MASS HAUL DIAGRAMtutorial 3PREPARED BY : KMASZ

QUESTION 1

Chainage , mCut volume (m3)Fill volume (m3)(+ 10 % shrinkage)Corrected volume(+) CUT(-) FILL Cumulative volumes,m3

0100290200760300168040062048012050020600110700350800600900780100069011004001200120

0029029076010501680273062033501203470-203450-1103340-3502990-6002390-7801610-690920-400520-120400

QUESTION 2

Chainage (m)Volume of cutt (m3)Volume of fill (m3)Shrinkage volume (20%) Shrinkage volume corrected Corrected volume Cumulative volume (m3)(1)(2)(3)(4)(5)= (3)+(4) + for cutfor fill 050130001002250025075003004375 35013646400169794503050050093250550163250600229500

875.02729.23395.8

52501637520375

013000225007500-5250-16375-203753050093250163250229500

01300035500430003775021375100031500124750288000517500

From the data, draw a mass haul diagram using the scale below:X axis : 1 cm = 100 mY axis: 1 cm = 250 m3

Agregate volume for setting out circular curves proposed as follows:QUESTION 3Estimate of freehaul, haul and overhaul.

Chainage , mCumulative volumes,m300100290200105030027304003350480347050034506003340700299080023909001610100092011005201200400

Analysis of MHD; GivenFreehaul distance is 600 m ,Balance line at 400 m3 of aggregate volume.

Cumulative volume m3Chainage ,m

Draw a MHD using the scale below:X axis : 1 cm = 100 mY axis: 1 cm = 250 m3

X axis : 1 cm = 100 mY axis: 1 cm = 250 m3

GivenFreehaul distance is 600 m ,Balance line at 400 m3 of cumulative volume.Cumulative volume m3Chainage ,mMeasuring freehaul line = 6 cmFreehaul lineBalance line400m3 Cumulative volume6 cm

Freehaul volume = 6cm x 250 m3 = 1500 m3Freehaul distance = 600m (given)Axis y; Measurement line = 6 cmFreehaul = Freehaul volume x freehaul distance stn.m 100 Freehaul = 1500 x 600 = 9000 stn.m 100 Axis x; Measurement line = 6 cmFreehaul distance = 6cm x 100 m = 600 mCumulative volume m3Chainage ,m

Axis y; Measurement line AB = 12.3 cmHaul volume = 12.3cm x 250 m3 = 3075 m3Axis x; Measurement line EF = 6.1 cmHow to determine average haul distance???Average haul distance = Line AB /2 = 12.3 / 2 = 6.15

ABAt the point line parallel with axis-x = Line EF Average haul distance = 6.1 cm x 100 m = 610 mHaul = Haul volume x average haul distance stn.m 100 Haul = 3075 x 610 = 18757.5 stn.m 100 Chainage ,mCumulative volume m3

Axis y; Measurement line AB = 6.3 cmOverhaul volume = 6.3cm x 250 m3 = 1575 m3How to determine average over haul distance???Average overhaul distance = Line AB /2 = 6.3 / 2 = 3.15

At the point line parallel with axis-x = Line EF ABAxis x; Measurement line EF = 7.5 cmAverage overhaul distance = 7.5 cm x 100 m = 750 mOverhaul = Overhaul volume (average overhaul distance freehaul distance) stn.m 100 Overhaul = 1575 (750 600) = 2362.5 stn.m 100 STEP 5 determine overhaulChainage ,mCumulative volume m3

QUESTION 4Cumulative volume m3Chainage ,m

DistanceHAUL5.6cm X 50= 280mFREEHAUL4 cm x 50= 200mOVERHAUL6 cm x 50= 300m

VolumeHAUL4.4cm x 1000044000m3FREEHAUL0.8 cm x 100008000m3OVERHAUL3.6 cm x 1000036000m3WASTE13 cm x 10000130000m3

HAUL44000 x 280100123200 Stn. mFREEHAUL8000 x 20010016000Stn. mOVERHAUL36000 x (300-200)10036000Stn. m

QUESTION 5Cumulative volume m3Chainage ,m

DistanceFREEHAUL4 cm x 50200 mOVERHAUL4.9 cm x 50245 mFREEHAUL4 cm x 50200 mOVERHAUL7.2 cm x 50360 m

VolumeFREEHAUL4.4 cm x 500022 000m3OVERHAUL3.6 cm x 500018 000m3FREEHAUL2 cm x 500010 000m3OVERHAUL4.3 cm x 500021 500m3BORROW4.5 cm x 500022 500m3

TOTAL COST OF EARTHWORKFreehaul prices in freehaul distance = freehaul volume x freehaul distance x freehaul prices= (22 000 + 10 000) x 200 x RM1.25/200= RM 40 000

Overhaul prices in freehaul distance = overhaul volume x freehaul distance x freehaul prices= (18 000 + 21 500) x 200 x RM1.25/200= RM 49 375Overhaul prices in overhaul distance = overhaul volume x (average overhaul distance freehaul distance) x overhaul prices= [(18 000 x (245 200) x (RM1.25 + RM0.40)/100) + (21 500x (360 200) x (RM1.25 + RM0.40)/100)]=RM 70 125

Borrow prices= borrow volume x borrow prices= 22500 x RM 0.75 = RM 16 875TOTAL COST OF EARTHWORK = RM 176 375