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The IITian’s Prashikshan Kendra A Resonance of Brilliant Minds…! Answerkey - Test – 4 (Jan. 2014) In-Program Test for PRODIGY (SCHOLARS) Program MATHEMATICS Sol.1 (c) Sol.2 (a) = Sol.3 (d) Sol.4 (d) Sol.5 (b) We have . Sol.6 (b) If a, b, c are in G. P. Then c . Sol.7 (c) Roots of the equation are equal Page 1 of 5

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STWT-5

The IITians Prashikshan Kendra

A Resonance of Brilliant Minds!

Answerkey - Test 4 (Jan. 2014)In-Program Test for PRODIGY (SCHOLARS) Program

MATHEMATICS Sol.1(c)

Sol.2(a)

=

Sol.3(d)

Sol.4(d) (

Sol.5(b) We have .

Sol.6(b) If a, b, c are in G. P. Then c

.

Sol.7(c) Roots of the equation are equal

(

(

(

(

Sol.8(a) = by

= by

= by

But

Sol.9(a) If are the roots, then

(

and

(

The required equation is

Sol.10(a) Given series

Hence nth term of given series .So,

Sol.11(c) Sum of root and product of roots

So,

Sol.12(d) Series, are in H.P. ( will be in A.P.

Now first term and common difference

So, 5th term of the A.P = ,Hence 5th term in H.P. is 10.Sol.13(c)

Sol.14(c) by

by

Sol.15(d) Accordingly,

EMBED Equation.3

.

Sol.16(a)

Squaring on both sides, we get

,

Sol.17(c) We have , therefore is in IV quadrant.,So

Now

(

(

(

Sol.18(a) We have

(

(

(

( .Sol.19(b)

=

=

Sol.20(d)

(

(

CHEMISTRY

Sol.41(a) Because of smallest size.

Sol.42(a) Increases from left to right since, the size decreases.

Sol.43(a)

Sol.44(a)

Sol.45(d)

Sol.46(a)s character in

s character in

s character in

Sol.47(a) Mg Ba. Both belong to IIA group.

Sol.48(a)

Sol.49(c)

Sol.50(b)

Sol.51(c)Sol.52(c)Sol.53(a)

( 4( bonds)

Sol.54(d)

Sol.55(a) As pressure is constant use ; ; On solving ml

Sol.56(a) mm

Sol.57(b)

Sol.58(a) Use or

EMBED Equation.3 gm/liter

Sol.59(c) Using

gm

Sol.60(c) Under similar conditions of pressure and temperature equal volume of and will have same number of molecules.

Hence in 2L of molecules will be 2N.

Page 1 of 4The IITians Prashikshan Kendra A Resonance of Brilliant Minds!

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