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7/31/2019 lecture3_16
1/18
16.711 Lecture 3 Optical fibers
Last lecture
Geometric optic view of waveguide, numeric aperture Symmetric planar dielectric Slab waveguide
Modal and waveguide dispersion in palnar waveguide
Rectangular waveguide, effective index method
7/31/2019 lecture3_16
2/18
16.711 Lecture 3 Optical fibers
Today
Fiber modes Fiber Losses
Dispersion in single-mode fibers
Dispersion induced limitations
Dispersion management
The Graded index fibers
7/31/2019 lecture3_16
3/18
16.711 Lecture 3 Optical fibers
Fiber modes --- single mode and multi-mode fibers
V-number
,2
2
2
1
2
2
2
nn
nnb
eff
,)/996.01428.1( 2Vb
,)(2 2/12
2
2
1 nna
V
,41.2)(
2 2/122
2
1 nna
Vc
cutoff
Number of modes when V>>2.41
,2
2
VM
Normalized propagation constant
for V between 1.52.5.
Mode field diameter (MFD)
),11(22
Vaw
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
Examples --- single mode and multi-mode fibers
1. Calculate the number of allowed modes in a multimode step index fiber, a = 100 m, core
index of 1.468 and a cladding index of 1.447 at the wavelength of 850nm.
,44.91)(2 2/12
2
2
1 nna
V
,4181
2
2
V
M
Solution:
a < 2.1m
2. What should be the core radius of a single mode fiber that has the core index of 1.468 and the
cladding index of 1.447 at the wavelength of 1.3m.
,4.2)(2 2/12
2
2
1 nna
V
Solution:
3. Calculate the mode field diameter of a single mode fiber that has the core index of 1.458 and
the cladding index of 1.452 at the wavelength of 1.3m.
,1.10)/11(22 0 mVaw
Solution:
7/31/2019 lecture3_16
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7/31/2019 lecture3_16
6/18
7/31/2019 lecture3_16
7/18
16.711 Lecture 3 Optical fibers
Dispersions in single mode fiber
Waveguide dispersion
,|0
d
dvg ,
g
gv
L
,
2)2(
984.1)(
2
2
2
2
cna
N
d
d
L
gg
, LDmg
Example --- waveguide dispersion
n2 = 1.48, and delta n = 0.2 percent. Calculate Dw at 1310nm.
Solution:
,)()(
)(2
2
212
dV
VbdV
c
nnn
d
d
L
g
,)()(2
2
212
dV
VbdV
c
nnnDw
,)/996.01428.1( 2Vb for V between 1.52.5.
,26.0)(2
2
dV
VbdV
),/(9.1)()(2
2
212 kmnmps
dV
VbdV
c
nnnDw
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
chromatic dispersion (material plus waveduide dispersion)
,)(
wm
gDD
L
material dispersion is determined by
the material composition of a fiber.
waveguide dispersion is determined
by the waveguide index profile of a
fiber
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
Polarization mode dispersion
, pg D
L
fiber is not perfectly symmetric,
inhomogeneous.
refractive index is not isotropic.
dispersion flattened fibers:
Use waveguide geometry and
index profiles to compensate
the material dispersion
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
Dispersion induced limitations
,
2
1
2/1
B
For RZ bit With no intersymbol interference
,1
2/1B
For NRZ bit With no intersymbol interference
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
Dispersion induced limitations
,212/1
B
Optical and Electrical Bandwidth
,7.03 Bf dB
Bandwidth length product
,25.0
D
BL
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
Dispersion induced limitations
,16/ 12/1 pskmDL
,8.27.03 GHzBf dB
,9.3625.0 1kmGbsD
BL
Example --- bit rate and bandwidthCalculate the bandwidth and length product for an optical fiber with chromatic dispersion
coefficient 8pskm-1nm-1 and optical bandwidth for 10km of this kind of fiber and linewidth of
2nm.
Solution:
Fiber limiting factor absorption or dispersion?
,5.21025.0 dBkmdBLoss
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
Dispersion Management
],)(2
1exp[),0(
2
0
0T
tAtA ),
2exp()2(),0(
~2
0
22/12
00
TTAA
,
1
0
0T
Pre compensation schemes
1. Prechirp
Gaussian Pulse:
...,|2
1)(|)(
000 2
2
0
d
kd
d
dkkk
...,)(2
1...|)(|
)()( 22102
2
00 00
d
d
d
d
c
k
),2
exp(),0(~),(
~2 z
iAzA
],)(2
1exp[)(
)2
exp(),0(~
2
1),(
2
0
020
zQTzQ
Adz
iAtzA
,1)( 20
2
TzizQ ,])(1[)( 0
2/122
0
2 TTzzT
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
Dispersion Management
],)(2
)1(exp[),0(
2
0
0T
tiCAtA
),
)1(2exp()
1
2(),0(
~2
0
22/1
2
00
iC
T
iC
TAA
Pre compensation schemes
1. Prechirp
Prechirped Gaussian Pulse:
],)1()1(2
exp[)1
2()
2exp(),0(
~),(
~2
2
2
02
2
2
0
22/1
2
00
2
2C
iCT
C
T
iC
TAz
iAzA
],)(2
1exp[)(
)2
exp(),0(~
2
1),(
2
0
020
zQTzQ
Adz
iAtzA
,)(
1)(2
0
2
T
ziCzQ
,])()1[()(
0
2/12
2
0
22
2
0
2 TT
z
T
zCzT
,1)1(0
2/12
0T
C
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
Dispersion Management
1. Prechirp
With T1/T0 = sqrt(2), the transmission distance is:
,1
212
2
DLC
CCL
,/ 2
2
0 TLD
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
Dispersion Management
Examples:
),(1052
1 11
sBTFWHM
1. Whats the dispersion limited transmission distance for a 1.55m light wave system making
use of direct modulation at 10Gb/s? D = 17ps(km-nm). Assume that frequency chirping
broadens the guassian-shape by a factor of 6 from its transform limited width.
Solution:
,10366.1/11
0 sTT FWHM
,1)1(0
2/12
0T
C ,9.5C
,])()1[()( 002/12
2
0
22
2
0
2 TTT
z
T
zCzT
,2
22
cD ,/24
2
2 kmps
,12kmz
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
Dispersion compensation fiber or dispersion shifted fiber
Why dispersion compensation fiber:
02211 LDLD
for long haul fiber optic communication.
Alloptical solution
Approaches
),(2
2
d
nd
cDm
longer wavelength has
a larger index.
make the waveguide
weakly guided so that
longer wavelength has a
lower index.
7/31/2019 lecture3_16
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16.711 Lecture 3 Optical fibers
The Graded index fibers
02211 LDLD
Approaches
,;)1(1
,];)/(1[)(
2
1
ann
aann
General case Intermode dispersion
,1
2
2
d
dn
ndz
d
),sin(')cos( 00 pzpz
,)/2(2/12
ap ,/2 pz
,32021
c
nL
Only valid for paraxial approximation
Calculate the BL product of a grade index filber of 50m core with refractive index of n1 =
1.480 and n2 = 1.460. At 1.3 m.
,6.925.0 1kmGbsLBL
Solution:
,026.032021 ns
cnL