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Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables. For example, we may know the velocity of an object at a particular time, but we may want to know the position of the object at that time. To find this direct relationship, we need to use integration or anti-differentiation which is opposite to differentiation. roduction to Integrat

Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

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Page 1: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables.

For example, we may know the velocity of an object at a particular time, but we may want to know the position of the object at that time.

To find this direct relationship, we need to use integration or anti-differentiation which is opposite to differentiation.

Introduction to Integration

Page 2: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

Over 2000 years ago, Archimedes found formulas for the surface areas and volumes of solids such as the sphere, and the cone. Later Leibniz and Newton discovered calculus with the idea that differentiation and integration can undo each other. Then Gauss created the first table of integrals, and many continued to apply integrals mathematically. Riemann and Lebesgue created a logical explanation for integration. Then in 1969 Risch created a general theory and practice of integrating functions.

HISTORY

Page 3: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

DEFININTIONIntegration is a way to determine the anti derivative or a way to undo the derivative process.

b

a

cxFdxxf )()(

Page 4: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

Real- Life Application of Integration

The Sydney Opera House has a design based on slices out of a ball. Many differential equations (one type of integration) were solved to create the design of this building.

Page 5: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

Historically, one of the first applications of integration was in finding the volumes of wine-casks (which have curved surfaces).The Petronas

Towers in Kuala Lumpur experience high forces due to the wind.. Integration was used to create this design for strength.

Page 6: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

WASHER METHOD

Outer Ring Inner Ring

VOLUME =

Note: Use this formula to find the volume of a solid when two equations are given

Page 7: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

Rose is celebrating a friend’s birthday on Tuesday and decides to make an angel cake of three layers for the event. If Region A which is bounded by y= 1, x = 0, and y = x2 and rotated about the x-axis forms a layer of cake, what is the volume of the cake in cubic inches?

Page 8: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

A

Volume= dxx 1

0

222 ))(1(

Given: y=1, x=0 y=x2

1. Find the limits of integration or the x-values for which the 2 equations intersect

1=x2 x=1 2. Set up the equation

3. Integrate Volume= = (1 - 1/5 ) =2.513 in3

Since there are 3 layers…2.513 x3 = 7.539 in3

1

0

5

5

x

x

Page 9: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

DISK METHOD

Note: Use this formula to find the volume of a solid when one equation is given

Page 10: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

Peter has to make a metal cone for his engineering class. If Region R in the 1st quadrant is bounded by y= -x+6, what is the volume of the cone in cubic centimeters?

Page 11: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

dxx 6

0

26

1. Set up equation

Volume=

dxxx 6

0

2 3612

2. IntegrateVolume=

6

0

23

3663

xx

x

3. SolveVolume= (216/3 – 216 + 216 )

= 226.195 cm3

Page 12: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

When is integration used?Find area under a curve:

b

a

dxxf )(

Basic Formula:

Page 13: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

Find area between two curves:Basic Formula:

b

a

dxxgxf )]()([

Note: To find the area between two curves take the top function subtract the bottom function.

Page 14: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

Determine the original function when the initial condition is given:When given the velocity function the position (original) function could be determined.Example: Velocity function = 3x2 + 6x – 2 , x(0) = 7. Find the position function.

b

a

cxxxdxxx 23)263( 232

723 23 xxx

Page 15: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

Real Life ExampleBob drove around Long Island at 10 a.m. andreturned home at 8 p.m. at night. He was drivingat a rate modeled by the function

12)( 2 xxtVFind how many miles Bob drive from 10 a.m. to 8 p.m.?

miles

xxx

dxxx

333.423

]3

)12(

100

23

10

0

2

Page 16: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

Pictures.

Page 17: Many times the relationship involving the rate of change of two variables is known, but we may need to find the direct relationship between the two variables

http://us.cdn4.123rf.com/168nwm/hurricanehank/hurricanehank1010/hurricanehank101000042/8011842-record-player-spinning-the-disc-with-music.jpg

http://www.clipartguide.com/_named_clipart_images/0511-1004-1301-0555_Cartoon_of_a_Man_Washing_His_Laundry_clipart_image.jpg

http://www.sportscarcup.com/cars/lamborghini-concept-s.jpg

http://74.11.50.38/calculus/Chapter7/ch7_7_1_files/image003.jpg

http://www.a-levelmathstutor.com/images/integration/curve-area-prob02b.jpg

http://2.bp.blogspot.com/_Uhdl_70J--E/THMgokWqQ9I/AAAAAAAAAVM/GnviAwC2Crs/s320/Washer+Method.png http://www.nipissingu.ca/calculus/tutorials/area_volumegifs/av_vol_washer.gif http://www.mathdemos.org/mathdemos/washermethod/

http://www.intmath.com/integration/integration-intro.php

Works Cited