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Lecture 29 — The Planck Distribution Chapter 8, Wednesday March 26 th. The Planck distribution The Free energy of a photon gas Radiation pressure Quiz (if time). Reading: All of chapter 8 (pages 160 - 185) Homework 8 due Mon. Mar. 31st Assigned problems, Ch. 8 : 2, 6, 8, 10, 12. - PowerPoint PPT Presentation
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Lecture 29 — The Planck Distribution Lecture 29 — The Planck Distribution Chapter 8, Wednesday March 26Chapter 8, Wednesday March 26thth
•The Planck distribution
•The Free energy of a photon gas
•Radiation pressure
•Quiz (if time)
Reading: Reading: All of chapter 8 (pages 160 - 185)All of chapter 8 (pages 160 - 185)Homework 8 due Mon. Mar. 31stHomework 8 due Mon. Mar. 31stAssigned problems, Assigned problems, Ch. 8Ch. 8: 2, 6, 8, 10, : 2, 6, 8, 10,
1212
20 40 60 80 1000
2
4
6
84 perfect scores
Q1 - 7.9Q2 - 7.3Q3 - 6.0
Num
ber
of s
tude
nts
Score (%)
Exam 2 statisticsExam 2 statistics
Planck's law (quantization of light energy)Planck's law (quantization of light energy)
N distinguishable oscillators in the walls of the cavityM indistinguishable energy elements (quanta) hso that UN = M
1 1 1 11 !; 1 ln 1 ln
! 1 ! B
N M U U U UW S k
M N
1 1is the average energy of a single oscillator, i.e. NU U NU
1 1 1 11 ln 1 ln/ / / /B
U U U US k
hc hc hc hc
1 1/ /4 5
/ 8 8gives ;
1 1B Bhc k T hc k T
hc hcU u U
e e
(energy quantization)hc
h
Maxwell-Boltzmann statisticsMaxwell-Boltzmann statistics
Define energy distribution function: 0
exp / ,such that 1Bf A k T f d
Then,
0 0exp( / )B Bf d A k T d k T
This is simply the result that Rayleigh and others used, i.e. the average energy of a classical harmonic oscillator is kBT, regardless of its frequency.
Planck Planck postulatedpostulated that the energies of harmonic oscillators could that the energies of harmonic oscillators could only take on discrete values equal to multiples of a fundamental only take on discrete values equal to multiples of a fundamental energy energy = = hh, where , where is the frequency of the harmonic oscillator, is the frequency of the harmonic oscillator, i.e.i.e. 0, 0, , 2, 2, 3, 3, , etc.etc.......
Then,Then, UUnn = = nnnhnh = = 0, 1, 2...0, 1, 2...
Where Where nn is the number of modes excited with frequency is the number of modes excited with frequency . Although . Although Planck knew of no physical reason for doing this, he is credited with Planck knew of no physical reason for doing this, he is credited with the birth of quantum mechanics.the birth of quantum mechanics.
The new quantum statisticsThe new quantum statistics
exp / exp /n n B Bf A U k T A nh k T
Replace the continuous integrals with a discrete sums:
0 0
exp /n n Bn n
U U f nh A nh k T
0 0
exp / 1n Bn n
f A nh k T
Solving these equations together, one obtains:
/
exp / 1 exp / 1 exp / 1B B B
h hcU
k T h k T hc k T
Multiplying by D(), to give....
5
8( )
exp / 1B
hcu
hc k T
This is Planck's lawThis is Planck's law
12n n
n = 0, 1, 2... (quantum number)
= naturalfrequency ofvibration
Bk T
Vibrational energy levels for diatomic Vibrational energy levels for diatomic moleculesmolecules
En
ergy
En
ergy