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Inventory and Models in Project 3
Load Driven SystemsJohn H. Vande Vate
Spring, 2001
Outline
• What are the inventory implications
• How to build a model
Inventory• Laurel, Montana
• Orilla, Washington
At the Plants
• Half a rail car load on average for each ramp
• Conclusion: Inventory at the origins depends on the capacity of the transportation units and the number of destinations served.
At the Mixing Center
• Models we have:– In Bound Only (if Out Bound is one-by-one) – In Bound and Out Bound (eg. Case #1)
• Simplicity of mixing center allows detailed model
• Model depends on operating policy
Two Operating Policies• Minimum Inventory Policy
– Whenever there’s a full load to a destination, bring in an empty rail car (if necessary) and haul it away
– Requires an inventory of empty railcars
• Equipment Balance Strategy– Never bring in an empty rail car– Strive to have rail cars arrive full and depart full. – Sometimes, they may depart empty
Minimum Inventory• Just like the plant!• Expect half a rail car in each load lane • Inventory depends on the capacity of the transportation
units and the number of destination the mixing center serves
• Why no dependence on the number of plants the mixing center serves?
• Why no in-bound inventory?
Building the Lot
• How many vehicles can there be on the lot?
• How large must we make it?
Equipment Balance• The inventory will slowly rise to a point where we
achieve equipment balance and then remain there.• A Fiction:
– We serve r destination ramps so there are r load lanes– Each rail car holds c vehicles– Suppose each load lane had c-1 vehicles and one load lane, #1,
was empty – What happens when the next railcar arrives?
The Fiction
• If all c vehicles go to load lane #1, we have a full load …
• If any vehicle goes to another load lane, we have a full load…
• Can’t haul away more than c vehicles … why not?
Why is this a fiction?
• Under the equipment balance policy we can have more than c vehicles in a load lane. How?
• Question: How many vehicles can there be at the mixing center?
An Answer• No more than (r-1)(c-1)
• That’s as though we had one empty load lane and the rest just short of full.
• Argument: If we have (r-1)(c-1) and c vehicles arrive, then we have r(c-1) + 1.
• Some load lane must have at least c vehicles.
In Either Case
• Inventory at the mixing center depends on the capacity of the transportation units c and the number of destinations it serves r.
At the Ramps
• Inventory at the rail ramp?
• What does it depend on?
A Basic Model
• Cont. Variable: path from plant to ramp• Examples:
– Direct: plant to ramp without visiting mixing center– Mixing center: plant to mc to ramp
• Binary Variable: on each leg to count dest.– Plant to ramp– Plant to mc– mc to ramp...
Constraints• Meet Demand
– sum over all the paths out of the plant to a ramp =
– demand at the ramp for the plants production.
• Count the destinations the plant serves– for each path that uses the leg from-to
flow on the path Demand at the destination ramp from the origin plant*binary variable on leg from-to
Complications
• What should the costs be?
• Long paths through several mixing centers
• How do different modes influence the question?– Do unit trains have different inventory influences at
the plants and mixing centers than individual rail cars?
– What’s the influence of speed?
• How to model different modes?