LEADER TEST SERIES / JOINT PACKAGE COURSETARGET : PRE-MEDICAL 2017

Form Number :

DISTANCE LEARNING PROGRAMME(Academic Session : 2016 - 2017)

1. A seat marked with Reg. No. will be alloted to each student. The student should ensure that he/she occupies the correct seat

only. If any student is found to have occupied the seat of another student, both the students shall be removed from the examination

and shall have to accept any other penalty imposed upon them.

izR;sd fo|kFkhZ dk jftLVªs'ku ua- ds vuqlkj LFkku fu;r gS rFkk os vius fu;r LFkku ij gh cSBsaA ;fn dksbZ fo|kFkhZ fdlh nwljs fo|kFkhZ ds LFkku

ij cSBk ik;k x;k rks nksuksa fo|kfFkZ;ksa dks ijh{kk d{k ls ckgj dj fn;k tk,xk vkSj nksuksa dks dksbZ vU; tqekZuk Hkh Lohdk;Z gksxkA

2. Student can not use log tables and calculators or any other material in the examination hall.

fo|kFkhZ ijh{kk d{k esa yksx Vscy] dsYdwysVj ;k fdlh vU; lkexzh dk mi;ksx ugha dj ldrk gSA

3. Student must abide by the instructions issued during the examination, by the invigilators or the centre incharge.

ijh{kk ds le; fo|kFkhZ dks ijhoh{kd }kjk fn;s x;s funsZ'kksa dh ikyuk djuk vko';d gSA

4. Before attempting the question paper ensure that it contains all the pages and that no question is missing.

iz'u i= gy djus ls igys fo|kFkhZ vk'oLr gks tk, fd blesa lHkh ist layXu gSa vFkok ughaA

5. Each correct answer carries 1 marks, while one third mark will be deducted from the total of individual subject for each

incorrect answer.

izR;sd lgh mÙkj ds 1 vad gSa tcfd ,d frgkbZ vad] xyr mÙkj dk ml fo"k; ds dqy vadksa esa ls de dj fy;k tk;sxkA

Do not open this Test Booklet until you are asked to do sobl ijh{kk iqfLrdk dks tc rd uk [kksys a tc rd dgk u tk,sA

Important Instructions / egRoiw.kZ funsZ'k

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+91-744-5156100, 5162200 dlp@allen.ac.in www.dlp.allen.ac.in, dsat.allen.ac.in

Your Target is to secure Good Rank in Pre-Medical 2017

Note : In case of any Correction in the test paper, please mail to dlpcorrections@allen.ac.in within 2 days along with Paper code and YourForm No.uksV% ;fn bl iz'u i= esa dksbZ Correction gks rks Ïi;k Paper code ,oa vkids Form No. ds lkFk 2 fnu ds vUnj dlpcorrections@allen.ac.in ijmail djsaA

Test Type : ALL INDIA OPEN TEST (MAJOR) Test Pattern : AIIMS

TEST DATE : 19 - 02 - 2017

Paper Code : 0999DM310316021

TEST SYLLABUS : FULL SYLLABUS

ALL INDIA OPEN TEST/Pre-Medical /AIIMS/19-02-2017

1/350999DM310316021

1. Electric field at the centre 'O' of a semicircle ofradius 'a' having linear charge density l is givenas :-

(1) 2

0

lÎ a

(2) lp

Î0 a

aOl++++++

+ ++ ++ ++ +

+ ++(3)

02 al

p Î (4) 0 a

lp Î

2. For the network of resistance shown in the fig.the equivalent resistance of the network betweenthe points A and B is 18 W. The value of unknownresistance R is :-

B 10W 10W 10W

10W

10W 10W

R

A

(1) 8 W (2) 10 W(3) 16 W (4) 24 W

3. Circular loop of a wire and a long straight wire

carry currents IC and Ie , respectively as shown infigure. Assuming that these are placed in the sameplane.The magnetic fields will be zero at the centreof the loop when the separation H is :-

(1) I RIe

Cp

(2) I RIC

ep

(3) pII R

C

e

(4) II RC

C

p

4. The length of the seconds pendulum is decreasedby 0.3 cm when it is shifted to Chennai fromLondon. If the acceleration due to gravity atLondon is 981 cm/sec2, the acceleration due togravity at Chennai is : (assume p2 = 10) :-(1) 981 cm/sec2 (2) 978 cm/sec2

(3) 984 cm/sec2 (4) 975 cm/sec2

BEWARE OF NEGATIVE MARKINGHAVE CONTROL ¾® HAVE PATIENCE ¾® HAVE CONFIDENCE Þ 100% SUCCESS

1. l js[kh; vkos'k ?kuRo okys a f=T;k ds v¼Z o`Ùk ds dsUnz

O ij fo|qr {ks= gksxk %&

(1) 2

0

lÎ a

(2) lp

Î0 aaO

l++++++

+ ++ ++ ++ +

+ ++(3) 02 a

lp Î (4)

0 al

p Î

2. fp= esa iznf'kZr izfrjks/kksa ds ifjiFk tky dk Ao B fcUnqvksa

ds e/; ifj.kkeh izfrjks/k 18 vkse gSA vKkr izfrjks/k R

dk eku gksxk :–

B 10W 10W 10W

10W

10W 10W

R

A

(1) 8W (2) 10 W

(3) 16 W (4) 24 W

3. tSlk fd fp= esa n'kkZ;k x;k gS] ,d rkj ds o`rh; ik'k (ywi)

vkSj ,d yEcs lh/ks rkj esa Øe'k% fo|qr /kkjk;sa IC vkSj Ie

dk izokg gks jgk gSA ;g ekurs gq;s fd ; s ,d gh ry esa

j[ks gSa] rks ik'k ds dsUnz ij pqEcdh; {ks= 'kwU; gksxk tc

ikFkZD; nwjh H gS :-

(1) I RIe

Cp

(2) I RIC

ep

(3) pII R

C

e

(4) II RC

C

p

4. psUubZ ls yUnu rd ,d "lsd.M yksyd" dks ys tkus ij

bldh yEckbZ 0.3 lseh ?kVrh gSA ;fn yUnu esa xq:Roh;

Roj.k dk eku 981 lseh@lsd.M2 gS] rc psUubZ esa xq:Roh;

Roj.k dk eku gS (eku yks p2 = 10) :-

(1) 981 lseh@lsd.M2 (2) 978 lseh@lsd.M2

(3) 984 lseh@lsd.M2 (4) 975 lseh@lsd.M2

ALL INDIA OPEN TEST/Pre-Medical /AIIMS/19-02-2017

2/35 0999DM310316021

5. In the relation :-Z

KP e ,a

-q

a=

b

where, P is pressure, Z is distance, K isBoltzmann's constant and q is the temperature.The dimensional formula of b will be :

(1) [M0L2T0] (2) [M1L2T–1]

(3) [M1L0T–1] (4) [M0L2T–1]

6. Five equal resistances each of resistance R areconnected as shown in the Figure. A battery ofvoltage V is connected between A and B.Thecurrent flowing in AFCEB will be

A B

C

D E

R

R

RR R

F

(1) VR

(2) V

2R(3)

2VR

(4) 3VR

7. A current time curve is shown in the followingdiagram. This type of current is passed in theprimary coil of transformer. The nature of inducedemf in the secondary coil will be :-

t

I

0

(1) t

e

0 (2) t

e

0

(3) t

e

0(4)

t

e

0

8. A particle is executing simple harmonic motionwith an amplitude of 4 cm. At the mean positionthe velocity of the particle is 10 cm/sec. Thedistance of the particle from the mean positionwhen its speed becomes 5 cm/s is :-

(1) 3 cm (2) 5 cm

(3) 2 3 cm (4) 2 5 cm

5. lEcU/k

Z

KP e ,a

-q

a=

b

esa] 'P' nkc, 'Z' nwjh, K cksYV~teku fu;rkad rFkk q rki gSAb dk foeh; lw= gksxk&

(1) [M0L2T0] (2) [M1L2T–1]

(3) [M1L0T–1] (4) [M0L2T–1]

6. izR;sd R izfrjks/k ds ik¡p leku izfrjks/kksa dks fp=kuqlkj

O;ofLFkr fd;k x;k gSA A vkSj B ds chp V oksYV dh

cSVjh tksM+h tkrh gSA AFCEB iFk esa izokfgr /kkjk dk

eku gksxk :–

A B

C

D E

R

R

RR R

F

(1) VR

(2) V

2R(3)

2VR

(4) 3VR

7. ,d /kkjk le; oØ fp=kuqlkj gSA ;fn ;g /kkjk VªkUlQkWeZjdh izkFkfed dq.Myh ls izokfgr gks rks f}fr;d esa izsfjrfo|qr okgd cy gksxk %&

t

I

0

(1) t

e

0 (2) t

e

0

(3) t

e

0(4)

t

e

0

8. ,d d.k 4.0 lseh vk;ke ls ljy vkorZ xfr djrk gSA

ek/; fLFkfr esa d.k dk osx 10 lseh@ls gSA tc d.k dh

pky 5 lseh@ls gksrh gS rc ek/; fLFkfr ls mldh nwjh D;k

gksxh\

(1) 3 lseh (2) 5 lseh

(3) 2 3 lseh (4) 2 5 lseh

ALL INDIA OPEN TEST/Pre-Medical /AIIMS/19-02-2017

3/350999DM310316021

9. Three forces start acting simultaneously on a

particle moving with velocity v.r These forces are

represented in magnitude and direction by thethree sides of a triangle ABC as shown in thefigure. The particle will now move with velocity :-

A B

C

(1) less than vr

(2) greater than vr

(3) vr , remaining unchanged

(4) | vr | in the direction of the largest force along

BCuuur

10. The value of equivalent capacitance of thecombination shown in figure, between the pointsP and Q is :

2C

2C

C

2C

C

C

P

Q

(1) 3C (2) 2C (3) C (4) C/3

11. An experiment takes 10 min for an electric kettleto heat a certain quantity of water from 0°C to100°C. If it takes 54 min to convert this water at100°C into steam, then latent heat of steam is :-(1) 80 cal/gm (2) 540 cal/kg(3) 540 cal/gm (4) 80 cal/kg

12. What should be the maximum acceptance angleat the air–core interface of an optical fibre if n1

and n2 are the refractive indices of the core andthe cladding, respectively

(1) sin–1(n2/n1) (2) sin–1 n n12

22–

(3) tan–1 nn

2

1

LNM

OQP (4) tan–1 n

n1

2

LNM

OQP

13. Two infinitely long parallel wires having linearcharge densities l1 and l2 respectively are placedat a distance R. The force per unit length on eitherwire will be :–

(1) 1 22

k2

R

l l(2)

l l1 22kR

(3) 1 22

k

R

l l(4) 1 2k

Rl l

9. rhu cy vr

osx ls xfreku ,d d.k ij ,d lkFk yxukçkjEHk djrs gSaA ;s cy ifjek.k o fn'kk esa ,d f=Hkqt ABCdh Hkqtkvksa }kjk fu:fir gksrs gSa] tSlk fd fp= esa n'kkZ;kx;k gSA vc d.k dk osx gksxk :-

A B

C

(1) vr ls de

(2) vr ls vf/kd

(3) vr vifjofrZr jgrs jgsxk

(4) | vr | , BC

uuur

ds vuqfn'k lcls cM+s cy dh fn'kk esa

10. fp=kuqlkj la/kkfj=ksa ls cus ifjiFk dh fcUnqvksa P rFkk Q

ds e/; rqY; /kkfjrk gSa &

2C

2C

C

2C

C

C

P

Q

(1) 3 C (2) 2 C (3) C (4) C/3

11. ,d oS|qr&dsryh }kjk ty dh ,d fuf'pr ek=k dks 0°Cls 100°C rd xeZ djus esa 10 feuV yxrs gSaA 100°Cij fLFkr bl ty dks Hkki esa :ikUrfjr djus esa ;fn54 feuV yxrs gSa rks Hkki dh xqIr Å"ek gS :-(1) 80 dSyksjh@xzke (2) 540 dSyksjh@xzke(3) 540 dSyksjh@xzke (4) 80 dSyksjh@xzke

12. vxj ØksM vkSj ifjfu/kku (DySfMax) ds viorZukad Øe'k%

n1 vkSj n2 gS rks ,d izdk'kh; Qkbcj ds ok;q&ØksM varjki`"B

(,vj&dksj bUVjQsl) ij vfèkdre Lohdj.k dks.k D;k

gksuk pfg;s :-

(1) sin–1(n2/n1) (2) sin–1 n n12

22–

(3) tan–1 nn

2

1

LNM

OQP (4) tan–1 n

n1

2

LNM

OQP

13. nks vuUr yEckbZ ds lekUrj rkj ftu ij js[kh; vkos'k ?kuRo

Øe'k% l1 vkSj l2 gSa] R ehVj dh nwjh ij j[ks gSa] muesa ls

fdlh ,d dh ,dkad yEckbZ ij cy gksxk &

(1) 1 22

k2

R

l l(2)

l l1 22kR

(3) 1 22

k

R

l l(4) 1 2k

R

l l

ALL INDIA OPEN TEST/Pre-Medical /AIIMS/19-02-2017

4/35 0999DM310316021

14. A smooth sphere of radius R is made to translatein a straight line with a constant accelerationa = g. A particle kept on the top of the sphere isreleased with zero velocity with respect to thesphere. The speed of the particle with respect tothe sphere as a function of angle q as it slidesdown is :-

(1) Rg(sin cos )

2

q + q

(2) Rg(1 cos sin )+ q - q

(3) 4Rgsinq

(4) 2Rg(1 sin cos )+ q - q

15. A solenoid of radius R and length L has a currentI = I0 coswt. The value of induced electric field ata distance of r outside the solenoid, is :

(1) 2

0 0µ nI Rsin t

2rw

w (2) 2

0 0µ nI Rsin t

rw

w

(3) 2

0 0µ nI Rsin t

2rw (4) Zero

16. For a parallel beam of monochromatic light ofwavelength 'l', diffraction is produced by a singleslit whose width 'a' is of the order of thewavelength of the light. If 'D' is the distance ofthe screen from the slit, the width of the centralmaxima will be :

(1) Dal

(2) Dal

(3) 2Dal

(4) 2D

al

17. A pole is held vertically with one end on theground. The length of the pole is 30 m. The poleis allowed to fall. Assuming that the lower endof the pole does not slip, with what velocity willthe upper end strike the ground?(Take g = 10 ms–2) :-(1) 5 m s–1 (2) 10 m s–1

(3) 20 m s–1 (4) 30 m s–1

18.

V

C3

C1

C2

Potential difference across C3 is:

(1)1 2

1 2 3

(C – C )VC C C+ + (2)

1 2

1 2 3

(C C )VC C C

++ +

(3)1 2

1 2 3

(C 2C )VC C C

++ + (4)

1 2

1 2 3

(C –2C )VC C C+ +

14. R f=T;k dk ,d fpduk xksyk fu;r Roj.k a = g ls ,dlh/kh js[kk esa LFkkukUrfjr fd;k tkrk gSA xksys dh pksVh ij

fLFkr ,d d.k xksys ds lkis{k 'kwU; osx ls NksM+k tkrk gSA

d.k tSls&tSls uhps dh vksj fQlyrk gS] xksys ds lkis{k

dks.k q ds Qyu ds :i esa d.k dk osx gS :-

(1) Rg(sin cos )

2

q + q

(2) Rg(1 cos sin )+ q - q

(3) 4Rgsinq

(4) 2Rg(1 sin cos )+ q - q

15. ,d R f=T;k rFkk L yEckbZ dh ifjukfydk esa I = I0 coswt

/kkjk izokfgr gks jgh gSA ifjukfydk ds ckgj r nwjh ij izsfjrfo|qr {ks= dk eku gksxk :

(1) 2

0 0µ nI Rsin t

2rw

w (2) 2

0 0µ nI Rsin t

rw

w

(3) 2

0 0µ nI Rsin t

2rw (4) 'kwU;

16. fdlh ,dy f>jh (fLyV) dh pkSM+kbZ 'a', izdk'k dh rjaxnS/;Z

dh dksfV dh gSA bl f>jh ij 'l' rjaxnS/;Z dh ,do.khZ i zdk'k

dh lekUrj fdj.k iqat vkifrr gksus ls foorZu mRiUu gksrk

gSA ;fn f>jh ls insZ dh nwjh 'D' gks rks] dsUæh; mfPp"B dh

pkSM+kbZ gksxh :

(1) Dal

(2) Dal (3)

2Dal (4)

2Dal

17. ,d [kEHks (Pole) dks Å/okZ/kjr% bl çdkj j[kk x;k gS

fd bldk fupyk fljk tehu ij gSA [kEHks dh yEckbZ30 ehVj gSA [kEHks dks fxjus fn;k tkrk gSA ;g ekurs gq,fd [kEHks dk fupyk fljk vius LFkku ls ugha f[kldsxk ]Åijh fljk fdl osx ls tehu ls Vdjk;sxk\(g = 10 eh@ls2) :-(1) 5 eh@ls (2) 10 eh@ls(3) 20 eh@ls (4) 30 eh@ls

18.

V

C3

C1

C2

iznf'kZr ifjiFk esa C3 ij foHkokUrj gksxk :-

(1)1 2

1 2 3

(C –C )VC C C+ + (2)

1 2

1 2 3

(C C )VC C C

++ +

(3)1 2

1 2 3

(C 2C )VC C C

++ + (4)

1 2

1 2 3

(C –2C )VC C C+ +

ALL INDIA OPEN TEST/Pre-Medical /AIIMS/19-02-2017

5/350999DM310316021

19. The P-V diagram of a certain process (Carnotcycle) is as shown in the figure. The process isrepresented as :-

V

PA

B

D C

isothermal

adia

batic

isothermal

adia

batic

(1)

V

T A

D C

B

(2)

T

P B

A D

C

(3)

V

T A

D C

B

(4)

T

P

C

B

A

D

20. An open pipe is suddenly closed with the resultthat the second overtone of the closed pipe isfound to be higher in frequency by 100 Hz thanthe first overtone of the original pipe. Thefundamental frequency of open pipe will be :-

(1) 100 Hz (2) 300 Hz

(3) 150 Hz (4) 200 Hz

21. Velocity-time graph corresponding todisplacement-time graph shown in adjoiningfigure is :-

(1) (2)

(3) (4)

19. ,d fuf'pr çØe (dkuksZ pØ) ds P-V vkjs[k dks fp=esa n'kkZ;k x;k gSA bl çØe dks fuEuor~ n'kkZ ldrs gSa :-

V

PA

B

D C

isothermal

adia

batic

isothermal

adia

batic

(1)

V

T A

D C

B

(2)

T

P B

A D

C

(3)

V

T A

D C

B

(4)

T

P

C

B

A

D

20. ,d [k qys ikbi dks vpkud cUn dj fn;k tkrk gSA

ifj.kkeLo:i] cUn ikbi ds nwljs vf/kLojd dh vko`fÙk

ewy ikbi ds igys vf/kLojd dh rqyuk esa 100 gV~Zt vfèkd

ikbZ tkrh gSA [kqys ikbi dh ewy vkofÙk gksxh :-

(1) 100 gV~Zt (2) 300 gV~Zt

(3) 150 gV~Zt (4) 200 gV~Zt

21. fp= esa n'kk Z; s x;s foLFkkiu≤ xz kQ ds laxr(corresponding) osx≤ xzkQ gS :-

(1) (2)

(3) (4)

ALL INDIA OPEN TEST/Pre-Medical /AIIMS/19-02-2017

6/35 0999DM310316021

22. A wire PQRST carrying current I = 5A is

placed in uniform magnetic field B = 2T as

shown in figu re If the length of part

QR = 4 cm and SR = 6 cm then the magnetic

force on SR edge of the wire is :-

(1) 0.4 N B=2TR

T PS Q I=5A

(2) 0.6 N(3) zero(4) 6 N

23. A resistance of 300W and an inductance of1/p henry are connected in series to a A.C. voltageof 20 volts and 200 Hz frequency. The phase anglebetween the voltage and current is :-

(1) tan–143

æ öç ÷è ø

(2) tan–134

æ öç ÷è ø

(3) tan–132

æ öç ÷è ø

(4)tan–1 23

æ öç ÷è ø

24. Speed of sound wave is v. If a reflector movestowards a stationary source emitting waves offrequency f, with speed u, the frequency ofreflected wave can't be :-

(1) v u

fv u

-æ öç ÷è ø+ (2)

v uf

v+æ ö

ç ÷è ø

(3) v u

fv u

+æ öç ÷è ø- (4)

v uf

v-æ ö

ç ÷è ø25. Two paper screens A and B are separated by

150 m. A bullet pierces A and then B. The holein B is 15 cm below the hole in A. If the bulletis travelling horizontally at the time of hitting A,then the velocity of the bullet at A is :-

(1) 1100 3 ms- (2) 1200 3 ms-

(3) 1300 3 ms- (4) 1500 3 ms-

26. A block Q of mass M is placed on a horizontalfrictionless surface AB and a body P of mass mis relased on its frictionless slope. As P slides bya length L on this slope of A inclination q, theblock Q would slide by a distance :-

(1) m

LcosM

q

(2) m

L(M m)+

MQ

P

Bq

A

C

(3) (M m)mLcos

+q

(4) mLcos(m M)

q+

22. ,d rkj PQRST ftlesa 5 ,Eih;j dh èkkjk çokfgr gksjgh gSA bldks B = 2 Vslyk ds le:i pqEcdh; {ks=fp=kuqlkj j[krs gSaA ;fn QR o SR Hkqtk dh yEckbZ;kaØe'k% 4 cm o 6 cm gks rks Hkqtk SR ij yxus okykpqEcdh; cy gksxk%&(1) 0.4 U;wVu B=2TR

T PS Q I=5A

(2) 0.6 U;wVu

(3) 'kwU;

(4) 6 U;wVu

23. 300 W ds çfrjksèk vkSj 1/p gsujh ds ,d çsjdRo dks

20 oksYV o 200 gVZ~t ds çR;korhZ èkkjk L=ksr ds lkFk tksM+k

x;k gSA foHko vkSj èkkjk ds chp dykUrj gksxk %&

(1) tan–143

æ öç ÷è ø

(2) tan–134

æ öç ÷è ø

(3) tan–132

æ öç ÷è ø

(4)tan–1 23

æ öç ÷è ø

24. /ofu dh pky v gSA f vkofÙk ij rjaxsa mRlftZr djrs gq,

fLFkj L=ksr dh vksj ;fn ,d ijkorZd pky u ls pyrk

gS] rc ijkofrZr rjax dh vko`fÙk ugha gks ldrh :-

(1) v u

fv u

-æ öç ÷è ø+ (2)

v uf

v+æ ö

ç ÷è ø

(3) v u

fv u

+æ öç ÷è ø- (4)

v uf

v-æ ö

ç ÷è ø25. nks dkxt dh LØhu A o B, 150 eh dh nwjh ij gSaA ,d

xksyh A o B dks Hksn tkrh gSA B esa gqvk fNæ A esa gq;sfNæ ls 15 lseh uhps gSA ;fn A ls Vdjkrs le; xksyh {kSfrtfn'kk esa xfr'khy gS] rc A ij xksyh dk osx gS :-(g = 10 eh@ls2)

(1) 100 3 eh@ls (2) 200 3 eh@ls

(3) 300 3 eh@ls (4) 500 3 eh@ls

26. M æO;eku dk ,d xqVdk Q ,d ?k"kZ.kghu {kSfrt lrgAB ij j[kk gS rFkk blds ?k"kZ.kjfgr <+ky ij m æO;ekudh ,d oLrq P dks fQlyus ds fy;s NksM+k tkrk gSA q >qdkookys bl <+ky ij tc P, L nwjh fQly ysrk gS] rc xqVdsQ }kjk fQlyh x;h nwjh gS :-

(1) m

LcosM

q

(2) m

L(M m)+

MQ

P

Bq

A

C

(3) (M m)mLcos

+q

(4) mLcos(m M)

q+

ALL INDIA OPEN TEST/Pre-Medical /AIIMS/19-02-2017

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27. What is the velocity v of a metallic ball of radiusr falling in a tank of liquid at the instant when itsacceleration is one-half that of a freely fallingbody ? (The densities of metal and of liquid arer and s respectively and the viscosity of the liquidis h) :-

(1) 2r g

( 2 )9

r - sh (2)

2r g(2 )

9r- s

h

(3) 2r g

( )9

r - sh (4)

22r g( )

9r- s

h28. A sinusoidal voltage of rms value of 200 volt is

connected to the diode and a capacitor C in thecircuit shown so that half wave rectificationoccurs. The final potential difference in voltacross C is :-

~

Diode C

(1) 500 (2) 200

(3) 283 (4) 141

29. The horizontal range and maximum heightattained by a projectile are R and H respectively.If a constant horizontal acceleration a = g/4 isimparted to the projectile due to wind, then itshorizontal range and maximum height will be:-

(1) H

(R H),2

+ (2) H

(R ,2H2

æ ö+ç ÷è ø

(3) (R + 2H), H (4) (R + H), H

30. Three thin rods each of length L and mass M are placedalong x, y and z-axis in such a way that one end of eachof the rods is at the origin. The moment of inertia ofthis system about z-axis is :-

(1) 22

3ML

(2) 24

3ML

(3) 25

3ML

(4) 2

3ML

27. æo ls Hkjs ,d VSad esa fxjrh gqbZ f=T;k r dh ,d /kkrq dhcuh xsan dk ml {k.k ij osx D;k gksxk] tc bldk Roj.keqDr :i ls fxjrh gqbZ fdlh oLrq ds Roj.k dk vk/kk gS\

/kkrq ,oa æo ds ?kuRo Øe'k% r ,oa s gS rFkk æo dh ';kurk

h gSA

(1) 2r g

( 2 )9

r - sh (2)

2r g(2 )

9r- s

h

(3) 2r g

( )9

r - sh (4)

22r g( )

9r- s

h

28. fn[kk;s x;s ifjiFk esa oxZ ek/; ewy eku 200 oksYV okyh

T;koØh; oksYVst ij ,d Mk;ksM vkSj ,d la/kkfj= C tksM+k

x;k gS ftlls v¼Zrjax fnf"Vdj.k gksrk gSA C ij oksYV esa

vfUre foHkokUrj gS :-

~

Diode C

(1) 500 (2) 200

(3) 283 (4) 141

29. fdlh ç{ksI; }kjk çkIr {kSfrt ijkl o vf/kdre Å¡pkbZØe'k% R o H gSaA ;fn gok ç{ksI; dks fu;r Roj.k

a = g/4 çnku djrh gSA rc bldk {kSfrt ijkl o vfèkdre

Å¡pkbZ gksxh :-

(1) H

(R H),2

+ (2) H

(R ,2H2

æ ö+ç ÷è ø

(3) (R + 2H), H (4) (R + H), H

30. L yEckbZ rFkk M æO;eku dh rhu NM+ksa dks x, y rFkk z-v{kds vuqfn'k bl çdkj j[krs gSA fd çR;sd NM + dk ,d fljkewy fcUnq ij gSA z-v{k ds ifjr% bl fudk; dktM+Ro&vk?kw.kZ gS :-

(1) 22

3ML

(2) 24

3ML

(3) 25

3ML

(4) 2

3ML

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31. The r.m.s. value of potential difference V shownin the figure is :-

O

V0

V

T/2 T t

(1) 0V

3(2) V0 (3) 0V

2(4) 0V

2

32. In Young's double slit experiment, the slits are2mm apart and are illuminated by photons of twowavelengths l1 = 12000Å and l2 = 10000Å. Atwhat minimum distance from the common centralbright fringe on the screen 2m from the slit willa bright fringe from one interference patterncoincide with a bright fringe from the other ?(1) 3 mm (2) 8 mm(3) 6 mm (4) 4 mm

33. A heavy small-sized sphere is suspended by astring of length l. The sphere rotates uniformlyin a horizontal circle with the string making anangle q with the vertical. Then, the time periodof this conical pendulum is :-

(1) T 2g

= pl

(2) sin

T 2g

q= p

l

(3) cos

T 2g

q= p

l(4) T 2

gcos= p

ql

34. Moment of inertia of a uniform horizontal cylinderof mass M about an axis passing through its edgeand perpendicular to the axis of the cylinder whenits length is 6 times of its radius R is :-

(1) 239

4MR

(2) 239

2MR

(3) 249

4MR

(4) 249

2MR

35. In an electromagnetic wave the energy densityassociated with magnetic field will be

(1) 21L I

2(2)

2

0

B2m

(3) 20

1B

2m (4) 0

2

12 B

m

31. vkjs[k (fp=) esa fn[kk;s x;s foHkokUrj V dk oxZ ek/; ewy

(vkj-,e-,l-) eku gS :-

O

V0

V

T/2 T t

(1) 0V

3(2) V0 (3) 0V

2(4) 0V

2

32. ;ax ds ,d f}f>jh iz;ksx esa f>fj;ksa (fLyVksa) ds chp dh

nwjh 2mm gSA budks l1 = 12000Å rFkk l2 = 10000Å

rjaxnS/;Z ds QksVkWuksa ls iznhIr (izdkf'kr) fd;k x;k gSA ;fn

f>fj;ksa ls insZ dh nwjh 2m gks rks] dsUnzh; nhIr fÝat ds fdruh

U;wure nwjh ij] O;frdj.k ds mRiUu nksuksa rjaxksa dh nhIr fÝatsa

laikrh (,d nwljs ds Åij) gksaxh ?

(1) 3 mm (2) 8 mm (3) 6 mm (4) 4 mm33. ,d Hkkjh o vkdkj esa NksVs xksys dks l yEckbZ dh Mksjh ls

yVdk;k x;k gSA xksyk ,dleku :i ls {kSfrt o`Ùk esa bl

çdkj ?kwerk gS fd Mksjh Å/okZ/kj ls q dks.k cukrh gSA bl

'kaDokdkj yksyd dk vkorZdky gS :-

(1) T 2g

= pl

(2) sin

T 2g

q= p

l

(3) cos

T 2g

q= p

l(4) T 2

gcos= p

ql

34. M æO;eku ds ,d ,dleku csyu dk tM+Ro&vk?kw.kZ] ,dv{k ds ifjr% tks blds dksj (edge) ls gksdj tkrk gS rFkk

csyu ds v{k ds yEcor~ gS] D;k gS tcfd csyu dh yEckbZ

mldh f=T;k R dh 6 xquh gS\

(1) 239

4MR

(2) 239

2MR

(3) 249

4MR

(4) 249

2MR

35. fo|qr&pqEcdh; rjaxksa e sa ÅtkZ ?kuRo] pqEcdh; {ks= ds lkFk

lEcfU/kr gksxk :–

(1) 21L I

2(2)

2

0

B2m

(3) 20

1B

2m (4) 0

2

12 B

m

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36. For photoelectric emission from certain metal thecutoff frequency is n. If radiation of frequency 2nimpinges on the metal plate, the maximumpossible velocity of the emitted electron will be(m is the electron mass) :-

(1) n2 h / m (2) nh /(2m)

(3) nh /m (4) n2h /m

37. Two blocks, one of mass A = 1 kg and anotherB = 2 kg are shown in figure. A force of 5 N isapplied on A. Coefficient of friction betweenA and B is 0.2 and between B and horizontalsurface is 0.2. Find the time taken for the frontface of A to coincide with front face of B :-

A

B

8m

4m

(1) 2 2 s (2) 8

s3

(3) 3

s8

(4) 2 s

38. A radioactive nucleus ZXA emit 3a–particles and

5b–particles. The ratio of number of neutrons tothat of protons in the product nucleus will be :-

(1) A Z

Z- --

126 (2)

A ZZ--1

(3) A Z

Z- --

116 (4)

A ZZ- --

111

39. Two lenses of focal length + 10 cm and –15 cmwhen put in contact behave like a convex lens.They will have zero longitudinal chromaticaberration if their dispersive powers are in the ratio(1) + 3/2 (2) + 2/3(3) - 3/2 (4) -2/3

40. A photosensitive metallic surface has workfunction, hn0. If photons of energy 2hn0 fall onthis surface, the electrons come out with amaximum velocity of 4 × 106 m/s. When thephoton energy is increased to 5hn0, then maximumvelocity of photo electrons will be:-

(1) 2 × 107 m/s (2) 2 × 106 m/s

(3) 8 × 105 m/s (4) 8 × 106 m/s

36. fdlh /kkrq ls izdk'k fo|qr mRltZu ds fy;s fujks/kh (vard)

vkofÙk n gSA ;fn] bl /kkrq ij 2n vko`fÙk ds fofdj.k

vkifrr gksa rks] mRlftZr bysDVªkWuksa dk vf/kdre laHkkfor

osx gksxk: (m bysDVªkWu dk æO;eku gSA )

(1) n2 h / m (2) nh /(2m)

(3) nh /m (4) n2h /m

37. nks xqVds] ftuesa ,d dk æO;eku A = 1 fdxzk rFkk nwljsdk æO;eku B = 2 fdxzk] fp=kuqlkj j[ks x;s gSaA 5 U;wVudk ,d cy A ij yxk;k x;k gSA A ,oa B ds chp ?k"kZ.kxq.kkad 0.2 rFkk B ,oa {kSfrt i`"B ds chp 0.2 gSA A dslkeus okys i`"B dks B ds lkeus okys i`"B (front face)ls fey tkus esa fdruk le; yxsxk\

A

B

8m

4m

(1) 2 2 s (2) 8

s3

(3) 3

s8

(4) 2 s

38. ZXA jsfM;ks lfØ; ukfHkd 3a o 5b d.kksa dk mRltZu djrk

gSA mRikn ukfHkd esa U;wVªkWu o izksVksu dk vuqikr gksxk :-

(1) A Z

Z- --

126 (2)

A ZZ--1

(3) A Z

Z- --

116 (4)

A ZZ- --

111

39. + 10 cm rFkk –15 cm Qksdl nwjh okys nks mÙky ysalksadks lEidZ esa j[kus ij os mÙky ysal dh Hkk¡fr O;ogkj djrsgSaA mudh vuqnS/;Z o.khZ; foiFku dk eku 'kwU; gksxk] ;fnmuds fo{ksi.k {kerkvksa dk vuqikr gS -(1) + 3/2 (2) + 2/3

(3) - 3/2 (4) -2/3

40. ,d izdk'k lqxzkgh èkkRoh ry dk dk;ZQyu hn0 gSA ;fnbl ry ij 2hn0 ÅtkZ ds QksVksu vkifrr gks rks mRlftZrbysDVªkWuksa dk vfèkdre osx 4 × 106 m/s gksrk gSA tcQksVksu ÅtkZ c<+dj 5hn0 gksxh rks izdk'kh; bysDVªkWuksa dkvfèkdre osx gksxk :-

(1) 2 × 107 m/s (2) 2 × 106 m/s

(3) 8 × 105 m/s (4) 8 × 106 m/s

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41. Which of the following is correctly matched(1) H2O2 .... Basic nature

(2) D2O ...... Hard water

(3) HD ...... An acid

(4) O3 ...... Bleaching agent

42. Which among the following has highest Boilingpoint ?

(1) H2 (2) He (3) Ne (4) Xe

43. Arrange the following in order of their reactivitytowards CH3MgBr?

(I) CCl3 C H

O(II) CH3 C CH3

O(III) CH3 C H

O

(IV) C CH3

O

Ph

(1) I > IV > III > II (2) II > I > III > IV(3) I > II > III >IV (4) I > III > II > IV

44. Potential energy of electron present in He+ is

(1) 2

0

e2 rpe (2)

2

0

3e4 rpe

(3) 2

0

2e4 r-pe (4)

2

20

e4 r

-pe

45. In the 4th pariod of the periodic table, How manyelement have one or more 4 d electrons ?

(1) 2 (2) 18 (3) 0 (4) 6

46. Which one of the following configuration of anatom has the highest ionisation energy

(1) 1s2, 2s2, 2p3 (2) 1s2, 2s2, 2p6, 3s1

(3) 1s2, 2s2, 2p6 (4) 1s2, 2s2, 2p5

47. Arrange the following towards their reactivity forelectrophilic addition reaction (EAR)

(I)

CH CH2

OMe

(II)

CH CH2

CH3

(III)

CH CH2

Cl

(IV)

CH CH2

NO2

(1) I > III > II > IV (2) II > I > III > IV(3) I > II > III > IV (4) II > III > I > IV

41. fuEu esa ls dkSu lgh esy [kk jgs gS(1) H2O2 .... {kkjh; izd`fr

(2) D2O ...... dBksj ty

(3) HD ...... ,d vEy

(4) O3 ...... fojatd dkjd

42. buesa ls fdldk DoFkukad vf/kd gksxk ?

(1) H2 (2) He (3) Ne (4) Xe

43. fuEu dks CH3MgBr ds izfr fØ;k'khyrk ds Øe esaO;ofLFkr dhft;sA

(I) CCl3 C H

O

(II) CH3 C CH3

O

(III) CH3 C H

O

(IV) C CH3

O

Ph

(1) I > IV > III > II (2) II > I > III > IV(3) I > II > III >IV (4) I > III > II > IV

44. He+ esa mifLFkr e– dh fLFkfrt ÅtkZ gksxh

(1) 2

0

e2 rpe (2)

2

0

3e4 rpe

(3) 2

0

2e4 r-pe (4)

2

20

e4 r

-pe

45. vkoZr lkj.kh ds 4th vkoZr ds fdrus rRoksa esa ,d ;kvf/kd 4 d e– jgsxsa ?

(1) 2 (2) 18 (3) 0 (4) 6

46. fdl ijek.kq ds fn;s gq, bysDVªkfud foU;klksa esa vf/kdrevk;uu ÅtkZ iznf'kZr djsxs(1) 1s2, 2s2, 2p3 (2) 1s2, 2s2, 2p6, 3s1

(3) 1s2, 2s2, 2p6 (4) 1s2, 2s2, 2p5

47. fuEu dks bysDVªkWuLusgh ;ksxkRed vfHkfØ;k ds izfrfØ;k'khyrk ds Øe esa O;ofLFkr dhft;sA

(I)

CH CH2

OMe

(II)

CH CH2

CH3

(III)

CH CH2

Cl

(IV)

CH CH2

NO2

(1) I > III > II > IV (2) II > I > III > IV(3) I > II > III > IV (4) II > III > I > IV

ALL INDIA OPEN TEST/Pre-Medical /AIIMS/19-02-2017

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48. A fuel cell involves combustion of the butane at1 atm and 298 K,

( ) ( ) ( ) ( )4 10 2 2 2

13C H g O g 4CO g 5H O

2+ ® + l ,

0G 2746 kJ/molD = -What is Eo of a cell?

(1) +4.74 V (2) + 0.547 V

(3) +1.09 V (4) +4.37 V

49. Which of following will show largest tendeny foranion formation

(1) O (2) F (3) Cl (4) Br

50. In which of the following options, order ofarrangement does not agree with the variation ofproperty indicated against it ?

(1) Al+3 < Mg+2 < Na+ < F– : (Decreasing Zeff)

(2) B < C < O < N : (Increasing IE1)

(3) I < Br < Cl < F : (Increasing electron gain enthalpy)

(4) Li < Na < K < Rb : (Increasing shielding constant)

51. C OO

CH3 E+

¾¾® major product

major product will be

(1) C OO

CH3E

(2) C OO

CH3

E

(3) C OO

CH3

E

(4) C OO

CH3

E

52. pH of a 0.1 M monobasic acid is measured to be 2.Its osmotic pressure at a given temp. T K is

(1) 0.1 RT (2) 0.11 RT

(3) 1.1 RT (4) 0.01 RT

48. ,d bZ/ku lsy esa C;wVsu dk ngu 1 atm nkc vkSj 298 Krki ij fuEu vfHkfØ;k ds vuqlkj gksrk gSa

( ) ( ) ( ) ( )4 10 2 2 2

13C H g O g 4CO g 5H O

2+ ® + l ,

0G 2746 kJ/molD = -lsy ds ekud foHko dk eku gksxk\(1) +4.74 V (2) + 0.547 V

(3) +1.09 V (4) +4.37 V

49. fuEu esa fdl rRo ds fy, ½.kk;u cukus dh izo`fÙkvf/kdre gksxh

(1) O (2) F (3) Cl (4) Br

50. fuEu esa ls dk Sulk fodYi mlds lkeus n'kk Z, x,xq.k/keZ esa ifjorZu ds lkFk O;oLFkk ds Øe ls lger ughgS ?

(1) Al+3 < Mg+2 < Na+ < F– : (?kVrk Zeff)

(2) B < C < O < N : (c<+rk IE1)

(3) I < Br < Cl < F : (c<+rh gqbZ bySDVªkWu xzg.k ,sUFksyih)(4) Li < Na < K < Rb : (c<+rk gqvk ifjj{k.k fu;rkad)

51. C OO

CH3 E+

¾¾® eq[; mRikn] eq[;

mRikn gksxk

(1) C OO

CH3E

(2) C OO

CH3

E

(3) C OO

CH3

E

(4) C OO

CH3

E

52. 0.1 M ,d {kkjdh; vEy dk pH 2 gS vr% fn;s x;s rkiT K ij bldk ijklj.k nkc gksxk(1) 0.1 RT (2) 0.11 RT

(3) 1.1 RT (4) 0.01 RT

Take it Easy and Make it Easy

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53. Arrange the following in order of increasingacidity H3PO4, H2CO3, HCl, HI

(1) H3PO4, HCl, H2CO3, HI

(2) H3PO4, H2CO3, HCl, HI

(3) H2CO3, H3PO4, HCl, HI

(4) None of these

54. Which of the following compounds will give ayellow ppt with iodine and alkali

(1) Acetamide

(2) 3-Hydroxypentane

(3) Acetophenone

(4) Methyl acetate

55. What is relation between following compounds

CH3 CH2 CH CH2 CHO

CN

& CH3 CH CH2 CH2

CN

CHO

(1) positional isomers

(2) chain isomers

(3) optical isomers

(4) metamers

56. The concentration of OH– in the reaction

( ) ( ) 33 aq aqM OH s M 3OH+ -+������

is decreased by 1/2 times then equilibriumconcentration of M3+ will increase by(1) 64 times (2) 4 times(3) 8 times (4) 16 times

57. The element which forms oxides in all oxidationstates +I to +V is

(1) N (2) P (3) As (4) Sb

58. Which of the following reactions will not resultin the formation of carbon-carbon bonds

(1) Friedel Craft's alkylation

(2) Reimer Tieman reaction

(3) Cannizaro reaction

(4) Wurtz reaction

59. Which of the following is not correctly matched

(1) Antacid-Renitidine(2) Sucrose-Reducing sugar(3) Antihistamine-Seldane(4) Lactose-Milk sugar

53. fuEu fn;s H3PO4, H2CO3, HCl, HI dh vEyh;rk dkc<+rk Øe gS

(1) H3PO4, HCl, H2CO3, HI

(2) H3PO4, H2CO3, HCl, HI

(3) H2CO3, H3PO4, HCl, HI

(4) buesa ls dksbZ ugha

54. fuEu esa ls dkSulk vk;ksMhu rFkk {kkj ds lkFk ihyk vo{ksinsrk gS\(1) ,slsV,sekbM(2) 3-gkbMªkWDlhisUVsu(3) ,sflVksfQukWu(4) esfFky ,slhVsV

55. fuEu ;kSfxdksa esa lEcU/k gS\

CH3 CH2 CH CH2 CHO

CN

& CH3 CH CH2 CH2

CN

CHO

(1) fLFkfr leko;oh

(2) J`a[kyk leko;oh

(3) izdkf'kd leko;oh

(4) e/;ko;oh

56. ;fn OH– dh lkanzrk fuEu vfHkfØ;k

( ) ( ) 33 aq aqM OH s M 3OH+ -+������

esa ?kVkdj vk/kk dj nh tkrh gS rks M3+ dk lkE;koLFkk ijlkUnzrk fdruh xquk c<+ tk;sxh(1) 64 xquk (2) 4 xquk(3) 8 xquk (4) 16 xquk

57. rRo tks +I ls +V rd lHkh vkWDlhdj.k voLFkk okysvkWDlkbZM cukrk gS

(1) N (2) P (3) As (4) Sb

58. fuEu esa ls dkSulh vfHkfØ;k esa dkcZu dkcZu cU/k fuekZ.kugha gksrk gS(1) fÝMsy Øk¶V ,fYdyhdj.k(2) jkbej Vheku vfHkfØ;k(3) dSfutkjks vfHkfØ;k(4) oqVZ~t vfHkfØ;k

59. fuEu esa ls dkSu lgh lqesfyr ugha gS

(1) izfrvEy&jsfuVhMhu(2) lqØksl&vipk;h 'kdZjk(3) izfrfgLVkehu&lsYMsu(4) ysDVksl&nqX/k 'kdZjk

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60. Lyophilic sols are more stable than lyophobic solsbecause :(1) The colloidal particles have positive charge(2) The colloidal particles have no charge(3) The colloidal particles are solvated(4) There are strong electrostatic repulsions

between the negatively charged colloidalparticles

61. The acid having O–O bond is

(1) H2S2O3 (2) H2S2O6

(3) H2S2O8 (4) H2S4O6

62. Which of the following is most basic

(1) Diphenylamine

(2) Triphenyl amine

(3) p-Nitroaniline

(4) Benzylamine

63. CH3–CºCH 4

2 4

HgSOdil.H SO

¾¾¾¾® product

Product of the above reaction is

(1) an aldehyde

(2) a ketone

(3) an alcohol

(4) a carboxylic acid

64. A weak acid 0.1M HA is 1% ionised, pH of the

solution will be -

(1) 1 (2) 2 (3) 3 (4) 4

65. In test of NO3– brown ring formed by

(1) [Fe (H2O)5(NO)]+2

(2) FeSO4 NO2

(3) [Fe (H2O)4(NO)2]+2

(4) FeSO4 HNO3

66. Which of the following statement is not correctfor nucleophilic substitution reaction?

(1) correct decreasing order for SN1 reactivity is(CH3)3C–Cl > (CH3)2CHCl > CH3CH2Cl

(2) Stereochemical inversion occurs in SN2reaction

(3) Racemisation occurs in SN1 reaction

(4) Carbocation is formed during SN2 reaction

60. nzofojks/kh lkWy dh rqyuk esa nzoLusgh lkWy vf/kd LFkkbZgksrs gSa D;ksafd&

(1) dksykbMh d.kksa ij /ku vkos'k gksrk gSA

(2) dksykbMh d.kksa ij dksbZ vkos'k ugha gksrk gSA

(3) dksykbMh d.k foyk;dhÏr gksrs gSaA

(4) ½.kkosf'kr dksykbMh d.kksa ds e/; izcy fo|qr LFkSfrd

izfrd"kZ.k gksrs gSaA61. vEy ftlesa O–O ca/k mifLFkr gS

(1) H2S2O3 (2) H2S2O6

(3) H2S2O8 (4) H2S4O6

62. fuEu esa ls dkSulk vf/kdre {kkjh; gksrk gS(1) MkbZ Qsfuy , sekbu(2) VªkbZ Qsfuy , sekbu(3) p-ukbVªks ,suhyhu(4) csfUty ,sekbu

63. CH3–CºCH 4

2 4

HgSOdil. H SO

¾¾¾¾® mRikn

mijksDr vfHkfØ;k dk mRikn gS

(1) ,d ,YMhgkbM

(2) ,d dhVksu

(3) ,d ,YdksgkWy

(4) ,d dkcksZDlhfyd vEy

64. 0.1M HA; ,d nqcZy vEy 1% vk;fur gksrk gS] vr%

bl foy;u dk pH eku gksxk

(1) 1 (2) 2 (3) 3 (4) 4

65. NO3– ds oy; ijh{k.k esa Hkwjs oy; dk cuuk fdl dkj.k gksrk gS

(1) [Fe (H2O)5(NO)]+2

(2) FeSO4 NO2

(3) [Fe (H2O)4(NO)2]+2

(4) FeSO4 HNO3

66. fuEu esa ls ukfHkd Lusgh izfrLFkkiu vfHkfØ;k ds fy; s dkSulkdFku lR; ugha gS\

(1) SN1 vfHkfØ;k'khyrk dk ?kVrk gqvk Øe(CH3)3C–Cl > (CH3)2CHCl > CH3CH2Cl gS

(2) SN2 vfHkfØ;k esa f=foe jklk;fud izrhiu gksrk gS

(3) SN1 vfHkfØ;k esa jsflehdj.k gksrk gS

(4) SN2 vfHkfØ;k esa dkcZ/kuk;u curk gS

fdlh iz'u ij nsj rd :dks ugha A

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67. NH2

O

( )2Br KOH aq+¾¾¾¾¾® X 3CHCl KOH+D¾¾¾¾¾® Y;

Y is

(1)

CH2 CN

(2)

CH2 NC

(3)

NC

(4)

NC

Br

68. Which of the following will have highest freezingpoint of solution(1) 0.5 M NaCl(2) 0.5 M K4[Fe(CN)6](3) 0.5 M Fe4 [Fe(CN)6]3

(4) 0.5 M glucose solution69. The Bond having the min Bond energy is

(1) C–C (2) O–O (3) S–S (4) P–P

70. Which of the following group has maximum hyperconjugation effect but minimum inductive effect

(1) –CH3 (2) –CH2–CH3

(3) –CD3 (4) CCH3

CH3

CH3

71. If a is the edge length of the unit cell ofmonoatomic crystal having ccp arrangement thenwhat will be distance of closest approach betweentwo atoms in the crystal ?

(1) 2 a (2) a2

(3) 2

a(4)

a 22

67. NH2

O

( )2Br KOH aq+¾¾¾¾¾® X 3CHCl KOH+D¾¾¾¾¾® Y;

Y gS

(1)

CH2 CN

(2)

CH2 NC

(3)

NC

(4)

NC

Br

68. fuEu esa ls fdl foy;u dk fgekad vf/kdre gksxk\(1) 0.5 M NaCl

(2) 0.5 M K4[Fe(CN)6]

(3) 0.5 M Fe4 [Fe(CN)6]3

(4) 0.5 M glucose solution

69. blesa ls fdlesa ca/k ÅtkZ de gksxh

(1) C–C (2) O–O (3) S–S (4) P–P

70. fuEu esa ls dkSuls lewg dk vf/kdre vfrla;qXeu ysfduU;wure izsjf.kd izHkko gS(1) –CH3 (2) –CH2–CH3

(3) –CD3 (4) CCH3

CH3

CH3

71. ,d ijek.k qd fØLVy tks ccp lajpuk es a gS ds ,dddksf'kdk dh yEckbZ a gS rks fØLVy ds nks ijek.kqvksa ds eè;

lehiLFk nwjh D;k gksxh ?

(1) 2 a (2) a2

(3) 2

a(4)

a 22

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72. 20 mL of 0.1 M KMnO4 solution will oxidised .....

in acidic medium(1) 120 mL of 0.25 M H

2C

2O

4

(2) 150 mL of 0.10 M H2C

2O

4

(3) 25 mL of 0.20 M H2C

2O

4

(4) 50 mL of 0.20 M H2C

2O

4

73. The material mixed before the calcnide ore issubjected for smelting in the extraction of iron are

(1) Coke and silica

(2) Coke & limestone

(3) limestone & silica

(4) Coke, limestone and silica

74. What is the correct order of decreasing stabilityof the following cations

CH3 CH CH3

Å

(I) CH3 CH OMe

Å

(II)

CH3 CH CH2 OMeÅ

(III)

(1) II > I > III (2) II > III > I(3) III > I > II (4) I > II > III

75. Rate of formation of SO3 in the following reactionis 100 g min–1 then find rate of disapperance of O2

2SO2 + O2 ¾® 2SO3

(1) 50 g min–1

(2) 40 g min–1

(3) 200 g min–1

(4) 20 g min–1

76. Calculate volume of H2 gas kept at STP if itcontains as many H atoms as in 98 gm H3PO4.[Atomic mass of P = 31](1) 68.1 litre (2) 33.6 litre(3) 89.6 litre (4) 44.8 litre

77. Which of the following compound is formed byaddition of minral acid to an aqueous solutionof borax ?

(1) Boron oxide

(2) Orthoboric acid

(3) Metaboric acid

(4) Pyroboric acid

72. vEyh; ek/;e esa 20 mL 0.1 M KMnO4 foy;u.....

dks iw.kZ :i ls vkWDlhd`r djsxk(1) 120 mL, 0.25 M H

2C

2O

4 foy;u

(2) 150 mL, 0.10 M H2C

2O

4 foy;u

(3) 25 mL, 0.20 M H2C

2O

4 foy;u

(4) 50 mL, 0.20 M H2C

2O

4

73. iron ds fu"kd"kZ.k esa fuLrkfir v;Ld ds izxyu ls igysfeyk;k tkus okyk inkFkZ dk feJ.k gS

(1) dksd o flfydk

(2) dksd o ykbeLVksu

(3) ykbeLVksu o flfydk

(4) dksdk, ykbeLVksu o flfydk

74. fuEu /kuk;uksa ds fy;s LFkkf;Ro dk lgh ?kVrk Øe D;kgksxk

CH3 CH CH3

Å

(I)CH3 CH OMe

Å

(II)

CH3 CH CH2 OMeÅ

(III)

(1) II > I > III (2) II > III > I(3) III > I > II (4) I > II > III

75. fuEu vfHkfØ;k esa SO3 ds fuekZ.k dh nj 100 g min–1 gS 2SO2 + O2 ¾® 2SO3

vr% O2 ds [kpZ gksus dh nj gksxh :-

(1) 50 g min–1

(2) 40 g min–1

(3) 200 g min–1

(4) 20 g min–1

76. STP ij izkIr H2 xSl ds vk;ru dh x.kuk dhft, ;fnblesa mrus gh H ijek.kq mifLFkr gks ftrus 98 gm H3PO4

esa gS [P dk ijek.kq nzO;eku = 31](1) 68.1 litre (2) 33.6 litre(3) 89.6 litre (4) 44.8 litre

77. ;fn cksjsDl ds tyh; foy;u esa [kfut vEy feyk;k tk,rks izkIr mRikn fuEu esa ls gksxk?

(1) cksjku vkWDlkbM

(2) vkFkksZcksfjd vEy

(3) esVkcksfjd vEy

(4) ik;jkscksfjd vEy

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78. Phenol and carboxylic acid can be distinguishedby(1) Na(2) NaHCO3

(3) Litmus test(4) all of these

79. On the basis of information given below mark the

correct option

Information : On adding acetone to methanol

some of the hydrogen bonds between methanol

molecules break.

(1) At specific composition methanol- acetone

mixture will form minimum boiling azetrope

and will show positive deviation from Raoult's

law

(2) At specific composition methanol-acetone

mixture forms maximum boiling azeotrope

and will show positive deviation from Raoult's

law.

(3) At specific composition methanol-acetone

mixture will form minimum boiling azeotrope

and will show negative deviation from

Raoult's law

(4) At specific composition methanol-acetone

mixture will form maximum boiling

azeotrope and will show negative deviation

from Raoult's law.

80. If average molecular wt. of air is 29, thenassuming N2 and O2 gases are there which optionsare correct regarding composition of air

(i) 75% by mass of N2

(ii) 75% by moles N2

(iii) 72.41% by mass of N2

(1) only (i) is correct

(2) only (ii) is correct

(3) both (ii) and (iii) are correct

(4) both (i) and (ii) are correct

78. fQukWy rFkk dkcksZfDlfyd vEy dks fdlds }kjk foHksfnrfd;k tk ldrk gS(1) Na(2) NaHCO3

(3) fyVel ijh{k.k(4) mijksDr lHkh

79. fuEufyf[kr lwpuk ds vk/kkj ij lgh fodYi dk p;u

dhft,

lwpuk : esFksukWy esa ,slhVksu feykus ij esFksukWy v.kqvksa ds

e/; mifLFkr dqN gkbMªkstu vkca/k VwV tkrs gSaA

(1) ,d fof'k"V la?kVu esa esFksukWy&,slhVksu feJ.k U;wure

DoFkukadh fLFkjDokFkh cuk,xk vkSj jkmYV ds fu;e

ls /kukRed fopyu n'kkZ,xkA

(2) ,d fof'k"V la?kVu esa esFksukWy&,slhVksu feJ.k vfèkdre

DoFkukadh fLFkjDokFkh cuk,xk vkSj jkmYV ds fu;e

ls /kukRed fopyu n'kkZ,xkA

(3) ,d fof'k"V la?kVu esa esFksukWy& ,slhVksu feJ.k U;wure

DoFkukadh fLFkjDokFkh cuk,xk vkSj jkmYV ds fu;e

ls ½.kkRed fopyu n'kkZ,xkA

(4) ,d fof'k"V la?kVu esa esFksukWy&,slhVksu feJ.k vfèkdre

DoFkukadh fLFkjDokFkh cuk,xk vkSj jkmYV ds fu;e

ls ½.kkRed fopyu n'kkZ,xk

80. ekuk ok;q dk vkSlr vkf.od æO;eku 29, gS rks ;g ekursgq, fd ok;q esa dsoy N2 rFkk O2 mifLFkr gS] ok;q ds la?kVuds lUnHkZ esa lgh dFku dkSu&lk gS ?

(i) 75% N2 (æO;ekukuqlkj)

(ii) 75% N2 (eksy ds inksa esa)

(iii) 72.41% N2 (æO;ekukuqlkj)

(1) dsoy (i) lgh gSA

(2) dsoy (ii) lgh gSA

(3) nksuksa (ii) rFkk (iii) lgh gSA

(4) nksuksa (i) rFkk (ii) lgh gSA

LoLFk jgks] eLr jgks rFkk i<+kbZ esa O;Lr jgks A

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81. Refer the given statement :-(i) Outer exine is made up of sporopollenin(ii) Inner intine is pecto-cellulosic in nature(iii) Generative cell is bigger and contains

abundant food reserve(iv)Vegetative cell is small and floats in the

cytoplasm of the generative cellWhich of the given statements are not trueregarding structure of pollen grain ?(1) (i) and (ii) (2) (ii) and (iii)(3) (iii) and (iv) (4) (i) and (iv)

82. Plant factor affecting photosynthesis is :-

(1) Sunlight

(2) Temperature

(3) Internal CO2 concentration

(4) Water

83. The observations about the number of whitewinged and dark winged moths in England duringdifferent environmental conditions shows that :-

(1) Predators can't spot a moth against contrastingbackground

(2) No variant is completely wiped out

(3) The areas where industrialization did notoccur, the count of melanic moths was high

(4) Moths that were able to camouflage themselves,didn't survive

84. Which of the following group of animals areammonotelic in nature ?(1) Many bony fishes, amphibians, Insects.(2) Marine Fishes, amphibians, aquatic insects(3) Mammals, birds, Reptiles(4) Many bony fishes, aquatic amphibians, aquatic

insects.85. How many pollen mother cells should undergo

meiotic division to produce 64 pollen grains ?(1) 64 (2) 32 (3) 16 (4) 8

86. The aerobic respiration of one sucrose moleculeyeilds :-

(1) 8, NADH2, 2 FADH2, 2 ATP

(2) 10 NADH2, 2 FADH2, 38 ATP

(3) 12 NADH2, 30 ATP, H2O

(4) 20 NADH2, 4 FADH2, 4 GTP, 4 ATP

81. fn;s x, dFkuksa dks nsf[k, %&(i) ckápksy Liksjksiksysfuu dk cuk gksrk gSA(ii) vUr%pksy izÏfr esa isDVks&lsY;wyksfld gksrk gSA(iii) tuu dksf'kdk cM+h vkSj cgqrk;r esa lafpr Hkkstu j[krh

gSA(iv)dkf;d dksf'kdk NksVh gksrh gS vkSj tuu dksf'kdk ds

dksf'kdknzO; esa Iyou djrh gSAfuEu dFkuksa esa ls dkSulk dFku ijkx.k dh lajpuk ds fo"k;esa lgh ugha gS\(1) (i) o (ii) (2) (ii) o (iii)(3) (iii) o (iv) (4) (i) o (iv)

82. çdk'k l'ys"k.k dh çHkkfor djus okyk ikni dkjd gS :-(1) lw;Z dk çdk'k(2) rkieku(3) vkUrfjd CO2 lkæark(4) ty

83. baXyS.M esa fofHkUu okrkoj.kh; ifjfLFkfr;ksa esa 'osr ia[khrFkk v'osr ia[kh 'kyHkksa dh la[;k ds lanHkZ esa fy, x,izs{k.k n'kkZrs gSa fd :-

(1) foi;kZlh i`"BHkwfe esa f'kdkjh 'kyHk dks vklkuh ls ughaigpku ikrk gS

(2) fdlh Hkh :i dk iw.kZ fouk'k ugha gksrk gS

(3) ,sls bykds tgk¡ vkSn~;ksfxdhdj.k ugha gqvk ogk¡ v'osria[kh 'kyHkksa dh la[;k T;knk gksrh gS

(4) ,sls 'kyHk tks Nn~ekoj.k djus esa l{ke Fks] oks thforugha jg ik,

84. tarqvksa dk dkSulk lewg veksfu;k mRlxhZ izÏfr dk gksrk

gS\

(1) dbZ vfLFky eNfy;ka] mHk;pj dhV

(2) vfLFky eNfy;ka] mHk;pj] tyh; dhV

(3) Lru/kkjh] i{kh] ljhl`i

(4) dbZ vfLFky eNfy;ka] tyh; mHk;pj] tyh; dhV

85. 64 ijkxd.kksa dks mRiUu djus ds fy;s fdruh ijkx ekrdksf'kdkvksa esa v¼Zlw=h foHkktu gksxk \(1) 64 (2) 32 (3) 16 (4) 8

86. ,d lqØkst v.kq dk 'olu esa mi;ksx ij çkIr gksrk gS :-

(1) 8, NADH2, 2 FADH2, 2 ATP

(2) 10 NADH2, 2 FADH2, 38 ATP

(3) 12 NADH2, 30 ATP, H2O

(4) 20 NADH2, 4 FADH2, 4 GTP, 4 ATP

J ges'kk eqLdjkrs jgsa A

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87. The anormous amount of data expected to begenerated also necessitated the use of high speedcomputational devices for data storage and retrieval,and analysis. HGP was closely associated with therapid development of new area in biology called :

(1) Genetic engineering

(2) Computer science

(3) Information technology

(4) Bio informatics88. The state of heart when it not pumping blood effective

enough to meet the needs of the body is called

(1) CAD (2) Atherosclerosis

(3) Angina (4) Heart failure

89. Read the following statements :-(I) The presence of vessels is a characteristics

feature of angiosperms.(II) In stems, protoxylem lies toward periphery

and metaxylem lies towards the centre.(III) Parenchyma forms the major components

within organs.(IV) Vessel have obliterated central lumen.How many statements are wrong ?(1) Three (2) Four(3) One (4) Two

90. Which intermediate compound is involved in thesynthesis of amino acids :-

(1) Malic acid (2) Citric acid

(3) a-ketoglutaric acid (4) Isocitric acid

91. If E. Coli was allowed to grow for 80 minutes thenwhat would be proportions of light and hybriddensities DNA molecules ?

(1) 1 : 1 (2) 3 : 1

(3) 7 : 1 (4) 1 : 3

92. The condition which is favourable for dissociationof oxyhaemoglobin is :-(1) High PO2 (2) Low PCO2

(3) High H+ conc. (4) Low temp

93. The inner most layer of bark is :-(1) Secondary cortex (2) Primary phloem(3) Secondary phloem (4) Phellem

94. Which of the following PGR is used to break seedand bud dormancy ?

(1) Auxins (2) Verneline

(3) Cytokinine (4) Ethylene

87. cMh la[;k esa vkadM+ks dh izkfIr dds fy, mPp xfrdh;lax.kd lk/ku dh vko';drk gksrh gSa] ftlls vk¡dM+ks dslaxzg] fo'ys"k.k o iqu% mi;ksx esa lgk;rk feyrh gSA ,pthihds ckjs esa tkudkjh tho foKku ds bl rsth ls foLrkj lslaHko gks ik;k ftls dgrs gS &

(1) vkuqokaf'kd vfHk;kaf=dh(2) dEI;wVj lkabl(3) lwpuk rduhdh

(4) tSo lwpuk foKku

88. og voLFkk ftles a ân; 'kjhj ds fofHkUu Hkkxk s a dks

vko'drkuqlkj i;kZIr vkiw£r ugh dj ikrk gS] dgykrh gSA

(1) lh-,-Mh- (CAD) (2) ,fFkjksdkfBa;

(3) ân'kwy (4) ân ikr (ân; foQyrk)89. fuEu dFkuksa dks if<+, :-

(I) okfgdk dk gk suk , a ft;ksLieZ dk ,d izeq[k xq.kgSA

(II) rus esa izksVkstkbye ifjf/k dh vksj esVktkbye dsUnz dhvksj gksrs gSaA

(III) isjsadkbZek vaxksa ds vUnj ds eq[; ?kVd gSA(IV) okfgdk dh dsUnzh; xqgk foyqIr gksrh gSAfdrus dFku xyr gS ?

(1) rhu (2) pkj(3) ,d (4) nks

90. fuEu esa ls dkSu lk e/;orhZ ;kSfxd vehuks vEy ds la'ys"k.kesa Hkkx ysrk gS :-(1) eSfyd vEy (2) flVªhd vEy(3) a-fdVksXywVsfjd vEy (4) vkblksflVªhd vEy

91. bZ-dksykbZ ds 80 feuV ckn o`f¼ ls izkIr Mh,u, esa gYds

o ladfjr ?kuRo dk vuqikr gksxk &

(1) 1 : 1 (2) 3 : 1

(3) 7 : 1 (4) 1 : 3

92. fLFkfr tks vkWDlhgheksXyksfcu ls O2 ds fo;kstu ds fy,vuqdwy gksrh gSA(1) mPp PO2 (2) fuEu PCO2

(3) mPp H+ lkUnzrk (4) fuEu rkieku93. Nky dh lcls vkarfjd ijr gS :-

(1) f}rh;d oYdqV (2) izkFkfed iks"kokg(3) f}rh;d iks"kokg (4) Qsye

94. fuEu es ls dkSu lk PGR cht o tfydk çlqfIr dks rksMrkgS\(1) vkWfDtu (2) ousZfyu

(3) lk;Vksdk;fuu (4) bFkkbfyu

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95. Which one of the following statment is wrong ?

(1) Sucrose is a disaccheride

(2) Cellulose is a polysaccharide

(3) Uracil is a pyrimidine

(4) Glycine is a sulphur containing amino acid

96. Which of the following is not a breed ofBos indicus ?(1) Holstein – Friesian(2) Brown swiss(3) Bhadawari(4) Ayrshire

97. According to genic balance theory, what wouldbe the sex of Drosophila having XX + 2A andXY + 3A. Karyotype resepctively :-(1) Normal female and super male(2) Super male and normal female(3) Intersex and super female(4) Metafemale and super male

98. In prokaryotes, the regulation of gene expressioncould be occurs at :

(1) Transcription initiation

(2) RNA processing

(3) Transport of m-RNA form nucleus to thecytoplasm

(4) Translation initiation99. E + S ® ES ® X ® E + P

In above reaction 'X' is represented by :

(1) Enzyme

(2) Product

(3) Enzyme-product complex

(4) Enzyme substrate complex

100. Net primary productivity (NPP) is equal to :-

(1) GPP–loss in reproduction

(2) GPP–loss in respiration

(3) Secondary productivity–GPP

(4) GPP–HR (Heterotrophic Respiration)

101. The distillation process is not required in theformation of :-

(1) Rum and Beer

(2) Brandy and Whisky

(3) Brandy and Wine

(4) Wine and Beer

95. fuEu esa ls dkSulk dFku xyr gS &

(1) lqØksl MkbZlSdsjkbM + gSA

(2) lsyqyksl ikWyhlSdsjkbM+ gSA

(3) ;wjsfly ikbfjfefMu gSA

(4) Xykbflu lYQj ; qDr vehuks vEy gSA96. fuEu esa ls dkSulh uLy xk; dh ugha gS &

(1) gksyLVhu– fÝf'k;u

(2) czkmu fLol

(3) Hknkojh

(4) vk;jfFkj

97. Genic balance theory ds vuqlkj Drosophila dk fyaxD;k gksxk ftldk dSfj;ksVkbi Øe'k% XX + 2A vkSjXY + 3A gS :-(1) Normal female vkSj super male(2) Super male vkSj normal female(3) Intersex vkSj super female(4) Metafemale vkSj super male

98. izksdsj;ksV~l esa thu vfHkO;fDr dk fu;eu fdl Lrj ijgks ldrk gS &

(1) vuqys[ku izkjEHku

(2) RNA vkPNknu

(3) m-RNA dk dsUnzd ls dksf'kdk izo.k esa vfHkxeu

(4) vuqoknu izkjaHku

99. E + S ® ES ® X ® E + P

Åij nh xbZ vfHkfØ;k esa 'X' dks fu:fir fd;k tkrk gS&

(1) ,atkbe

(2) mRikn

(3) ,atkbe&mRikn dkWEIysDl

(4) ,atkbe&lClVªsV dkWEIysDl100. izkFkfed mRikndrk (NPP) fdlds cjkcj gS :-

(1) GPP–iztuu gqbZ gkfu

(2) GPP–'olu esa gqbZ gkfu

(3) f}rh; mRikndrk–GPP

(4) GPP–HR (fo"keiks"kh 'olu)

101. vklou izfØ;k dh t:jr fdlls fuekZ.k esa ugh gksrhgS :-

(1) je vkSj fc;j

(2) czkaMh vkSj fOgLdh

(3) czkaMh vkSj okbu

(4) okbu vkSj fc;j

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102. Identify the correct match from the columns andfind out correct answer :

Column-I Column-II Column-III

(A) Leydig cell (a)extraembryonicmesoderm

(i) A.B.P.

(B) Primordialgerm cell (b) Interstitial

space (ii)Uptopuberty nodevelopment

(C) Spermatogonia (c) Germ cellof testis (iii)

Duringembryoniclife

(D) Sertoli cell (d) Nurse cellof testis (iv) Testosterone

(1) A-b-iv, B-a-iii, C-c-ii, D-d-i

(2) A-d-iv, B-a-iii, C-b-ii, D-c-i

(3) A-b-i, B-c-ii, C-d-iii, D-a-iv

(4) A-b-iv, B-c-ii, C-a-i, D-d-iii103. Identify the given cell organelles with their

respective function

Options :-

Cell Organelles Functions

(1) Golgi body Sife for synthesis ofsteroid hormone

(2) SER Sife for synthesis of lipid

(3) Golgi apparatus Site for formation ofglycoprotein

(4) Peroxisome Involved inphotorespiration

104. In succession climax community in warm tropicalregion is represented by :-

(1) Conifer forest (2) Evergreen forest

(3) Thorn forest (4) Alpine grasses

102. fuEu fn;s x;s dkWye esa ls lgh feyku igpkfu;s ,oa lghmÙkj dk p;u dhft;s &

dkWye-I dkWye-II dkWye-III

(A)ySfMxdksf'kdk (a)

vfrfjDrHkwz.kh;ehtksMeZ

(i) A.B.P.

(B)vkfn tuudksf'kdk (b) varjkyh LFky (ii)

I;qcfVZ rd dksbZfodkl ugha

(C) 'kqØk.kqtu (c)o"k.k dh tuudksf'kdk (iii)

Hkwz.kkoLFkk dsnkSjku

(D)lVksZyhdksf'kdk (d)

o"k.k dh ulZdksf'kdk (iv) VsLVksLVhjkWu

(1) A-b-iv, B-a-iii, C-c-ii, D-d-i

(2) A-d-iv, B-a-iii, C-b-ii, D-c-i

(3) A-b-i, B-c-ii, C-d-iii, D-a-iv

(4) A-b-iv, B-c-ii, C-a-i, D-d-iii

103. uhps fn, x, dksf'kdkax dks mlds dk;Z ds lkFk igpkfu,A

fodYi :-

dksf'kdkax dk;Z

(1) xkWYthdk; LVhjk;My gkeksZu ds fuekZ.k dkizeq[k LFky

(2) SER fyfiM fuekZ.k dk eq[; LFky

(3) xkWYthdk; XykbdksizksVhu ds fuekZ.k dkLFky

(4) ijvkWDlhlkse izdk'k 'olu esa lfEefyr

104. m".kdfVca/kh; {ks= esa vuqØe.k esa pje leqnk; iznf'kZrgksrk gS :-

(1) 'kadq/kkjh ou ls (2) gjsHksj ou ls(3) dkaVs okys ou ls (4) vYikbu ?kkl ls

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105. ikni iztuu dk mi;ksx ,slh fdLeks dks fodflr djus esfd;k tkrk gS tks fd :-

(1) jksxk.kq ds fy, izfrjks/kh gks

(2) blls [kk| dk mRiknu c<+k gS

(3) bl fof/k dk mi;ksx ikni [kk|ks ds izksVhu va'kks rFkk[kk| dh xq.koÙkk c<+kus es fd;k tkrk gSA

(4) mijksDr lHkh

106. Luk;q ds ckjs esa fuEu esa ls fdrus dFku lgh gS\

(A) Luk;q esa tkfydk rarq vuqifLFkr gksrs gS

(B) ihr rarq ek=k esa T;knk feyrs gS fdUrq dkWystu rarq de

ek=k esa feyrs gS

(C) esfVªDl vfu;fer de esa O;ofLFkr gksrk gS

(D) Luk;q vfLFk ls vfLFk dks tksM+rk gS

(1) ,d (2) rhu

(3) pkj (4) nks107. iwokZoLFkk (izksQst) dh igpku fdlls gksrh gS :-

(1) lsUVªkseh;j dk iw.kZ:i ls fo?kVu(2) xq.klw=h; inkFkksZ ds la?kuu dk izkjEHku(3) dsUæd dk iquZfuekZ.k(4) xq.klw=ksa dk e/;koLFkk ifV~Vk dk dh vksj tkuk

108. fuEu esa ls dkSulk dFku vlR; gS ?

(1) 'PMNL' dksf'kdh; jks/k esa lfEefyr gksrs gSaA

(2) baVjQsjkWu lafØfer dksf'kdkvksa dks vkSj vkxs fo"kk.kq

laØe.k ls cpkrk gSA

(3) bUusV bE;qfuVh ,d izdkj dh vfof'k"V izfrj{kk gSA

(4) baVjQsjkWu lkbVksdkbu jks/k esa lfEefyr gksrs gSaA

109. dkSulk dFku vlR; gS\

(1) ekbdksIykTek ,sls tho/kkjh gS tks fd iw.kZr;k dksf'kdkfHkfÙk jfgr gksrs gS

(2) ekbdksIykTek vkWDlhtu ds fcuk thfor jg ldrs gS

(3) ekbdksIykTek lw{ere thfor dksf'kdk,a gS

(4) ekbdksIykTek isfuflfyu ds izfr laosnu'khy gksrs gS

110. fpduh isf'k;ka ____A____ gksrh gSA muds dk;k± s dks____B____ fu;af=r ugha fd;k tk ldrkA

A ,oa B Øe'k% gSA

(1) A ® vuSfPNd] B ® vizR;{k :i ls

(2) A ® vuSfPNd] B ® izR;{k :i ls

(3) A ® ,sfPNd] B ® vizR;{k :i ls

(4) A ® ,sfPNd] B ® izr;{k :i ls

105. Plant breeding may be used to create varietieswhich are :-(1) Resistance to pathogen(2) This increases the yield of the food(3) This method has also been used to increase

the protein content of plant food and these byenhance the quality of food.

(4) All of these

106. How many statements are correct about ligamentfrom followings.

(A) Reticular fibre are absent in ligament

(B) Yellow fibre are more in quantity but collagenfibre are less in quantity

(C) Matrix distributed in a irregular pattern

(D) Ligament connects bone to bone

(1) One (2) Three

(3) Four (4) Two

107. Prophase is marked by the :-

(1) Complete disintegration of centromere

(2) Initiation of condensation of chromosomal material

(3) Reformation of nucleus

(4) Align of the chromosome at equatorial plate

108. Which of the following statement is false?

(1) 'PMNL' are included in cellular barrier.

(2) Interferons protect infected cells from further

viral infection.

(3) Innate immunity is non specific type of

defence.

(4) Interferons are included in cytokine barrier.109. Which is incorrect statement ?

(1) The mycoplasma are organism that completelylack a cell wall

(2) Mycoplasma can survive without oxygen

(3) Mycoplasma are the smallest living cells

(4) Mycoplasma are sensitive to penicillin

110. Smooth muscle are ____A____ as theirfunctioning can not be ____B____ controlled.

A & B is respectively ?

(1) A ® Involuntary, B ® Indirect

(2) A ® Involuntary, B ® Directly

(3) A ® Voluntary, B ® Indirect(4) A ® Voluntary, B ® Direct

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111. O;kid :i esa Lohd`r dksf'kdk f>Yyh ds rjy ekstdekWMy ds vuqlkj fuEu esa ls dkSulk dFku lgh gS :-

(1) fyfiM ds v/kZrjyh; izd`fr ds dkj.k f}lrg ds HkhrjizksVhu ikf'oZd xfr djrk gSA

(2) f>Yyh dh rjyh; izd`fr vUrjdksf'kdh; la;kstd dsfuekZ.k ds fy, vko';d ugha gSA

(3) vaxHkwr çksVhu f>Yyh dh lrg ij gksrh gS tcfd

ifj/kh; izksVhu f>Yyh esa /kals gksrs gSA

(4) lHkh ;wdSfj;ksfVd dksf'kdkvksa esa 52 izfr'kr izksVhu rFkk40 izfr'kr fyfiM feyrk gSA

112. fuEu esa ls dkSulk dFku ekuo tuu ds ckjs esa lgh gS ?

(1) ‘lgsyh’ uj ds fy, u;k xHkZfujks/kd gSA

(2) ukfHk jTtq ls izkIr dksf'kdk ds }kjk] xq.klw=h; izk:i

le>us ds fy, ,fEu;kslsUVksfll fd;k tkrk gSA

(3) v.MksUlxZ] Lruiku ls lqlk/; gks tkrk gSA

(4) izk stsLVhjkWu ,ao ,LVªkstu ds lfEeJ.k izHkkoh xHkZ

fujksèkd ds :i esa Ropk ds uhps lqbZ ds }kjk vFkokizR;kjksfir dj fn;k tkrk gSA

113. fuEu esa ls fdl vk/kkj dks fogsdj us ik¡p txr oxhZdj.k

esa lfEefyr ugha fd;k\

(1) tuu

(2) tkfro`Ùkh; lEca/k

(3) iks"k.k dk izdkj

(4) mikip;

114. dkSulk fodYi xyr gS ?

gkeksZu izHkko

(1) bUlqfyu ® gkbiksXykblsfe;k

(2) Xywdsxksu ® Xykbdkstsuksykbfll

(3) dkfVZlksy ® Xywdksfu;kstsusfll

(4) ,Mªhuyhu ® Xykbdksykbfll

115. dksf'kdk pØ dh ml izkoLFkk dks fpfUgr dhft;s ftlesaxq.klw=fcUnq fo[kf.Mr gks tkrs gS rFkk v/kZxq.klw= foijhr/kqzoksa dh vksj xfr djrs gS :-(1) ,ukQst - II(2) esVkQst - II(3) VhyksQst - I(4) ,ukQst - I

111. Keeping in view the fluid mosaic model for thestructure of cell membrane. Which one of thefollowing statement is correct :-

(1) The quasifluid nature of lipid enables lateralmovement of proteins within overall bilayer

(2) The fluid nature of the membrane is notimportant for formation of intercellular junction

(3) Integral proteins lie on the surface ofmembrane while the peripheral proteins areburied in the membrane

(4) All eukaryotic cell membrane have 52 percentprotein and 40 percent lipid

112. Which of the following is correct about humanReproduction ?

(1) ‘Saheli’ is a new contraceptive for males

(2) Amniocentosis is carried out to know thechromosomal pattern from the sample takenfrom the cells of umbilical cord.

(3) Ovulation is facilitated by breast-feeding

(4) A combination of progesterone and oestrogenis injected or implanted under the skin as aneffective contraceptive

113. Which among the following was not the criteriafor classification of organism in to 5 kingdomproposed by whittaker ?

(1) Reproduction

(2) Phylogenetic relationship

(3) Mode of nutrition

(4) Metabolism

114. Which option is incorrect ?

Hormone Effect

(1) Insulin ® Hypoglycemia

(2) Glycogen ® Glycogenolysis

(3) Cortisol ® Gluconeogenesis

(4) Adrenalin ® Glycolysis

115. Mark the stage of cell cycle in which centromeressplit and chromatids move to opposite poles :-

(1) Anaphase - II

(2) Metaphase - II

(3) Telophase - I

(4) Anaphase - I

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116. Study the given figure of reproductive system ofmale cockroach. In which of the following part(A,B,C and D) sperms are stored :-

A

B

CD

(1) A (2) B(3) C (4) D

117. PEPcase enzyme found in :-(1) Cytoplasm of bundle sheath in C4 plants(2) Cytoplasm of guard cell of stomata in C3 plant(3) Chloroplast of mesophyll cell of C4 plant(4) Chloroplast of mesophyll cell of C3 plants

118. Identify the character which do not belong toclasschondrichthyes:-

(1) Air bladder is absent

(2) They are poikilothermous

(3) Teeth are modified placoid scales

(4) Gills are covered by an operculum119. A doctor advises a patient to include yellow fruits

carrots and butter in his diet. What deficiencydisease do you think the patient is suffering from.

(1) Colour blindness

(2) Scurvy disease

(3) Night blindness

(4) Marasmus disease

120. Select the correct statements about MOET?

(a) MOET is programme for herd size increase

(b) In this method fish is administered hormoneswith FSH like activity.

(c) Fertilised eggs at 8-32 cells are recoveredsurgically and transfered in surrogatemothers.

(d) The genetic mother is available for anotherround of super ovulation.

(1) a, b, c(2) b, c, d(3) a, d only(4) a,b,c,d all are correct

116. dkWdjksp ds uj tuu ra= dks v/;;u dfj;s buesa lsdkSulk Hkkx (A,B,C rFkk D) 'kqØk.kqvksa dk laxzg djrk gS :-

A

B

CD

(1) A (2) B

(3) C (4) D

117. PEPcase ,Utkbe feyrk gS :-(1) C4 ikniksa dh iwykPNn dksf'kdkvksa ds dksf'kdk æO; esa(2) C3 ikniksa dh }kj dksf'kdkvksa dh dksf'kdk æO; esa(3) C4 ikniksa dh i.kZ&e/;ksrd dksf'kdkvksa ds gfjr yod esa(4) C3 ikniksa dh i.kZ&e/;ksrd dksf'kdkvksa ds gfjr yod esa

118. dkf.MªDFkht oxZ ls lca/k ugh j[kus okyk y{k.k gS:-

(1) okrk'; vuqifLFkr

(2) ;s vlerkih gksrs gSA

(3) nkWr #ikUrfjr IysdkWbM Ldsy gksrs gSA

(4) fXkYl ls <ds gksrs gSA

119. ,d fpfdRld ,d jksxh ds vkgkj esa ihys Qy xktj vkSjeD[ku 'kkfey djrk gSA rks vki D;k lksprs gks jksxh dkSulsvYirk jksx ls xzflr gSA(1) o.kkZU/krk(2) LØoh(3) [kkS/kh jrkSa/kh(4) esjkLel

120. MOET ds lEcU/k esa lgh dFku dk p;u djsa ?

(a) MOET dk;ZØe ls > q.M ds vkdkj esa o`f¼ gksrh gSA(b) bl fof/k esa eNyh dks FSH ds dk;Z tSlk gkeksZUl fn;k

tkrk gSA(c) 8-32 dksf'kdkvksa rd fu"ksfpr v.Ms 'kY; fØ;k }kjk

izkIr fd;s tkrs gS rFkk /kk=h ekrk esa LFkkukUrfjr fd;stkrs gSA

(d) vkuqokaf'kd ekrk nwljs mPp v.MksRlxZ ds fy, RkS;kjjgrh gSA

(1) a, b, c

(2) b, c, d

(3) dsoy a, d

(4) a,b,c,d lHkh

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DIRECTIONS FOR Q. NO. 121 TO 180

These questions consist of two statements each,printed as Assertion and Reason.Whileanswering these Questions you are required tochoose any one of the following four responses.

A. If both Assertion & Reason are True & theReason is a correct explanation of the Assertion.

B. If both Assertion & Reason are True but Reasonis not a correct explanation of the Assertion.

C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False.

121. Assertion : A vector quantity is a quantity thathas both magnitude and a direction and obeys thetriangle law of addition and equivalently theparallelogram law of addition.Reason : The magnitude of the resultant vectorof two given vectors can never be less than themagnitude of any of the given vector.(1) A (2) B (3) C (4) D

122. Assertion :- In the series LCR circuit, the

impedance is minimum at resonance.

Reason :- The currents in inductance and capaci-

tance are same and out of phase at resonance in

series LCR circuit.(1) A (2) B (3) C (4) D

123. Assertion : The equation y = 2x + t is physicallyincorrect if x & y are distances and t is time.Reason : Quantities with different dimensionscannot be added or subtracted.(1) A (2) B (3) C (4) D

124. Assertion : If a person wants to observe sharp

and clear frings of good contrast then interference

experiment is prefrable compare to diffraction.

Reason : In diffraction intensity after the

central maxima decreases rapidly, so fringe

pattern become blurred.(1) A (2) B (3) C (4) D

125. Assertion: In a projectile motion, the accelerationis constant in both magnitude and direction butthe velocity changes in both magnitude anddirection.Reason : When a force or acceleration is actingin an oblique direction to the direction of velocity,then both magnitude and direction of the velocitymay be changed.(1) A (2) B (3) C (4) D

iz'u la[;k 121 ls 180 ds fy, funs Z'k

izR;sd iz'u es a dFku rFkk dkj.k fn, x;s gSaA iz'uks a

dks gy djrs le; uhps fn, x, pkjks a fodYiks a es a

ls lgh fodYi dks pqfu,A

A. ;fn dFku ,oa dkj.k nksuks a lR; ga S rFkk dkj.k dFkudk lgh Li"Vhdj.k gSA

B. ;fn dFku ,oa dkj.k nksuks a lR; gaS] ysfdu dkj.k] dFkudk lgh Li"Vhdj.k ugha gSA

C. ;fn dFku lR; gS] ysfdu dkj.k vlR; gSAD. dFku o dkj.k nk suks a vlR; gSaA

121. dFku % lfn'k og jkf'k gksrh gS] ftlesa ifjek.k o fn'kk

nksuksa gksrs gSa rFkk tks] lfn'k ;ksx ds f=Hkqt fu;e ;k lfn'k

;ksx ds lekukUrj prqHkZqt ds fu;e dk ikyu djrh gSA

dkj.k % fdUgha nks lfn'kksa ds ifj.kkeh lfn'k dk ifjek.k]

nksuksa lfn'kksa ds ifjek.kksa ls dHkh de ugha gks ldrk gSA

(1) A (2) B (3) C (4) D

122. dFku :- Js.khØe LCR ifjiFk esa vuqukn dh fLFkfr esaçfrckèkk U;wure gksrh gS Adkj.k :- Js.khØe LCR ifjiFk esa vuqukn dh fLFkfr esaçsjdRo rFkk laèkkfj= esa èkkjk foifjr dyk esa rFkk lekugksrh gSA(1) A (2) B (3) C (4) D

123. dFku : lehdj.k y = 2x + t lR; ugha gks ldrh] ;fn xvkSj y nwfj;k¡ gS rFkk t le; gSAdkj.k : fHkUu&fHkUu foekvksa dh jkf'k;ksa dk ;ksx ;kO;odyu ugha fd;k tk ldrk gSA(1) A (2) B (3) C (4) D

124. dFku : ;fn ,d O;fDr rh{.k rFkk Js"B foi;kZl okykfÝat izfr:i ns[kuk pkgrk gS rks foorZu dh rqyuk esaO;frdj.k iz;ksx vf/kd Bhd gSAdkj.k : foorZu esa dsfUæ; mfPp"B ds i'pkr vU; mfPp"Bksadh rhozrk rsth ls ?kVrh gS blfy;s fÝat izfr:i /kqa/kyk gkstkrk gSA(1) A (2) B (3) C (4) D

125. dFku : ç{ksI; xfr esa Roj.k dk ifjek.k rFkk fn'kk nksuksafu;r gksrs gS fdUrq osx dk ifjek.k rFkk fn'kk nksuksa ifjofrZr

gksrs gSA

dkj.k : tc osx dh fn'kk ls fdlh dks.k ij dksbZ cy ;k

Roj.k dk;Zjr gksrk gS rks osx dh fn'kk rFkk ifjek.k nksuksa

cny ldrs gSaA

(1) A (2) B (3) C (4) D

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126. Assertion : Work function of a metal is

8 eV.Two photons each having energy 5 eV can't

eject the electron from the metal.

Reason : More than one photon can't collide

simultaneously with an electron.(1) A (2) B (3) C (4) D

127. Assertion : When a spring balance is pulled bytwo forces of equal magnitude and oppositedirections, its reading must be non-zero.

F FSpring Balance

Reason : For the spring balance, shown the netforce acting on the balance is zero.(1) A (2) B (3) C (4) D

128. Assertion :– Heavy water is preferred over

ordinary water as a moderator in reactors.

Reason :– Heavy water, used for slowing down

the neutrons; has lesser absorption probability of

neutrons than ordinary water.(1) A (2) B (3) C (4) D

129. Assertion :- If more electric field lines leave aGaussian surface than those which enter into it,then the net charge enclosed by that surface willbe positive.Reason :- If the net flux passing through aGaussian surface is zero, then the net chargeenclosed by that surface will be zero.(1) A (2) B (3) C (4) D

130. Assertion : The root mean square and most

probable speeds of the molecules in a gas are the

same.

Reason : The maxwell's distribution for the speed

of molecules in a gas is symmetrical.(1) A (2) B (3) C (4) D

131. Assertion :- Consider a current carrying wirewhose cross sectional area decreases graduallyalong the direction of current, as shown in figure.As one goes from cross-section A to cross-sectionB, the drift speed of electrons increases.

A I B

Reason :- Electric field intensity at any cross-section in a current carrying wire is inverselyproportional to its cross sectional area.(1) A (2) B (3) C (4) D

126. dFku :- ,d èkkrq dk dk;ZQyu 8 eV gSA bl èkkrq ij nks5 eV Åtk Z oky s Qk sV k su vkifrr gk sr s g S a rk sQksVks bysDVªkWu mRlftZr ugha gksxkAdkj.k : ,d bysDVªkWu ls ,d lkFk] ,d ls vf/kd QksVksuugha Vdjk ldrs gSA(1) A (2) B (3) C (4) D

127. dFku : tc ,d fLiazx rqyk dks nks cjkcj ifjek.k ds cyksa}kjk foijhr fn'kk esa [khapk tkrk gSA rc fLizax rqyk dkikB~;kad v'kwU; gksxkA

F FSpring Balance

dkj.k : fp= esa fn[kk;s x;s fLizax rqyk ij dqy cy 'kwU;

gSA(1) A (2) B (3) C (4) D

128. dFku :– Hkkjh ikuh dks fj,sDVjksa esa lkèkkj.k ikuh dh vis{kkojh;rk nh tkrh gSAdkj.k :– Hkkjh ikuh ftldk iz;ksx U;wVªkWuksa dks èkhek djusds fy;s gksrk gS] dh U;wVªkWuksa dh vo'kks"k.k izkf;drk lkèkkj.k

ikuh dh vis{kk de gksrh gSA(1) A (2) B (3) C (4) D

129. dFku :- ;fn xkÅlh; lrg ls fuxZr fo|qr cy js[kk,sa fuos'kh

ls vfèkd gks rc ml lrg ls ifjc¼ dqy vkos'k èkukRed gksxkA

dkj.k :- ;fn xkÅlh; lrg ls ikfjr dqy ¶yDl 'kwU;

gks rc ml lrg ls ifjc¼ dqy vkos'k 'kwU; gksxk A

(1) A (2) B

(3) C (4) D

130. dFku : xSl ds v.kq dh rms pky vkSj lokZfèkd lEHkkfor

pky cjkcj gksrh gSA

dkj.k : xSl ds v.kqvksa dh pky ds fy, eSDlosy forj.k

lefer gksrk gSA(1) A (2) B(3) C (4) D

131. dFku :- ,d èkkjkokgh rkj dh dYiuk dhft, ftldkvuqçLFk dkV {ks=Qy fp=kuqlkj èkkjk dh fn'kk ds vuqfn'kèkhjs&èkhjs ?kV jgk gSA tc vuqçLFk dkV A ls B dh vksjxfr djrs gSa rks bysDVªkWu dh viogu pky c<+rh gS A

A I B

dkj.k :- fdlh èkkjkokgh rkj esa fdlh vuqçLFk dkV ijfo|qr {ks= dh rhozrk blds vuqçLFk dkV {ks=Qy dsO;qRØekuqikrh gksrh gS A(1) A (2) B (3) C (4) D

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132. Assertion : Air quickly leaking out of a ballon

becomes cooler.

Reason : The leaking air undergoes adiabatic

expansion.(1) A (2) B (3) C (4) D

133. Assertion :- Circuits containing high capacitycapacitors, charged to high voltages should behandled with caution, even when the current inthe circuit is switched off.Reason :- When an isolated capacitor is touchedby hand or any other part of the human body, thereis an easy path to the ground available for thedischarge of the capacitor.(1) A (2) B (3) C (4) D

134. Assertion : A heavy metal sphere is suspended by

a spring. When pulled down a little and released,

it oscillates up and down with a frequency f. If it

is taken to the moon where the acceleration due to

gravity is g/6, the frequency of oscillation is 6f .

Reason : The frequency of oscillation of the

spring depends only on the mass of the sphere

and spring constant.

(1) A (2) B (3) C (4) D

135. Assertion : Various regular polygons formed by

a constant length current carrying wire, then

magnetic induction at their centres are increases

when their number of sides increases.

Reason : A magnetic dipole placed in non uniform

magnetic field, then torque acting on it is always

zero.(1) A (2) B (3) C (4) D

136. Assertion : Node of pressure wave is formed at theopen end of an organ pipe.Reason : Due to huge volume of the atmosphereoutside the tube, deformation in its volume isnegligible.(1) A (2) B (3) C (4) D

137. Assertion :– Unlike charges are projected inopposite direction in transverse magnetic field,then they are deflected in same directions.Reason :– If a voltmeter connected across twoperipherial points of farday copper disc generator,its reading is zero.

(1) A (2) B (3) C (4) D

132. dFku : ,d xqCckjs ls rsth ls fjlko gksus okyh ok;q B.M+hgksrh gSAdkj.k : xqCckjs dh ok;q dk fjlko :¼ks"e izlkj ds vUrxZrgksrk gSA(1) A (2) B (3) C (4) D

133. dFku : ,sls ifjiFk ftlesa mPp /kkfjrk okys la/kkfj= mifLFkr

gS rFkk ftUgsa mPp oksYVrk ls vkosf'kr fd;k x;k gS] lko/kkuh

ls iz;ksx eas ysuk pkfg, pkgs ifjiFk esa /kkjk 'kwU; gksA

dkj.k : tc ,d foyfxr la/kkfj= dks ekuo ds gkFk ;k

vU; fdlh vax ls Li'kZ fd;k tkrk gS rks la/kkfj= dks Hkwfe

esa fujkos'ku ds fy, ,d vklku iFk fey tkrk gSA

(1) A (2) B (3) C (4) D

134. dFku : ,d Hkkjh /kkfRod xksys dks fLiazx ls fuyafcr fd;k

x;k gS tc bls FkksM+k lk [khapdj NksM+rs gSa rks ;g f vkofÙk

ls Åij uhps nksyu djrk gSA ;fn bls pUæek ij ys tk;sa

tgk¡ xq:Roh; Roj.k i`Foh dk g/6 gS rks nksyu vkofÙk 6f

gksxhA

dkj.k : ,d fLiazx dh nksyu vko`fÙk dsoy xksyd ds

æO;eku rFkk fLiazx fu;rkad ij fuHkZj gSA(1) A (2) B (3) C (4) D

135. dFku :- ,d fu;r yEckbZ ds /kkjkokgh rkj ls fofHkUu

vkÏfr ds lecgqHkqt cuus ij mudh Hkqtkvksa dh la[;k

c<+us ij muds T;kferh; dsUnz ij pqEcdh; {ks= dk eku c<+rk

tkrk gSA

dkj.k :- vle:i pqEcdh; {ks= esa j[ks pqEcdh; f}èkqzo

ij cy vk?kw.kZ lnSo 'kwU; gksrk gSA

(1) A (2) B (3) C (4) D

136. dFku : vkxZu ikbZi ds [kqys fljs ij nkc rjax dk fuLiUn

mRiUu gksrk gSAdkj.k : uyh ds ckgjh Hkkx esa ok;qe.My ds fo'kky vk;ruds dkj.k] vk;ru foÏfr ux.; gksrh gSA

(1) A (2) B (3) C (4) D

137. dFku :– fotkrh; vkos'kksa dks ijLij foijhr fn'kk esa

vuqizLFk pqEcdh; {ks= esa iz{ksfir djus ij os leku fn'kkvksa

esa fo{ksfir gksrs gSaA

dkj.k :– rkez pdrh tfu= dh ifjf/k fcUnqvksa ds ifjr fdlh

oksYVehVj dks tksM+us ij bldk ikB~;kad 'kwU; gksxkA

(1) A (2) B (3) C (4) D

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138. Assertion : Due to end correction fundamental

frequency of any pipe becomes less than

frequency without end correction.

Reason : Due to end correction effective length

of pipe increases.(1) A (2) B (3) C (4) D

139. Assertion :- Voltage across L (see figure) at

t = 0 is E

Reason :- Becuase E = VL + VR and at t = 0,

i = 0

E

RLi

t = 0

(1) A (2) B (3) C (4) D

140. Assertion :- Surface energy of an oil drop is same

whether placed on glass or water surface.

Reason :- Surface energy is dependent only on

the properties of oil.(1) A (2) B (3) C (4) D

141. Assertion :- The molality of a certain solution isalways greater than molarity. If density of solutionis nearly 1 gm/mL.Reason :- Molality of solution is given as,

m = solute

1000M1000d M M- ´

(Here m= Molality and M = Molarity)(1) A (2) B (3) C (4) D

142. Assertion :- Benzyne is aromatic.Reason :- In Benzyne all carbons are sp2.(1) A (2) B (3) C (4) D

143. Assertion :- Kc for process 2H2O(l) � 2H2(g) + O2(g)may be written as : Kc = [H2]

2 [O2]Reason :- Concentration of pure liquid is fixedand cannot vary. (taken as 1)(1) A (2) B (3) C (4) D

144. Assertion :- Reactivity for 1NS >

Reason :- Stability of carbocation

Å

>

Å

(1) A (2) B (3) C (4) D

138. dFku : fljk la'kks/ku ds dkj.k fdlh Hkh ufydk dh vko`fr]

fcuk fljk la'kks/ku ls de gksrh gSA

dkj.k :fljk la'kks/ku ls ufydk dh izHkkoh yEckbZ c<+ tkrh

gSA

(1) A (2) B (3) C (4) D

139. dFku :– izn£'kr fp= esa t = 0 ij] L ij oksYVrk E gSA

dkj.k :– D;ksafd E = VL + VR ,oa t = 0, ij i = 0

E

RLi

t = 0

(1) A (2) B (3) C (4) D

140. dFku :- rsy dh cwan dh i`"Bh; ÅtkZ leku jgrh gS] pkgs

mls dk¡p dh lrg ij j[kk tk;s ;k ikuh dh lrg ijAdkj.k :- i`"Vh; ÅtkZ dsoy rsy ds xq.kksa ij fuHkZj djrhgSA(1) A (2) B (3) C (4) D

141. dFku :- ;fn fdlh foy;u dk ?kuRo 1 gm/mL gks rksml foy;u dh eksyyrk ges'kk eksyjrk ls vf/kdgksxhAdkj . k :- foy;u dh ek syyrk nh tk; sxh ]

m = solute

1000M1000d M M- ´

(;gka m = eksyyrk rFkk M = eksyjrk)(1) A (2) B (3) C (4) D

142. dFku :- csUtkbu ,sjksesfVd gSAdkj.k :- csUtkbu esa lHkh dkcZu sp2 gSaA(1) A (2) B (3) C (4) D

143. dFku :- vfHkfØ;k 2H2O(l) � 2H2(g) + O2(g) ds fy,Kc dk O;atd gSa : Kc = [H2]

2 [O2]dkj.k :- 'kq¼ nzo dh lkUnzrk fu;r jgrh gS] vkSj ifjofrZrugh gksrh gSA (lfØ; nzO;eku =1 fy;k tkrk gS)(1) A (2) B (3) C (4) D

144. dFku :- 1NS ds çfr fØ;k'khyrk >

dkj.k :- dkcuZ/kuk;u dk LFkkf;Ro

Å

>

Å

(1) A (2) B (3) C (4) D

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145. Assertion :- –I effect of Cl atom is greater thanF atom.

Reason :- Cl atom has more electronegativity thanF atom.

(1) A (2) B (3) C (4) D

146. Assertion :- Acetaldehyde can show tautomerismwhile formaldehyde does not.Reason :- Boiling point of acetaldehyde is morethan formaldehyde.(1) A (2) B (3) C (4) D

147. Assertion :- The IUPAC name of the compound

O is cyclohexylidene methanone.

Reason :- CH2=C=O is called ketene.(1) A (2) B (3) C (4) D

148. Assertion :- Aluminium and zinc metal evolve H2

gas from NaOH solution.Reason :- Several elements such as Be, P, S, Cl etc.yield a hydride instead of H2 gas from NaOH.(1) A (2) B (3) C (4) D

149. Assertion :- Electron gain enthalpy strictly becomesless negative on moving down the group.Reason :- Size increases amd addition of extraelectron is close to nucleas on moving down thegroup.(1) A (2) B (3) C (4) D

150. Assertion :- In Benzene and Borazine boths and p electrons are completely delocalised.Reason :- Both molecules, C6H6 and B3N3H6 arehaving 12 atoms those are lying in the same plane.(1) A (2) B (3) C (4) D

151. Assertion :- BaSO4 forms white ppt in water.Reason :- Its lattice energy is lower than itshydration energy.(1) A (2) B (3) C (4) D

152. Assertion : On increasing the temprature, pH ofwater decreases thus water becomes acidicReason : Increasing the temperature increasesionisation of water(1) A (2) B (3) C (4) D

153. Assertion :- Mn2O7 is acidic but MnO is basic.Reason :- Mn+7 is strong oxidising agent thanMn+2.

(1) A (2) B (3) C (4) D

145. dFku :- Cl ijek.kq dk –I izHkko F ijek.kq ls vf/kd gksrkgSAdkj.k :- Cl ijek.kq dh fo|qr½.krk F ijek.kq ls vf/kdgksrh gSA(1) A (2) B (3) C (4) D

146. dFku :- ,sflVsfYMgkbM pyko;ork n'kkZrk gS tcfdQkWesZfYMgkbM ughaAdkj.k :- QkWesZfYMgkbM dh rqyuk esa ,sflVsfYMgkbM dkDoFkukad vf/kd gSaA(1) A (2) B (3) C (4) D

147. dFku :- ;k Sfxd O dk IUPAC uke

lkbDyksgsfDlyhMhu esFksuksu gSA

dkj.k :- CH2=C=O dks dhVhu dgrs gSA

(1) A (2) B (3) C (4) D

148. dFku :- ,Y;qfefu;e rFkk ftad /kkrq NaOH ds foy;uds lkFk fØ;k djds H2 xSl nsrs gSAdkj.k :- dqN rRoksa tSls Be, P, S, Cl bR;kfn H2 xSl ckgjfudkyus dh txg gkbMªkbM cukrs gSA(1) A (2) B (3) C (4) D

149. dFku :- oxZ esa uhps tkus ij bysDVªkWu xzg.k ,UFksYih dkeku loZFkk de ½.kkRed gksrk tkrk gSA

dkj.k :- oxZ esa uhps tkus ij f=T;k c<+rh gS rFkk u;s bysDVªkWu

dk tqMuk ukfHkd ls ikl gksrk gSA

(1) A (2) B (3) C (4) D

150. dFku :- csathu rFkk csjkthu esa s ,oa p bysDVªkWu iwjh rjgls foLFkkuhÏr gksrs gSAdkj.k :- C6H6 rFkk B3N3H6 esa 12 v.kq gksrs gSa tks fdleku ry esa gksrs gSA(1) A (2) B (3) C (4) D

151. dFku :- BaSO4 ty esa 'osr vo{ksi dk fuekZ.k djrk gSAdkj.k :- blds fy, tkyd ÅtkZ dk eku ty;kstu ÅtkZls de gksrk gSA(1) A (2) B (3) C (4) D

152. dFku: rki c<+kus ij ty dh pH ?kV tkrh gS vkSj tyvEyh; gks tkrk gSA

dkj.k: rki c<+us ij ty dk fo;kstu c<+ tkrk gSA

(1) A (2) B (3) C (4) D

153. dFku :- Mn2O7 vEyh; gS tcfd MnO {kkjh; gSAdkj.k :- Mn+2 dh rqyuk esa Mn+7 izcy vkWDlhdkjdgSA(1) A (2) B (3) C (4) D

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154. Assertion : A reaction which is spontaneous andaccompanied by decreases of randomness mustbe exothermic.Reason : All exothermic reaction are accompaniedby decrease of randomness.(1) A (2) B (3) C (4) D

155. Assertion : For fluorite structure, the F— ions occupytetrahedral void and Ca+2 ions are in CCP.Reason : The radius ratio of fluorite structure isbetween 0.155 to 0.414.(1) A (2) B (3) C (4) D

156. Assertion : At constant temperature PV vs V plotfor real gas is not a straight line.Reason : At high pressure, all gases have Z>1 butat low pressure most gases have Z < 1(1) A (2) B (3) C (4) D

157. Assertion :- Aniline gives positive isocyanide testwhile N-Methylaniline does not.Reason :- Aniline is more reactive for electrophilicsubstitution reaction as compared to N-Methylaniline.(1) A (2) B (3) C (4) D

158. Assertion : Change in internal energy is zero forall gases at constant temperature.Reason : Internal energy is function of temperatureonly.(1) A (2) B (3) C (4) D

159. Assertion :- Salicylic acid is more acidic thanbenzoic acid.Reason :- Ortho effect is observed in salicylic acid.(1) A (2) B (3) C (4) D

160. Assertion : For n =3, values of l may be 0, 1and 2.Reason : For each value of n, there are 0 to(n–1) possible values of l.(1) A (2) B (3) C (4) D

161. Assertion :- Osmosis involves movement ofsolvent molecules from lower concentrationsolution to its higher concentration solution.Reason :- Solutions having the same osmoticpressure are called isotonic solutions.(1) A (2) B (3) C (4) D

162. Assertion :- Whittaker proposed the five kingdomclassification.Reason :- He included virus, viroids and lichenon the basis of cellular mode of organization.(1) A (2) B (3) C (4) D

154. dFku: ,d vfHkfØ;k tks Lor% gksrh gS o ftlesa ;kn`fPNdrkesa deh gksrh gS oks vfHkfØ;k fuf'pr :i ls Å"ek{ksih gksuhpkfg,Adkj.k: lHkh Å"ek{ksih vfHkfØ;kvksa esa ;kn`fPNdrk esa dehvkrh gSA(1) A (2) B (3) C (4) D

155. dFku : ¶ywjkbV lajpuk esa F– prq"Qydh; fjDr esa rFkkCa+2 ccp esa mifLFkr gksrs gSaAdkj.k : ¶ywjkbV lajpuk dk flekUr f=T;k vuqikr 0.155ls 0.414 ds chp gksrk gSA(1) A (2) B (3) C (4) D

156. dFku: fLFkj rki ij] PV vs V vkjs[k okLrfod xSl dsfy, ljy js[kk ugha gksrh gSAdkj.k: mPp nkc ij lHkh xSl ds fy, Z > 1 gksrk gS ofuEu nkc ij vf/kdka'k xSlksa ds fy, Z < 1 gksrk gSA(1) A (2) B (3) C (4) D

157. dFku :- ,sfuyhu /kukRed vkblkslk;ukbM ifj{k.k nsrk gStcfd N-eSfFky,sfuyhu ughaA

dkj.k :- N-eSfFky,sfuyhu dh rqyuk esa ,sfuyhu bysDVªku

Lusgh çfrLFkkiu ds fy, vf/kd fØ;k'khy gSA

(1) A (2) B (3) C (4) D

158. dFku: vkUrfjd ÅtkZ esa ifjorZu lHkh xSl ds fy, fLFkjrki ij 'kwU; gksrk gSAdkj.k: vkUrfjd Åtk Z dsoy rki ij fuHk Zj djrhgSA(1) A (2) B (3) C (4) D

159. dFku :- csUtksbd vEy dh rqyuk esa lSfyflfyd vEyvf/kd vEyh; gSAdkj.k :- lSfyflfyd vEy esa vkWFkksZ çHkko gksrk gSA(1) A (2) B (3) C (4) D

160. dFku : n =3 ds fy, l dk eku 0, 1, 2 gks ldrkgSAdkj.k : n ds izR;sd eku ds fy;s l ds lEHko eku 0 ls(n–1) rd gksrs gSA(1) A (2) B (3) C (4) D

161. dF ku :- ijklj.k e s a foyk;d d s v.k q delkUnzrk ls vf/kd lkUnzrk okys foy;u dh vksj xfrdjrs gSAdkj.k :- leku ijklj.k nkc okys foy;u] leijkljhdgykrs gSA(1) A (2) B (3) C (4) D

162. dFku :- fOgVsdj us ikap txr iz.kkyh izfrikfnr dhAdkj.k :- mlus fo"kk.kq] okbjkWbM~l rFkk ykbdsUl dks laxBuds dksf'kdh; izk:i vk/kkj ij lfEefyr fd;kA

(1) A (2) B (3) C (4) D

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163. Assertion :- In angiosperms transport of food andwater are more efficient than gymosperm andpteridophytes.Reason :- In angiosperm sieve elements andvessels are longitudinally arranged with theirperforated and wall.

(1) A (2) B (3) C (4) D164. Assertion :- Bacillus thuriengenesis is incorporated

in plant genome to increase their yield.Reason :- It has antibiotic resistance gene, whichkills the larva of insects.

(1) A (2) B (3) C (4) D165. Assertion :- In some species of asteraceae and

poaceae seeds are not formed without fertilization.

Reason :- Formation of fruit without fertilization

is called pathenocarpy.

(1) A (2) B (3) C (4) D166. Assertion :- Arthritis occurs in synovial joint.

Reason :- Pain in arthritis is caused bydegeneration of synovial neurons.(1) A (2) B (3) C (4) D

167. Assertion :- Kreb's cycle is absent in bacteria

because mitochondria are absent.

Reason :- TCA cycle always occur in mitochondria.

(1) A (2) B (3) C (4) D

168. Assertion :– After fertilization corpus luteum is

stable till parturition.

Reason :– After 3 months of intrauterine life, it

dominantly secretes progesterone.

(1) A (2) B (3) C (4) D169. Assertion :- DNA is the best material for transmission

of genetic informations in the same generation.Reason :- The protein synthesis machinery hasevolved around DNA.(1) A (2) B (3) C (4) D

170. Assertion :- Any population has built in variation

in characteristics.

Reason :- Variations are always stable and

inheritable.

(1) A (2) B (3) C (4) D171. Assertion :- Multiple alleles can be found only

when population studies are made.Reason :- A diploid individual contains only twoalleles for a character.(1) A (2) B (3) C (4) D

163. dFku :- vko`rZchth;ks esa Hkkstu rFkk ty dk LFkkUrj.kvukorZchft;ks rFkk VsfjMksQkbVl ls vf/kd n{krk ls gksrkgSAdkj.k :- vko`rZchft;ks esa pkyuh rRo rFkk okfgdk rRoÅ/okZ/kj :i ls foU;kflr gksrs gS rFkk budh vUrfHkfÙk fNfnzrgksrh gSA(1) A (2) B (3) C (4) D

164. dFku :- cslhyl F;wfjutsusfll dks ikni ds thukse esaiSnkokj c<+kus ds fy, lfEefyr fd;k tkrk gSAdkj.k :- blesa tSo izfrjks/kh thu gksrk gS] tks dhV ds ykokZdks ekj nsrk gSA(1) A (2) B (3) C (4) D

165. dFku :- ,LVjslh rFkk ikW,lh dh dqN tkfr;ksa esa chtksa dkfuekZ.k fcuk fu"kspu ds gksrk gSAdkj.k :- fcuk fu"kspu ds Qyksa ds fuekZ.k dks vfu"ksd Qyudgrs gSA(1) A (2) B (3) C (4) D

166. dFku :- vkFkZjkbfVl lkbuksfo;y laf/k esa gksrk gSaAdkj.k :- vkFkZjkbfVl esa nnZ lkbuksfo;y raf=dkvksa ds àkflrgksus ls gksrk gSaA(1) A (2) B (3) C (4) D

167. dFku :- thok.kq esa ØsCl pØ vuqifLFkr gksrk gS D;ksafd

ekbVksdkWfMªU;k vuqifLFkr gksrs gSaA

dkj.k :- TCA pØ lnSo ekbVksdkWfUMª;k esa ik;k tkrk gSA

(1) A (2) B (3) C (4) D

168. dFku :– fu"kspu ds ckn dkiZl yqfV;e] izlo rd LFkk;hgks tkrh gSAdkj.k :– var% xHkkZ'k;h thou ds 3 eghus ds ckn ;gizHkkoh :i ls izkstsLVsjkWu L=kfor djrh gSA(1) A (2) B (3) C (4) D

169. dFku :- DNA vkuqoaf'kd lqpukvksa ds leku ih<h esaLFkkukarj.k ds fy, lcls mi;qDr inkFkZ gSAdkj.k :- izksVhu la'ys"k.k dh e'khujh DNA ds bZn fxnZfodflr gqbZA(1) A (2) B (3) C (4) D

170. dFku :- izR;sd tho la[;k esa fofHkUurk fufgr gksrh jghgSAdkj.k :- fofHkUurk,¡ lnSo fLFkj vkSj oa'kkxr gksrhgSA

(1) A (2) B (3) C (4) D

171. dFku :- cgq;qXe fodYih dsoy rHkh izkIr fd;s tk ldrsgS tc ,d lfe"V dk v/;;u fd;k tkrk gSAdkj.k :- fdlh Hkh f}xqf.kr lnL; esa fdlh y{k.k ds fy,dsoy nks gh ,yhYl ik;s tkrs gSA(1) A (2) B (3) C (4) D

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172. Assertion :- Large amount of water could be

reabsorbed from collecting duct to produce a

concentrated urine.

Reason :- Collecting duct plays a role in the

maintenance of pH and ionic balance of blood by

selective secretion of H+ and K

+ ions.

(1) A (2) B (3) C (4) D173. Assertion :- Number of chromosome double in

Anaphase of mitosis and Anaphase-II ofMeiosis.Reason :- Number of chromosome is double dueto splitting of centromere.(1) A (2) B (3) C (4) D

174. Assertion :- The T-cells themselves do not secrete

antibodies but help B-cells to produce them.

Reason :- T-Helper stimulates B-cells to produce

antibodies.

(1) A (2) B (3) C (4) D

175. Assertion :- Mitochondria is semi autonomus cellorganelle.Reason :- For some part of protein requirementit is depend on nucleus.(1) A (2) B (3) C (4) D

176. Assertion :- Alveoli are lined by ciliated epithelium.

Reason :- Cilia beat outward to move out anyexcess of air.

(1) A (2) B (3) C (4) D

177. Assertion :- Fatty acid and glycerol are notabsorbed in blood.

Reason :- Fatty acid and glycerol are absorbed inlymph.

(1) A (2) B (3) C (4) D178. Assertion :- Sensory neuron from toes to CNS is

one of the longest nerve in the bodyReason :- Sensory nerve form synapse at bothdendrites and axon terminals.(1) A (2) B (3) C (4) D

179. Assertion :- Tropical plants have a highertemperature optimum than the plants adapted totemperate climate.Reason :- The temperature optimum forphotosynthesis of different plants also depends upon habital that they are adapted to.(1) A (2) B (3) C (4) D

172. dFku :- lkfUnzr ew= ds fuekZ.k esa laxzkgd ufydk }kjk

vf/kd ek=k esa ty dk iqujko'kks"k.k gksrk gSA

dkj.k :- laxzkgd ufydk H+ rFkk K+

vk;uksa dk p;ukRed

L=o.k dj jDr ds vk;fud larqyu vkSj pH dks cukus esa

Hkwfedk fuHkkrh gSA

(1) A (2) B (3) C (4) D173. dFku :- xq.klw=k s a dh la[;k lelw=h foHkktu dh

i'pkoLFkk ,oa v¼Zlw=h foHkktu dh i'pkoLFkk-II esa nksxquhgksrh gSAdkj.k :- xq.klw=ksa dh la[;k lsUVªkseh;j ds fo[k.Mu dsdkj.k nksxquh gksrh gSA(1) A (2) B (3) C (4) D

174. dFku :- Vh&dksf'kdk,a [kqn rks izfrjf{k;ksa dk L=o.k ughadjrh ysfdu bUgsa mRiék djus esa ch&dksf'kdkvksa dh lgk;rkdjrh gSAdkj.k :- Vh&lgk;d] izfrj{kh fuekZ.k ds fy, ch&dksf'kdkdks izsfjr djrh gSA(1) A (2) B (3) C (4) D

175. dFku :- ekbVksdkWfUMª;k v¼ZLok;Rr dks'khdh; vaxdgSAdkj.k :- ;g izksVhu ds dqN Hkkx ds fuekZ.k ds fy;s dsUnzdij fuHkZj djrk gSA(1) A (2) B (3) C (4) D

176. dFku :- dqfidk,s i{ekHkh midyk ls vkLrfjr gksrh gSA

dkj.k :- i{ekHk vfrfjDr ok;q dks ckgj fudky nsrhgSA

(1) A (2) B (3) C (4) D177. dFku %& olh; vEy o fXyljkWy jä esa vo'kksf"kr ugha

gksrs gSAdkj.k %& olh; vEy o fXyljkWy] yfldk esa vo'kksf"krgksrs gSA

(1) A (2) B (3) C (4) D

178. dFku :- ik¡o ds vaxqBs ls ysdj dsUnzh; raf=dk ra= rdlaosnh U;wjkWu] 'kjhj dh lcls yEch U;wjkWu gSdkj.k :- laosnh raf=dk nqzfedk,¡ ,ao ,DlkWu VfeZuy] nksuksaij fluSIl cukrs gSA(1) A (2) B (3) C (4) D

179. dFku :- 'khrk s".k tyok;q esa vuqdwfyr ikniks dhvis{kk m".k dfVcU/kh; iknikas esa mfpr rkieku mPpgksrk gSAdkj.k :- fHkUu ikniksa ds çdk'k l'ys"k.k ds fy, mfprrkieku] os ftl vkokl esa vuqdwfyr gS] ij Hkh fuHkZj djrkgSA(1) A (2) B (3) C (4) D

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180. Assertion :- Maximum resolution occurs at fovea

centralis in eye.

Reason :- On fovea centralis cones, bipolar

neurons and ganglionic layers are connected.

(1) A (2) B (3) C (4) D181. Which Indian personality has been conferred

with the 2016 Bharat Gaurav Award?(1) Neerja Bhanot (2) Sunil Bharati Mittal(3) Suresh Mishra (4) Manoj Kumar

182. Which tennis pair have won the 2016 Italian OpenWomen's Doubles title?(1) Sara Errani and Roberta Vinci(2) Sania Mirza and Martina Hingis(3) Elena Vesnina and Vania King(4) Zheng Jie and Peng Shuai

183. The 2016 Nobel Peace Prize is awarded to whichcountry's president?(1) Colombia (2) Peru(3) Bolivia (4) Argentina

184. Ultraviolet rays can be used in water treatmentas :-(1) Condensation (2) Contamination(3) Distillation (4) Disinfectant

185. What is the theme of the World Environment Day2016 to raise global awareness to take positiveenvironmental action?(1) Safe wild for life (2) Go wild for life(3) Safe life for wild (4) Go safe wild

186. Silver Revolution was associated with theproduction of :-(1) Onion (2) Milk(3) Egg / Poultry (4) Fruits

187. Which of the following derives its name from ariver in the Democratic Republic of Congo ?(1) Chikungunya Virus(2) Lassa Fever(3) Ebola Virus(4) Salmonella Bacteria

188. With respect to Indian Science and Technology,what are Kamini, Purnima and Zerlina?(1) Artificial Satellites (2) Nuclear Reactors(3) Ballistic Missiles (4) Super Computers

189. Which of the following game is played in the courtsurrounded by four walls?(1) Lacrose (2) Squash(3) Boles (4) Snooker

180. dFku :- us= esa lokZf/kd foHksnu Qksfo;k lsUVªsfyl ij gksrk

gSaA

dkj.k :- Qksfo;k lsUVªsfyl ij 'kadq] f}/kzqoh; raf=dk rarq

rFkk xqfPNdh; ijr vkil esa lacaf/kr gksrh gSaA(1) A (2) B (3) C (4) D

181. o"kZ 2016 ds Hkkjr xkSjo iqjLdkj ls lEekfur 'kf[l;rdkSu gS\(1) uhjtk Hkuksr (2) lquhy Hkkjrh feÙky(3) lqjs'k feJk (4) eukst dqekj

182. o"kZ 2016 esa bVsfy;u vksiu efgyk ;qxy f[krkc fdl Vsful;qxy us thrk gS\(1) lkjk bZjkuh ,oa jkscVkZ foUlh(2) lkfu;k fetkZ ,oa ekfVZuk fgafxl(3) ,ysuk osLuhuk ,oa okfu;k fdax(4) >sax th ,oa isax 'kqvkbZ

183. o"kZ 2016 ds ukscsy 'kkafr iqjLdkj ls fdl ns'k ds jk"Vªifrdks lEekfur fd;k x;k gS\(1) dksyfEc;k (2) is:(3) cksfyfo;k (4) vtsZUVhuk

184. ijkcSaxuh fdj.kksa dks ty 'kks/ku es fdl :i esa iz;qDr fd;ktk ldrk gS :-(1) la?kuu (2) lanw"k.k(3) vklou (4) dhVk.kquk'kd

185. i;kZoj.k ds izfr oSf'od psruk tkx`r djus ds fy;s fo'o

i;kZoj.k fnol 2016 dh fo"k; oLrq D;k gS\

(1) Safe wild for life (2) Go wild for life

(3) Safe life for wild (4) Go safe wild

186. jtr Øka fr fuEu es ls fdlds mRiknu ls lac af/krgS :-(1) I;kt (2) nqX/k(3) vaMk @ iksYVªh (4) Qy

187. fuEu esa ls fdldk uke dkaxks yksdrkaf=d x.kjkT; esa fLFkr,d unh ds uke ls O;qRiUu fd;k x;k gS\(1) fpduxqfu;k ok;jl(2) yklk cq[kkj(3) bcksyk ok;jl(4) lYeksusyk cSDVhfj;k

188. Hkkjrh; foKku ,oa izks|ksfxdh ds lanHkZ esa dkfeuh] iwf.kZek,oa tfyZuk D;k gS\(1) Ïf=e mixzg (2) ukfHkdh; fj,DVj(3) cSfyfLVd felkby (4) lqij dEI;wVj

189. fuEu esa ls og dkSulk [ksy gS tks fd pkj nhokjksa ls f?kjsgq, eSnku esa [ksyk tkrk gS\(1) ySØksl (2) LDoS'k(3) cksYl (4) Luwdj

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190. Mahavir singh phogat, who has been chosen for

the 2016 Dronacharya Award, is associated with

which sport ?

(1) Hockey (2) Wrestling

(3) Gymnastics (4) Boxing

191. Which of these places got its name from a local

word for mangrove trees ?

(1) Vrindavan (2) Sunderbans

(3) Mussorie (4) Madhubani

192. Which of these fruits is not rich in vitamin C ?

(1) Orange (2) Lemon

(3) Kiwi (4) Apple

193. The sign for which mathematical function is the

logo of the Red Cross Society ?

(1) Subtraction (2) Multiplication

(3) Addition (4) Division

194. Which of these Union Cabinet Ministers have

never served as the Chief Minister of any state or

Union Territory ?

(1) D.V. Sadanand Gowda

(2) Rajnath Singh

(3) Sushma Swaraj

(4) Ram Vilas Paswan

195. If 'P + Q' means that P is the mother of

Q, 'P ÷ Q' means that P is the father of Q, 'P–Q'

means that P is the sister of Q. Then which of the

following relationship shows that M is the

daughter of R ?

(1) R ÷ M + N (2) R + N ÷ M

(3) R – M ÷ N (4) R – M + N

196. In an examination, 42% students failed in Hindi

and 52% failed in English. If 17% failed in both

the subjects, then the percentage of those who

passed in both the subjects, is :-

(1) 23% (2) 27%

(3) 35% (4) 40%

190. o"kZ 2016 ds nzks.kkpk;Z iqjLdkj ds fy;s p;fur egkohj

flag QksxkV] fuEu esa ls fdl [ksy ls lEcfU/kr gS &

(1) gkWdh (2) dq'rh

(3) ftEukfLVDl (4) eqDdsckth

191. fuEu esaa ls og dkSulk LFkku gS ftldk uke esaxzkso isM+ksa dsfy;s LFkkuh; 'kCn ls O;qRiUu fd;k x;k gS ?

(1) oankou (2) lqUnjcu

(3) elwjh (4) e/kqcuh

192. fuEu esa ls dkSuls Qy esa foVkfeu C izpqj ek=k esa ugha gS ?(1) ukjaxh (2) uhacw

(3) dhoh (4) lsc

193. fuEu esa ls og dkSulk xf.krh; Qyu gS ftldk fpUg] jsMØkWl lkslk;Vh dk yksxks gS ?

(1) O;odyu (2) xq.ku

(3) ;ksx (4) Hkkx

194. fuEu esa ls og dsUæh; dsfcusV ea=h dkSuls gS ftUgksus dHkhHkh fdlh jkT; ;k dsUæ 'kkflr izns'k ds eq[;ea=h ds :i esadk;Z ugha fd;k gS\

(1) Mh-oh- lnkuan xkSM+k

(2) jktukFk flag

(3) lq"kek Lojkt

(4) jke foykl ikloku

195. ;fn 'P + Q' dk vFkZ gS fd P, Q dh eka gS] 'P ÷ Q' dk vFkZ

gS P, Q ds firk gSa] 'P–Q' dk vFkZ gS P, Q dh cfgu gS] rks

fuEu esa ls dkSulk lEcU/k ;g iznf'kZr djsxk fd M, R dh

iq=h gS ?

(1) R ÷ M + N (2) R + N ÷ M

(3) R – M ÷ N (4) R – M + N

196. fdlh ijh{kk esa] 42% Nk= fgUnh esa vuqrh.kZ rFkk 52% Nk=vaxzsth esa vuqrh.kZ gks tkrs gSaA ;fn 17% Nk= nksuksa fo"k;ksa esavuqÙkh.kZ gS] rks nksuksa fo"k;ksa esa mÙkh.kZ gksus okys Nk=ksa dk izfr'krgksxk :-(1) 23% (2) 27%

(3) 35% (4) 40%

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197. Find the missing character in given figure :-

36

8

6

2 6 46 ?

7 7

8 10

2 45 6

(1) 42 (2) 46 (3) 48 (4) 50

198. If 'BOOK' is coded as 43, what will be the code

number for 'PEN" ?

(1) 33 (2) 35 (3) 43 (4) 53

199. Find the next two terms in the series :

A, C, F, J, ?, ?

(1) L, P (2) M, O

(3) O, U (4) R, V

200. Which planet is the nearest to the Earth ?

(1) Saturn (2) Venus

(3) Mercury (4) Jupiter

197. fn;s x;s fp=ksa esa foyqIr la[;k Kkr dhft;s :-

36

8

6

2 6 46 ?

7 7

8 10

2 45 6

(1) 42 (2) 46 (3) 48 (4) 50

198. ;fn dwV Hkk"kk esa 'BOOK' dks 43 fy[kk tk;s rks 'PEN"

dh dwV la[;k D;k gksxh ?(1) 33 (2) 35 (3) 43 (4) 53

199. nh xbZ Js.kh esa vxys nks in Kkr dhft;s :A, C, F, J, ?, ?

(1) L, P (2) M, O

(3) O, U (4) R, V

200. fuEu esa ls dkSulk xzg i`Foh ds fudVre gS ?(1) 'kfu (2) 'kqØ(3) cq/k (4) c`gLifr

Your moral dutyis to prove that ALLEN is ALLEN

Your Target is to secure Good Rank in Pre-Medical 2017

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SPACE FOR ROUGH WORK / jQ dk;Z ds fy;s txg