Upload
daiszybaraka
View
223
Download
0
Embed Size (px)
Citation preview
8/14/2019 M103LecNotesF09
1/101
CALCULUSIntroduction to Limits
Section 10.1
ccsun 2009
definition of the limit
limits from a graph
limits from an algebraic expression
indeterminate forms
1
Definition of the limit
Let f(x) be a function, and let c and L be real numbers.
limxc f(x) =L,
means that the value off(x) is close to the number L wheneverx is close to c.
Sometimes a limit does not exist. That is, there are functions
f and numbers c where f(x) doesnt get close to any number L
even through x is close to c.
2
8/14/2019 M103LecNotesF09
2/101
Limits from a graph
6 5 4 3 2 1 1 2 3 4 5 6
6
5
4
3
2
1
1
2
3
4
5
6
limx0 f(x) =
limx1 f(x) =
limx3f(x) =
limx4 f(x) =
3
Limits from a graph
6 5 4 3 2 1 1 2 3 4 5 6
6
5
4
3
2
1
1
2
3
4
5
6
limx0 f(x) =
limx1 f(x) =limx2f(x) =
limx4 f(x) =
4
8/14/2019 M103LecNotesF09
3/101
One-sided limits
6 5 4 3 2 1 1 2 3 4 5 6
6
5
4
3
2
1
1
2
3
4
5
6
limx4+ f(x) =
limx4 f(x) =
limx2+f(x) =
limx2 f(x) =
5
Limits that go to infinity
Example: f(x) = 1
x2 Here, lim
x0 f(x) =.
2 1 0 1 2
10
20
30
40
50
6
8/14/2019 M103LecNotesF09
4/101
Limits from an algebraic expression
Often, you can evaluate the limit of a function by just evalu-
ating the function at the desired point.
Here are some examples:
limx0 2x + 3 = 3
limx1 2x + 3 = 5
limx5
x + 3
2x 1 = 5 + 3
2 5 1=8
9
lim
x12x + 9 =
7
7
More difficult examples
Sometimes, you cannot simply evaluate the function to find thelimit.
Here are some examples:
A. limx0
1
x B. lim
x1x2 1x 1
C. lim
x12
1
2x 1
4x 2
x + 1
D. lim
x4
x2 16
x3
64In each case, a direct evaluation would require division by zero.
Still, some of these functions have a limit at the designated value
of x.
In all but one of these examples (which one? ? .), both the
numerator and the denominator have zero as their limit. In this
case, the limit problem is called a 0/0 indeterminate form.
8
8/14/2019 M103LecNotesF09
5/101
Indeterminate forms
If limxc f(x) = 0 and limxc g(x) = 0, then limxc
f(x)
g(x)
is indeterminate.
The term indeterminate is used because the limit may or may
not exist. And if the limit exists it can be any number.
9
Example of a 0/0 indeterminate form:
limx1
x2 1x 1
x .9 .99 .999 1.1 1.01 1.001x21x1 1.9 1.99 1.999 2.1 2.01 2.001
(.999)2 1.999
1
=.001999
.001
= 1.999
Why does x2 1
x 1 get close to 2 as x gets close to 1?Algebraic cancellation:
x2 1x 1 =
(x 1)(x + 1)x 1 =x + 1
So limx1
x2 1x 1 = ? .
10
8/14/2019 M103LecNotesF09
6/101
Example of a 0/0 indeterminate form:
limx2
x2 4x2 x 2
x 2.1 2.01 2.001
x24x2x2 1.32258 1.33223 1.33322
(2.01)2 42.012 (2.01) 2=
0.0401
0.0301= 1.33223
Why does x2 4x2 x 2 get close to
43 as x gets close to 2?
Algebraic cancellation:
x2 4x2 x 2
= =
So
limx2
x2 4x2 x 2=
?? .
11
Practice with 0/0 indeterminate forms
limx3
x2 9x + 3
limx3x2
9
x 3
limx5
x2 + 3x 10x2 + 5x
12
8/14/2019 M103LecNotesF09
7/101
Limits of rational functions at x horizontal asymptotes
Example: f(x) =1
x.
limx
1
x= 0 When x gets large (positively), 1/x gets close to 0.
limx
1
x= 0 When x gets large (negatively), 1/x gets close to 0.
What about?
limx 2x
limx6x
limx
5
x lim
x8
x
13
Limits of rational functions at x
Example: f(x) = x 2x + 3
.
Evaluate limxx 2x + 3
1412108642 2 4 6 8 10 12 14
14
12
10
8
6
4
2
2
4
6
8
10
12
14
x 2x + 3
= 1 2/x1 + 3/x
14
8/14/2019 M103LecNotesF09
8/101
More examples of horizontal asymptotes
Evaluate: Horizontal asymptotes
limx
2x 73x + 1
limx
x + 42x + 3
limx
3x 102x + 1
limx
x 15x + 11
15
16
8/14/2019 M103LecNotesF09
9/101
8/14/2019 M103LecNotesF09
10/101
Example:
10 8 6 4 2 2 4 6 8 10
10
8
6
4
2
2
4
6
8
10
19
Example:
10 8 6 4 2 2 4 6 8 10
10
8
6
4
2
2
4
6
8
10
20
8/14/2019 M103LecNotesF09
11/101
Example: Is the function f(x) = x 2x + 3
continuous at
x= 0?
x= 3?
x= 6?1412108642 2 4 6 8 10 12 14
14
12
10
8
6
4
2
2
4
6
8
10
12
14
21
Example from business
A car rental agency charges $30 per day (or partial day) or $150per week, whichever is least. The graph the cost function C(x)
is shown below. Discuss continuity.
1 2 3 4 5 6 7 8 9 10Days
30
60
90
120
150
180
210
240
270
Cost
22
8/14/2019 M103LecNotesF09
12/101
The graph of T(x):
1 00 00 0 2 00 00 0 3 00 00 0 4 00 00 0Income
20000
40000
60000
80000
100000
120000
Tax
Is T(x) continuous?
Would it be good tax policy
to have an income tax func-
tion that is not continuous?
Between But Not Over Base Tax Rate Of theAmount Over
$0 $7,550 0 10% $0.00$7,550 $30,650 $755.00 15% $7,550
$30,650 $74,200 $4,220.00 25% $30,650$74,200 $154,800 $15,107.50 28% $74,200
$154,800 $336,550 $37,675.50 33% $154,800$336,550 $97,653.00 35% $336,550
23
A tax function that is not continuous:
0 100 200 300 400 500Income0
20
40
60
80
100
120
140
160
Tax
Near the end of the tax year, your income is exactly 300.What is your tax?
What is your net (after-tax) income?
You have an opportunity to take a small job and earn an extra
10 before the year ends. Should you take it? Why?
24
8/14/2019 M103LecNotesF09
13/101
The Derivative
Section 10.4
ccsun 2009
Average rate of change = Slope of secant line
The derivative as instantaneous rate of change
Instantaneous rate of change = Slope of tangent line
Computing the derivative using the definition
(The four-step process)
25
Average rate of change: an example:
Revenue is given by R(x) =x(75
3x) for 0
x
20.
What is the change in revenue if sales change from 9 to 12?
What is the average rate of change in revenue if sales change
from 9 to 12?
26
8/14/2019 M103LecNotesF09
14/101
Revenue is given by R(x) =x(75 3x) for 0 x 20.
What is the average change in revenue if sales change from 9 to
11?
What is the average change in revenue if sales change from 9 to
10?
What is the average change in revenue if sales change from 9 to
9.1?
27
Average rate of change is slope: rise over run
7 8 9 10 11 12 13
414
420
426
432
438
444
450
456
462
468
474 Graphically, we are findingthe slope of the secant line
between the points (9, 432)
and (9 + h, R(9 + h)) on the
graph of R(x) =x(75 3x).The four values of h from
the previous slides are h =
3, 2, 1, 0.1.
R(9) = 432
R(9.1) = 434.07R(10) = 450
R(11) = 462
R(12) = 468
slope = riserunR(12)R(9)
129 = 36
3 = 12 R(11)R(9)
119 = 30
2 = 15R(10)R(9)
109 = 18
1 = 18 R(9.1)R(9)
9.19 = 2.07
.1 = 20.7
28
8/14/2019 M103LecNotesF09
15/101
Difference quotient: The slope of the secant line equalsthe difference quotient:
Difference quotient =f(x + h) f(x)
h .
x xh
fx
fxh
29
Instantaneous rate of change: The limit of the dif-ference quotient gives the instantaneous rate of change of the
function f(x) passing through the point (x, f(x)).
instantaneous rate of change at x = lim
h0
f(x + h) f(x)
h
The instantaneous rate of change depends on the function f(x)
and on the value of x.
30
8/14/2019 M103LecNotesF09
16/101
8/14/2019 M103LecNotesF09
17/101
An example of the four-step process:
f(x) =x2 3x, find f(x)Step 1. Compute f(x + h)
Step 2. Compute f(x + h) f(x)
Step 3. Compute and simplify f(x + h) f(x)
h
Step 4. Find the limit as h approaches 0
f(x) = limh0
f(x + h) f(x)
h
.
33
An example of the four-step process:
R(x) = 60x
.02x2 Find R(x)
Step 1. Compute R(x + h)
Step 2. Compute R(x + h)R(x)
Step 3. Compute and simplify R(x + h)R(x)
h
Step 4. Find the limit as h approaches 0
R(x) = limh0
R(x + h)R(x)h
.
34
8/14/2019 M103LecNotesF09
18/101
Application of the derivative:
The revenue in dollars from the sale of x car seats for infants is
R(x) = 60x .02x2.Find the revenue and the instantaneous rate of change in rev-
enue at a sales level of 1000 car seats. Write a summary for theinstantaneous rate of change at x= 1000.
35
36
8/14/2019 M103LecNotesF09
19/101
Derivatives of Constants,Power Functions, and Sums
Section 10.5
ccsun 2009
Notation for the derivative
Derivative of a constant function
Derivatives of powers (power rule)
Derivatives of sums and differences
Marginal cost
Slope
37
Notation for the derivative
The derivative of a function f(x) may be represented by any of
the following:f(x), y, or dy/dx.
38
8/14/2019 M103LecNotesF09
20/101
The derivative of a constant function
Let f(x) = 5.
What is the slope at the point (2, 5)?
What is the slope at (3, 5)?
Does the slope depend on the particular value of x?
Theorem: If f(x) =c is a constant function, then f(x) = 0.
39
Power rule
Use the four-step process to compute the derivative of the func-
tion f(x) =x2:
The same pattern holds for other powers of x:
f(x) =x3 f(x) =x4 f(x) =x5
f(x) = 3x2 f(x) = 4x3 f(x) = 5x4
Theorem: If f(x) =xn, then f(x) =nxn1.
This is true for any number n, not just integers.
40
8/14/2019 M103LecNotesF09
21/101
Examples of the power rule
Find the derivatives of these functions:
f(x) =x3 f(x) =x10
f(x) =x3.2 f(x) =x2
f(x) =x4 f(x) =x1/2
41
Examples of the power rule (in disguise)
Find the derivatives of these functions:
f(x) = 1x2
f(x) = 1x10
f(x) =
x f(x) = 1x
42
8/14/2019 M103LecNotesF09
22/101
Multiplication by a constant
An example: f(x) = 5x3.
We know that the derivative of u(x) = x3 is u(x) = 3x2. Thederivative of 5u(x) = 5x3 is 5u(x) = 5(3x2) = 15x2.
Theorem: Let f(x) =k u(x) where k is a constant. Then
f(x) =k u(x).
The proof follows from the fact that the constant k factors out
of the difference quotient:
f(x + h) f(x)h
=k u(x + h) k u(x)
h =k
u(x + h) u(x)h
.
43
Examples:
If f(x) = 10x4, then f(x) = 40x3.
If f(x) = 7x2, then f(x) = 14x.
If f(x) = 2
x3= 2x3, then f(x) = 6x4 = 6
x4.
If f(x) = 5
x= 5x1/2, then f(x) =5
2
x1/2.
If f(x) = 2x7, the f(x) =
If f(x) = 4x5
, then f(x) =
If f(x) = 30
x, then f(x) =
44
8/14/2019 M103LecNotesF09
23/101
Sum and Difference Properties
Theorem: If f(x) =u(x) + v(x), then f(x) =u(x) + v(x).
Examples
If f(x) =x2 + x3, then f(x) = 2x + 3x2.
If f(x) = 5x2 + x3, then f(x) = 10x + 3x2.
If f(x) = 3x +1
x, then f(x) = 3 1
x2.
If f(x) = x4 + 3x2, then f(x) =.
If f(x) = 2x +
x, then f(x) =.45
Use of the Derivative
For a particular value of x, the derivative f(x) gives the
instantaneous rate of change
slope of the line tangent to the graph of f(x)
marginal cost
If C(x) is a cost function, then
C(x) approximates the cost of producing on more item at aproduction level of x items.
C(x) is called the marginal cost.
46
8/14/2019 M103LecNotesF09
24/101
Marginal Cost
The total cost (in dollars) of producing x portable radios per day
is
C(x) = 1000 + 100x 0.5x2, for 0 x 100.
1. Find the marginal cost at a production level of x radios per
day.
2. Find the marginal cost at a production level of 80 radios.
47
Example continued
Cost function: C(x) = 1000 + 100x 0.5x2
3. Find the actual cost of producing the 81st radio and compare
this with the marginal cost in part 2.
4. Find the marginal cost at a production level of 20 radios and
compare this with the actual cost of producing the 21st radio.
48
8/14/2019 M103LecNotesF09
25/101
Slope of a Tangent Line
The derivative of a function f(x) at a point a gives the slope of
the line tangent to the graph of f(x) at the point (a, f(a)).
Example: The graph of the function f(x) = x3 3x2 + 2x+ 1and a tangent line are shown below.
0.5 0.5 1.0 1.5 2.0 2.5
1.0
0.5
0.5
1.0
1.5
2.0
What are the coordi-
nates of the point shown
on the graph?
What is the slope of the
tangent line?
49
50
8/14/2019 M103LecNotesF09
26/101
51
52
8/14/2019 M103LecNotesF09
27/101
Marginal Analysis in Businessand Economics
Section 10.7
ccsun 2009
marginal cost, revenue, and profit functions
interpreting the derivative as marginal cost, revenue, and
profit
Marginal refers to an instantaneous rate of change, that is, aderivative.
53
Example of marginal cost
The total cost of producing x electric guitars is
C(x) = 1, 000 + 100x 0.25x2.1. Find the exact cost of producing the 51st guitar.
2. Compute the derivative C(x) and its value C(50) at x= 50.
3. Compare C(50) with the exact cost from part 1.
54
8/14/2019 M103LecNotesF09
28/101
Marginal Cost
The marginal cost function is just the derivative of the cost func-
tion. In business, we use marginal costC(x) to approximate the
exact cost to produce the (x + 1)st unit.
Why does the approximation work? Because
C(a) = limh0
C(x + h) C(x)h
and when h= 1, the difference quotient equals
C(x + 1) C(x),which is the exact cost to produce the (x + 1)st unit.
55
Graphical interpretation of exact cost and marginalcost
The total cost to produce x items is C(x) and the total costto produce x + 1 items isC(x + 1). Therefore the exact cost toproduce the (x + 1)st item is
C(x + 1) C(x).The marginal cost is an approximation of the exact cost:
C(x) .=C(x + 1) C(x).
x x1
Cx
Cx1
56
8/14/2019 M103LecNotesF09
29/101
Example:
Let
C(x) = 10, 000 + 90x .05x2
be the total weekly cost (in dollars) of manufacturing x fuel tanksfor cars.
Compute the marginal cost function and use it to approximate
the exact cost to manufacture the 101st fuel tank.
Marginal cost function: C(x) = 90 .10xMarginal cost at x= 100: C(100) = 90 .10(100) = 80
Summary: It costs approximately $80.00 to produce the 101stfuel tank.
57
Example continued
The marginal cost function:
C(x) = 90 .10x
Is the cost of a fuel tank increasing, decreasing or remaining the
same as x increases?
The marginal cost function C(x) gives the (approximate) costto produce the (x+ 1)st tank. So the first tank costs about
C(0) = 90 dollars. But the second tank cost about C(1) =89.90 dollars. Apparently the cost to produce the (x + 1)st tank
is $.10 less than the cost to produce the xth tank.
Compute and interpret C(200):
Compute and interpret C(500):
58
8/14/2019 M103LecNotesF09
30/101
Marginal Revenue & Profit
The technique of approximating the cost to produce a single
item by the marginal cost also applies to revenue and profit.
Revenue: If R(x) is the revenue from selling x units, then theadditional revenue earned by selling x + 1 units rather than x
units is
R(x+1)R(x). (additional revenue from selling (x+1)st unit)The marginal revenue, R(x) is approximately equal to the addi-tional revenue:
R(x) .=R(x + 1)R(x).
Profit: The same thing holds for the profit function, P(x):P(x) .=P(x + 1) P(x).
59
Application
The price-demand equation and the cost function for the pro-
duction and sales of television sets are
x= 6, 000 30p, C(x) = 150, 0 0 0 + 3x.where p is the price of a TV and x is the number produced and
sold. Profit and cost are in dollars.
a. Express the price p as a function of x:
b. Express revenue R(x) as a function of x:
c. Express profit P(x) as a function of x:
60
8/14/2019 M103LecNotesF09
31/101
Application continued
d. Find the marginal cost, marginal revenue, and marginal profit
functions:
e. Find and interpret R(3000):
f. Find and interpret P(1500) and P(1500):
61
Application continued
The cost and revenue functions are graphed below.
1000 2000 3000 4000 5000 6000
x
50000
100000
150000
200000
250000
300000
dollars
Identify which curve goes with
which function
Shade the profit area
Mark the break even points
Mark the point where profit is
maximized
62
8/14/2019 M103LecNotesF09
32/101
63
64
8/14/2019 M103LecNotesF09
33/101
Derivatives of Products andQuotients
Section 11.3
ccsun 2009
Formulas for computing:
the derivative of a product of two functions, such as
S(t) = (9000t2 + t)(t2 + 50)
the derivative of a quotient of two functions, such as
S(t) =9000t2 + tt2 + 50
65
Derivative of a product: the product rule
If f
(x
) =F
(x
)S
(x
),
then f(x) =F(x)S(x) + S(x)F(x).
Example:
f(x) = (5x2)(x3 + 2):
Identify F(x) and S(x) (the first and second functions)
Find the derivatives F(x), S(x):
Find the derivative f(x):
66
8/14/2019 M103LecNotesF09
34/101
Practice problems
Find the derivatives of these functions:
1. f(x) = (5x2 + x + 1)(3x 2)
2. f(x) = (2x1/2 + x + 1)(3x 2)
3. f(x) = (x2
+
1
x+ 1)(x 7)
67
Answers to practice problems
1.
5x2 + x + 1
3 + ( 3x 2)(10x + 1) = 45x2 14x + 1
2. (2x1/2 + x + 1 ) 3 + (x1/2 + 1)(3x 2) = 6x + 9x + 1 2x
3. (x2 + x1 + 1 ) + (x 7)(2x x2) = 3x2 14x + 1 + 7x2
Verify the algebraic simplifications.
68
8/14/2019 M103LecNotesF09
35/101
8/14/2019 M103LecNotesF09
36/101
Answers to practice problems
(10x + 1)(3x 2) (5x2 + x + 1)3
(3x 2)2
=5
3x2 4x 1
(3x 2)2
(x1/2 + 1)(3x 2) (2x1/2 + x + 1)3(3x 2)2 =
3x 5x 2(3x 2)2x
(2x x2)(x 7) (x2 + x1 + 1)(x 7)2 =
x4 14x3 x2 2x + 7(x 7)2x2
Verify the algebraic simplifications.
71
Application: CD sales
The monthly sales of a new CD often increases and then levels
off. The graph below shows the monthly sales S(t) (in thou-
sands of CDs) as function of the number of months t since it
was released.
10 20 30 40t months
20
40
60
80
sales in thousands
72
8/14/2019 M103LecNotesF09
37/101
CD sales continued
The formula for the monthly sales is
S(x) = 90t2
t2 + 50.
Find the derivative S(x).
Find and interpret S(10) and S(10).
73
74
8/14/2019 M103LecNotesF09
38/101
8/14/2019 M103LecNotesF09
39/101
The Power Rule
Section 11.4
ccsun 2009
the derivative of a function raised to a power,
such as f(x) = (x3 + 2)5
combining different rules to get the derivative of more com-
pliated functions, such as f(x) = (x3 + 2)5(x 1)
77
Different methods for computing the derivative
of a simple power function
f(x) = (3x + 1)2
Multiply out
f(x) = 9x2 + 6x + 1 f(x) = 18x + 6
Product Rulef(x) = (3x + 1)(3x + 1) f(x) = 3(3x + 1 ) + ( 3x + 1)3
= 18x + 6
Power Rule
f(x) = (3x + 1)2 f(x) = 2(3x + 1)1(3)= 18x + 6
78
8/14/2019 M103LecNotesF09
40/101
The Power Rule
If f(x) = [u(x)]n, where u(x) i s a d ifferentiable function and
n is any real number, then
f(x) =n[u(x)]n
1u(x).
Example: Find the derivative of f(x) = (x3 + 2)5.
f(x) = [u(x)]n, where u(x) =x3 + 2 and n= 5.
The Power Rule calls for u(x). But we know that:
u(x) = 3x2.
Apply the Power Rule:
f(x) =n[u(x)]n1 u(x) = 5(x3 + 2)4(3x2) = 15x2(x3 + 2)4.
79
Work out the derivatives of these functions:
f(x) = (x3 2x + 1)3
f(x) = (5x2 x)4
f(x) = (x1 2x + 1)3
80
8/14/2019 M103LecNotesF09
41/101
Work out the derivatives of these functions:
f(x) = (x3 2x + 1)1/2
f(x) =
x3 2x + 1
f(x) = (x3
2x + 1)3
81
Combining rules of differentiation
Some functions require more than one rule to find their deriva-
tive. For example:
f(x) = (3x 2)4(2x + 1).The function f(x) is the product of two other functions, F(x) =
(3x 2)4 and S(x) = 2x + 1. So we will need the product rule.But to differentiate the first function F(x), we also need the
power rule.
First apply the product rule:
f(x) =F(x) S(x) + S(x) F(x) = (3x 2)4 2 + ( 2x + 1)F(x).At this point, we still need to differentiateF(x) using the power
rule:
F(x) = 4(3x 2)3 3.Combining the results we get
f(x) = 2(3x 2)4 + 12(2x + 1)(3x 2)3.
82
8/14/2019 M103LecNotesF09
42/101
Derivatives that require two rules:practice problems
Differentiate these functions:
f(x) = (x2 + 1)5(5x 7)
g(x) = (6x 11)2x + 3
83
84
8/14/2019 M103LecNotesF09
43/101
Relative Rate of Change,Elasticity of Demand Part 1
Section 11.7
ccsun 2009
Relative rate of change (percentage increase or decrease)
Elasticity of demand at a certain price
Elasticity: inelastic, unitary, or elastic
Estimate the percentage decrease in demand if price in-
creases
85
Example: Relative rate of change
You intend to invest $1000 in one of two stocks, Biotech or
Comstat. Your broker estimates that Biotechs market value will
increase by $2 per share over the next year, while Comstats will
increase by only $1 per share.
Is this sufficient information for you to choose betwenn these
two stocks? What other information might you request from
the broker to help you decide?
86
8/14/2019 M103LecNotesF09
44/101
Example: Relative rate of change (continued)
You need to know the price of each stock.
Suppose Biotech is selling for $100 per share and Comstat is
selling of $25 per share. Find the percentage increase in the
market value of these two stocks.
Biotech increases $2 per share.
Comstat increases $1 per share.
87
Relative rate of change
The relative rate of change of a function f(x) is
f(x)f(x)
.
The relative rate of change compares the amount of the change,
f(x) to the value of f(x).
88
8/14/2019 M103LecNotesF09
45/101
8/14/2019 M103LecNotesF09
46/101
Relative rate of change of demand
The most important example of the relative rate of change is
how demand changes as a function of price.
Example: A price-demand equation isx = f(p) = 5002p, wheref(p) is the demand for an product if the price of p.
What is the relative rate of change in demand f(p) as a function
of price p?
What is the relative rate of change in demand at a price of $50?
91
Elasticity of demand
We know the demand for a product decreases when the priceof the price increases. Elasticity of demand is the ratio of the
relative decrease in demand and the relative increase in price.
E(p) = percent change in demandpercent change in price
.
So if the elasticity of demand E(p) for a product is 1.5 and the
price of that product increases by 1%. then the demand will
decrease by 1.5%.
If price p and demand x are related by x = f(p), then the formula
for the elasticity of demand, E(p) at a price of p is
E(p) = pf(p)
f(p) .
Note that the price-demand equation must be in the form x =
f(p). That is, demand must be expressed as a function of price.
92
8/14/2019 M103LecNotesF09
47/101
Example: sunglasses
A sunglass retailer currently sells one type of sunglasses for $10
per pair. The price-demand function is x= f(p) = 7000 500p.
1. Find the elasticity of demand function, E(p).
93
Example: sunglasses (continued)
E(p) =
2. Find the elasticity of demand at a price of $10.
3. If the price is increased by 5%, what is the change in demand?
94
8/14/2019 M103LecNotesF09
48/101
Demand is: inelastic, unit, elastic
Elasticity Demand Interpretation
0< E(p)< 1 Inelastic
Percentage increase in price results
in smaller percentage decrease in
demand.
E(p) = 1 Unitary
Percentage change in price results in
same percentage change in demand.
E(p)> 1 Elastic
Percentage increase in price results
in larger percentage decrease in de-mand.
95
Elasticity of demand, complete example
Begin with a price-demand equation: 2p + 0.01x= 50.
1. Express the demand x as a function of the price p.
2. Find the elasticity of demand function E(p).
96
8/14/2019 M103LecNotesF09
49/101
Elasticity of demand, complete example (contin-ued)
E(p) =
3. Find the elasticity of demand at a price of $15. Is demand
inelastic, unitary, or elastic at that price?
4. If the price of $15 is increased 20%, what is the percentage
change in demand?
97
98
8/14/2019 M103LecNotesF09
50/101
99
100
8/14/2019 M103LecNotesF09
51/101
Elasticity of Demand Part 2
Section 11.7
ccsun 2009
An example from the book: Problem 17
Another complete example
101
Elasticity of Demand: Sec 11.7, Problem 17
E(p) = pf(p)f(p)
.
Begin with the price-demand equation:
p + 0.005x= 30.
(A) Express the demand x as a function of the price p.
(B) Find the elasticity of demand E(p).
(C) What is the elasticity of demand when p= $10?
If this price is increased by 10%, what is the approximate changein demand?
(D) What is the elasticity of demand when p= $25?
If this price is increased by 10%, what is the approximate change
in demand?
(E) What is the elasticity of demand when p= $15?
If this price is increased by 10%, what is the approximate change
in demand?
102
8/14/2019 M103LecNotesF09
52/101
8/14/2019 M103LecNotesF09
53/101
Elasticity of Demand: Sec 11.7, Problem 17
E(p) =
(D) What is the elasticity of demand when p= $25?
If this price is increased by 10%, what is the approximate change
in demand?
105
Elasticity of Demand: Sec 11.7, Problem 17
E(p) =
(E) What is the elasticity of demand when p= $15?
If this price is increased by 10%, what is the approximate change
in demand?
106
8/14/2019 M103LecNotesF09
54/101
Elasticity of Demand and Revenue,Sec 11.7, Problem 17
5 10 15 20 25 30
5000
10000
15000
20000
25000
30000
35000
40000
45000
50000
Revenue as a function of price. R(p) =xp = 200(30p)p.
Which price maximizes revenue?
How does this relate to elasticity?
107
Elasticity of Demand and Revenue,Sec 11.7, Problem 17
Elasticity of demand is 1 at the price where marginal revenue is
zero:
E(p) = 1:
R(p) = 0:
108
8/14/2019 M103LecNotesF09
55/101
109
Elasticity of Demand: New Example
E(p) = pf(p)
f(p) .
Begin with the price-demand equation:
2p + 0.10x= 50.
(A) Express the demand x as a function of the price p.
(B) Find the elasticity of demand E(p).
(C) What is the elasticity of demand when p= $15?If this price is increased by 20%, what is the approximate change
in demand?
(D) What is the elasticity of demand when p= $20?
If this price is increased by 5%, what is the approximate change
in demand?
110
8/14/2019 M103LecNotesF09
56/101
Elasticity of Demand: New Example continued
E(p) = pf(p)
f(p) .
Begin with the price-demand equation:
2p + 0.10x= 50.
(A) Express the demand x as a function of the price p.
(B) Find the elasticity of demand E(p).
111
Elasticity of Demand: New Example continued
E(p) = pf(p)f(p)
= .
(C) What is the elasticity of demand when p= $15?
If this price is increased by 20%, what is the approximate change
in demand?
112
8/14/2019 M103LecNotesF09
57/101
Elasticity of Demand: New Example continued
E(p) = pf(p)
f(p) = .
(D) What is the elasticity of demand when p= $20?
If this price is increased by 5%, what is the approximate change
in demand?
113
114
8/14/2019 M103LecNotesF09
58/101
115
116
8/14/2019 M103LecNotesF09
59/101
Maxima and Minima
Section 12.5
ccsun 2009
What is an absolute maximum (or minimum)?
Where do they occur?
117
A graphical example
The graph of a function f(x) is shown below.
2,4
1, 7
2,20
4, 32
2 1 1 2 3 4
20
10
10
20
30
The highest point on the graph is (4, 32). So the absolute max-imum of f(x) is 32 and it occurs where x= 4.
The lowest point on the graph is (2,20). So the absolute min-imum of f(x) is20 and it occurs where x= 2.The points (2,4) and (4, 32) are called the end pointsof thegraph. x= 2, 4 are the end pointsof the domain of f.The points (1, 7) and (2,20) are the critical points of thegraph. x= 1, 2 are the critical values of x.
118
8/14/2019 M103LecNotesF09
60/101
Definition of absolute maximum/minimum
Let f(x) be a function.
f(c) is an absolute maximumof the function f iff(c) f(x) forall x in the domain of f. In other words, the value of f at c is
greater than or equal to the values of f for every other x in the
domain
f(c) is an absolute minimum of the function f if f(c) f(x) forall x in the domain of f.
The example above suggests that the absolute maximum and
the absolute minimum must occur at an end point of the graph
or at a point where the slope of the tangent line is zero, that isf(x) = 0; these are critical points on the graph.
119
Identifying types of points on a graph
Identify the end points, points where the tangent is horizontal,
absolute maximums, and absolute minimums for the functionf(x) with the following graph:
0, 0
1, 467
3, 1971
4, 1792
5, 3275
1 1 2 3 4 5
1000
2000
3000
4000
What are the end points?
What are the points where the slope of the tangent line is zero?
What is the absolute maximum(s)?
What is the absolute minimum(s)?
120
8/14/2019 M103LecNotesF09
61/101
Extreme value theorem
A functionfthat is continuous on a closed interval [a, b] has both
an absolute maximum value and an absolute minimum value on
that interval.
If the function has a derivative for every point in the interval [a, b],
then the absolute maximum and the absolute minimum must
occur either at an end point of the interval or at a point where
the slope of the tangent line is zero, that is where f(x) = 0.
121
Steps in finding absolute maximums and mini-mums
The values of x in the domain of f where f(x) = 0 or wheref(x) does not exist are called the critical values.
The absolute maximum and minimum of f(x) o n [a, b] always
must occur at critical values or at the end points of the interval.
1. Check to make sure f is continuous on the interval [a, b].
2. Find the critical values of x in the interval [a, b].
3. Evaluate f(x) at the end points a and b and at the critical
values of x.
4. The absolute maximum and minimum of f(x) o n [a, b] are
the largest and smallest of the values found in step 3
122
8/14/2019 M103LecNotesF09
62/101
8/14/2019 M103LecNotesF09
63/101
8/14/2019 M103LecNotesF09
64/101
127
128
8/14/2019 M103LecNotesF09
65/101
Maximizing Profit, Part 1
Section 12.6
ccsun 2009
Find the maximum profit from a graph
Profit is maximized when marginal revenue equals marginal
cost: R(x) =C(x).
129
Maximizing revenue: an example
A company can sell x fake tattoos per year at p dollars per
tattoo. The price-demand equation for the tattoos is
p= 10 .001x.To maximize its revenue, what price should the company charge
for each tattoo?
Summary:
What is the maximum revenue?
Summary:
130
8/14/2019 M103LecNotesF09
66/101
8/14/2019 M103LecNotesF09
67/101
The graph of revenue and cost: tattoos contin-ued
2000 4000 6000 8000 10 000
Number of tattoos
4000
8000
12 000
16 000
20 000
24 000
28 000
Revenue and Cost in Dollars
Locate the point on the graph where profit is maximized.
Locate the point on the graph where revenue is maximized.
133
Profit on the graph
Where does the profit appear on the graph?
Since profit is the difference between cost and revenue, the profit
for a particular value ofx is represented by the length of the ver-tical line between the cost and revenue functions. These verticallines have been added to the graph. For example, if the produc-
tion/sales level is x = 6000 tattoos, the profit is represented bythe thick line on the graph.
Which of the vertical lines is the longest?
What does this mean in terms of profit?
2000 4000 6000 8000 10 000
Number of tattoos
4000
8000
12000
16000
20000
24000
28000
Revenue and Cost in Dollars
134
8/14/2019 M103LecNotesF09
68/101
Summary
To find the maximum profit over an interval [a, b]:
1. Find the critical values in the interval by solving R(x) =C(x).
2. Evaluate the profit function P(x) at the end points a and b
and at the critical values found in step 1.
3. The maximum profit on [a, b] is the largest of the values
found in step 2.
Most often, the interval is [0,) and because of the fixed cost,the profit is negative at x = 0. In these cases, the maximum
profit does not occur at an end point. It will occur at a point
where marginal cost equals marginal revenue.
135
136
8/14/2019 M103LecNotesF09
69/101
Maximizing Profit, Part 2
Section 12.6
ccsun 2009
A complete example
Changes in the cost function
137
A complete example:
ArtCo produces and sells special drawing kits. The cost and
price-demand information is given below:
Fixed costs $4105Per item cost $30Price-demand equation p= 440 5x
(A) Find the production/sales level that maximizes profit.(B) Find the price that maximizes profit.(C) Find the production costs at the production levelthat maximizes profit.(D) Find the revenue at the sales level that maximizes profit.(E) Find the maximum profit.
138
8/14/2019 M103LecNotesF09
70/101
8/14/2019 M103LecNotesF09
71/101
(D) Find the revenue at the sales level that maximizes profit.
Summary:
(E) Find the maximum profit.
Summary:
141
The revenue and cost functions are shown on the graph below
along with the line tangent to the revenue curve at the point
where profit is maximum.
The maximum profit occurs when the production/sales level is
x= 41 kits.
20 40 60 80Kits
2000
4000
6000
8000
10000
12000
Cost, Revenue in dollars
142
8/14/2019 M103LecNotesF09
72/101
What happens if the fixed costs increase from $4105 to $5000?
Compare the two graphs:
20 40 60 80Kits
2000
4000
6000
8000
10000
12000
Cost, Revenue in dollars
20 40 60 80Kits
2000
4000
6000
8000
10000
12000
Cost, Revenue in dollars
Fixed costs are $4105 Fixed costs are $5000
It is clear from the graph that the production/sales level that
maximizes profit stays at x = 41. That is, the derivative of the
cost function, C(x) = 30, does not depend on the fixed costs,only the per-item cost.
The profit at that level decreases by the increase in the fixed
costs of $895. The break-even points are closer together when
the fixed costs are higher.
143
What happens if the per-item cost increases from $30 to $50?
Again we compare the two graphs:
20 40 60 80Kits
2000
4000
6000
8000
10000
12000
Cost, Revenue in dollars
20 40 60 80Kits
2000
4000
6000
8000
10000
12000
Cost, Revenue in dollars
Per-item cost is $30 Per-item cost is $50
This time the production/sales level that maximizes profit is
x = 39. The derivative of the cost function is now 50 instead of
30. So the point on the revenue curve where the slope is steeper
(50 instead of 30) is to the left of the point where x= 41. That
is, the solution to the equation R(x) = 50 (x= 39) is less thanthe solution to R(x) = 30 (x= 41).
144
8/14/2019 M103LecNotesF09
73/101
Another example:PatTech produces and sells patio furniture. The cost and price-
demand information for their outdoor lava lamp is given below:
Fixed costs $6156Per item cost $20
Price-demand equation p= 420 4x
(A) Find the production/sales level that maximizes profit.(B) Find the price that maximizes profit.(C) Find the production costs at the production levelthat maximizes profit.(D) Find the revenue at the sales level that maximizes profit.(E) Find the maximum profit.(F) If fixed costs decrease by $400, does the production/saleslevel that maximizes profit decrease, increase, or stay the same?
(G) If the per-item cost decreases, does the production/saleslevel that maximizes profit decrease, increase, or stay the same?
145
146
8/14/2019 M103LecNotesF09
74/101
Answers:
(A) x= 50(B) p= 220(C) C(50) = 7156(D) R(50) = 11, 000(E) P(50) = 3844(F) stays the same(G) increases
20 40 60 80 100Lamps
2000
4000
6000
8000
10000
12000Cost, Revenue in dollars
147
148
8/14/2019 M103LecNotesF09
75/101
Systems of Linear Equationsin Two Unknowns
Section 4.1
ccsun 2009
Solve by graphing
Sole using substitution
Solve by elimination (addition method)
149
Warm-up problem
A restaurant serves two types of fish dinnerssmall for $5.99
and large of $8.99.
Yesterday, there were 134 total orders of fish with total receipts
of $1024.66. How many small and how many large fish dinners
were ordered?
Set up the two equations in two unknowns, where s is the num-
ber of small dinners ordered andl
is the number of large dinners.
We will solve it later.
150
8/14/2019 M103LecNotesF09
76/101
Systems of two equations in two unknowns
This is an example of a system of two linear equations in two
unknowns:
3x + 5y = 9x + 4y = 10.
A solution is an ordered pari (x0, y0) that satisfies each equation.
The solution set is the set of all solutions.
Is (3, 0) a solution?
Is (2,3) a solution?
151
Solve the system by graphing
3x + 5y = 9x + 4y = 10.
5 4 3 2 1 1 2 3 4 5
5
4
3
2
1
1
2
3
4
5 Three points are shown on
the graph.
Write the coordinates of
each point.
Which of the points is a
solution to the system of
equations?
152
8/14/2019 M103LecNotesF09
77/101
8/14/2019 M103LecNotesF09
78/101
Solve this system using substitution
3x 2y = 7y = 2x 3
155
Independent consistent systems
A system of linear equations is consistent if it has one or
more solutions.
If a consistent system has exactly one solution then the sys-
tem is independent.
This system of equations has only one solution, (x, y) = (2, 5):
x + 2y = 12
x 3y = 13Is the system consistent?
Is the system independent?
What can you say about the graphs of the equations?
156
8/14/2019 M103LecNotesF09
79/101
Dependent consistent systems
If a consistent system has more than one solution, then the
system is dependent.
The system
p = 0.1x + 32p = 0.2x + 6
has infinitely many solutions: (x, p) = (0, 3), (10, 2), (20, 1), . . ..
So this system is dependent consistent.
What can you say about the graphs of these dependent equa-
tions?
157
Inconsistent systems
An inconsistent linear system is one that has no solutions. For
example, this system has no solutions:
p = 0.1x + 3p = 0.1x + 6
What can you say about the graphs of these inconsistent equa-tions?
158
8/14/2019 M103LecNotesF09
80/101
Test your understanding
For each of the system below, state whether it is consistent
or inconsistent. If the system is consistent, is it dependent or
independent?
x + y = 4
2x y = 2
6x 3y = 92x y = 3
2x y = 46x 3y = 18
159
Solution by elimination (addition)
2x 7y = 3 (1)5x + 3y = 7 (2)
You may do any of the following and the solutions will not
change:
1. Write the equations in any order.
2. Multiply any equation by a nonzero constant.
3. Multiply any equation by a nonzero constant and add it to
another equation.
Follow these steps to solve the system above:
1. Multiply Equation (1) by 5 and Equa-
tion (2) by 2.
2. Add the two equations and replace
Equation (2) with the sum.
3. Use the second equation to solve for y.
160
8/14/2019 M103LecNotesF09
81/101
Solve using elimination
2x 7y = 35x + 3y = 7
161
Solve using any method
The US Postal Service charges a base price for overnight de-
livery of packages that weigh one ounce or less and a surchargefor each additional ounce or partial ounce. The cost of mailing
a 6 ounce package is $1.68 and the cost of mailing a 13 ounce
package is $2.87. Find the base price and the surcharge. (Useb
for the base price and s for the surcharge.)
162
8/14/2019 M103LecNotesF09
82/101
Solve the warmup (fish) problem
A restaurant serves two types of fish dinnerssmall for $5.99
and large of $8.99. Yesterday, there were 134 total orders of fish
with total receipts of $1024.66. How many small and how many
large fish dinners were ordered?
163
164
8/14/2019 M103LecNotesF09
83/101
Systems of Linear Equationsand the Augmented Matrix
Section 4.2
ccsun 2009
In this section, we develop a matrix method for solving systems
of two linear equations in two unknowns. This method is a
generalization of the elimination method from Section 4.1 and
can be used by computers and calculators to solve systems of
equations with many equations and many unknowns.
165
Matrices
A matrix is a rectangular array of numbers written within brack-
ets.
Example with three rows and three columns:
1 6 82 4 1
7 3 5
Example with three rows and two columns: 1 34 3
1 9 How many rows (columns) does the matrix A have?
A=
1 3 0 01 3 4 31 0 7 9
166
8/14/2019 M103LecNotesF09
84/101
Entries of a matrix
The subscripts give the address
of each entry of the matrix. For
example the entry a23 is found in
row 2 and column 3.
a11 a12 a13 a14a21 a22 a23 a24
a31 a32 a33 a34
Circle a21 in each matrix, if it exists.
1 35 0
309
2 5 8 1
4 57 3
10 48 8
11 6
167
Size of a matrix
When a matrix has m rows and n columns, its size is written
m n, as in A is an m-by-n matrix.
So
1 3 65 7 0
is a 2 3 matrix.
What is the size of each matrix?
1 35 0
309
2 5 8 1
4 57 3
10 48 8
11 6
168
8/14/2019 M103LecNotesF09
85/101
Matrix method for solving a linear system
First, represent the linear system of equations as an augmented
matrix.
Linear system Augmented matrix
x + 3y = 52x y = 3
1 3 52 1 3
4x y = 6x y = 0
4 1 61 1 0
a11x1+ a12x2 = k1
a21x1+ a22x2 = k2
a11 a12 k1a21 a22 k2
Write the augmented matrix for this system:
4x y = 6x y = 0
169
Matrix method continued
Then, manipulate the augmented matrix (with row operations
coming in the next slide) to obtain one of the following forms.
Now you can just read off the solution. What is the solution to
each system?
1 0 50 1 3
1 2 50 0 0
1 2 50 0 3
170
8/14/2019 M103LecNotesF09
86/101
Row operations, which do not change the solu-tions to the system
Augmented matrix Symbol System of equationsInterchange rows i and j Ri Rj Change order of equa-
tions i and jMultiply row i by a nonzero
constant k
kRi Ri Multiply both sides ofequation i by a nonzero
constant k
Add k times row i to row j kRi+ Rj Rj Replace equationi by the
sum of equation i and k
times equation j
171
An example
Solve
x + 3y = 5
2x y = 3 1 3 52 1 3
Augmented matrix
2R1+ R2
R2
1 3 50
7
7 This makes a12 = 0
17R2 R2
1 3 50 1 1
This makes a22 = 1
3R2+ R1 R1
1 0 20 1 1
The matrix is in
reduced form
Solution: x= 2, y = 1 or (x, y) = (2, 1)
172
8/14/2019 M103LecNotesF09
87/101
New problem
Solve:
2x + 6y = 65x + 7y = 1
Write the symbols for the row operations. Start with the row
operation 12R1 R1. Read as replaces.
173
Intersecting lines
Use matrix methods to find the coordinates (x, y) of the pointof intersection for the lines with these equations:
x + 2.0y = 4.0
x + 0.5y = 2.5
174
8/14/2019 M103LecNotesF09
88/101
Another problem
Solve this system using matrix methods. Write the symbols for
the row operations.
10x1 2x2 = 65x1+ x2 = 3
175
Equilibrium points
Find the equilibrium point for these price/demand and price/supply
equations.
price/supply: 2p= x 66price/demand: 5p= 0.5x + 105
176
8/14/2019 M103LecNotesF09
89/101
Summary
There are three possible reduced forms for the augmented matrix
of a system of two equations in two unknowns:
Form 1: Unique soluion: x= m, y =n (consistent
and independent)
1 0 m0 1 n
Form 2: Infinitely many solutions: y can be any
real number and x = m ry (consistent and de-pendent)
1 r m0 0 0
Form 3: n = 0 No solution: (inconsistent) 1 r m0 0 n
177
178
8/14/2019 M103LecNotesF09
90/101
179
180
8/14/2019 M103LecNotesF09
91/101
Gauss-Jordan Elimination
Section 4.3
ccsun 2009
A linear system must have exactly one solution, no solution, or an
infinite number of solutions. Just as in the case of two equations
in two unknowns:
the term consistent and independent is use to describe a
system with only one solution.
consistent and dependentis used for a system with an infinite
number of solutions.
inconsistent is used to describe a system with no solution.
181
An illustrative example
To solve this system using Gauss-Jordan elimination, start with
the augmented matrix.x + y z=2
2x y+ z= 5x + 2y+ 2z= 1
1 1 1 22 1 1 51 2 2 1
182
8/14/2019 M103LecNotesF09
92/101
Matrix representations of independent, inconsis-tent, and dependent systems
The following matrices represent systems of three linear equa-
tions in three unknowns. Write the solution for each.
consistent and independent
1 0 0 30 1 0 40 0 1 5
inconsistent
1 2 3 40 0 0 6
0 0 0 0
consistent and dependent
1 2 3 40 0 0 00 0 0 0
1 0 3 40 1 9 4
0 0 0 0
183
Reduced row echelon form
A matrix is in reduced row echelon form or more simply, in re-duced form, if:
1. The rows consisting entirely of zeros are below the other
rows.
2. The leftmost nonzero entry in each row is 1.
3. All other entires in the column containing the leftmost 1 of
the row are zeros.
4. The leftmost 1 in any row is to the right of the leftmost 1in the row above it.
All but one of these matrices are in reduced form. Which one is
not and which of the four conditions is not satisfied? 1 0 0 40 1 0 2
0 0 1 6
1 2 0 30 5 1 2
0 0 0 0
1 2 3 40 1 0 8
0 0 0 0
1 0 0 70 1 0 7
0 0 0 9
184
8/14/2019 M103LecNotesF09
93/101
More on reduced form
Which matrices are in reduced form? If a matrix is not in reduced
form, use a row operation to get it into reduced form. 2 0 4 40 1 0 7
0 0 1 5
1 0 3 40 1 2 9
0 0 0 0
1 2 0 40 1 0 5
0 0 1 8
185
186
8/14/2019 M103LecNotesF09
94/101
187
188
8/14/2019 M103LecNotesF09
95/101
Matrices: Basic Operations
Section 4.4
ccsun 2009
Add and subtract two matrices
Multiply a number and a matrix
Multiply two matrices
Matrix models
189
Addition and subtraction of Matrices
To add or subtract two matrices, they must be the same size.
To add (or subtract) matrices of the same size, add (or subtract)
their corresponding entries.
For example, if
A=1 2
5 2
, and B =4 5
9 1
,
then
A + B =
, and AB =
.
190
8/14/2019 M103LecNotesF09
96/101
More examples:
4 3 10 1 5
+
2 1 04 2 1
=
6 1 14 1 52 1 1
2 1 04 2 13 2 7
=3 1
1 5
+
2 1 04 2 1
=
2 110 4
1 0
+
1 02 10 0
=
14
10
+
1
231
=
191
Scalar Multiiplication
To find the scalar product of a number k and a matrix A,
multiply each entry in A by the number k. The number k is
called a scalar.
For example, if k = 2 and
A=
6 1 14 1 5
2 1 1
, then 2A=
.
192
8/14/2019 M103LecNotesF09
97/101
Combining operations
2
4 3 11 5 1
2 1 04 2 1
=
2
3 1 0
2 1 50 0 2
+ 3
2 1 0
4 2 15 2 1
=
193
Multiplying a Row Matrix and a Column Matrix
Observe how a 1 4 row matrix is multiplied by a 4 1 columnmatrix:
1 2 3 4
5678
= 1 5 + 2 6 + 3 7 + 4 8 = 70
Now try this example:
1 0 5 2
74
13
=
194
8/14/2019 M103LecNotesF09
98/101
8/14/2019 M103LecNotesF09
99/101
8/14/2019 M103LecNotesF09
100/101
Revenue of a Clothing Store
The number of items sold at a clothing store and the price of
each item are given below. Use a matrix operation to determine
the total revenue each day.
Monday: 3 T-shirts at $10 each, 4 hats at $15 dollars each, and
1 pair of shorts at $20.
Tuesday: 4 T-shirts at $10 each, 2 hats at $15 each, and 3 pairs
of shorts at $20.
199
Revenue of a Clothing Store:Solution
Price matrix P and quantity matrix Q:
P =
10 15 20
Q=
3 44 2
1 3
Total revenues for the two days:
P Q=
10 15 20 3 44 2
1 3
= 110 130
Summary: The total revenue for Monday is $110.00 and for
Tuesday is $130.00.
200
8/14/2019 M103LecNotesF09
101/101
Labor and Wage Requirements
A boat-manufacturing company has plants in Massachusetts and
Virginia. The labor-hour and wage requirements for manufactur-
ing three types of boats are recorded in these tables and matrices:
cutting assembly packagedept. dept. dept.
1 man boat 0.6 0.6 0.22 man boat 1.0 0.9 0.33 man boat 1.5 1.2 0.4
M=
0.6 0.6 0.21.0 0.9 0.3
1.5 1.2 0.4
MA VAcutting $17 $ 14assembly $12 $10package $10 $9
N =
17 1412 1010 9
Which is the labor-hours matrix?
Interpret the entry in row 1, column 3 of the matrix M.
201
Labor and Wage Requirements, continued
M =
0.6 0.6 0.2
1 0 0 9 0 3
N =
17 14
12 10