Infinite Series Module 1 -July 2007

Embed Size (px)

Citation preview

  • 7/21/2019 Infinite Series Module 1 -July 2007

    1/20

    02/28/15 5. Series IA 1

    InfniteSeries

    InfniteSeries

    Module 1

  • 7/21/2019 Infinite Series Module 1 -July 2007

    2/20

    02/28/15 5. Series IA 2

    Learning Outcome

    Learning Outcome

    At the end of the module, students able to

    identify the difference between sequenceand series.

    determine whether a series converges or

    diverges.

  • 7/21/2019 Infinite Series Module 1 -July 2007

    3/20

    02/28/15 5. Series IA 3

    An infinite sequence :

    ,...,...,,, 321 naaaa

    What is an infnite sequence?

    What is an infnite sequence?

  • 7/21/2019 Infinite Series Module 1 -July 2007

    4/20

    02/28/15 5. Series IA 4

    An infinite series is formed by addingterms

    of an infinite sequence;

    ......321 +++++

    n

    aaaa

    In other words:

    In other words:

    ......3211

    +++++=

    =

    n

    n

    n aaaaa

    What is an infnite series?

    What is an infnite series?

  • 7/21/2019 Infinite Series Module 1 -July 2007

    5/20

    02/28/15 5. Series IA 5

    Infnite sequence versus series

    Infnite sequence versus series

    sequence series

    na

    nS

    1a 11 aS =

    2a 212 aaS +=

    3a3213 aaaS ++=

    ...3211

    +++=

    =

    aaaa

    n

    n

    Infinite Seriesor Series

  • 7/21/2019 Infinite Series Module 1 -July 2007

    6/20

    02/28/15 5. Series IA 6

    Example 1

    Example 1

    =

    +++=1

    ...8

    1

    4

    1

    2

    1

    2

    1

    ,...

    2

    1,...,

    8

    1,

    4

    1,

    2

    1

    )i(

    n

    n

    n sequence

    series

    1S

    2S

    3S

  • 7/21/2019 Infinite Series Module 1 -July 2007

    7/2002/28/15 5. Series IA 7

    Example 1Example 1

    =

    +

    +

    ++++=+

    +

    1

    1

    1

    ...)4

    1()

    3

    1(

    2

    11

    1

    )1(

    ,...1

    )1(,...,4

    1,3

    1,2

    1,1)ii(

    k

    k

    k

    k

    k sequence

    series

  • 7/21/2019 Infinite Series Module 1 -July 2007

    8/2002/28/15 5. Series IA 8

    Let denote the series nthpartial sum:

    ......3211

    +++++=

    =

    n

    n

    n aaaaa

    The series converge or diverge?

    Given a series

    nS

    n

    n

    k

    kn aaaaaS ++++==

    =

    ...3211

    321

    3

    1

    3

    21

    2

    1

    2

    11

    aaaaS

    aaaS

    aS

    n

    n

    n

    n

    ++==

    +==

    =

    =

    =

  • 7/21/2019 Infinite Series Module 1 -July 2007

    9/2002/28/15 5. Series IA 9

    The series converges.

    f the sequence !Sn" is convergent and

    e#ists , then the series

    is said to be convergent to S.

    SSnn =lim

    =1n

    na

    A sequence of partial sum

    is formed.

    ,...,...,,, 321 nSSSS

    $ $ $ $

  • 7/21/2019 Infinite Series Module 1 -July 2007

    10/2002/28/15 5. Series IA 10

    The series converges.

    %he numberSis called the sum of the series,

    and we write .1

    San

    n =

    =

  • 7/21/2019 Infinite Series Module 1 -July 2007

    11/20

    02/28/15 5. Series IA 11

    The series diverges.

    f does not e#ists,

    the series is said to be divergent.

    nn

    S

    lim

    =1n

    na

  • 7/21/2019 Infinite Series Module 1 -July 2007

    12/20

    02/28/15 5. Series IA 12

    o! to determine a seriesconverge"diverge?

  • 7/21/2019 Infinite Series Module 1 -July 2007

    13/20

    02/28/15 5. Series IA 13

    =

    +++=1

    ...8

    1

    4

    1

    2

    1

    2

    1

    n

    n

    IllustrationIllustration

    nnS

    S

    S

    S

    S

    2

    1

    4

    3

    2

    1

    1

    .

    .

    .

    16

    15

    16

    1

    8

    1

    4

    1

    2

    1

    87

    81

    41

    21

    4

    3

    4

    1

    2

    1

    21

    =

    =+++=

    =++=

    =+=

    =

    &ow this formula

    is obtained$

  • 7/21/2019 Infinite Series Module 1 -July 2007

    14/20

    02/28/15 5. Series IA 14

    IllustrationIllustration

    nS,...,

    8

    7,

    4

    3,

    2

    1

    Thus,

    nnS

    S

    S

    S

    S

    2

    1

    4

    3

    2

    1

    1

    .

    .

    .

    16

    15

    16

    1

    8

    1

    4

    1

    2

    1

    87

    81

    41

    21

    4

    3

    4

    1

    2

    1

    2

    1

    =

    =+++=

    =++=

    =+=

    =

    n211,...,

    211,

    211,

    211 32

    nnS

    2

    11=

  • 7/21/2019 Infinite Series Module 1 -July 2007

    15/20

    02/28/15 5. Series IA 15

    ==+++=

    11...8

    1

    4

    1

    2

    1

    2

    1

    n

    n

    IllustrationIllustration

    1)1(limlim2

    1==

    nnnn

    S

    %he series is convergent and has the sum

    equal to ', i.e.,1

    2

    1

    1

    =

    =nn

    .

  • 7/21/2019 Infinite Series Module 1 -July 2007

    16/20

    02/28/15 5. Series IA 16

    IllustrationIllustration

    .

    n Sum o# the frst n terms $ %

    1 &.'

    ( &.)'* &.+)', &.-*)'' &.-+)' &.-+,*)'

    ) &.--(1+)'+ &.--(1+)'&

    =12

    1

    n

    n

  • 7/21/2019 Infinite Series Module 1 -July 2007

    17/20

    02/28/15 5. Series IA 17

    (etermine whether the series

    converges or diverges.

    Example 2

    =

    1

    )1(n

    n

  • 7/21/2019 Infinite Series Module 1 -July 2007

    18/20

    02/28/15 5. Series IA 18

    Example 2

    =

    1

    )1(n

    n

    1111

    011

    1

    3

    2

    1

    =+=

    ==

    =

    S

    S

    S

    diverges.

  • 7/21/2019 Infinite Series Module 1 -July 2007

    19/20

    02/28/15 5. Series IA 19

    Exercises

    Exercise 10.3 , !"e 653

    #o. 1$2, 15$16

  • 7/21/2019 Infinite Series Module 1 -July 2007

    20/20

    02/28/15 5. Series IA 20

    E/0 o# O02LE