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Math Analysis Notes 1
Math Analysis
Chapter 2 Notes: Polynomial and Rational Functions
Day 13: Section 2-1 Complex Numbers; Sections 2-2 Quadratic Functions
2-1: Complex Numbers
After completing section 2-1 you should be able to do the following:
1. Add and subtract complex numbers
2. Multiply complex numbers
3. Divide complex numbers
4. Perform Operations with square roots of negative numbers
5. Solve quadratic equations with complex imaginary solutions
In order to take a square root of a negative number mathematicians invented an expanded system of numbers
called complex numbers.
Complex Numbers
The set of all numbers in the form
a + bi
with real numbers a and b, and i, the imaginary unit are called the set of complex numbers. The real number a
is called the real part and the real number b is called the imaginary part of the complex number a + bi.
In order to add complex numbers you must add like terms.
Practice: In 1-2, Add or subtract as indicated:
1. (5 – 2i) + (3 + 3i) 2. (2 + 6i) – (12 – i)
In order to multiply complex numbers it is done using the distributive property and the FOIL method.
After completing multiplication, we replace any occurrences of i2 with −1.
Practice: In 1-2, Find the products:
1. 7i(2 – 9i) 2. (5 + 4i)(6 – 7i)
The Imaginary Unit i The imaginary unit is defined as
1i , where i2 = −1
Conjugate of a Complex Number The complex conjugate of the number a + bi is a – bi, and the complex conjugate of a – bi is a + bi. The
multiplication of complex conjugates gives a real number:
(a + bi)(a – bi) = a2 + b
2
(a – bi)(a + bi) = a2 + b
2
Math Analysis Notes 2
In order to divide complex numbers is really a process of multiplying by the complex conjugate of the
denominator. Remember that you want to keep the expression the same value so you must multiply by 1, so
what ever you do to the bottom of a fraction you must do to the top of the fraction.
Practice: In 1-2, Divide and express the result in standard form:
1. 5 4
4
i
i
2.
7 3
4
i
i
Roots of Negative Numbers
When performing operations with square roots of negative numbers, begin by expressin all square roots
in terms of i. The perform the indicated operations.
Practice: In 1-4, Perform the indicated operations and write the result in standard form.
1. 27 48 2. 2
1 5
3. 25 50
15
4. 9 25
Quadratic Equations with Complex Imaginary Solutions
A quadratic equation can be expressed in the general form ax2 + bx + c = 0 and can be solved using the
quadratic formula: 2 4
2
b b acx
a
When solving quadratic equations that have complex imaginary solutions you must express the final answer in
standard form a + bi.
Principal Square Root of a Negative Number
For any positive real number b, the principal square root of the negative number −b is defined by:
b i b
Math Analysis Notes 3
Practice: Solve using the quadratic formula: x2 – 2x + 2 = 0
2-2 Quadratic Functions
After completing section 2-2 you should be able to do the following:
1. Use transformations of the common function y = x2 to determine the characteristics of parabolas.
2. Graph parabolas (quadratic equations)
3. Determine quadratic function’s minimum or maximum value
Graph Quadratic Functions in Standard Form
Steps for changing from general form to standard form of a quadratic function.
1. Move constant term to other side of equal sign.
2. Factor out “a” if it is not 1.
3. Complete the square, remember what you add to one side you must add to the other.
4. Factor the x side to a square of a binomial.
5. Resolve for y and the quadratic should now be in standard form: y = a(x – h)2 + k
Practice: in 1-2, Rewrite the quadratic into standard form:
1. f(x) = x2 – 6x + 10 2. f(x) = 3x
2 + 12x – 8
The standard Form of a Quadratic Function
The quadratic function 2
( ) ( )f x a x h k
is in standard form. The graph of f is a parabola whose vertex is at the point (h, k). The parabola is
symmetric with respect to the line x = h. If a > 0, the parabola opens upward; if a < 0, the parabola opens
downward.
Graphing Quadratic Functions with Equations in Standard Form
1. Determine whether the parabola opens upward or downward. If a > 0, it opens upward. If a < 0,
it opens downward.
2. Determine the vertex of the parabola. The vertex (h, k).
3. Find any x-intercepts by solving f(x) = 0. The function’s real zeros are the x-intercepts.
4. Find the y-intercepts by evaluating f(0).
5. Plot the intercepts, the vertex and additional points as necessary. Connect these points with a
smooth curve that is shaped line a “u”. called a parabola.
Math Analysis Notes 4
Practice: Graph the quadratic function f(x) = −x2 + 2x + 3. Find the vertex and intercepts to sketch the graph.
Give the equation of the parabola’s axis of symmetry. Use the graph to determine the function’s domain and
range (use interval notation).
Minimum and Maximum Values of Quadratic Functions.
If a parabola opens downward a < 0, then the quadratic function has a maximum at the vertex (h, k).
If a parabola opens upward a > 0, then the quadratic functions has a minimum at the vertex (h, k).
Practice: In 1-2, (a) Determine without graphing, whether the function has a minimum value or a maximum
value. (b) Find the order pair were the minimum value or maximum values occur. (c) Identify the function’s
domain and its range without graphing.
1. f(x) = 3x2 – 12x – 1 2. f(x) = −4x
2 + 8x – 3
Math Analysis Notes 5
More Trig Review
A ratio of the lengths of two sides of a right triangle is called a trigonometric ratio. The six trigonometric
ratios are defined for the acute angles of a right triangle as:
leg opposite to sin
hypotenuse
A opp aA
hyp c
leg adjacent to cos
hypotenuse
A adj bA
hyp c
leg opposite to tan
leg adjacent to
A opp aA
A adj b
hypotenuse 1csc
leg opposite to sin
hyp cA
A opp a A
hypotenuse 1sec
leg adjacent to cos
hyp cA
A adj b A
leg adjacent to 1cot
leg opposite to tan
A adj bA
A opp a A
C
b
ca
B
A
A harmonic that can be used to remember the 1st three trigonometric ratios: sine, cosine, and tangent is
SOH-CAH-TOA. To remember the reciprocal functions cosecant, secant, and cotangent you can use
“HO”, “HA” and “AO” respectively.
Practice: In 1-2, Use the given trigonometric equation to find the remaining five trigonometric equations.
1.) 6
sin2
X 2.) 3
csc4
G
Practice: In 3-6, Use the given trigonometric equation to find the indicated trigonometric ratio.
3.) sec 2, cot ?X X 4.)
2sin , tan ?
2X X
5.) csc 5, cos ?X X 6.)
3tan , sin ?
2X X
Math Analysis Notes 6
Day 14: Section 2-3 Polynomial Functions and Their Graphs
After completing section 2-3 you should be able to do the following:
1. Identify polynomial functions and state their degree.
2. Determine left and right side end behavior
3. Use factoring to find zeros of polynomial functions
4. Identify zeros and their multiplicities
5. Use the Intermediate Value Theorem
6. Understand the relationship between degree and turning points.
7. Graph polynomial functions
Examples of Polynomials:
Degree Type Standard Form
0 Constant 0
( )f x a example: f(x) = 10
1 Linear 1 0
( )f x a x a example: f(x) = 2x + 5
2 Quadratic 2
2 1 0( )f x a x a x a example: 21 5 1
2 3 4( )f x x x
3 Cubic 3 2
3 2 1 0( )f x a x a x a x a example: f(x) = 5x
3 – 3x + 1
4 Quartic 4 3 2
4 3 2 1 0( )f x a x a x a x a x a example: 45
23
x
A polynomial may not have x in the denominator of the expression, also all exponents on the variable must be
positive whole numbers.
Practice: 1-4, Determine which functions are polynomial functions. For those that are, identify the degree.
1. 3 2 17 2( )h x x x
x 2.
7
2( )
xf x
3.
1
22 3 5( )g x x x 4. 5
8
8( )
xk x
x
Graphs of Polynomials are Smooth and Continuous Graphs
Polynomial functions of degree 2 or higher have graphs that are smooth and continuous. By smooth, we mean
that the graphs contain only rounded curves with no sharp corners. By continuous, we mean that the graphs
have no breaks and can be drawn without lifting your pencil from the rectangular coordinate system.
Definition of a Polynomial Function
A polynomial function is a function of the form: 1 2
1 2 1 0( ) ....
n n n
n n nf x a x a x a x a x a
The exponents are all whole numbers, and the coefficients are all real numbers.
Math Analysis Notes 7
End Behavior of Graphs of Polynomial Functions
Graphs of Polynomials Functions Not Graphs of Polynomials Functions
Smooth
rounded
corner
Smooth
rounded corner
Smooth
rounded corner
Smooth
rounded corner
Smooth
rounded corner
Discontinuous:
a break in the graph
Sharp
Corner
Sharp
Corner
Odd-degree polynomial functions have graphs with opposite behavior at each end.
Even-degree polynomial functions have graphs with the same behavior at each end.
The Leading Coefficient Test
The coefficient on the term with the largest exponent on the variable is called the leading coefficient.
If the largest exponent is an odd number:
If the leading coefficient is
positive, the graph falls to
the left and rises to the right.
If the leading coefficient is
negative, the graph rises to
the left and falls to the right.
Falls
Left
Rises
Right
Rises
Left
Falls
Right
Odd Degree; positive leading
coefficient
Odd Degree; negative leading
coefficient
Math Analysis Notes 8
Practice: In 1-4, Use the Leading Coefficient Test to determine the end behavior of the graph of each function:
1. f(x) = 5x + 2x2 – 3x
3 2. f(x) = x
4 + 2x
3 + 3x
2 + 5x – 20
3. f(x) = 7x7 4. f(x) = 5x
5 −3x
6
Zeros of Polynomial Functions
A zero of a polynomial function is found by setting the functions equal to zero and solving the resulting
equation. Zeros are also called solutions and roots.
If a zero occurs at the same x-value an even number of times the graph of the function at that point
touches the x-axis and turns around.
If a zero occurs at the same x-value an odd number of times the graph of the function at that point
crosses the x-axis.
The Leading Coefficient Test (continued)
The coefficient on the term with the largest exponent on the variable is called the leading coefficient.
If the largest exponent is an even number:
If the leading coefficient is
positive, the graph rises to
the left and rises to the right.
If the leading coefficient is
negative, the graph falls to
the left and falls to the right.
Rises
Right Rises
Left
Falls
Right
Falls
Left
Even Degree; positive leading
coefficient
Even Degree; negative leading
coefficient
Math Analysis Notes 9
Practice: In 1-4, Find the zeros for each polynomial function and give the multiplicity for each zero. State
whether the graph crosses the x-axis or touches the x-axis and turns around, at each zero.
1. f(x) = 2x(x – 4)2(x + 3)
3 2. f(x) = 4(x – 3)(x + 2)
2
3. f(x) = x3 − 2x
2 + x 4. f(x) = x
3 + 7x
2 – 4x – 28
Zero occurs an odd
number of times at
x = −3, because it
crosses the x-axis.
Zero occurs an odd
number of times at
x = 4, because it
crosses the x-axis.
Zero occurs an even number of
times at x = −1, because it turns
around at that point.
The Intermediate Value Theorem for Polynomials
Let f be a polynomial function with real coefficients. If f(a) and f(b) have opposite signs, then there is at
least one value of c between a and b for which f(c) = 0. Therefore, the equation f(x) = 0 has at least one
real root between a and b.
Math Analysis Notes 10
Practice: In 1-2, Use the Intermediate Value Theorem to show that each polynomial has a real zero between the
given integers.
1. f(x) = x3 – x
2 – 1; between 1 and 2 2. f(x) = x
3 + x
2 – 2x + 1 between −3 and −2
Graphing a Polynomial Function.
1. Use the Leading Coefficient Test to determine the graph’s end behavior.
2. Find the x-intercepts by setting f(x) = 0 and solving the resulting polynomial equation.
If the same zero occurs an even number of times, the graph touches the x-axis at that x-value and
turns around.
If the same zero occurs an odd number of times, the graph crosses the x-axis at that x-value.
3. Find the y-intercept by computing f(0).
4. Use symmetry, if applicable, to help draw the graph.
y-axis of symmetry: f(−x) = f(x) (even function)
Origin symmetry: f(−x) = −f(x) (odd function)
5. Use the fact that the maximum number of turning points of the graphs is the degree minus 1 to check
whether it is drawn correctly.
Practice: In 1-2, (a) Use the Leading Coefficient Test to determine the graph’s end behavior. (b) Find the x-
intercepts. State whether the graph crosses the x-axis, or touches the x-axis and turns around, at each intercept.
(c) Find the y-intercept. (d) Determine whether the graph has y-axis of symmetry, origin symmetry, or neither.
(e) If necessary, find a few additional points and graph the function.
1. f(x) = −x4 + 16x
2 2. f(x) = x
2(x – 1)
3(x + 2)
Math Analysis Notes 11
Day 15: Section 2-4 Dividing Polynomials; Remainder and Factor Theorems; Section 2-5 Zeros of
Polynomial Functions.
After completing section 2-4 you should be able to do the following:
1. Use long division to divide polynomials
2. Use synthetic division to divide polynomials
3. Evaluate a polynomial using the Remainder Theorem
Long Division of Polynomials
Practice In 1-2, divide using long division. State the quotient, q(x) and the remainder, r(x).
1. (12x2 + x – 4) ÷ (3x – 2) 2.
5 4 3 2
3
2 8 2
2 1
x x x x
x
1. Arrange the terms of both the dividend and the divisor in descending powers of the variable.
2. Divide the first term in the dividend by the first term in the divisor. The result is the first term
of the quotient.
3. Multiply every term in the divisor by the first term in the quotient. Write the resulting product
beneath the dividend with like terms lined up.
4. Subtract the product for the dividend.
5. Bring down the next term in the original dividend and write it next to the remainder to form a
new dividend.
6. Use this new expression as the dividend and repeat this process until the remainder can no
longer be divided. This will occur when the degree of the remainder (the highest exponent on a
variable in the remainder) is less than the degree of the divisor.
Math Analysis Notes 12
Synthetic Division: Use only when divisor is a linear expression.
To divide a polynomial by x – c Example
5 32 6 2 3 1x x x x
1. Arrange the polynomial in descending powers, 1. 6x5 + 0x
4 – 2x
3 + 0x
2 – 3x + 1
with a 0 coefficient for any missing term.
2. Write c for the divisor, x – c. To the right, 2. 2 6 0 −2 0 −3 1
Write the coefficients of the dividend.
3. Write the leading coefficient of the dividend 3. 2 6 0 −2 0 −3 1
on the bottom row. Bring down 6
6
4. Multiply c (in this case 2) times the value just 4. 2 6 0 −2 0 −3 1
written on the bottom row. Write the product 12
in the next column in the second row. 6
5. Add the values in this new column, writing 5. 2 6 0 −2 0 −3 1
the sum in the bottom row. 12 Add
12
6. Repeat this process of multiplications and 6. 2 6 0 −2 0 −3 1
additions until all columns are filled in. 12 24 Add
6 12 22
2 6 0 −2 0 −3 1
12 24 44 88 170
6 12 22 44 85 171
7. Use the numbers in the last row to write the
Quotient, plus the remainder above the divisor.
The degree of the first term of the quotient is
one less than the degree of the first term of
the dividend. The final value in this row is the
remainder.
5 32 6 2 3 1x x x x
Multiply by 2:
2 • 6 = 12
Multiply by 2:
2 • 12= 24
4 3 2 1716 12 22 44 85
2x x x x
x
Written Form
6 12 22 44 85 171
The last row of the synthetic division
Math Analysis Notes 13
Practice: In 1-2, divide using synthetic division.
1. (x2 – 5x – 5x
3 + x
4) ÷ (5 + x) 2.
7 5 310 12
2
x x x
x
Practice: In 1-2, use synthetic division and the Remainder Theorem to find the indicated function value.
1. f(x) = x3 – 7x
2 + 5x – 6; f(3) 2. f(x) = 6x
4 + 10x
3 + 5x
2 + x + 1;
2
3f
Zeros of Polynomial Functions After completing section 2-5 you should be able to do the following:
1. Use the Rational Zero Theorem to find possible rational zeros.
2. Find zeros of a polynomial function
3. Solve polynomial equations
4. Use the linear Factorization Theorem to find polynomials with given zeros.
The Rational Zero Theorem
If a polynomial is written in descending order of the variable then a list of possible zeros can be made from:
Factors of the constant termPossible rational zeros=
Factors of the leading coefficient
Practice: In 1-2, List all possible rational zeros of:
1. f(x) = 12x4 + 4x
5 – 3 – x 2. f(x) = x
3 + 2x
2 – 6
Finding the zeros of the Polynomial Function.
1. Begin by listing all possible rational zeros.
2. Use division to show that the remainder is zero.
Remember that The Remainder Theorem states the remainder is the value of the function.
The Remainder Theorem
If the polynomial f(x) is divided by x – c, then the remainder is f(c).
Math Analysis Notes 14
Practice: Find all the zeros of f(x) = x3 + x
2 – 5x – 2
Properties of a Polynomial Equation.
1. Counting the number of roots, zeros, or solutions separately, it should equal the degree (highest exponent on
the variable) of the polynomial.
2. If the polynomial has one complex imaginary root a + bi then it will also have it will also have the conjugate
complex imaginary root a – bi as a root also. Complex imaginary roots, if they exist, occur in conjugate pairs.
Practice: Solve: x4 – 6x
3 + 22x
2 – 30x + 13 = 0
The Linear Factorization Theorem
If 1 2
1 2 1 0( ) ....
n n n
n n nf x a x a x a x a x a
where n ≥ 1 and an ≠ 0, then
1 2( ) .......
n nf x a x c x c x c
Where c1, c2, ….cn are the zeros of the function. In words, an nth degree polynomial can be expressed as the
product of a non zero constant (an) and n linear factors.
Practice: Find an nth degree polynomial function with real coefficients satisfying the given conditions.
1. n = 3; 4 and 2i are zeros; f(−1) = −50 2. n = 4; 1
4 and 2 33
, , i are zeros; f(1)=100
Math Analysis Notes 15
Day 16: Section 2-6 Rational Functions and Their Graphs
After completing section 2-6 you should be able to do the following:
1. Find the domain of rational functions
2. Identify vertical asymptotes
3. Identify horizontal asymptotes
4. Identify slant asymptotes
5. Graph rational functions
Finding the Domain of a Rational Function.
Remember there are two things that restrict the domain and they are radical signs on variables and variables in
the denominator of fractions.
1. If you have even indexed radicals set what is under the radical greater than or equal to zero
and solve the resulting inequality for the domain.
2. If you have variables in the denominator set the denominator not equal to zero and sove the
resulting inequality for the domain.
Practice: in 1-3, Find the domain of each rational function. Write answer in interval notation.
1. 2 25
5( )
xf x
x
2.
2 4( )
xg x
x
3.
2
4
16( )
xh x
x
Vertical Asymptotes of Rational Functions
A vertical asymptote is a vertical line in the graph of the rational function that the graph will never intersect.
The graph of a rational function may have no vertical asymptote, one vertical asymptote, or several vertical
asymptote. We will use dashed lines to show asymptotes.
Graph the common function 1
( )f xx
.
Step 1 State Domain
The value of the domain that is
restricted is the value of the
asymptote(s). If the domain is all real
numbers then the graph of the
rational function has no vertical
asymptote.
Step 2 Graph the vertical asymptote as a
dashed line.
Step 3 Choose 3 x-values smaller and larger
than each vertical asymptote
Step 4 Connect points with smooth curve,
make sure you do not intersect the vertical
asymptote(s).
Math Analysis Notes 16
Rational Function
Rational Function are quotients of polynomial functions: ( )
( )( )
p xf x
q x .
Locating Vertical Asymptotes.
If ( )
( )( )
p xf x
q x is a rational function in which p(x) and q(x) have no factors and a is a zero of q(x), the
denominator, then x = a is a vertical asymptote of the graph of f.
The vertical asymptote is related to the domain. A vertical asymptote will exist at each restriction on the
domain of the rational function as long as the factor that produced the restriction is not a common factor
with the numerator.
Practice: In 1-3, Find the vertical asymptotes, if any, of the graph of each rational function:
1. 2 1
( )x
f xx
2. 2
1
1( )
xf x
x
3.
2
1
1( )
xf x
x
Horizontal Asymptotes of Rational Functions
If a function has a value that x that is restricted in it’s domain, the rational function may be a y-value the that is
also restricted. If a rational function has a restriction in it’s y-value we call that y-value a horizontal asymptote
at y = b, where b equals the y-value that is restricted.
Rules for finding Horizontal Asymptotes:
If ( )
( )( )
p xf x
q x is the rational function then:
1. The H.A. is y = 0 if the degree of q(x) is larger than p(x).
2. The H.A. is the ratio of the leading coefficients if the degree of q(x) is equal to the degree of p(x).
3. There is no H.A. if the degree of p(x) is larger than q(x).
Practice: Find the horizontal asymptote, if any, of the graph of each rational function:
1. 2
2
9
3 1( )
xf x
x
2.
2
9
3 1( )
xf x
x
3.
3
2
9
3 1( )
xf x
x
Math Analysis Notes 17
Graphing Rational Functions
1. Find vertical asymptote(s) and draw as a dashed vertical line on graph
2. Find horizontal asymptote and draw as a dashed horizontal line on graph
3. Choose 3 points smaller and larger than the for each vertical asymptote.
4. Plot points from step 3 connecting with a smooth curve making sure not to intersect the vertical or horizontal
asymptotes.
Practice: In 1-4, graph each rational function
1. 1
12
( )f xx
2. 3
2( )
xf x
x
Math Analysis Notes 18
3. 2
2
2
9( )
xf x
x
Slant Asymptotes.
We have seen that if the degree of the numerator is larger than the denominator then the rational function does
not have a horizontal asymptote. Over it may still have y-values that are restricted.
The graph of a rational function has a slant asymptote if the degree of the numerator is one more than
the degree of the denominator.
The slant asymptote is the equation y = the quotient of the division of the rational function.
Practice: Find the slant asymptote of 22 5 7
2( )
x xf x
x
Practice: Graph the rational function: 2 1
( )x
f xx
Math Analysis Notes 19
More Trig Review
Remember to use SOH-CAH-TOA & HO-HA-A0 to find the six trigonometric ratios.
Side
Adjacent
to A
Hypotenuse Side
Opposi te
to A
A
1sin ( )
csc
oppA SOH
hyp A
1cos ( )
sec
adjA CAH
hyp A
1tan ( )
cot
oppA TOA
adj A
1csc ( )
sin
hypA HO
opp A
1sec ( )
cos
hypA HA
adj A
1cot ( )
tan
adjA AO
opp A
Practice: In 1-2, Use the given trigonometric equation to find the remaining five trigonometric equations.
1.) 5
cos3
X 2.) 2
cot6
G
Practice: In 3-6, Use the given trigonometric equation to find the indicated trigonometric ratio.
3.) csc 3, tan ?X X 4.)
1sin , tan ?
2K K
5.) 5
sec , sin ?2
X X 6.) 3
cot , sec ?2
X X
Math Analysis Notes 20
Day 18: Section 2-7 Polynomial and Rational Inequalities
After completing section 2-7 you should be able to do the following:
1. Solve polynomial inequalities
2. Solve rational inequalities
Practice 1-4: Solve each polynomial inequality and graph the solution set on a real number line. Express each solution set in interval
notation.
1. x2 – 5x + 4 > 0 2. 5x ≤ 2 – 3x
2
3. (x – 1)(x – 2)(x + 3) > 0 4. x4 + x
3 + 4x
2 + 4x ≥ 0
Procedure for Solving Polynomial Inequalities
1. Express the inequality in the form:
0 or 0( ) ( )f x f x
where f is a polynomial function.
2. Solve the equation f(x) = 0. The solutions are boundary points.
3. Locate these boundary points on the number line, thereby dividing the number line into intervals.
4. Choose one representative number, called a test value, within each interval and evaluate f at that number.
If the value of f is positive, then f(x) > 0 for all numbers x, in the interval.
If the value of f is negative, then f(x) < 0 for all numbers x, in the interval.
5. Write the solution set, selecting the interval or intervals that satisfy the given inequality.
Math Analysis Notes 21
Solving Rational Inequalities
Practice: In 1-4, Solve each rational inequality and graph the solution set on a real number line. Express each solution set in interval
notation.
1. 5
02
x
x
2.
2 60
1
x x
x
3. 2
22
x
x
4. 0
2
x
x
Procedure for Solving Rational Inequalities
1. Express the inequality so that one side is zero and the other side is a single quotient, if necessary.
2. Set the numerator and the denominator of f equal to zero. These real solutions are the boundary points
3. Locate the boundary points on a number line and separate the line into intervals
4. Choose one test value within each interval and evaluate f at that number.
5. Write the solutions set, selecting the interval or intervals that satisfy the given inequality.
Math Analysis Notes 22
Day 19: Section 2-8 Modeling using Variation
After completing section 2-8 you should be able to do the following:
1. Solve direct variation problems
2. Solve inverse variation problems
3. Solve combined variation problems
4. Solve problems involving joint variation
Direct Variation If a situation is described by an equation in the form:
y = kx, where k is a nonzero constant, we say the y varies directly as x. The number k is called the constant of variation.
Practice:
1. The number of gallons of water, W, used when taking a shower varies directly as the time, t, in minutes, in the shower. A shower
lasting 5 minutes uses 30 gallons of water. How much water is used in a shower lasting 11 minutes?
2. The distance required to stop a car varies directly as the square of its speed. If 200 feet are required to stop a car traveling 60 miles
per hour, how many feet are required to stop a car traveling 100 miles per hour?
Inverse Variation If a situation is described by an equation in the form
ky
x
where k is a nonzero constant, we say that y varies inversely as x.
Practice:
1. The length of a violin string varies inversely as the frequency of its vibrations. A violin string 8 inches long vibrates at a frequency
of 640 cycles per second. What is the frequency of a 10-inch string?
Procedure for Solving Variation Problems
1. Write an equation that describes the given English statement.
2. Substitute the given pair of values into the equation in step 1 and solve for k, the constant of variation
3. Substitute the value of k into the equation in step 1.
4. Use the equation from step 3 to answer the problem’s question.
Math Analysis Notes 23
Combined Variation Some problems will use both direct variation and inverse variation to relate two variables. When this happens you will only have one
k value.
If a situation is described by an equation in the form
kzy
x
where k is a nonzero constant, we say that y varies directly with z and inversely with x.
Practice:
1. The number of minutes needed to solve an exercise set of variation problems varies directly as the number of problems and
inversely as the number of people working to solve the problems. It takes 4 people 32 minutes to solve 16 problems. How many
minutes will it take 8 people to solve 24 problems?
Joint Variation If a situation is described by an equation in the form
y kxwz
where k is a nonzero constant, we say that y varies jointly with x, w, and z.
Practice:
1. The volume of a cone, V, varies jointly as its height, h, and the square of its radius, r. A cone with a radius measuring 6 feet and a
height measuring 10 feet has a volume of 120π cubic feet. Find the volume of a cone having a radius of 12 feet and a height of 2 feet.
Math Analysis Notes 24
Math Analysis
Chapter 2 Review Sheet
Please use a separate sheet of paper to answer the following questions. Show all of your work! NO
WORK = NO CREDIT!
1. Show the process of completing the square to put the quadratic equation into vertex form. Then identify the
vertex. 2( ) 24 3 3f x x x .
2. The demand for motors depends on the price per motor. A manufacturer determines that the number of
motors he can sell is 23 444 80d p p where p is the price per motor in dollars. At what price will the
demand for motors be at a maximum?
3. Use the leading coefficient test to identify the left and right end behavior of the graph of 2 7( ) 3 5f x x x .
4. Use long division to divide: 4 3 2
2
3 4 4 9
3
x x x x
x x
.
5. Use synthetic division to divide: 4 1 1x x .
6. Find the zeros of the polynomial: 3 24 3 49 12x x x .
7. Write the complex number in standard form: 22 9i i
8. Divide and write the result in standard form: 3 2
4 6
i
i
.
9. Use the Rational Zero Theorem to determine the possible zeros of: 2 3 4( ) 8 2 3 5 3f x x x x x .
10. Write the polynomial equation of nth degree with real coefficients given zeros at 1 and 2 5i and
f(3) = 104.
11. Find the zeros of 4 3 22 7 5 28 12 x x x x given that (2x – 1) is one of the factors.
12. Determine the maximum number of zeros of: 5 3( ) 4 (3 2 1)f x x x x .
For questions 13-15, find all the zeros of each function.
13. 3 2( ) 4 7 12f x x x x . 14. 4 2( ) 34 225f x x x .
15. 4 3 2( ) 10 26 10 25f x x x x x
Math Analysis Notes 25
In 16-20, identify all of the equations of the horizontal, vertical, and slant asymptotes, if any exist. Find
the x- and y-intercepts, if they exist. State the domain of the function in interval notation. Then graph
the function.
16. 5
( )6
xf x
x
17.
2
5( )
16f x
x
18. 2
4( )
6
xf x
x x
19.
2
( )1
xf x
x
20. 3
2( )
4
xf x
x
In 21-22, write the polynomial function in standard form of the function graphed below.
21. The function passes through (1, −6) 22. The function passes through (−1, −4)
Items not on review sheet that will be on exam: 2-7 Solving Polynomial and Rational Inequalities
and 2-8 Variation and all trig review.
Math Analysis Notes 26
Trig Worksheet #7 Name:
Period:
In 1-2, Find the value of the other five trigonometric functions of θ.
1.) 5
sin13
2.) 2
tan5
In 3-4, Find the exact values of x and y.
3.) 4.)
In 5-6, Show all work and choose the best answer.
5.) Given 3
tan5
, what is the value of
cosθ?
(A) 34
5 (B)
3 34
34 (C)
5 34
34
(D) 5
3 (E) None of these
6.) What is the value of x in the triangle
shown:
(A) 8 (B) 8 2 (C) 8 3
(D) 16 2 (E) None of these
60
xy
6
3 6
y
x
4545
45
x16
Math Analysis Notes 27
Trig Worksheet #6 Name:
Period:
1.) Evaluate the six trigonometric functions of angle θ.
In 2-5, Use the given trigonometric equation to find the indicated ratio.
2.) 4
sin , sec ?5
3.) 5
cos , csc ?6
4.) 73
sec , sin ?8
5.) cot 3, sec ?
In 6-8, Find the exact values of x and y.
6.) 7.) 8.)
yx
45
13
y
4
x
60
2 3
yx
30
6
2 3
Math Analysis Notes 28
Trig Worksheet #5 Name:
Period:
In 1-9, Use the given trigonometric equation to find the indicated trigonometric ratio.
1.) 1
sin , cot ?2
X X
2.) 2
cos , csc ?2
X X 3.) tan 3, csc ?X X
4.) 4 3
sec , cot ?5
X X
5.) 4
csc , tan ?3
X X 6.) 5
cot , sin ?2
X X
7.) 5
csc , cos ?2
X X 8.) 6
tan , cos ?7
X X 9.) 4
cos , sec ?7
X X
Math Analysis Notes 29
Trig Worksheet #4 Name:
Period:
In 1-2, Write the six trigonometric ratios for D
1.)
2.)
In3-10, find the indicated trigonometric ration using the right triangles to the right. Final answers should be in
reduced fractional form.
3.) sin P
5.) secT
7.) tan D
9.) tan P
4.) csc D
6.) cot M
8.) cos M
10.) cscT
10
4 3
E
FD
E3 3
4 5
F
D
T
O
P
A 53
D
M 7 2
4
Math Analysis Notes 30
Trig Ws #3 Name:
Period:
In 1-2, Write the six trigonometric ratios for B :
1.)
2.)
In 3-8, Use the given trigonometric equation to find the indicated trigonometric ratio.
3.) 5
sin , cos ?17
U U
4.) 2 3
sec , cot ?3
K K 5.) 3
cot , sec ?4
E
6.) 6 3
csc , sin ?5
A A 7.) 3
tan , sec ?5
K K 8.) 5 2
cot , cos ?7
P P
48
I
B
G
8 2
8
I
BG