laboratorio analisis señales

8/17/2019 laboratorio analisis señales

1/19

LABORATORIO DE ANALISIS DE SEÑALES Y SISTEMAS de Juniodel 2015

UNIVERSIDAD NACIONAL TECNOLOGICA

DE LIMA SUR

(UNTELS)

INGENIERÍA ELECTRÓNICA Y

TELECOMUNICACIONES

LABORATORIO DE ANALISIS DE SEÑALES

Y SISTEMAS

LABORATORIO Nº4

TITULO: CONVOLUCION DE SEÑALES CON

MATLAB

NOMBRES:

VEGA MAYTA JHAN CARLOS ALFREDO

CICLO: VI

PROFESOR: GUSTAVO PAZ PURIZACA

1


2/19


LIMA - PERU

2015

CONVOLUCION CONTINUA

En este laboatoio se obse!a" el #o$eso de $on!olu$i%n& tal $o'ose (a$)a $on la#i$eo& #eo (a$iendo uso del So*t+ae de In,enie)aMATLAB-Sean las tes se.ales

/aa nuesto laboatoio !a'os a to'a las se.ales e*e$tuae'osuna seie de $on!olu$iones& tales $o'o

34t 6 4t 7 84t34t 6 !4t 7 84t34t 6 !4t 7 4t

34t 6 4t 7 4t34t 6 84t 7 84t34t 6 9 !4t : 84t ; 7 84t


3/19


CONVOLUCION

1.Hallar la convolucion de x(t) = y(t) * (t)

Al!orit"o#

T = 0.05;

t = [-0.5:T:0.5];

y = 1 + square(2*pi*t);

z = 1 + sawtooth(2*pi*t);

= e!p(-t);

! = "o#(y$z);

su%p&ot(1$'$1)

p&ot(y);

ri o#;

a!is ([0 0 0 ']);

su%p&ot(1$'$2)

p&ot(z);

ri o#;

su%p&ot(1$'$')

p&ot(!);

ri o#;


4/19


$. Hallar la convolucion de x(t) = v(t) * (t)

Al!orit"o#

T = 0.05;

t = [-0.5:T:0.5];



= e!p(-t);

! = "o#($z);

su%p&ot(1$'$1)

p&ot();

ri o#;

su%p&ot(1$'$2)

p&ot(z);

ri o#;

su%p&ot(1$'$')

p&ot(!);

ri o#;

?


5/19


%. Hallar la convolucion de x(t) = v(t) * (t)

Al!orit"o#

T = 0.05;

t = [-0.5:T:0.5];



= e!p(-t);

! = "o#($y);

su%p&ot(1$'$1)

p&ot();

ri o#;

su%p&ot(1$'$2)

p&ot(y);

a!is([0 0 0 ']);

ri o#;

su%p&ot(1$'$')

p&ot(!);

ri o#;

5


6/19


&. Hallar la convolucion de x(t) = y(t)* y(t)

Al!orit"o#

T = 0.05;

t = [-0.5:T:0.5];



= e!p(-t);

! = "o#(y$y);su%p&ot(1$'$1)

p&ot(y);

ri o#;

a!is ([0 0 0 ']);

su%p&ot(1$'$2)

p&ot(y);

ri o#;

a!is ([0 0 0 ']);

su%p&ot(1$'$')

p&ot(!);

ri o#;

@


7/19


'. Hallar la convolucion de x(t) = (t)* (t)

Al!orit"o#

T = 0.05;

t = [-0.5:T:0.5];



= e!p(-t);

! = "o#(z$z);

su%p&ot(1$'$1)

p&ot(z);

ri o#;

su%p&ot(1$'$2)

p&ot(z);

ri o#;

su%p&ot(1$'$')

p&ot(!);

ri o#;


8/19


. Hallar la convolucion de x(t) = v(t) * v(t)

Al!orit"o#

T = 0.05;

t = [-0.5:T:0.5];



= e!p(-t);! = "o#($);

su%p&ot(1$'$1)

p&ot();

ri o#;

su%p&ot(1$'$2)

p&ot();

ri o#;

su%p&ot(1$'$')

p&ot(!);

ri o#;


9/19


. Hallar la convolucion de x(t) = v(t) * (t) + * (t)

Al!orit"o#

T = 0.05;

t = [-0.5:T:0.5];


= e!p(-t);

# = "o#($z);

! = "o#(#$z);

su%p&ot(1$'$1)

p&ot(#);

ri o#;

su%p&ot(1$'$2)

p&ot(z);

ri o#;

su%p&ot(1$'$')

p&ot(!);

ri o#;

C


10/19


,-CALON UNITAIO

/a0o # ,-CALON UNITAIO

t = -5:.001:5;

= ustep(t);

p&ot(t$$,i#eith,$5$,/o&or,$,r,);

a!is([-5 5 -1 2]);

ho& o#p&ot([-5 5]$[0 0]);

p&ot([0 0]$[-1 2]);

!&a%e&(,aria%&e i#epe#ie#te t,);

y&a%e&(,u(t),)

10


11/19


,2e"3lo./A-O 4# /UL-O UNITAIO

t = -5:.001:5;

1 = ustep(t-2).*ustep(t+2);

2 = ustep(t-2).*ustep(2-t);

' = ustep(t+2).*ustep(2-t);

su%p&ot(1$'$1);

p&ot(t$1$,i#eith,$'$,/o&or,$,%,);

a!is([-5 5 -1 2]);

ho& o#

tit&e(, u(t-2) u(t+2) ,);

su%p&ot(1$'$2);

p&ot(t$2$,i#eith,$'$,/o&or,$,,);

a!is([-5 5 -1 2]);ho& o#

tit&e(, u(t-2) u(2-t) ,);

su%p&ot(1$'$');

p&ot(t$'$,i#eith,$'$,/o&or,$,r,);

a!is([-5 5 -1 2]);

ho& o#

tit&e(, u(t+2) u(2-t) ,);

11


12/19


ale de$i ue el anteio e>e'#lo ea #aa des#e>a dudas es#e$to a la*un$i%n es$al%n unitaio- En la #i'ea ,"=$a& le>os de a$ota nuesta*un$i%n& est" !ale F G (asta el in=nito- En la se,unda ,"=$a& solo

obtene'os 1 #unto en 42&1- /o Hlti'o& en la te$ea ,"=$a& s) lo,a'osobtene la ,"=$a ue uee'os a$otada ente 2 2-

,2e"3loAl!orit"o#

t = -5:.001:5;

! = (e!p(-'*t).*ustep(t+2)) + (e!p('*t).*ustep(2-t))

p&ot(t$!$,i#eith,$'$,/o&or,$,y,);

a!is([-5 5 0 50]);

ho& o#

ri o#

tit&e(, e3p&o ,);

5UNCION I6/UL-O

/A-O 17.

Al,oit'ot = -5:.001:5;

e&ta1 = ue&ta(t);

p&ot(t$e&ta1);

12


13/19


5UNCION A6/A

/A-O 11.

t = -10:.01:10;

! = 2*ura3p(t) - 2*ura3p(t-2) - ura3p(t+1) + ura3p(t-');

p&ot(t$!$,/o&or,$,,);

CONVOLUCION 8, -,9AL,- :A-ICA-#

/A-O 1$# CONOLKION DE N /LSO Y NA E3/ONENKIAL

t = 0:0.001:';

= ustep(t-1).*ustep(2-t);

p&ot(t$$,i#eith,$'$,/o&or,$,r,);

tit&e(,4ri"a e &a u#"i6# es"a&6# u#itario u(t),);

!&a%e&(,aria%&e i#epe#ie#te t,);

iure

a!is([0 ' 0 1.5]);

ho& o#;

p&ot([0 ']$[0 0]);p&ot([0 0]$[0 1.5]);

y&a%e&(,u(t),);

1


14/19


t = -':0.001:';

! = (e!p(-a%s(t)).*ustep(t+2).*ustep(2-t));

p&ot(t$!);

a!is([-2 2 0 1.5]);

iure

= "o#($!);

p&ot()

TA,A

ealiar todo0 lo0 3ro;le"a0


15/19


% Ejercicio 1

su%p&ot(1$'$1)

t = 0:0.001:';

ht = ura3p(t).*ustep('-t);

p&ot(t$ht$,i#eith,$'$,/o&or,$,r,);

tit&e(,7u#"io# 8a3pa,);a!is([-1 ' 0 ']);

su%p&ot(1$'$2)

ho& o#;

t = -1:0.001:1;

!t = ustep(t+1).*ustep(1-t);

p&ot(t$!t);

tit&e(,7u#"io# s"a&o# 9#itario,);

a!is([-1 ' 0 ']);

su%p&ot(1$'$')

= "o#(ht$!t);

p&ot()

tit&e(,!(t) * h(t),);

?r@ca#

$. Hallar la convoluci>n# y(t) = x(t) *


16/19


a!is([0 0 ']);

su%p&ot(1$'$2)

ho& o#;

t = 2:0.001:;

ht = ustep(t-2).*ustep(-t);

p&ot(t$ht);

tit&e(,7u#"io# s"a&o# 9#itario,);a!is([0 0 ']);

su%p&ot(1$'$')

= "o#(!t$ht);

p&ot()

tit&e(,!(t) * h(t),);

?r@co#

%. Hallar la convoluci>n# y(t) = x(t) *


17/19


ho& o#;

t = 1:0.001:2;

ht = ustep(t-1).*ustep(2-t);

p&ot(t$ht);

tit&e(,7u#"io# s"a&o# 9#itario,);

a!is([-2 2 0 2]);

su%p&ot(1$'$') = "o#(!t$ht);

p&ot()

tit&e(,!(t) * h(t),);

?r@co#

&. Hallar la convoluci>n# y(t) = x(t) *


18/19


a!is([-1 2 0 2]);

su%p&ot(1$'$2)

ho& o#;

t = -1:0.001:2;

ht = ue&ta(t);

p&ot(t$ht);

tit&e(,7u#"io# s"a&o# 9#itario,);a!is([-1 2 0 2]);

su%p&ot(1$'$')

= "o#(ht$!t);

p&ot()

tit&e(,!(t) * h(t),);

?r@co#

'. Hallar la convoluci>n# y(t) = x(t) *


19/19


p&ot(t$ht);

tit&e(,7u#"i6# s"a&6# 9#itario,);

a!is([-1 2 0 2]);

su%p&ot(1$'$')

ho& o#;

= "o#(!t$ht);

p&ot()tit&e(,!(t) * h(t),);

?r@ca#

1C

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