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Signals and SystemsSignals and Systems
6552111 Signals and Systems6552111 Signals and Systems
Sopapun Suwansawang
Lecture #1
1
Lecture #1
Elementary Signals and Systems
Week#1-2
SignalsSignals
Signals are functions of independent variables that
carry information.
FUNCTIONS OF TIME AS SIGNALS
6552111 Signals and Systems6552111 Signals and Systems
Sopapun Suwansawang 2
Figure : Domain, co-domain, and range of a real function of continuous time.
)(tfv =
SignalsSignals
For example:
Electrical signals voltages and currents in a circuit
Acoustic signals audio or speech
6552111 Signals and Systems6552111 Signals and Systems
Acoustic signals audio or speech signals (analog or digital)
Video signals intensity variations in an image
Biological signals sequence of bases in a gene
Sopapun Suwansawang 3
There are two types of signals:
Continuous-time signals (CT) are functions of a continuous variable (time).
Discrete-time signals (DT) are functions of
6552111 Signals and Systems6552111 Signals and Systems
SignalsSignals
Discrete-time signals (DT) are functions ofa discrete variable; that is, they aredefined only for integer values of theindependent variable (time steps).
4Sopapun Suwansawang
CT and DT Signals CT and DT Signals
6552111 Signals and Systems6552111 Signals and Systems
CT DT
5Sopapun Suwansawang
Signal such as : )(tx ),...(),...,(),( 10 ntxtxtx
or in a shorter form as :
,...,...,,
],...[],...,1[],0[
10 nxxx
nxxx
or
where we understand that
6552111 Signals and Systems6552111 Signals and Systems
)(][ nn txnxx ==
and 's are called samples and the time intervalbetween them is called the sampling interval.When
nx
CT and DT Signals CT and DT Signals
6Sopapun Suwansawang
between them is called the sampling interval.Whenthe sampling intervals are equal (uniform sampling),then
n
)()(][ snTtn nTxtxnxxs
=== =
where the constant is the sampling intervalsT
6552111 Signals and Systems6552111 Signals and Systems
<
≥=
0,0
0,8.0)(
t
t
tx
t
<
≥=
0,0
0,8.0][
n
n
nx
n
CT and DT Signals CT and DT Signals
7Sopapun Suwansawang
)(tx
t
0
1
0
1
][nx
n
1 2 3 4 5
A discrete-time signal x[n] can be defined in two
ways:
1. We can specify a rule for calculating the nthvalue of the sequence. (see Example 1)
6552111 Signals and Systems6552111 Signals and Systems
CT and DT Signals CT and DT Signals
value of the sequence. (see Example 1)
2. We can also explicitly list the values of thesequence. (see Example 2)
8Sopapun Suwansawang
6552111 Signals and Systems6552111 Signals and Systems
DT Signals DT Signals
≥
==
0][ 2
1n
xnx
n
n
Example 1
9Sopapun Suwansawang
<
00 n
...,81
,41
,21
,1 =nx
6552111 Signals and Systems6552111 Signals and Systems
DT Signals DT Signals
Example 1: Continue
10Sopapun Suwansawang
DT SignalsDT Signals
6552111 Signals and Systems6552111 Signals and Systems
Example 2
11Sopapun Suwansawang
DT Signals DT Signals
6552111 Signals and Systems6552111 Signals and Systems
The sequence can be written as
Example 2 : continue
,...0,0,2,0,1,0,1,2,2,1,0,0..., =nx
12Sopapun Suwansawang
2,0,1,0,1,2,2,1 =nx
We use the arrow to denote the n = 0 term.We shall use theconvention that if no arrow is indicated, then the first termcorresponds to n = 0 and all the values of the sequence arezero for n < 0.
Example 3 Given the continuous-time signal
specified by
DT Signals DT Signals
6552111 Signals and Systems6552111 Signals and Systems
≤≤−−
=otherwise
tttx
0
111)(
Determine the resultant discrete-time sequence
obtained by uniform sampling of x(t) with a
sampling interval of 0.25 s
13Sopapun Suwansawang
otherwise0
Solve :
Ts=0.25 s,
Ts=1 s,
DT Signals DT Signals
6552111 Signals and Systems6552111 Signals and Systems
=
↑,...0,25.0,5.0,75.0,1,75.0,5.0,25.0,0...,][nx
= ,...0,1,0...,][nxTs=1 s,
14Sopapun Suwansawang
=
↑,...0,1,0...,][nx
Analog signals
6552111 Signals and Systems6552111 Signals and Systems
Analog and Digital Signals Analog and Digital Signals
If a continuous-time signal x(t) can take on any
value in the continuous interval (-∞∞∞∞ , +∞∞∞∞), thenthe continuous-time signal x(t) is called an analog
Digital signals
A signal x[n] can take on only a finite number of
distinct values, then we call this signal a digital
signal.
15Sopapun Suwansawang
the continuous-time signal x(t) is called an analogsignal.
CT and DT
6552111 Signals and Systems6552111 Signals and Systems
Digital Signals Digital Signals
16Sopapun Suwansawang
CT
Binary signal Multi-level signal
6552111 Signals and Systems6552111 Signals and Systems
Digital Signals Digital Signals
17Sopapun Suwansawang
Intuitively, a signal is periodic when it repeats
itself.
A continuous-time signal x(t) is periodic if there exists a positive real T for which
6552111 Signals and Systems6552111 Signals and Systems
Periodic SignalsPeriodic Signals
for all t and any integer m.The fundamental period
T0 of x(t) is the smallest positive value of T
18Sopapun Suwansawang
)()( mTtxtx +=
00
2ωπ
=T
Fundamental frequency
6552111 Signals and Systems6552111 Signals and Systems
Periodic SignalsPeriodic Signals
00
1T
f = Hz
Fundamental angular frequency
19Sopapun Suwansawang
000
22
Tf
ππω == rad/sec
A discrete-time signal x[n] is periodic if there exists a positive integer N for which
6552111 Signals and Systems6552111 Signals and Systems
Periodic SignalsPeriodic Signals
][][ mNnxnx +=
for all n and any integer m.The fundamental period N0 of
x[n] is the smallest positive integer N
20Sopapun Suwansawang
00
2Ω
=π
N
Any sequence which is not periodic is called a non-periodic (or aperiodic) sequence.
6552111 Signals and Systems6552111 Signals and Systems
NonperiodicNonperiodic SignalsSignals
21Sopapun Suwansawang
6552111 Signals and Systems6552111 Signals and Systems
Periodic SignalsPeriodic Signals
CT
22Sopapun Suwansawang
DT
Example 3 Find the fundamental frequency
in figure below.
6552111 Signals and Systems6552111 Signals and Systems
Periodic SignalsPeriodic Signals
23Sopapun Suwansawang
HzT
f4
11
00 ==.sec40 =T
(sec.)
Exercise Determine whether or not each of the
following signals is periodic. If a signal is periodic,
determine its fundamental period.
6552111 Signals and Systems6552111 Signals and Systems
Periodic SignalsPeriodic Signals
ttx )4
cos()(.1π
+=
24Sopapun Suwansawang
nnnx
nnx
enx
tttx
tttx
nj
4sin
3cos][.6
41
cos][.5
][.4
2sincos)(.3
4sin
3cos)(.2
4
)4/(
ππ
ππ
π
+=
=
=
+=
+=
Solve EX.1
6552111 Signals and Systems6552111 Signals and Systems
Periodic SignalsPeriodic Signals
14
cos)4
cos()( 00 =→
+=+= ω
πω
πtttx
ππ 22
25Sopapun Suwansawang
ππ
ωπ
21
22
00 ===T
x(t) is periodic with fundamental period T0 = 2π.
Solve EX.2
6552111 Signals and Systems6552111 Signals and Systems
Periodic SignalsPeriodic Signals
)()(4
sin3
cos)( 21 txtxtttx +=+=ππ
( ) .62
cos3/cos)( 111 ==→==π
ωπ Ttttxwhere
26Sopapun Suwansawang
( )
.84/
2sin)4/sin()(
.63/
cos3/cos)(
222
111
==→==
==→==
ππ
ωπ
πωπ
Ttttx
Ttttxwhere
numberrationalaisT
T
43
86
2
1 ==
x(t) is periodic with fundamental period T0 = 4T1=3T2=24.
Note : Least Common Multiplier of (6,8) is 24
6552111 Signals and Systems6552111 Signals and Systems
Even and Odd Signals:Even and Odd Signals:
A signal x(t) or x[n] is referred to as an even signal if
][][
)()(
nxnx
txtx
−=
−=
27Sopapun Suwansawang
A signal x(t) or x[n] is referred to as an odd signal if
][][
)()(
nxnx
txtx
−=−
−=−
6552111 Signals and Systems6552111 Signals and Systems
Even and Odd Signals:Even and Odd Signals:
28Sopapun Suwansawang
Any signal x(t) or x[n] can be expressed as asum of two signals, one of which is even andone of which is odd.That is,
6552111 Signals and Systems6552111 Signals and Systems
Even and Odd Signals:Even and Odd Signals:
)()()( txtxtx oe +=
29Sopapun Suwansawang
][][][ nxnxnx oe
oe
+=
][][21
][
)()(21
)(
nxnxnx
txtxtx
e
e
−+=
−+=
][][21
][
)()(21
)(
nxnxnx
txtxtx
o
o
−−=
−−=
even part odd part
6552111 Signals and Systems6552111 Signals and Systems
Even and Odd Signals:Even and Odd Signals:
Example 4 Find the even and odd components ofthe signals shown in figure below
30Sopapun Suwansawang
Solve even part )()()(2 tftftfe −+=
2fe(t)
Example 4 : continue
Odd part
6552111 Signals and Systems6552111 Signals and Systems
Even and Odd Signals:Even and Odd Signals:
)()()(2 tftftfo −−=
2fo(t)
31Sopapun Suwansawang
2fo(t)
Example 4 : continue
Check
)()()( tftftf oe +=
6552111 Signals and Systems6552111 Signals and Systems
Even and Odd Signals:Even and Odd Signals:
)()(2
1)( tftftfo −−= ,)()(
2
1)( tftftfe −+=
32
)()()( tftftf oe +=
Sopapun Suwansawang
2
fo(t)
fe(t)
Note that the product of two even signals or oftwo odd signals is an even signal and that theproduct of an even signal and an odd signal is anodd signal.
(even)(even)=even
6552111 Signals and Systems6552111 Signals and Systems
Even and Odd Signals:Even and Odd Signals:
(even)(even)=even
(even)(odd)=odd
(odd)(even)=odd
(odd)(odd)=even
33Sopapun Suwansawang
Example 5 Show that the product of two evensignals or of two odd signals is an even signaland that the product of an even and an oddsignaI is an odd signal.
6552111 Signals and Systems6552111 Signals and Systems
Even and Odd Signals:Even and Odd Signals:
Let )()()( txtxtx =
34Sopapun Suwansawang
Let )()()( 21 txtxtx =
If x1(t) and x2(t) are both even, then
)()()()()()( 2121 txtxtxtxtxtx ==−−=−
If x1(t) and x2(t) are both even, then
)()()())()(()()()( 212121 txtxtxtxtxtxtxtx ==−−=−−=−
A deterministic signal is a signal in which eachvalue of the signal is fixed and can bedetermined by a mathematical expression, rule,or table. Because of this the future values of thesignal can be calculated from past values with
6552111 Signals and Systems6552111 Signals and Systems
Deterministic and Random Signals: Deterministic and Random Signals:
signal can be calculated from past values with
complete confidence.
A random signal has a lot of uncertainty aboutits behavior. The future values of a randomsignal cannot be accurately predicted and canusually only be guessed based on the averagesof sets of signals
35Sopapun Suwansawang
6552111 Signals and Systems6552111 Signals and Systems
Deterministic and Random Signals: Deterministic and Random Signals:
Deterministic
36Sopapun Suwansawang
Random
RightRight--Handed and LeftHanded and Left--Handed SignalsHanded Signals
A right-handed signal and left-handed signal arethose signals whose value is zero between agiven variable and positive or negative infinity.
Mathematically speaking,
A right-handed signal is defined as any signal
6552111 Signals and Systems6552111 Signals and Systems
A right-handed signal is defined as any signal where f(t) = 0 for
A left-handed signal is defined as any signal where f(t) = 0 for
37Sopapun Suwansawang
∞<< 1tt
−∞>> 1tt
RightRight--Handed and LeftHanded and Left--Handed SignalsHanded Signals
6552111 Signals and Systems6552111 Signals and Systems
Right-Handed
1t
38Sopapun Suwansawang
Left-Handed
1
1t
Causal vs. Anticausal vs. NoncausalCausal vs. Anticausal vs. Noncausal
Causal signals are signals that are zero forall negative time.
Anticausal signals are signals that are zerofor all positive time.
6552111 Signals and Systems6552111 Signals and Systems
for all positive time.
Noncausal signals are signals that havenonzero values in both positive andnegative time.
39Sopapun Suwansawang
Causal vs. Anticausal vs. NoncausalCausal vs. Anticausal vs. Noncausal
6552111 Signals and Systems6552111 Signals and Systems
Causal
40Sopapun Suwansawang
Anticausal
Noncausal
Energy and Power SignalsEnergy and Power Signals
6552111 Signals and Systems6552111 Signals and Systems
Consider :
41Sopapun Suwansawang
Rti
R
tv
titvtp
)(
)(
)()()(
2
2
=
=
⋅=
∫∫
∫
∞
∞−
∞
∞−
∞
∞−
==
=
)()()()(1
)(
22 tdtitdtvR
dttpE
Power Energy
Total energy E and average power P on a per-ohm basis are
Energy and Power SignalsEnergy and Power Signals
6552111 Signals and Systems6552111 Signals and Systems
dttiE ∫∞
∞−
= )(2 Joules
42Sopapun Suwansawang
dttiT
PT
TT∫
−∞→
∞−
= )(21 2lim Watts
For an arbitrary continuous-time signal x(t), the normalized energy content E of x(t) is defined as
∫∫−∞→
∞
∞−
==T
TTdttxdttxE 22 )()( lim
Energy and Power SignalsEnergy and Power Signals
6552111 Signals and Systems6552111 Signals and Systems
The normalized average power P of x(t) is defined as
43
−∞→∞− TT
∫−∞→
=T
TTdttx
TP 2)(
21
lim
Sopapun Suwansawang
Similarly, for a discrete-time signal x[n],
the normalized energy content E of x[n] is defined as
Energy and Power SignalsEnergy and Power Signals
6552111 Signals and Systems6552111 Signals and Systems
∑∑−=∞→
∞
−∞===
N
NnNnnxnxE 22 ][lim][
The normalized average power P of x[n] is defined as
44Sopapun Suwansawang
−=∞→−∞= NnNn
∑−=∞→ +
=N
NnNnx
NP 2][
121
lim
x(t) (or x[n]) is said to be an energy signal (or sequence) if and only if 0 < E < ∞∞∞∞, and P = 0.
x(t) (or x[n]) is said to be a power signal (or sequence) if and only if 0 < P < ∞∞∞∞, thusimplying that E = ∞∞∞∞.
Energy and Power SignalsEnergy and Power Signals
6552111 Signals and Systems6552111 Signals and Systems
implying that E = ∞∞∞∞. Note that a periodic signal is a power signal if its energy content per period is finite, and then the average power of this signal need only be calculated over a period.
45Sopapun Suwansawang
∫=0
0
2
0)(
1T
dttxT
P
Exercise Determine whether the followingsignals are energy signals, power signals, orneither.
1.
Energy and Power SignalsEnergy and Power Signals
6552111 Signals and Systems6552111 Signals and Systems
)cos()( 0 θω += tAtx1.
2.
3.
46Sopapun Suwansawang
)cos()( 0 θω += tAtxtjeAtx 0)( ω=
)()( 3 tuetv t−=
Solve Ex.1
The signal x(t) is periodic with T0=2π/ω0.
Energy and Power SignalsEnergy and Power Signals
6552111 Signals and Systems6552111 Signals and Systems
dttAT
dttxT
PTT
∫∫ +==00
00
22
00
2
0)(cos
1)(
1θω
)cos()( 0 θω += tAtx
47Sopapun Suwansawang
0000
dttT
AP
T
∫ ++=0
00
0
2)22cos(1(
21
θω
++= ∫ ∫ dttdt
T
AP
T T0 0
00
00
2)22(cos1
2θω0
2
2A= ∞<
Thus, x(t) is power signal.
Energy and Power SignalsEnergy and Power Signals
6552111 Signals and Systems6552111 Signals and Systems
Solve Ex.2 tjAtAeAtx tj00 sincos)( 0 ωωω +==
The signal x(t) is periodic with T0=2π/ω0.
Note that periodic signals are, in general, power signals.
∫T
21∫T
21
48Sopapun Suwansawang
∫=T
x dttxT
P0
2)(
1∫=T
tj dtAeT 0
20
1 ω
2 22
0 0
2
1 T T
x
A AA dt dt T
T T T
P A W
= = = ⋅
=
∫ ∫