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"#$% &'()*) &#*+,) -..)..*)/0 "#0)$1#, GCSE 23&4 1/ "#0()*#01'. &+)'151'#016/ - 718()$ 91)$ :#+)$ ;<=>6/?3#,'@,#06$A Edexcel Limited. Registered in England and Wales No. 4496750 Registered Office: One90 High Holborn, London WC1V 7BH

Mark Scheme Spec A

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Marking Scheme for Edexcel

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  • !"#$%!&'()*)!!

    *+,)!-..)..*)/0!"#0)$1#,!

    GCSE

    23&4!1/!"#0()*#01'.!&+)'151'#016/!-!!718()$!91)$!!:#+)$!;6/?3#,'@,#06$A!!

    Edexcel Limited. Registered in England and Wales No. 4496750 Registered Office: One90 High Holborn, London WC1V 7BH

  • General Marking Guidance !

    x -,,!'#/B1B#0).!*@.0!$)')1C)!0()!.#*)!0$)#0*)/0D!!4E#*1/)$.!*@.0!*#$%!0()!51$.0!'#/B1B#0)!1/!)E#'0,F!0()!.#*)!G#F!#.!0()F!*#$%!0()!,#.0D!

    x "#$%!.'()*).!.(6@,B!H)!#++,1)B!+6.101C),FD!3#/B1B#0).!*@.0!H)!$)G#$B)B!56$!G(#0!0()F!(#C)!.(6G/!0()F!'#/!B6!$#0()$!0(#/!+)/#,1.)B!56$!6*1..16/.D!!

    x -,,! 0()!*#$%.!6/! 0()!*#$%! .'()*)!#$)!B).18/)B! 06!H)!#G#$B)BD!4E#*1/)$.!.(6@,B!#,G#F.!#G#$B!5@,,!*#$%.! 15!B).)$C)BI! 1D)D! 15! 0()!#/.G)$!*#0'().!0()!*#$%!.'()*)D!!4E#*1/)$.!.(6@,B!#,.6!H)!+$)+#$)B!06!#G#$B!J)$6!*#$%.!15!0()!'#/B1B#0)K.!$).+6/.)!1.!/60!G6$0(F!65!'$)B10!#''6$B1/8!06!0()!*#$%!.'()*)D!

    x L()$)!.6*)!M@B8)*)/0!1.!$)N@1$)BI!*#$%!.'()*).!G1,,!+$6C1B)!0()!+$1/'1+,).!HF!G(1'(!*#$%.!G1,,!H)!#G#$B)B!#/B!)E)*+,151'#016/!*#F!H)!,1*10)BD!

    x 3$6..)B! 6@0! G6$%! .(6@,B! H)!*#$%)B! O>P4&&! 0()! '#/B1B#0)! (#.! $)+,#')B! 10!G10(!#/!#,0)$/#01C)!$).+6/.)D!

    x "#$%!.'()*).!G1,,!1/B1'#0)!G10(1/!0()!0#H,)!G()$)I!#/B!G(1'(!.0$#/B.!65!QL3I!!#$)!H)1/8!#..)..)BD!9()!.0$#/B.!#$)!#.!56,,6G.!!"#$%&'($#)*+)#)$,)#!-$.!/-$#+%0#)*+)#&1$--!%.2#1'%3)'+)!4%#+%0#.(+55+(#+($#+33'(+)$#&4#)*+)#5$+%!%.#!-$+(#36*+$)()/.16/!#/B!*)#/1/8!1.!',)#[email protected]/8!'6$$)'0!/60#016/!#/B!,#H),,1/8!'6/C)/016/.D##!!"#&$-$3)#+%0#'&$#+#64(5#+%0#&)7-$#46#8(!)!%.#+11(41(!+)$#)4#1'(14&$#+%0#)4#3451-$,#&'/9$3)#5+))$(#R)#.6/1/8I!)E+,#/#016/!6$!#$8@*)/0!1.!'6$$)'0!#/B!#++$6+$1#0),F!.0$@'0@$)B!06!'6/C)F!*#0()*#01'#,!$)#.6/1/8D!# #!!!"#4(.+%!&$#!%64(5+)!4%#3-$+(-7#+%0#34*$($%)-72#'&!%.#&1$3!+-!&)#:43+/'-+(7#8*$%#+11(41(!+)$;#9()!*#0()*#01'#,!*)0(6B.!#/B!+$6')..).!@.)B!#$)!'6()$)/0,F!#/B!',)#$,F!6$8#/1.)B!#/B!0()!#++$6+$1#0)!*#0()*#01'#,!C6'#H@,#$F!@.)BD!

    !

    Guidance on the use of codes within this mark scheme ";!S!*)0(6B!*#$%!-;!S!#''@$#'F!*#$%!T;!S!G6$%1/8!*#$%!3;!S!'6**@/1'#016/!*#$%!QL3!S!N@#,10F!65!G$100)/!'6**@/1'#016/!6)!S!6$!)N@1C#,)/0!!'#6!S!'6$$)'0!#/.G)$!6/,F!50!S!56,,6G!0($6@8(!.'!?!.+)'1#,!'#.)!

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    75

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    76 1MA0/1H

    Question Working Answer Mark Additional Guidance 3.FE

    No of tiles around room = 2 ! lengths of room = 8, 16, 16, 12 Total number of tiles= 8 ! 16 + 8 ! 12 = 224 Cost = 4 ! 224 ORArea of the room =4 ! 8 + 4 ! 6 = 56 Area of a tile = 0.5 ! 0.5 = 0.25 Number of tiles = 56y 0.25 = 224 Cost = 4 ! 224

    896 6 M1 for doubling each length to show number of tiles for each side B1 for 8, 16, 16 and 12 M1 for a full method of finding the number of tiles (12 u 16 + 8 u 4) A1 for at least one section correct M1 for 4 u 224 A1 cao ORM1 for full method for finding the area of the room A1 at least one area correct B1 for area of tile = 0.25m2 or 2500 cm2 or 4 tiles = 1 m2

    M1 for area of room y area of a tile M1 for 4 ! number of tiles A1 cao

    Total for Question: 6 marks 4. (a) 5p = 20 p = 4 2 M1 add 16 to both sides

    A1 cao

    (b) 9 = 3q q = 3 2 M1 correct method to isolate 3qA1 cao

    (c) 6x 3 10 6x = 13 2 M1 at least one expansion correct A1 13 or a statement that the answer is indep of x depending on correct working

    Total for Question: 6 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    77

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    78 1MA0/1H

    Question Working Answer Mark Additional Guidance 8. 1

    214 xx

    215 x ,

    101 x

    OR

    Chooses a suitable number of balls (say 10) 5 will be red The other 5 need to be shared out in the ratio 1:4, Hence 1 yellow and 4 blue

    104 3 M1 1

    214 xx

    A1101 x

    A1104 oe

    Total for Question: 3 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    79

    1MA0/1H Question Working Answer Mark Additional Guidance 9. (a) (i)

    (ii)

    a2

    6x4y3

    3 B1 cao

    B2 6x4y3(B1 for 2 out of 3 terms correct in a product)

    (b) x2 + 3x + 7x + 21 x2 + 10x + 21 2 M1 3 or 4 terms out of 4 correct in a 4 term expansion A1 cao

    (c) 3p(q 4p) 2 B2 cao

    (B1 p(3q 12p), 12p(41

    q p), p(aq + bp) where a and b are numbers)

    (d)(i)

    (ii)

    )32(1)2(3 xxOR

    3201012123 2 xxx

    = 523 2 xx

    (3y1)(y 3)

    )1)(53( xx

    4 B2 cao (B1 (3y m)(y n) where mn = 3 or m + n = 10

    M1 use of the factorised form with y replaced twice by 3x + 2A1 cao ORB1 523 2 xxB1 cao

    Total for Question: 11 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    80 1MA0/1H

    Question Working Answer Mark Additional Guidance 10. Reds 6, 12, 18, 24, 30

    Greens 9, 18, 27 201 3 B1 list of red and green multiples (both to at least 18) or explicitly

    states LCM B1 works out highest number (90 seen)

    B1201 (accept

    1005 )

    Total for Question: 3 marks 11.

    42

    5 x

    69

    5

    xy or

    65

    9 xy

    x = 2.5

    y =11.25

    4 M1 a correct expression for x involving ratios of sides, e.g. 42

    5 x oe

    A1 cao

    M1 69

    5 x

    y or6

    59

    xy oe

    A1 cao OR

    49

    5 y

    A1 cao

    Total for Question: 4 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    81

    1MA0/1H Question Working Answer Mark Additional Guidance 12. (a) 4 6 8 10

    6 8 10 12 8 10 12 14 10 12 14 16

    OR

    41

    41 u

    441

    41 uu

    164 3 M1 Attempts to list all outcome pairs

    A1 all 16 found A1 cao

    OR

    M2 441

    41 uu

    (M1 2,141

    41 uu or 3)

    A1164

    oe

    (b) Prob Ali wins = 166

    Number of wins = 80166 u

    30 3 B1 Prob Ali wins =

    166 oe

    M1 80'166' u

    A1 ft

    Total for Question: 6 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    82 1MA0/1H

    Question Working Answer Mark Additional Guidance 13. (a) 7104.3 u 1 B1 cao

    (b)

    1005104.2 12 uu ( 610y )

    5102.1 u 2 M1 100

    5104.2 12 uu oe ( 610y )A1 cao

    Total for Question: 3 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    83

    1MA0/1H Question Working Answer Mark Additional Guidance 14. Let AB = x, AD = y

    Area of rectangle = xy

    Area AXD = 4xy

    Area CYZ =8xy

    Shaded area = 8

    5 xy

    85 4 M1 a full method to find the unshaded area and subtracting from 1

    B1 area of AXD = area of ABCDy 4B1 area of CYZ = area of ABCDy 8A1 cao ORDiagramM1 for dividing left into 2 congruent triangles for dividing right into 4 congruent triangles B1 left = 2A and 2A or

    shaded = 21 of

    21 =

    41 =

    82

    B1 right = 2A and A and A or

    shaded = 43 of

    21 =

    83

    A1 cao

    SubstitutionM1 for deciding upon suitable side lengths for AD and AB and calculating dimensions of internal shapes B1 for area of DZXB1 for area of ZXBYA1 cao

    ORM1 for deciding upon suitable side lengths for AD and AB and calculating dimensions of internal shapes B1 for area ADXB1 for area ZCYA1 cao

    Total for Question: 4 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    84 1MA0/1H

    Question Working Answer Mark Additional Guidance 15. (a)

    (i)

    (ii)

    oBC =

    ooOBCO

    oAQ =

    ooo BQOBAO

    = 4a + 4b + 41

    (12a 4b)

    12a 4b

    3b a

    4

    M1 o

    BC = oo

    OBCOA1 cao

    M1 4a + 4b + 41

    (12a 4b)A1 cao

    (b) oOX = 12b ,

    oAX =4a + 12b

    = 4(a + 3b)

    Correct reason, with

    correct working

    3B1

    oOX = 12b

    B1o

    AX =4a + 12bC1 convincing explanation

    Total for Question: 7 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    85

    1MA0/1H Question Working Answer Mark Additional Guidance 16.

    85

    96

    104 uu =

    720120

    720120 +

    84

    95

    106 uu +

    85

    94

    106 uu

    720360 4

    M1 for 85

    96

    104 uu

    A1 for 720120

    oe

    M1 720

    '120' + 2 correct cases (M1 any 2 correct cases)

    or720

    '120' X 3

    A1 cao

    SC with replacement

    M1106

    106

    104 uu

    M1 106

    106

    104 uu !3

    Total for Question: 4 marks 17.

    )53)(53()7)(53(

    xxxx

    537

    xx 3 B1 )7)(53( xx

    B1 )53)(53( xx

    B1537

    xx

    Total for Question: 3 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    86 1MA0/1H

    Question Working Answer Mark Additional Guidance 18. (a)

    21 1 B1

    (b) (2 + 3 ) )31( u= 93322

    335 2 M1 4 term expansion with 3, 4 terms correct and sight of 3 or 9A1 cao

    Total for Question: 3 marks 19. (a) Smooth

    curve2 B1 correct plot of their values

    B1 smooth curve through their points

    (b) x = 3 y = 0

    3 M1 attempts to draw circle at origin M1 uses radius 3 cm (using graph scale correctly) A1 cao

    OR

    B1 for substituting a value of x into y = x(x 3) and 22 ryx B1 for substituting y into x = 3 into x(x 3) and 22 ryx B1 cao

    Total for Question: 5 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    87

    1MA0/1H Question Working Answer Mark Additional Guidance 20.

    QWCii, iii

    22 )12()12( nn=

    )144(144 22 nnnn

    = 8n

    OR22 )12()12( nn =

    ))1212()12()12( nnnn

    = 2 ! 4n = 8n

    Fullyalgebraic argument, set out in a logical and coherentmanner

    6 B2 the nth term for consecutive odd numbers is 2n 1 oe (B1 2n + k, 1zk or n = 2n 1 or 2x 1B1 use of 2n + 1 and 2n 1 oe M1 22 )12()12( nnM1 )144(144 22 nnnn

    C1 conclusion based on correct algebra QWC: Conclusion should be stated, with correct supporting algebra.

    ORB1 use of 2n + 1 and 2n 1 oe M1 22 )12()12( nnM1 ))1212()12()12( nnnnC1 conclusion based on correct algebra QWC: Conclusion should be stated, with correct supporting algebra.

    Total for Question: 6 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    88 1MA0/1H

    Question Working Answer Mark Additional Guidance 21.

    L F FD CF 010 40 4 40 1020 60 6 100 2040 90 4.5 190 4080 60 1.5 250 >80 0 0 250

    HistogramOR

    Cumulative Frequencypolygon

    82%

    6 B1 Scales labelled and also marked on the vertical axis with frequency density or with cumulative frequency M1 frequency densities calculated, at least one non-trivial one correct. A1 all correctly plotted (M1 cumulative frequencies correct)

    M1 Use 50 on the horizontal scale of CF diagram read off vertical axis (200-210)or Use 50 on the horizontal scale of a histogram and covert area to the left to a frequency M1 convert to a percentage A1 80 85

    Total for Question: 6 marks

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    89

    2.

    Fraction Decimal % kg Jan

    101

    0.1 10% Not known

    Feb

    81 0.125 12.5% 15 kg

    Mar

    10013 0.13 13% 14.56 kg

    14.A B

    CD

    X

    Y

    Z

    A B

    CD

    X

    Y

    Z

  • Edexcel GC

    SE Sam

    ple Assessm

    ent Materials

    Edexcel Lim

    ited 2009in M

    athematics A

    90

  • November 2009 For more information on Edexcel and BTEC qualifications please visit our website: www.edexcel.org.uk Edexcel Limited. Registered in England and Wales No. 4496750 Registered Office: One90 High Holborn, London WC1V 7BH. VAT Reg No 780 0898 07