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Copyright reserved Please turn over T870(E)(N21)T NOVEMBER EXAMINATION NATIONAL CERTIFICATE MATHEMATICS N3 (16030143) 21 November 2016 (X-Paper) 09:00–12:00 Nonprogrammable scientific calculators may be used. This question paper consists of 6 pages and 1 formula sheet.

N3 Mathematics November 2016 - Future Managers...ALL values at the points of intersection with the system of axes and the coordinates of the turning points must be shown. (6) 6.4.2

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Page 1: N3 Mathematics November 2016 - Future Managers...ALL values at the points of intersection with the system of axes and the coordinates of the turning points must be shown. (6) 6.4.2

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T870(E)(N21)T

NOVEMBER EXAMINATION

NATIONAL CERTIFICATE

MATHEMATICS N3

(16030143)

21 November 2016 (X-Paper) 09:00–12:00

Nonprogrammable scientific calculators may be used.

This question paper consists of 6 pages and 1 formula sheet.

Page 2: N3 Mathematics November 2016 - Future Managers...ALL values at the points of intersection with the system of axes and the coordinates of the turning points must be shown. (6) 6.4.2

(16030143) -2- T870(E)(N21)T

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DEPARTMENT OF HIGHER EDUCATION AND TRAINING REPUBLIC OF SOUTH AFRICA

NATIONAL CERTIFICATE MATHEMATICS N3

TIME: 3 HOURS MARKS: 100

INSTRUCTIONS AND INFORMATION 1. 2. 3. 4. 5. 6. 7. 8.

Answer ALL the questions. Read ALL the questions carefully. Number the answers according to the numbering system used in this question paper. Questions may be answered in any order but subsections of questions must NOT be separated. Clearly show ALL calculations, diagrams, graphs, et cetera, which you have used in determining the answers. If necessary, answers should be rounded off to THREE decimals, unless stated otherwise. Diagrams are NOT drawn to scale. Write neatly and legibly.

Page 3: N3 Mathematics November 2016 - Future Managers...ALL values at the points of intersection with the system of axes and the coordinates of the turning points must be shown. (6) 6.4.2

(16030143) -3- T870(E)(N21)T

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QUESTION 1 1.1 Simplify: 1.1.1 (2) 1.1.2

(7) 1.1.3

(6) 1.2 If is divided by , the remainder is –7. Determine the

value of .

(4) [19] QUESTION 2 2.1 Express as a power of 4. (3) 2.2 Solve for :

2.2.1

Show All the steps. The use of a calculator is excluded.

(6)

2.2.2

(5) [14] QUESTION 3 3.1 Solve for by completing the square: (5) 3.2 There are 302 residents in a town. There are 34 more women than men and 60 more

children than women. How many women are there?

(3) 3.3 Given:

Calculate the value of if =2000, =0,48 and =18,3.

(5) [13]

249 56 16x x+ +

1 21 13 3 ( 2)a a a a

- - -æ ö- + -ç ÷

è ø

2 2

2 2

3 7 2 62 5 3 9x x x xx x x- + + -

÷- - -

31216 23 ++- xpxx 12 +xp

0,125

x3 32log + log log 2 04 4

x xæ ö- + =ç ÷è ø

24 2 3 52 4 2

xx x x

-+ =

- - +

x 218 9x x- - =

CPV n =n P V C

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(16030143) -3- T870(E)(N21)T

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QUESTION 4

4.1 Prove that the midpoint M, of AC is equal to .

(2) 4.2 Use the co-ordinates of the midpoint, M to determine the co-ordinates of

the fourth vertex, D.

(3) 4.3 Determine the length of BC. (2) 4.4 Calculate the angle of inclination, of the line BC. (2) 4.5 Determine the equation of the line in the form which is

perpendicular to BC and passes through A.

(3) 4.6 Determine the coordinates of the point of intersection of the line through

A(-2;1), which is parallel to the y-axis and the line .

(3) [15]

1 1( ; )2 2

- -

a

y mx c= +

2 5y x- =

Consider FIGURE 1 below. ABCD is a parallelogram with vertices A(-2;1), B (2;2), C(1;-2) and D .

FIGURE 1

( ; )x y

Page 5: N3 Mathematics November 2016 - Future Managers...ALL values at the points of intersection with the system of axes and the coordinates of the turning points must be shown. (6) 6.4.2

(16030143) -3- T870(E)(N21)T

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QUESTION 5 5.1 Sketch the graph of in the ANSWER BOOK. ALL values at the points

of intersection with the axes must be shown.

(3)

5.2 FIGURE 2 shows the graph of .

A and B(6;0) are turning points.

FIGURE 2 5.2.1 Find the values of , and . Show ALL your calculations. (5) 5.2.2 If , find the coordinates of A. (4) 5.3 Determine if by making use of the rules of differentiation. ALL

final answers must be with positive exponents and in surd form where applicable.

(4)

[16]

236y x= - -

3 2( )f x x ax bx c= - + + +

a b c

3 2( ) 12 36f x x x x= - + -

dydx

12

2

3y xx

= -

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(16030143) -6- T870(E)(N21)T

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QUESTION 6 6.1 Make use of trigonometric identities to prove the following:

(7) 6.2 To find the height of a tower, a surveyor sets up his theodolite 150 m from the base of

the tower. He finds that the angle of elevation to the top of the tower is 60°. What is the height of the tower?

(3) 6.3

Consider FIGURE 3 below. The crew in a boat, C noticed two lighthouses A and B, one on either side of a beach. The two lighthouses are 0,67 km apart and one is exactly due east of the other. The lighthouses tell how close a boat is by taking bearings to the boat. The bearing from the lighthouse A to the boat C is 127° and the bearing from the lighthouse B to the boat C is 255°. A bearing is an angle measured clockwise from north. Calculate how far the boat, C is from the lighthouse at B.

(5)

FIGURE 3

6.4 6.4.1 Draw the graphs which are represented by

on the same system of axes for . ALL values at the points of intersection with the system of axes and the coordinates of the turning points must be shown.

(6) 6.4.2 Use the graph to read off the value(s) of if for (2)

[23] TOTAL: 100

2 o

o 2

cos (90 ) 1 cossin(90 ) 1 sin cos

x xx x x

+ -=

- + -

( ) 2sin 2 and ( ) cos 2f x x g x x= =0 180x° £ £ °

x 2 tan 2 1x = 0 180x° £ £ °

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(16030143) T870(E)(N21)T

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FORMULA SHEET 1. Factors 3. Quadratic formula

4. Parabola 2. Logarithms

5. Circle

6. Straight line 8. Trigonometry

Perpendicular lines : Parallel lines :

Distance :

Midpoint :

Angle of inclination : 7. Differentiation

For turning point :

3 3 2 2( )( )a b a b a ab b- = - + + 2 42

b b acxa

- ± -=

3 3 2 2( )( )a b a b a ab b+ = + - +

2y ax bx c= + +

log log logab a b= +24

4ac bya-

=

log log loga a bb= -

2bxa-

=

logloglog

cb

c

aab

=

log logma m a=1log

logba

ab

=2 2 2x y r+ =

log 1 , ln 1a a e= \ = 2

4xD hh

= +

log ln,a t ma t e m= \ = 24 4x Dh h= -

1 1( )y y m x x- = - 1sincos

yr ec

qq

= =

1 2 1m m´ =-

1 2m m=1cossec

xr

qq

= =coscotsin

qqq

=

2 22 1 2 1( ) ( )D x x y y= - + - 1tan

cotyx

qq

= =sintancos

qqq

=

1 2 1 2;2 2

x x y yM + +æ ö=ç ÷è ø

2 2sin cos 1q q+ =

1tan mq -= 2 21 tan secq q+ =2 21 cot cosecq q+ =

sin sin sinA B Ca b c

= =

0

( ) ( )limh

dy f x h f xdx h®

+ -=

2 2 2 2 cosa b c bc A= + -

1( )n nd x nxdx

-=1Area of sin2

ABC ac BD =

'( ) 0f x =