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Lesson 20 Series AC Circuits

Lesson 20 Series AC Circuits

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Lesson 20 Series AC Circuits. Learning Objectives. Compute the total impedance for a series AC circuit. Apply Ohm’s Law, Kirchhoff’s Voltage Law and the voltage divider rule to AC series circuits. Graph impedances, voltages and current as a function of phase. - PowerPoint PPT Presentation

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Page 1: Lesson 20 Series AC Circuits

Lesson 20Series AC Circuits

Page 2: Lesson 20 Series AC Circuits

Learning Objectives Compute the total impedance for a series AC

circuit.

Apply Ohm’s Law, Kirchhoff’s Voltage Law and the voltage divider rule to AC series circuits.

Graph impedances, voltages and current as a function of phase.

Graph voltages and current as a function of time.

Page 3: Lesson 20 Series AC Circuits

Impedance Impedance is a complex quantity that can be

made up of resistance (real part) and reactance (imaginary part).

Z = R + jX = Z ()

Unit of impedance is ohms ().

Review

Page 4: Lesson 20 Series AC Circuits

Resistance For resistors, voltage and current are in phase.

0 0R R j R Z

Review

Page 5: Lesson 20 Series AC Circuits

For inductors, voltage leads current by 90º.

0 90 90L L Lj L L X X j Z

Review

Page 6: Lesson 20 Series AC Circuits

For capacitors, voltage lags current by 90º.

1 10 90 90C C Cj X X j

C C

Z

Review

Page 7: Lesson 20 Series AC Circuits

Impedance Because impedance is a complex quantity, it can be

represented graphically in the complex plane.

ZR = R0º = R + j0 = R

ZL = XL90º = 0 + jXL = jXL

ZC = XC-90º = 0 - jXC = -jXC

Page 8: Lesson 20 Series AC Circuits

ELI the ICE man

E leads I I leads E

When voltage is applied to an inductor, it resists the change of current. The current builds up more slowly, lagging in time and phase.

Since the voltage on a capacitor is directly proportional to the charge on it, the current must lead the voltage in time and phase to conduct charge to the capacitor plate and raise the voltage

Volta

geIn

duct

ance

Curre

nt

Volta

ge

Capac

itanc

e

Curre

nt

Page 9: Lesson 20 Series AC Circuits

Solving complex EE problems

1. Convert sine waves to phasors

2. Perform multiplication/division if needed

3. Convert phasors to complex numbers if needed to perform addition/subtraction

4. Convert back to phasor form for the answer to the problem

Page 10: Lesson 20 Series AC Circuits

Important Notes

Peak values are useful for time domain representations of signals.

RMS values are the standard when dealing with phasor domain representations

If you need to represent something in the time domain, you will need to convert RMS->Peak voltage to obtain Em

2 ( ) sin(2 )RMS m RMS mV E V e t E ft E

Page 11: Lesson 20 Series AC Circuits

Example Problem 1

For the circuit below:

a) Time Domain voltage and current v(t) and i(t)

b) Draw the sine waveforms for v and i

c) Draw the phasor diagram showing the relationship between V and I

Page 12: Lesson 20 Series AC Circuits

Example Problem 1

i(t)=50 sin (20000t) mA

v(t)=25 sin (20000t -90°) V

314 μsec

Page 13: Lesson 20 Series AC Circuits

AC Series Circuits Total impedance is sum of

individual impedances. Also note that current is the

same through each element.

1 2T n Z Z Z Z

Page 14: Lesson 20 Series AC Circuits

Impedance example

Page 15: Lesson 20 Series AC Circuits

Impedance example

3 4 5 3

3.2 18.4

TZ j j j

??????TZ

Page 16: Lesson 20 Series AC Circuits

Special case of Impedance

Whenever a capacitor and inductor of equal reactances are placed in series, the equivalent circuit is a short circuit.

Page 17: Lesson 20 Series AC Circuits

Impedance If the total impedance has only real

component, the circuit is said to be resistive (X = 0 or = 0°).

But since If > 0°, the circuit is inductive. ELI If < 0°, the circuit is capacitive. ICE

E IZ

Page 18: Lesson 20 Series AC Circuits

Example Problem 2

A network has a total impedance of ZT=24.0kΩ-30˚ at a frequency of 2 kHz.

If the network consists of two series elements, what types of components are those and what are their R/L/C values?

Page 19: Lesson 20 Series AC Circuits

The phasor sum of voltage drops and rise around a closed loop is equal to zero.

Kirchhoff’s Voltage Law (KVL)

10 0 8 36.87 12 53.13

6 126.87

c R LE V V

V

KVL ??????cV

Page 20: Lesson 20 Series AC Circuits

Voltage Divider Rule (VDR)

310 0

4 6 3

6 126.87

Cc

R L C

VDR

ZE

Z Z Z

j

j j

V

EZ

ZV

T

xx

??????cV

Page 21: Lesson 20 Series AC Circuits

Example Problem 3es(t)=170 sin (1000t + 0) V.

Determine ZTOT

Determine total current ITOT

Determine voltages VR, VL, and Vc

Verify KVL for this circuit Graph E, VL, VC, VR in the time domain

Page 22: Lesson 20 Series AC Circuits

Example Problem 3

180° phase difference between L and C

Page 23: Lesson 20 Series AC Circuits

Example Problem 4

es(t)=294 sin (377t + 0) V.

Use the voltage divider rule to find VL

Determine the value of inductance