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Mixture of benzoic acid, anthracene, and p-nitroaniline
Extractions
COH
O
NH2
NO2
Mixture
Density of CH2Cl2 is 1.33 g/mL
CH2Cl2
H2O
Methylene Chloride and Water
If we dissolve NaCl in this mixture which phase has the highest salt concentration?
Salts concentrate in the water layer
Add Salt
If we dissolve benzoic acid in this mixture in which phase would it concentrate?
Neutral organic compounds concentrate in the organic phase
Salts
Add Benzoic Acid
Salts in water phase
Neutral organic compounds in the organic phase
Water
CH2Cl2
Phases
COOH + Na OH COO Na
Benzoic Acid Sodium Benzoate
Treatment of benzoic acid with sodium hydroxide converts it into the salt, sodium benzoate.
Sodium Benzoate
COOH + Na OH COO Na
Salts in Water Phase
NH3 + HCl NH4+ Cl-
Base Acid Salt
Ammonia and Acid
NH2O2N + HCl NH3O2N Cl
Aniline and Acid
Use separatory funnel for separating liquid phases.
Separatory Funnel
Hold stopper and stopcock
Shake to be sure phases equilibrate
Vent frequentlyVent frequently
benzoic Acid
p-nitroaniline
anthracene
HCl CH2Cl2
NH3O2N ClBenzoic acid
Anthracene
Extract with HCl
benzoic Acid
anthracene
NaOH CH2Cl2
COO Na anthracene
Extract with NaOH
NH3O2N Cl COO Na
NH2O2N
NaOH
COOH
Filter wash dry weigh
HCl
Filter wash dry weigh
Dry filter evaporate weigh
Extraction Summary
Addition of acid to the sodium benzoate solution causes benzoic acid to precipitate.
Precipitate Benzoic Acid
The benzoic acid is filtered, washed, and dried.
Purify Benzoic Acid
Weigh the benzoic acid and measure its melting point.
Weight, m.p.
NH2O2NNH3O2N ClNaOH
Cool to complete precipitation
Precipitate p-Nitroaniline
Dry the methylene chloride solution of anthracene with a small amount of sodium sulfate.
Dry Methylene Chloride
Remove the drying agent by filtration through a fluted filter paper.
Filter
Evaporate the methylene chloride on a steam bath.
Use an inverted funnel connected to the vacuum line to collect the vapor.
Remove Methylene Chloride
Put your samples in labeled vials and give them to your TA.
Weigh your products and measure their melting points.
10 g t-butyl alcohol100 mL ether100 mL water
Partition Coefficients
2.2 = x g / 200 mL
( 10 - x)g /100 mL
x = 8.1 grams
10 grams t-butyl alcohol
Extract once with 200 mL or twice with 100 mL?
Which is better?
Extract once with 200 mL yields 6.7 grams
Extract once with 100 mL yields 5.0 grams
Second extraction with 100 mL yields 2.5 grams
Total 2 extractions with 100 mL = 7.5 grams
If K = 1.0, a = 10 grams, S2 = 100 mL
Grams extracted vs. number of extractions