of AB3 is equal
to 27
(b.) If A is an invertible matrix, then )(det 1A is equal to )(det A
(c.) If A and B are matrices of the same order, then 222 2)( BABABA is possible if IAB :
(d.) 111)( BAAB
Sol. (d)
(a) We have |||||| BAAB
Also for a square matrix of order ||||,3 3 AkkA because each element of the matrix A is multiplied by
k and hence in this case we will have 3k common
81)3()1(27||||3|3| 3 BAAB
(b) Since A is invertible, therefore 1A exists and 11 AA
)(det)(det 1 IAA 1)(det)(det 1 AA )(det
1)(det 1
AA
(c) )()()( 2 BABABA
22 BBAABA
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
23
22 2 BABA if .BAAB
Q6 Let
000
A and .50)( 50
dcba
AIA Then the value of dcba is
(a.) 2 (b.) 1 (c.) 4 (d.) 3
Sol. (a)
We have, 2,,2 kOAOA k
Thus,
AIIA 50)( 50
AIIA 50)( 50
1,0,0,1 dcba
Q7 If ,1sin1sin1sin 111
bax then the value of x is
(a.)
11 22 baab
(b.)
11 22 baab
(c.)
112
22 baab
(d.)
112
22 baab
Sol. (a)
Let
ba1sin;1sin 11 then
x1sin 1
)(sin1sinsin 1
x
ab
aab
bbabax
111.11111sincoscossin1 22
22
11 22
ba
abx
Q8 The inverse of
xxxf
11tan)( 1 is:
If given invertible
(a.)
yyyy
cottancottan
(b.)
yyyy
cottancottan
(c.)
yyyy
tancottancot
(d.)
yyyy
tancottancot
Sol. (c)
Given, xxy
11tan 1
yxx tan
11
yxx 2tan
11
yx
x2tan
111
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
24
yyyy
yyx
tancottancot
tan1tan1
2
2
Q9 The value of
sincoscot
sin1costan 11
xxx
is
(a.) 2 (b.) (c.) 2/ (d.) Independent of
Sol. (b)
Q10
Range of the function Rxxxxf
,3
1tan)(2
1 is
(a.)
2,
6
(b.)
3,
6
(c.)
4,
6
(d.) ),(
Sol. (c)
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Q11 If ,2500...941)( Rxxxxxxf then all the values of x where )(xf has
minimum values lies in
(a.) )700,600( (b.) )678,576( (c.) )678,625( (d.) )200,100(
Sol. (c)
Q12
nnn 2tan
21....
2tan
21
2tan
21tanlim 22
(a.)
1
(b.)
2cot21
(c.) 2cot2 (d.)
tan1
Sol. (b)
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Q13
Let ,}1)1{()1(
)(1
0
n
rn xrrxxLtxf then
(a.) )(xf is continuous but not differentiable at 0x (b.) )(xf is both continuous and differentiable at 0x
(c.) )(xf is neither continuous nor differentiable at 0x (d.) )(xf is a periodic function
Sol. (c)
1111 xrrx
xtr
111
111
xrrx
rxxr
1
0 111
n
rrn nx
tS
0,1 x
0,0 x
1
11nx
LtSLtnnn
Thus,
0,00,1
xx
xf
10
xfLtx
and 00 f
Hence xf is neither continuous nor differentiable at 0x
Clearly xf is not a periodic function.
Q14
2
11
1 1)cos(sinlim
xx
x
equals
(a.) 0 (b.) 1 (c.)
21
(d.)
1
Sol. (c)
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Q15
))2ln(cos()sin(lim 2
2
0 xxx
x is equal to
(a.) 2 (b.) 2 (c.) 1 (d.) 1
Sol. (b)
Q16 In order that the function xxxf cot)1()( is continuous at )0(,0 fx must be defined as
(a.) 0)0( f (b.) ef )0( (c.) ef /1)0( (d.) 1)0( f
Sol. (b)
For continuity actual value must be equal to limiting value
A = x
xx cot
0)1(lim
log A = )1(logcotlim0
xxx
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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= x
xx tan
)1(loglim0
form00
= 1sec
11
lim 20
x
xx
(By L’ Hospital Rule)
log A = 1 A = e1 = e.
For )0(f must be defined as .)0( ef
Hence (b) is the correct answer.
Q17
If
2
2)441(logsinlog.
)2(sin1
)(222
xk
xxx
xxx
xf is continuous at ,2
x then k
(a.)
161
(b.)
321
(c.)
641
(d.)
281
Sol. (c)
For )(xf to be continuous at ,2
x we must have
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Q18 If ]),[]([.1)( xxxxf then ][ is GIF
(a.) )(xf is continuous and differentiable at 1x (b.) )(xf is discontinuous at 1x
(c.) )(xf is continuous at 2x (d.) )(xf is continuous but non-differentiable at 1x
Sol. (d)
Q19 The 2),1(),1(max)( xxxf is, where ),( x (a.) discontinuous at all points (b.) differentiable at all points (c.) differentiable at all points except 1 and 1 (d.) continuous at all points except 1 and 1
Sol. (c)
We draw the graph of xyxy 1,1 and 2y
}2,1,1{.max)( xxxf
1,1)( xxxf
21,2 x
2,1 xx
From graph it is clear that )(xf is continuous at all x and differentiable at all x except 1x and 1x Q20
If
1
1,0)( 2
2
xcaxbxxbbax
xf then )(xf is continuous and differentiable at 1x if
(a.) bac 2,0 (b.) Rcba , (c.) 0, cba (d.) 0, cba
Sol. (a)
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Q21 If )(),( xgxf be twice differentiable functions on ]2,0[ satisfying 4)1(',2)1('),(")(" gfxgxf
and ,9)2(,3)2( gf then )()( xgxf at 4x equals
(a.) 0 (b.) 10 (c.) 8 (d.) 2
Sol. (b)
Let )()()( xgxfxh
)(')(')(' xgxfxh
0)(")(")(" xgxfxh
cxh )(' … (1)
kcxxh )( … (2)
From (1)
242)1(')1(')1(' gfhc
Also 693)2()2()2( gfh
From (2),
kch 2)2(
k 46 2k
Hence 22)( xxh
10242)4( h
Q22 The differential coefficient of xeca1
10 coslog
is
(a.)
axxxec
a xec
1021
log
log1
1cos
1cos10
(b.)
axxxec
a xec
1021
log
log1
1cos
1cos10
(c.)
10log1
1cos 21
log 1cos10
axxxec
a xec
(d.)
10log1
1cos 21
log 1cos10
axxxec
a xec
Sol. (b)
Let
xecay
1cos10log
axecy elog.cosloglog 110
aexec ee log.log.coslog 101
axece 101 log.coslog
Differentiating w.r. to x , we get
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
31
1
1cos
1.log12110
xxxeca
dxdy
y
xecxxay
dxdy
1210 cos1.
11log
xecxxaa xec
1210
log
cos1
log.
1cos10
Q23 If )(.)(.)()( zfyfxfzyxf for all zyx ,, and ,3)0(',4)2( ff then )2('f equals
(a.) 12 (b.) 9 (c.) 16 (d.) 6
Sol. (a)
Q24 Let the function )(xfy be given by ,7205 35 tttx and ,31834 23 ttty where
).2,2(t Then )(' xf at 1t is
(a.)
25
(b.)
52
(c.)
57
(d.)
75
Sol. (b)
Q25 The maximum slope of the curve 2723 23 xxxy is
(a.) 5 (b.) 5 (c.)
51
(d.)
51
Sol. (a)
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Q26
Let ,1,23
10,2
sin)(
xx
xxxf
then
(a.) )(xf has local maxima at 1x (b.) )(xf has local minima at 1x
(c.) )(xf does not have any local extrema at 1x (d.) )(xf has a global minima at 1x
Sol. (a)
Q27 Consider the statements (i) xxn )1( in ),0( (ii) )1( xnx in ),0( (iii) xx tan in )2/,0( (iv) xx tan in )2/,0( Among above statements
(a.) (i) and (iii) are correct (b.) (i) and (iv) are correct (c.) (ii) and (iii) are correct (d.) (ii) and (iv) are correct
Sol. (a)
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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Q28 Let .41,|43|)( 2 xxxxf Then
(a.) )(xf is monotonically increasing in
23,1
(b.) )(xf is monotonically increasing in
4,
23
(c.) The minimum value of )(xf is
41
(d.) The maximum value of )(xf is 2
Sol. (a)
Q29 If Rxxf 0)(" and )6()2()( 22 xfxfxg then
(a.) )(xg is an increasing in ]0,2[ (b.) )(xg is an increasing in ),2[
(c.) )(xg has a local minima at 2x (d.) )(xg has a local maxima at 2x
Sol. (d)
Q30 The probability of a man hitting a target is .
41
If he fires n times such that the probability of his hitting the
target at least once is greater than ,32
then the value of n is
(a.) 3 (b.) 4 (c.) 5 (d.) 2
Sol. (b)
Let p is the probability of hit and q is the probability of miss
12th Mains 23rd July Test Solution
101, Blue Diamond Complex, Fatehgunj, Vadodara-02 .Tel. No. 2787268 / 2750018 / 2782232
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4n